Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Django - Custom ModelAdmin form not overriding default models
I have a model defined class subnet(models.Model): subnet_id = models.AutoField(primary_key=True) subnet_pod = models.ForeignKey(pod, null=True, on_delete=models.SET_NULL, verbose_name='Select Pod') subnet_number = models.IntegerField(verbose_name='VLAN/SVI Number') subnet_description = models.CharField(max_length=10, verbose_name='Subnet Description') LAYER_CHOICES = ( ('Layer2', 'Layer2'), ('Layer3', 'Layer3'), ) subnet_layer = models.CharField(max_length=50, choices=LAYER_CHOICES,verbose_name='Layer2/3') subnet_ip = models.CharField(max_length=50, verbose_name='Gateway IP/Mask') vrf = models.ForeignKey(vrf,blank=True, null=True, on_delete=models.SET_NULL, verbose_name='Select VRF') class Meta: verbose_name = 'Subnet' verbose_name_plural = 'Subnets' def __str__(self): return self.subnet_number I want to override the subnet_ip and add a label and placeholder to it using a custom form, so I have: class subnetForm(forms.ModelForm): class Meta: model = subnet fields = ['subnet_number', 'subnet_description', 'subnet_layer', 'vrf'] widgets = { 'subnet_ip': forms.TextInput(attrs={'placeholder': 'e.g,: x.x.x.x/x'}), } However the placeholder does not get applied to the model and does not show in front-end. I also have a admin.py: class subnetAdmin(admin.ModelAdmin): list_display = ('subnet_number','subnet_description','subnet_layer','subnet_ip','vrf') ordering = ('-subnet_number',) Any help is appreciated!! -
MultiValueDictKeyError instead of Form Errors in Template
I've a form for users to Upload a CSV File. If user does not select a file from PC and clicks the Submit button, the template should be rendered but instead it returns: MultiValueDictKeyError at /productos/productos-csv/ 'file' I understand that it is because I cannot find: elif request.method == "POST": csv_file = request.FILES['file'] But how can I tell Django just to render the Template and Show an error saying to "Please, Upload a File". HTML: {% if messages %} {% for message in messages %} <div> <!-- | means OR operator--> <strong>{{message|safe}}</strong> </div> {% endfor %} {% else %} <h1>Creación de productos</h1> <p>{{orden}}</p> <form action="" method="POST" enctype="multipart/form-data"> {% csrf_token %} <label for="file1">Subir archivo</label> <input type="file" id="file1" name="file"><br> <small>Solo se aceptan CSV files</small> <button type="submit">Crear productos</button> </form> {% endif %} In my view I'm adding an error to messages to tell user to upload a file: if not csv_file: messages.error(request, 'Por favor, seleccione un archivo CSV') views.py: def products_upload(request): # declaring template template = "scolarte/productos/subir-productos.html" data = Product.objects.all() # prompt is a context variable that can have different values depending on their context prompt = { 'orden': 'El orden de las columnas del archivo CSV debe ser: producto, direccion, referencia, provincia, … -
Django: too many values to unpack (expected 2) while making dynamic Q OR model query
I am currently trying to dynamically generate a Django or query using Q objects. I have created some code to do so based off of what I've read people having success with, however I'm not having any with my implementation. My code is as follows query = reduce(or_, (Q(target[search_class] + '__icontains=' + keyword) for search_class in range(2, len(target)))) model.objects.filter(query) # Error happens while making the query itself (too many values to unpack (expected 2)) This is the simplest implementation of this method that I could find. Any help solving this issue would be greatly appreciated. Thanks in advance! -
when I try to do a migration on a hosting I get an error, what should I do?
I'm trying to upload a website to hosting. But when in the bash console I write python manage.py migrate, I get an error. File "/var/www/u0932024/data/djangoenv/lib/python3.7/site-packages/MySQLdb/connections.py", line 239, in query _mysql.connection.query(self, query) django.db.utils.OperationalError: (1067, "Invalid default value for 'id'") what should I do? -
Django save ManyToManyField Model with ModelMultipleChoiceField
So I know there are a few similar questions but none of the solutions worked for me. I've tried save(commit=false) and save_m2m as well as a bunch of other stuff but i get the error NOT NULL constraint failed: home_services.managers_id Anyways here's my code: views.py def service(request): if request.user.is_authenticated: if request.method == 'POST': #Create Service form = CreateServiceForm(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect('/service') #Later change this to redirect to server page else: form = CreateServiceForm() args = {'user': request.user, 'form': form} return render(request, 'service.html', args) else: return HttpResponseRedirect('/feed') models.py class Services(models.Model): name = models.CharField(max_length=100, default='') description = models.CharField(max_length=500, default='') owner = models.OneToOneField(User, on_delete=models.CASCADE) managers = models.ForeignKey(User, related_name="managers", on_delete=models.CASCADE) members = models.ManyToManyField(User, related_name="members") def __str__(self): return str(self.name) + ": id" + str(self.id) forms.py class CreateServiceForm(forms.ModelForm): owner = forms.ModelChoiceField(queryset=User.objects.all()) members = forms.ModelMultipleChoiceField(queryset=User.objects.all()) class Meta: model = Services fields = [ 'name', 'description', 'owner', 'members', ] I want the user to be able to create a service and select 1 or more members that is in the default django User model. -
configuring celeryd as managed service on aws beanstalk with django
I'm trying configure AWS ElasticBeanstalk to start the celeryd service but it fails when creating a new environment because it starts celeryd before the django source is copied into the container. celeryd fails to start because it depends on the django app source which blcoks further environment setup. in .ebextensions/django.config I have: services: sysvinit: celeryd: enabled: "true" ensureRunning: "true" I've tried setting ensureRunning to false and set the sources path to the django app thinking that the failure would be accepted and it would get restarted when the app is unpacked, but this does not work either services: sysvinit: celeryd: enabled: "true" ensureRunning: "false" sources: - "/opt/python/current/app" How can I start the service after the app is unpacked? -
Django after login still anonymous user
I made a customized view using Django view and tried to login. Login is successful and I checked user models' last login data and session data updated, but If I try other APIs after login It says, anonymous user. customized view class CustomView(View): @method_decorator(csrf_exempt) def dispatch(self, request, *args, **kwargs): if self.LOGIN_REQUIRED is True and self.is_authenticated(request) is False: return JsonResponse({'code': 'AUTHENTICATION_ERROR', 'message': 'Login is required'}, status=401) if request.method in self.ADMIN_REQUIRED_METHODS: if self.is_authenticated(request) is False: return JsonResponse({'code': 'ADMIN_REQUIRED', 'message': 'Admin is required'}, status=401) if request.user.is_administrator is False: return JsonResponse({'code': 'ADMIN_REQUIRED', 'message': 'Admin is required'}, status=401) Login view class SignInView(CustomVeiw): def post(self, request): email = request.POST['email'] password = request.POST['password'] user = User.objects.filter(email=email).first() if not user or (type_ == 'email' and not user.check_password(password)): return {'status': 'WRONG_CREDENTIALS'}, 401 if user.status is False: return {'status': 'INACTIVATED_USER'}, 401 login(request, user) return JsonResponse(dict(data=UserSerializer(user).data)) settings.py REST_FRAMEWORK = { 'DEFAULT_AUTHENTICATION_CLASSES': [ 'rest_framework.authentication.BasicAuthentication', 'rest_framework.authentication.SessionAuthentication', ] } -
How to mention other user with @username in status update like Twitter in Django
Hey guys I don't know where to begin but I have my status update code exactly how I want it. Now when a user is mentioned in the status update by using "@" like Twitter and Instagram. I want the username to be @username as permalink to that users profile just like Twitter and Instagram. Any help is much appreciated!!! This is the code I have in my views.py def post(self, request): form = HomeForm(request.POST) if form.is_valid(): post = form.save(commit=False) post.user = request.user post.save() text = form.cleaned_data['post'] form = HomeForm() return redirect('home') context = {'form': form, 'text': text} return render(request, self.template_name, context) This is the code in my models.py class Status1(models.Model): post = models.CharField(max_length=333) user = models.ForeignKey(User, on_delete=models.CASCADE) date = models.DateTimeField(auto_now=True) blockchain = models.TextField() -
How do I set my django debug=False and show 404 on the web when there is error?
My settings.py code: SECRET_KEY = os.environ['SECRET_KEY'] # SECURITY WARNING: don't run with debug turned on in production! DEBUG = os.environ.get('DJANGO_DEBUG', '') != 'False' My .bash_profile: # Django test deploy export SECRET_KEY='67bd6db221e2be1b5b16cb70b79d3bbee8928d9053a8eb32' export DJANGO_DEBUG="False" -
Celery, RabbitMQ and Django on Heroku: Reaching Memory Limit
I'm reaching the RAM memory limit on my Heroku Dyno (hobby) currently while running Celery tasks with RabbitMQ in a Django app. I'm played around with the Celery settings a little bit but I keep hitting the memory limit, and I'm missing the technical knowledge on memory optimization. I'm wondering if there is anything I can do with my current settings to prevent reaching the limit or is the only solution here to upgrade the Heroku Dyno? BROKER_URL = 'amqp://url' BROKER_POOL_LIMIT = 5 CELERY_RESULT_BACKEND = None CELERY_MAX_TASKS_PER_CHILD = 10 CELERY_MAX_MEMORY_PER_CHILD = 80000 Procfile:web: gunicorn app_name.wsgi worker: celery -A app_name worker -l info --without-heartbeat Task.py file:@shared_task(acks_late=True, ignore_result=True) def function_name(args): -
How to include full name from google data into my user model upon signup (django-rest-auth)
Please, How can I get a user's full name on google to be added to the user model when they sign up as a new user with google, using the django-rest-auth package? below is how the related apps are set up: models.py class User(AbstractBaseUser, PermissionsMixin): username = None email = models.EmailField(max_length=254, unique=True) name = models.CharField(max_length=250) is_staff = models.BooleanField(default=False) is_superuser = models.BooleanField(default=False) is_active = models.BooleanField(default=True) last_login = models.DateTimeField(null=True, blank=True) date_joined = models.DateTimeField(auto_now_add=True) slug = models.SlugField(max_length=255, unique=True, blank=True) USERNAME_FIELD = 'email' REQUIRED_FIELDS = ['name'] settings.py SOCIALACCOUNT_PROVIDERS = { 'google': { 'SCOPE': [ 'email', 'profile', ], 'AUTH_PARAMS': { 'access_type': 'offline', }, 'APP': { 'client_id': 'secret.apps.googleusercontent.com', 'secret': 'specialsecret', 'key': '' } } } views.py class GoogleLogin(SocialLoginView): adapter_class = GoogleOAuth2Adapter -
Why must I cast int to bool before checking "is True"?
In my url.py file in Django, I have the following line: if bool(settings.DEBUG) is True: This works well because settings.DEBUG == 1 therefore it equals True after the bool() function. However, I needed to add the bool() to make it work. The original line was not working and the original line was: if settings.DEBUG is True: This always evaluates to False, even when settings.DEBUG == 1. Why is the value 1 evaluating to False when I do not cast it explicitly to bool? In other words, why doesn't "1 is True" evaluate true? Note that I am using python 3 in case that matters to the answer. -
problem with user print None instead of my user
hello in a project I have a little problem I did what is necessary as the code shows but when I launch the server I do not have my user which is written but None thank you for your help views.py class ArticleUpdateView(LoginRequiredMixin,UpdateView): template_name='Article/detail-update.html' form_class=ArticleForm def form_valid(self,form): obj=form.save(commit=False) obj.user=self.request.user return super(ArticleUpdateView,self).form_valid(form) def get_from_kwargs(self): kwargs=super(ArticleUpdateView, self).get_form_kwargs() kwargs['user']=self.request.user return kwargs def get_queryset(self): return Article.objects.filter(user=self.request.user) def get_context_data(self, *args, **kwargs): context=super(ArticleUpdateView, self).get_context_data(*args,**kwargs) context['title']='edit article' return context forms.py class ArticleForm(forms.ModelForm): class Meta: model=Article fields=["Category","description","shortdescription", "price", "mandator","image","name","public"] def __init__(self, user=None,*args,**kwargs): print(user) super(ArticleForm,self).__init__(*args,**kwargs) self.fields['Category'].queryset=Category.objects.filter(owner=user) models.py class Article(models.Model): user=models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE) Category=models.ForeignKey(Category,on_delete=models.CASCADE) name=models.CharField('article',max_length=100,unique=True) referance=models.IntegerField('reference',null=True) description=models.TextField('description') image=models.ImageField(upload_to="",blank=True) public = models.BooleanField(blank=True,null=True,default=True) mandator = models.ManyToManyField(Mandator,blank=True) created_at = models.DateTimeField('created', auto_now_add=True) price=models.IntegerField('price',blank=True,null=True) shortdescription=models.TextField('short_description') -
Manage.py migrate fails in this Heroku python "Get Started Guide" at Step 14 "Provision a Database"
Here's the link to the guide: Getting Started on Heroku with Python The guide says to run: heroku run python manage.py migrate which produces the following output: ... Your models have changes that are not yet reflected in a migration, and so won't be applied. Run 'manage.py makemigrations' to make new migrations, and then re-run 'manage.py migrate' to apply them. So then I run >heroku run python manage.py makemigrations and get: Running python manage.py makemigrations on ⬢ sleepy-reef-12488... up, run.5322 (Free) Migrations for 'hello': hello/migrations/0002_auto_20200125_2146.py - Alter field when on greeting Then re-running the first code: heroku run python manage.py migrate produces the same message as before. The end result is this template error at: my test app TemplateSyntaxError at /db/ 'staticfiles' is not a registered tag library. Must be one of: admin_list admin_modify admin_urls cache i18n l10n log static tz Request Method: GET Request URL: https://sleepy-reef-12488.herokuapp.com/db/ Django Version: 3.0.2 Exception Type: TemplateSyntaxError Exception Value: 'staticfiles' is not a registered tag library. Must be one of: admin_list admin_modify admin_urls cache i18n l10n log static tz Exception Location: /app/.heroku/python/lib/python3.7/site-packages/django/template/defaulttags.py in find_library, line 1025 Python Executable: /app/.heroku/python/bin/python Python Version: 3.7.3 Python Path: ['/app/.heroku/python/bin', '/app', '/app/.heroku/python/lib/python37.zip', '/app/.heroku/python/lib/python3.7', '/app/.heroku/python/lib/python3.7/lib-dynload', '/app/.heroku/python/lib/python3.7/site-packages'] Server time: Sat, 25 … -
Unable to login to Django admin after changing SESSION_COOKIE_NAME
Hallo I want to change the SESSION_COOKIE_DOMAIN because it is set incorrect on a production server. Due to this I also need to change the SESSION_COOKIE_NAME to something else. If not there might be 2 cookies with the same name but different domains on the users side because it's already in production as I already mentioned. And with this 2 cookies user can have trouble logging in. So far so good now the problem. After I just change the SESSION_COOKIE_NAME (So I didn't even change the SESSION_COOKIE_DOMAIN yet) I am unable to login into the admin. I can see the cookie with the new name being set. The application itself has no problems so users can login without problems. Which is strange because it's the same authentication. What I tried: - Deleting all session on the server site - private mode - other Browser - Flushing all possible caches on the server but might have mist one. - checking for hardcoded session names, but there are not. What else could I possibly check? If I set the SESSION_COOKIE_NAME back to what it was it is working again. It only happens on the production server not locally and on not on … -
django sayfalar arası url
arkadaşlar djangoda sayfalar arası geçişte girdiğim bir urldeyken aynı urlye giderken üzerine ekliyor ör: http://127.0.0.1:8000/signin.html/signup.html ben zaten signin.html deyim ama aynı linke basınca üzerine ekliyor tersine eklememesi lazım aynı veya farklı linklere gidebilmesi lazım http://127.0.0.1:8000/signin.html deyken herhangi bir linke giderken http://127.0.0.1:8000/signin.html/ornek.html olmaması lazım doğrusunun http://127.0.0.1:8000/ornek.html böyle olması lazım yardım ederseniz sevinirim from django.contrib import admin from django.urls import path from index.views import index_view from signin.views import signin_view urlpatterns = [ path(r'admin/', admin.site.urls), path(r'',index_view), path(r'signin.html/',signin_view) ] -
Foreign Key data type
I have two classes in models.py in my DJango Project. class person(models.Model):- field1 = models.AutoField(primary_key=True) person_name = models.CharField(max_length=100, null=True, blank=True) class orders(models.Model):- field22 = models.ForeignKey(person, on_delete=models.CASCADE, null=True) As observed in the above two models,field22 is a foreign key that is mapped to the primary key of the table person. Now, What will be the datatype of field22, int (or) str? (or) it will inherit the data type of the primary key? -
Optimizing CSV file processing in POST request (Django Rest Framework)
I have a post request that takes a CSV file and saves all valid data in this file to DB models. But it is incredibly slow, cause CSV files can be huge. Is there any better way to do it? def post(self, request, *args, **kwargs): serializer = self.get_serializer(data=request.data) serializer.is_valid(raise_exception=True) file = serializer.validated_data['file'] decoded_file = file.read().decode() io_string = io.StringIO(decoded_file) reader = csv.reader(io_string) for row in reader: if check_deal_validity(row): try: Client.objects.get(username=row[0]) except ObjectDoesNotExist: client = Client(username=row[0]) client.save() try: Item.objects.get(name=row[1]) except ObjectDoesNotExist: item = Item(name=row[1]) item.save() deal = Deal( client=Client.objects.get(username=row[0]), item=Item.objects.get(name=row[1]), total=row[2], quantity=row[3], date=row[4], ) deal.save() Client.objects.filter(username=deal.client).update(spent_money=F('spent_money') + deal.total) if check_item_existence_for_client( client=deal.client, item=deal.item ): pass else: deal.client.gems.add(deal.item) return Response(status=status.HTTP_204_NO_CONTENT) -
How to detect all model's insert or update actions on django framework?
i use django cache system. I want to that when anyone update or insert model, django cache clean. I think, if i get this question's answer i can do it :) also i want to advice for fix this problem. Thank you. My Example signal; from django.core.cache import cache @receiver(post_save, sender=*) def cache_celan(sender, created, instance, **kwargs): if created: print("anyone created something so i clean cache.") cache.clean() else: print("anyone updated something so i clean cache.") cache.clean() This nice way but i can use it for only model. Is possible i use for it all model? Thank you. -
Return custom response to successful POST request in django rest framework
I want to return a custom response to the user when they hit the API with a POST request and it's a success. Here are the code snippets : views.py class BlogPostAPIView(mixins.CreateModelMixin,generics.ListAPIView): # lookup_field = 'pk' serializer_class = BlogPostSerializer def get_queryset(self): return BlogPost.objects.all() def perform_create(self, serializer): serializer.save(user=self.request.user) def post(self,request,*args,**kwargs): return self.create(request,*args,**kwargs) urls.py app_name = 'postings' urlpatterns = [ re_path('^$', BlogPostAPIView.as_view(),name='post-create'), re_path('^(?P<pk>\d+)/$', BlogPostRudView.as_view(),name='post-rud'), ] Right now it's returning the details of the post request as successful response, is there any way I can return some other response based on my own custom queryset? -
Django Rest Knox Auth Token on Client Doesn't Match Token on Server
I'm currently working on an API to query a database for the token sent and return a username and password, so users are not logged out after a refresh (I am using react, redux, and django). However, the token passed to the redux store doesn't seem to match the token in the database: In the shell, after running AuthToken.objects.all(): <QuerySet [<AuthToken: 96e87b29ac75d67980acdfd5688762fa9ffda4a7d9a4dd0ba7300a3c8a59eb82a0546c17763efa9f8b95dc44960349864abaa4353f40cae1e0b88d040ffff2db : TestUser>]> Redux store: Api.py: class LoginAPI(generics.GenericAPIView): serializer_class = LoginSerializer def post(self, request, *args, **kwargs): serializer = self.get_serializer(data=request.data) serializer.is_valid(raise_exception=True) user = serializer.validated_data return Response({ "user": UserSerializer(user, context=self.get_serializer_context()).data, "token": AuthToken.objects.create(user)[1] }) This might be a dumb question, but I can't figure out for the life of me why the client side and server have two different tokens. I only have one token in the database so I can't have misread. I am hesistant to continue because I just discovered this and want to figure out why. Any help would be appreciated! -
Calling attributes from a different python file that has data attached
Hope this makes sense - I'm basically working on a long bit of code I want to break into smaller files to be more manageable So I have tried the following, but get a "company not defined", so obviously when it moves from parent to child it loses that data from the loop. If I replace it with print("some text"), it will work fine - just not happy to use the data already called in parent.py # this is parent.py from companies.models import Data from .child import * for company in companies: print_childdata() # this is child.py from .parent import * def print_childdata(): print(company.id) To put it another way, the following works, but I want to take the "print(company.id)" part into a new file and call on that when running the same file (this is obviously pointless for this data, but looking to see what I can do for a larger file). from companies.models import Company for company in companies: print(company.id) -
How do I retrieve bulk_create objects to assign them to the foreign_key of another object?
I am trying to fins the best way to bulk_create two different kind of objects (Orders and Customers). Each Order is tied to a Customer with a foreign key. Objects are defined this way: class Customer(models.Model): unique_cust_id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False) client_id = models.ForeignKey(Client, on_delete=models.CASCADE) customer_id = models.CharField(max_length=30) cohort = models.DateField('Customer cohort') def __str__(self): return self.customer_id class Order(models.Model): unique_ord_id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False) order_id = models.CharField(max_length=30) client_id = models.ForeignKey(Client, on_delete=models.CASCADE) customer_id = models.ForeignKey(Customer, on_delete=models.CASCADE) amount = models.IntegerField(default=0) timestamp = models.DateTimeField('Order creation date') upload_tag = models.CharField(max_length = 100, default = 'manual_creation') def __str__(self): return self.order_id As my primary key is generated by django as an uuid and not an AutoField it may seem to me there is no problem on retrieving it. If primary key is created on bulk_create action and uuid is then generated, how can I retrieve the Objects itself without the primary key? (if I query by any other field, it may give back more than one instance since they are not unique values in the table). My intention would be to: df1 = pandas.DataFrame() # All Customer information but uuid generated by django on storage # Create Customer objects Customer.objects.bulk_create( Customer(**vals) for vals in df1.to_dict('records') ) # … -
Django model divded on 3 sub models - allowed way to do so?
I'm working on cinema booking system and want to ask for something. I have 3 models: Movie - main model representing movie, Movie_dates - Foreign key to Movie, representing different dates/times (One movie can repeat many times within the week), rows_and_seats - model representing reserved seats, foreign key to Movie_dates As you see my vision is a bit wide - Movie, dates, seats. I was wonder if this process could be simplified ? Or at least the confirmation that this way is allowed in terms of "good habbits" - I'm new in django :) Appreciate ! class Movies(models.Model): title = models.CharField(max_length=100) age = models.CharField(choices=AGE_CATEGORY, max_length=2) kind = models.CharField(choices=MOVIE_CATEGORY, max_length=3) price = models.FloatField() description = models.TextField() def __str__(self): return self.title def absolute(self): return reverse("movie", kwargs={ 'pk':self.pk }) def order(self): return reverse("movie-order", kwargs={ 'pk':self.pk }) class Movie_dates(models.Model): movie = models.ForeignKey(Movies, on_delete=models.CASCADE) date = models.DateTimeField() def __str__(self): return(f"{self.movie.title}:{self.date}") class rows_and_seats(models.Model): movie = models.ForeignKey(Movie_dates, on_delete=models.CASCADE) user = models.ForeignKey(User, on_delete=models.CASCADE) row = models.CharField(max_length = 1) number = models.IntegerField() -
Validating form across parent form and formset
I'm using example code here to present the problem so please excuse any errors and please don't get caught up in the architecture. The aim is to allow users to enter Split Payments into my expenses keeping app. Imagine you visit the supermarket and use your credit card to buy some food for £20 and a pair of jeans for £15. This would be entered as a £35 payment split into two categories: food and clothing. My project uses double-entry book keeping so the system would record this as a single entry with three child line items: £35 out of the credit card ledger, £20 into the clothing ledger, and £15 into the food ledger. My questions: 1. How do I validate across the parent form and the formset to ensure that the amount entered in the parent form is equal to the sum of the amounts entered in the formset? 2. Should I be using a formset_factory() or inlineformset_factory() in the view when creating a new entry? And when creating the edit view? models.py: class Ledger(models.Model): name = models.CharField(max_length=255) LEDGER_TYPE_CHOICES = ( ('AC', 'Account'), ('EX', 'Expense'), ) type = models.CharField( max_length=2, choices=ENRTY_TYPE_CHOICES, blank=False, null=False, default='0' ) class Entry(models.Model): date …
