Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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python *args as an tuple? directory?
How can I turn a phrasebook into a *argument I mean, specifically, the example in django we have: .order_by('field1', 'field2'...) and I'd like to do if sort =="byName": a=[] #???? a.append('name') a.append('surname') .order_by(a) #??? -
Am trying to deploy my django app on heroku using gcs google cloud storage
Am trying to deploy my django app on heroku using gcs google cloud storage as my storage it can't find the json file enter image description here -
DJANGO: How to use custom user types for social login?
I have custom models for users with multiple user types. Like user1@gmail.com is type A, and he/she can do a,b and c thing, user2@outlook.com is type B, and he/she can do a,b,d or e thing. And that system is working perfectly. But I have an option to login via google and Facebook via social_django, and office365 login via django-microsoft-auth. So how can I add that users (from login via Google, Facebook etc.) to user types for normal users? Also can I add the to existing user types or I need new ones? -
Django - How can I get birthday and gender using GoogleOAuth2
I managed to set google login working well but I am trying to get additional information from the users, specifically gender and birthday. Unfortunately I am having trouble trying to achieve this. Here are my configurations in settings.py: SOCIAL_AUTH_GOOGLE_OAUTH2_KEY = 'xxxx' SOCIAL_AUTH_GOOGLE_OAUTH2_SECRET = 'xxxx' SOCIAL_AUTH_GOOGLE_OAUTH_SCOPE = [ 'https://www.googleapis.com/auth/user.birthday.read', ] SOCIAL_AUTH_PIPELINE = ( 'social_core.pipeline.social_auth.social_details', 'social_core.pipeline.social_auth.social_uid', 'social_core.pipeline.social_auth.auth_allowed', 'social_core.pipeline.social_auth.social_user', 'social_core.pipeline.user.get_username', 'social_core.pipeline.social_auth.associate_by_email', # <--- enable this one 'social_core.pipeline.user.create_user', 'social_core.pipeline.social_auth.associate_user', 'social_core.pipeline.social_auth.load_extra_data', 'social_core.pipeline.user.user_details', ) After adding the link to the scope I was expecting to get the birthday but when I check the response from: https://www.googleapis.com/oauth2/v1/userinfo?access_token='xxxx' I get the following response: { "id": "xx", "email": "xx@gmail.com", "verified_email": true, "name": "xx", "given_name": "xx", "family_name": "xx", "picture": "https://xx.com/a-/xx", "locale": "xx" } As you can see birthday is missing. Anyone that got through this one out there? Thanks -
Django: request.POST.get from form data not working correctly
I have been trying to come up with a solution and have been searching the web for hours now. I hope you guys can help me find the problem in my code! I am trying to implement a form in Django, a simple textfield. As soon as the user submits the text data in the field, I want it to POST the data and I want a next view to retrieve that data and print it on screen. In detail: I want the user to enter some text in the form on page home.html then submit it, and the user input will then be printed on the next page predict.html (of course, I am planning to transform the inpur in between, but first I want the text to at least get printed on the second page). This is my code: views.py from django.shortcuts import render from django.http import HttpResponse from .forms import NameForm from django.template import RequestContext def index(request): return render(request, 'personal/home.html') def predicted(request): predicted = request.POST.get('data') return render(request, 'personal/predicted.html', {"predicted": predicted}) def get_name(request): if request.method == 'POST': if form.is_valid(): return render_to_response('personal/predcited.html', RequestContext(request)) else: form = NameForm() return render(request, 'home.html', {'form': form}) forms.py from django import forms class NameForm(forms.Form): data … -
Django - Editing a Query from two different tables
I have got a query running from two different tables but I when I go in to edit the query I am hitting a roadblock; A roadblock in my own logic on how django works. I run a query of all devices at a specific location and this works fine. In the database I have a table for location, a table for devices and a table for maintenance. search device by location search_device.html {% extends "example/base.html" %} {% block content %} <head> <title>Search Devices at Locations</title> </head> <body> <form action="{% url 'search_device' %}" method="POST" > {% csrf_token %} <table> <tr> <td><b>Locations: &nbsp;&nbsp; </b></td> <td> <select name="location_name"> {% for location in locations %} <option value="{{location.location_name}}">{{location.location_name}}</option>{% endfor%} </select> </td> <td><input type="submit" value="Submit"/></td> </tr> </table> </form> <br> <h3 align="left">Render Device List based on Location Choice</h3> <table> <tr> <td><b> Devices: </b></td> <td><b>License Key:</b><br> <td><b>Maintenance Support End Date: &nbsp;</b> <br> <td><b>Actions</b></td> </tr> {% for device in devices %} <tr> <td id="device_name"> {{device.device_name}} </td> <td id="license_key"> {{device.maintenance.license_key}} </td> <td id="maintenance_support_end_date"> {{device.maintenance.maintenance_support_end_date}} </td> <td><a href="{% url 'edit_device' device.id %}"><button id="edit_device">Edit Device</button></a> </td> </tr> {% endfor %} </table> This works fine and gives me a list of all devices at each location. What I'd like to be able … -
Django Custom user login form doesn't work
I'm a beginner at Django and I created custom user model (Person) using AbstractBaseUser and custom forms for registration (RegForm) and login (LogForm). With RegForm everything is okay and it works right but when I try to login I always have error messages that's my username or password incorrect, even when it's correct. I have tried to read documentation but I didn't find solution. And I have no idea what is wrong. views.py : from django.shortcuts import render,redirect from django.contrib import messages #from .models import Tutorial from django.http import HttpResponse from django.contrib.auth import logout, authenticate, login, get_user_model # для входа, выхода from .forms import RegForm , LogForm from .models import Person, Service, Category from django.contrib.auth.decorators import login_required from django.contrib.auth.forms import AuthenticationForm @login_required def homepage(request): return render(request = request, template_name='barter/home.html', context = {"category":Category.objects.all}) def register(request): #вход аккаунта next = request.GET.get('next') # if request.method == 'POST': form = RegForm(request.POST or None) if form.is_valid(): user = form.save(commit = False) Username = form.cleaned_data.get('Username') password = form.cleaned_data.get('password') user.set_password(password) user.save() new_user = authenticate(Username=user.Username, password=password) login(request, new_user) if next: return redirect(next) return redirect('/') context = { 'form' : form, } return render(request,"register.html",context) def login_request(request): #вход next = request.GET.get('next') form = LogForm(request.POST or None) if form.is_valid(): Username = … -
Python reportlab - Last page
I'm trying to create an invoice with the python reportlab library. (to return in a Django view) What I am already able to do is the following: I can create the first page with the header and add a table with all products, which can go over multiple pages. But now my problem: How can I write something at the bottom of the last page? (I already added a Spacer to be sure that there's enough space for the important part of the invoice. I need to get a canvas on which I can draw the invoice. (That function which draws the invoice is all set up) I hope you can help me! PS: I'm sorry for my english, I'm from switzerland. -
Summary values on a Django Model with tens of millions of records
I have a Django model developed on PostgreSQL with more than 20 Millions of records. The large volume of data makes it impossible to get even a simple count of all rows. from myapp.models import LargeModel len(LargeModel.objects.all()) Is there any workaround for this? -
Why is Django Channels websocket connect call failing?
I am working on a web app that consists of a Django channels 2 app running on AWS Elastic Beanstalk, where AWS Elasticache serves as my redis instance. Everything works completely fine in development, but once I deploy it to AWS I start having websocket issues. Initially it works just fine, sending data over the websocket, for about two minutes, but at some point the connection always fails. Django throws the exception [Errno 110] Connect call failed. In my past experience this has always been related to it not being able to connect to the redis instance, however, in those cases it failed immediately. I have no idea why it's suddenly failing after some amount of time. Any suggestions for causes of this error? -
Hi there. I would like to register the models in admin.py but it doesn't work
Here is admin.py code and I registered app in INSTALLED_APPS and I created three app beside this app . from django.contrib import admin admin.autodiscover() from .models import ( Teacher,Student,Group, Subject,Table,Dairy, NotParticipating,Task,StudentTask, ) @admin.register(Teacher) class TeacherAdmin(admin.ModelAdmin): list_display = ('created_at', ) admin.site.register(Student) admin.site.register(Group) admin.site.register(Subject) admin.site.register(Table) admin.site.register(Dairy) admin.site.register(NotParticipating) admin.site.register(Task) admin.site.register(StudentTask) -
How to deploy changes made to my django project, which is hosted on pythonanywhere?
I am new to git and Pythonanywhere. So, I have a live Django website which is hosted with the help of Pythonanywhere. I have made some improvements to it. I have committed and pushed that changes to my Github repository. But, now I don't know that how to further push that changes to my Pythonanywhere website. I am so confused. Please help!!! Forgive me, I am new to it. -
Reducing backlog and celery mem consumption
I have a Django app that simply checks an API and then stores the response from the API to my DB if the status is completed, I use celery for this, the celery task looks like this @task(bind=True, priority=5) def process_domain_scan(self, scan_url): response = self.get_status(scan_url) if response and (response.get('status') != "FAILED"): while response and response.get('status') == "PENDING": print "processing :: {}".format(response) time.sleep(5) response = self.get_status(scan_url) if response and response.get('status') == "COMPLETED": #store to database the problem here is that sometimes the job I am running on the external API might be pending for hours and hence my celery task will be in a loop for hours while waiting for the status to return Completed is there a better way of using celery to do this without waiting for the API to return Completed -
Deployment failed on heroku
I am relatively new to Django and I am finishing my first project. I've been following the heroku django tutorial at http://devcenter.heroku.com/articles/django and https://www.youtube.com/watch?v=kBwhtEIXGII&list=PL-51WBLyFTg2vW-_6XBoUpE7vpmoR3ztO&index=24&t=576s but I keep running into the following problem. heloku logs --tail 2020-04-27T17:49:06.576169+00:00 app[web.1]: ModuleNotFoundError: No module named 'crm-live' 2020-04-27T17:49:06.576364+00:00 app[web.1]: [2020-04-27 17:49:06 +0000] [10] [INFO] Worker exiting (pid: 10) 2020-04-27T17:49:06.614676+00:00 app[web.1]: [2020-04-27 17:49:06 +0000] [4] [INFO] Shutting down: Master 2020-04-27T17:49:06.614802+00:00 app[web.1]: [2020-04-27 17:49:06 +0000] [4] [INFO] Reason: Worker failed to boot. 2020-04-27T17:49:08.033207+00:00 heroku[router]: at=error code=H10 desc="App crashed" method=GET path="/" host=codrut-crm.herokuapp.com request_id=2d4b0b83-fb4b-4658-b465-d96b3cd3c4fd fwd="188.26.24.149" dyno= connect= service= status=503 bytes= protocol=https 2020-04-27T17:53:52.000000+00:00 app[api]: Build started by user ursache.codrut71@gmail.com 2020-04-27T17:54:58.618150+00:00 app[api]: Deploy 11a7c2b5 by user ursache.codrut71@gmail.com 2020-04-27T17:54:58.618150+00:00 app[api]: Release v9 created by user ursache.codrut71@gmail.com 2020-04-27T17:54:58.947798+00:00 heroku[web.1]: State changed from crashed to down 2020-04-27T17:55:10.000000+00:00 app[api]: Build succeeded 2020-04-27T17:55:37.135414+00:00 heroku[router]: at=error code=H14 desc="No web processes running" method=GET path="/" host=codrut-crm.herokuapp.com request_id=dad84a35-0089-44a8-9d8c-4c06e673f59d fwd="188.26.24.149" dyno= connect= service= status=503 bytes= protocol=https 2020-04-27T17:56:52.119540+00:00 heroku[router]: at=error code=H14 desc="No web processes running" method=GET path="/admin" host=codrut-crm.herokuapp.com request_id=485798b3-6d1b-48c7-beb2-5d9a0ba52dcf fwd="188.26.24.149" dyno= connect= service= status=503 bytes= protocol=https 2020-04-27T18:08:48.000000+00:00 app[api]: Build started by user ursache.codrut71@gmail.com 2020-04-27T18:09:49.587556+00:00 app[api]: Deploy 11a7c2b5 by user ursache.codrut71@gmail.com 2020-04-27T18:09:49.587556+00:00 app[api]: Release v10 created by user ursache.codrut71@gmail.com 2020-04-27T18:10:01.000000+00:00 app[api]: Build succeeded 2020-04-27T18:10:05.771483+00:00 heroku[router]: at=error code=H14 desc="No web processes running" method=GET path="/" … -
Django urls NoReverseMatch - missing argument
I've a more or less working comment and edit comment system. However, when I configured everything so that the proper userreview_id is pulled to the url in my UpdateView, it broke the link going from index page to details (it is in details thatare displayed comments, access to comment form and to updateview form). Here is my code with Broken URL urlpatterns = [ # ex: /restaurants/ path('', views.index, name='index'), # ex: /restaurants/15 path('<int:restaurant_id>/', views.details, name='details'), path('/edit/review/<int:userreview_id>', views.EditReview.as_view(), name='edit-review'), ] Details view def details(request, restaurant_id): # calling restaurant ID and displaying it's data restaurant = get_object_or_404(Restaurant, pk=restaurant_id) # calling a review and displaying it's data user_review_list = UserReview.objects.filter(pk=restaurant_id) user_reviews = [] for user_review in user_review_list: if user_review.posted_by == request.user: user_reviews.append({"user_review_grade": user_review.user_review_grade, "user_review_comment": user_review.user_review_comment, "posted_by": user_review.posted_by, "edit": user_review.get_edit_url}) else: user_reviews.append({"user_review_grade": user_review.user_review_grade, "user_review_comment": user_review.user_review_comment, "posted_by": user_review.posted_by}) return render(request, 'restaurants/details.html', {'restaurant': restaurant, 'user_review_list': user_reviews,}) index template {% extends "base_generic.html" %} {% block content %} <h1>Restauracje Poznan</h1> <p> Search by name or city <form action="{% url 'restaurants:search_results' %}" method="get" class="form-inline"> <div class="form-group mx-sm-3 mb-2"> <input name="q" type="text" placeholder="Search..."> </div> <div> <input type="submit" class="btn btn-primary mb-2" value="Search"> </div> </form> </p> <h2>Restaurants and other gastronomy places:</h2> {% if restaurants_list %} <ul class="list-group"> {% for restaurant in … -
How to check if a url is valid that youtube-dl supports
I am developing a project, where user submits a URL. I need to check if that URL is valid url , to download data from youtube-dl supported sites. Please help. -
Why is pytest throwing an "AttributeError: 'NoneType' object has no attribute '_meta'" error when testing model creation?
I'm using Django 2 and trying to write some unit tests for my models. I have these models ... class CoopTypeManager(models.Manager): def get_by_natural_key(self, name): return self.get_or_create(name=name)[0] class CoopType(models.Model): name = models.CharField(max_length=200, null=False, unique=True) objects = CoopTypeManager() class CoopManager(models.Manager): # Look up by coop type def get_by_type(self, type): qset = Coop.objects.filter(type__name=type, enabled=True) return qset class Coop(models.Model): objects = CoopManager() name = models.CharField(max_length=250, null=False) types = models.ManyToManyField(CoopType) address = AddressField(on_delete=models.CASCADE) enabled = models.BooleanField(default=True, null=False) phone = PhoneNumberField(null=True) email = models.EmailField(null=True) web_site = models.TextField() I have created the following factory for auto-generating these models ... import factory from .models import CoopType, Coop class CoopTypeFactory(factory.DjangoModelFactory): """ Define Coop Type Factory """ class Meta: model = CoopType class CoopFactory(factory.DjangoModelFactory): """ Define Coop Factory """ class Meta: model = Coop coop_type = factory.SubFactory(CoopTypeFactory) Then I created this simple test ... import pytest from django.test import TestCase from .tests.factories import CoopTypeFactory, CoopFactory class ModelTests(TestCase): @classmethod def setUpTestData(cls): print("setUpTestData: Run once to set up non-modified data for all class methods.") pass def setUp(self): print("setUp: Run once for every test method to setup clean data.") pass @pytest.mark.django_db def test_coop_type_model(): """ Test coop type model """ # create coop type model instance coop_type = CoopTypeFactory(name="Test Coop Type Name") assert coop_type.name … -
Can I refer to single value of foreign key in Django's template?
I have model: `class product(models.Model): product = models.CharField(primary_key=True, unique=True, max_length=7, editable=False) desc = models.CharField(max_length=50) class pricelist(models.Model): product = models.ForeignKey(product, on_delete=models.CASCADE) price_group = models.ForeignKey(pricegroup, on_delete=models.CASCADE) price = models.DecimalField(max_digits=8, decimal_places=2, null=True)` Basically I have 4 different price groups(one product may have up to 4 different prices- one for each price_group) and I'd like to display product's price of specified(filtered) price group on my product's template(DetailView). Let's say I have following price groups: "PG1", "PG2","PG3","PG4" I'm able to loop through the list of them: {% for pricelist in product.pricelist.all %} {{ pricelist.price }} {% endfor %} but I can't display prices for only two specified price groups. I need to display prices on my webpage in the following way: PG1 = 124 PG3 = 367 Sometimes only prices for two or three groups are available -
got this error while runing the django web service
django.template.library.InvalidTemplateLibrary: Invalid template library specified. ImportError raised when trying to load 'rest_framework.templatetags.rest_framework': cannot import name ' six' from 'django.utils' -
Modular python admin pages
I'm building a personal website that I need to apply modularity to it for purpose of learning. What it means is that there is a model that contains x number of classes with variations, as an example a button is a module that you can modify as much depending on provided attributes. I also have a pages model that need to select any of created modules and render it. I can't find any documentation of how to access multiple classes from one field to reference to. Model structure is as below: Modules, contains module A and module B Pages should be able to select any of module A and order its structure. Please let me know if not clear, this is the simplest form I could describe. Am I confusing this with meta classes? How one to achieve what I'm trying to achieve? -
AppRegistryNotReady: Apps aren't loaded yet
I am trying to query data from database using Python shell. settings.py includes: import django django.setup() ... INSTALLED_APPS = [ 'django.contrib.contenttypes', 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'products.apps.ProductsConfig', 'users.apps.UsersConfig', 'crispy_forms', ] When i open Python shell i do: > from django.conf import settings > settings.configure() Then I try to import models: > from products.models import Product However, Python returns: django.core.exceptions.AppRegistryNotReady: Apps aren't loaded yet. I tried adding django.setup() call in settings and also moving this statement after INSTALLED_APPS. -
why the super(ContactView, self) ? . isnt super use to call a function of parent class and why is that argument necessary
also this line in the below code why is the return necessary: return super(ContactView, self).form_valid(form). class ContactView(FormView): form_class = ContactForm template_name = 'contact-us.html' success_url = reverse_lazy('<app-name>:contact-us') def form_valid(self, form): self.send_mail(form.cleaned_data) return super(ContactView, self).form_valid(form) def send_mail(self, valid_data): # Send mail logic print(valid_data) pass -
Django Ajax post data is not clean on insert
I am posting the data via Ajax using $("#add").click(function () { var data = { 'content': $("#content-input").val(), 'csrfmiddlewaretoken': '{{ csrf_token }}' }; var request = $.ajax({ url: "/ajax/list", method: "POST", data: data, dataType: "json" }); }); I'm trying to save the data in my view using if request.is_ajax() and request.method == 'POST': form = listModel() tmpForm = form.save(commit=False) tmpForm.content = request.POST['content'], tmpForm.user_id = request.user tmpForm.save() return HttpResponse(json.dumps({"message":"saved"}),content_type="application/json") else: return Http404 The data is being saved as ('Test input',), What am I doing wrong? I want the text to be saved normally without the parentheses. Thanks -
how do I pass context variables which use request in Class-based views in django?
In my other views, I am passing in the following context variable. tab: 'documents' authenticated: request.user.is_authenticated Exec: ('Exec' in groups) ElectionOfficer: ('ElectionOfficer' in groups) Staff: request.user.is_staff Username: request.user.username URL_ROOT: settings.URL_ROOT How can I pass in those exact same variables when accessing the page that renders with the /multiple url? in my urls.py url(r'^multiple$', views.SubmissionUploadPage.as_view(), name='multiple_example') in my forms.py class MultipleFileExampleForm(BaseForm): input_file = MultipleUploadedFileField() def save(self): example = UserSubmission.objects.create( title=self.cleaned_data['title'] ) for f in self.cleaned_data['input_file']: UploadedFile.objects.create( example=example, input_file=f ) self.delete_temporary_files() in my views.py class BaseFormView(generic.FormView): template_name = 'file_uploads/example_form.html' def get_success_url(self): return reverse('success') def form_valid(self, form): form.save() return super(BaseFormView, self).form_valid(form) class SubmissionUploadPage(BaseFormView): form_class = forms.MultipleFileExampleForm -
I want to display pptx from my local to webpage using Django
<iframe class="default_position" src="{% static 'images/aa.pps' %}" ></iframe> When i am using this, and after refreshing it, its showing ad download. i want to display on web page, not download.
