Django community: Django Q&A RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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SystemCheckError: System check identified some issues:
I am building a project to place an order. when I run makemigrations command then it gives an error of SystemCheckError: System check identified some issues and I have deleted the migration file from migrations ERRORS: order.Order.price: (fields.E304) Reverse accessor for 'Order.price' clashes with reverse accessor for 'Order.product'. HINT: Add or change a related_name argument to the definition for 'Order.price' or 'Order.product'. order.Order.product: (fields.E304) Reverse accessor for 'Order.product' clashes with reverse accessor for 'Order.price'. HINT: Add or change a related_name argument to the definition for 'Order.product' or 'Order.price'. My models.py is as follows: class Order(models.Model): company = models.ForeignKey(Company, on_delete=models.CASCADE) product = models.ForeignKey(Product, on_delete=models.CASCADE) price = models.ForeignKey(Product, on_delete=models.CASCADE) def __str__(self): return self.company + self.product + self.price -
How do I POST a json file to Django and MySQL containing a base64 image string? (also using NGINX and Angular)
I've been trying to post this for days but haven't had any luck. Post method: public postDict(name: any, postData: Object) { var key = localStorage.getItem("access") var httpOptions = { headers: new HttpHeaders({ 'Content-Type': 'application/json', 'Authorization': 'Bearer ' + key, }), }; return this.http .post<any>( 'http://example.com:80/images/', putData, httpOptions ) .subscribe((data) => { console.log("sup") }); /* The data I'm sending looks like this in Angular: let item = {key: imgTimeKey, url: this.imgURL , owner: 'idiot'} where url is: data:image/jpeg;base64,/9j/...( bout 5mb worth of characters after this D-8 ) I've gotten past the problem of transmitting so much data in one post, but now its giving me a 404 Bad Request error. (It works if I replace the url with a regular string.) Now I have been storing these as regular strings in indexeddb just fine and I figure it should work the same with Django and MySQL. It should be fine to store the url in a string no? Here is my data model in Django: from django.db import models class Image(models.Model): created = models.DateTimeField(auto_now_add=True) key = models.CharField(max_length=100, blank=True, default='') url = models.TextField() owner = models.ForeignKey('auth.User', related_name='images', on_delete=mod> class Meta: ordering = ['created'] And finally, my NGINX server configuration: server { listen … -
How to run .py files as cronjob in aws?
I have a Django application which it's deployed to Amazon Elastic Beanstalk(Python 3.7 running on 64bit Amazon Linux 2/3.1.1). I have been trying to run a .py file as a cronjob that works at 4 a.m every day in AWS and I have created a .config file into .ebextensions for that such as below. cron.config file: files: "/etc/cron.d/cron_process": mode: "000644" owner: root group: root content: | 0 4 * * * root /usr/local/bin/task_process.sh "/usr/local/bin/task_process.sh": mode: "000755" owner: root group: root content: | #!/bin/bash date > /tmp/date source /var/app/venv/staging-LQM1lest/bin/activate cd /var/app/current python Bot/run_spiders.py exit 0 commands: remove_old_cron: command: "rm -f /etc/cron.d/cron_process.bak" run_spiders.py file: from first_bot.start import startallSpiders from .models import Spiders import importlib test = Spiders.objects.get(id=1) test.spider_name = "nigdehalk" test.save() I'm trying to change an attribute of one of my objects for testing but it didn't work. Am I missing something? How can I create this cronjob? -
django, typeerror: missing 1 required positional argument
models.py: class DoctorList(models.Model): doctorname = models.CharField(max_length=300) position = models.CharField(max_length=200) h_code = models.ForeignKey(HospitalList, related_name="h_code", on_delete=models.CASCADE) def doctor_code_create(h_code): testhospital = HospitalList.objects.filter(code = h_code).values('code') print(testhospital) return new_d_code d_code = models.CharField(primary_key=True, max_length = 200, default = doctor_code_create, editable=False) error code: Traceback (most recent call last): File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\rest_framework\serializers.py", line 948, in create instance = ModelClass._default_manager.create(**validated_data) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\manager.py", line 85, in manager_method return getattr(self.get_queryset(), name)(*args, **kwargs) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\query.py", line 445, in create obj = self.model(**kwargs) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\base.py", line 475, in __init__ val = field.get_default() File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\fields\__init__.py", line 831, in get_default return self._get_default() TypeError: doctor_code_create() missing 1 required positional argument: 'h_code' I want to use h_code that exists in class DoctorList (models.Model) by putting it in doctor_code_create. I think it's right to use it like this, but I don't know what went wrong. Do I have to specify it? (Some code has been omitted to make it easier to see.) view.py (add) class ListDoctor(generics.ListCreateAPIView): queryset = DoctorList.objects.all().order_by('-d_code') serializer_class = DoctorListSerializer -
Celery task can't access volume file in docker
Admin page can get access to the image file saved in database but Celery task can't get access to that image file and shows error FileNotFoundError(2, 'No such file or directory'). docker-compose.yml version: "3" services: app: &app build: context: . ports: - "8000:8000" volumes: - ./backend:/backend command: > sh -c "python manage.py wait_for_db && python manage.py migrate && python manage.py runserver 0.0.0.0:8000" environment: - SECRET_KEY=mysecretkey - DB_HOST=db - DB_NAME=election - DB_USER=postgres - DB_PASS=supersecretpassword depends_on: - db - redis db: image: postgres:12-alpine environment: - POSTGRES_DB=election - POSTGRES_USER=postgres - POSTGRES_PASSWORD=supersecretpassword volumes: - postgresql_data:/var/lib/postgresql/data ports: - 5432:5432 redis: image: redis:6-alpine celery: <<: *app command: celery -A app worker -l INFO ports: [] depends_on: - app - redis - db volumes: postgresql_data: Dockerfile FROM python:3.8 ENV PYTHONUNBUFFERED 1 # Face-recognition model RUN apt-get -y update RUN apt-get install -y --fix-missing \ build-essential \ cmake \ gfortran \ git \ wget \ curl \ graphicsmagick \ libgraphicsmagick1-dev \ libatlas-base-dev \ libavcodec-dev \ libavformat-dev \ libgtk2.0-dev \ libjpeg-dev \ liblapack-dev \ libswscale-dev \ pkg-config \ python3-dev \ python3-numpy \ software-properties-common \ zip \ # web3 libssl-dev \ # QR code zbar-tools \ libzbar-dev \ && apt-get autoremove \ && apt-get clean && rm -rf /tmp/* /var/tmp/* … -
django-parler-rest avoiding "translations" objects
While I'm creating an app by using django-parler-rest for internationalization support I realized that TranslatedFieldsField and TranslatableModelSerializer serialize the data in the following format: { "id": 528, "country_code": "NL", "translations": { "nl": { "name": "Nederland", "url": "http://nl.wikipedia.org/wiki/Nederland" }, "en": { "name": "Netherlands", "url": "http://en.wikipedia.org/wiki/Netherlands" }, "de": { "name": "Niederlande", "url": "http://de.wikipedia.org/wiki/Niederlande" } } } Is there any way to serialize the data in the following format? { "nl": { "id": 528, "country_code": "NL", "name": "Nederland", "url": "http://nl.wikipedia.org/wiki/Nederland" }, "en": { "id": 528, "country_code": "NL", "name": "Netherlands", "url": "http://en.wikipedia.org/wiki/Netherlands" }, "de": { "id": 528, "country_code": "NL", "name": "Niederlande", "url": "http://de.wikipedia.org/wiki/Niederlande" } } -
Why click on profile page, home page load as well using django jsonResponse and javascript API fetch to display the view
I want to display different data for the homepage and the profile page. The homepage should have all the posts while profile page has only the logged-in user's page. The data itself is ok. I have tested in django and javascript using print and console.log(). The problem is when I load the profile page, the homepage load again as well, so the profile view has both homepage and profile posts. And also if I click homepage twice, I get twice of the posts on homepage. Here below is my code. Any help is appreciated. Thanks! Javascript: document.addEventListener("DOMContentLoaded", function () { // Use button to toggle between views document.querySelector("#home").addEventListener("click", () => { load_view("home"); document.querySelector("#happening_form").style.display = "block"; document.querySelector("#home_view").style.display = "block"; document.querySelector("#profile_view").style.display = "none"; }); document .querySelector("#all_posts") .addEventListener("click", () => load_view("all_posts")); document .querySelector("#following") .addEventListener("click", () => load_view("following")); document.querySelector("#profile").addEventListener("click", () => { load_view("profile"); document.querySelector("#post_middle_container").style.display = "none"; document.querySelector("#happening_form").style.display = "none"; document.querySelector("#home_view").style.display = "none"; document.querySelector("#profile_view").style.display = "block"; }); // Prevent default upper submit document .querySelector("#upper_post_form") .addEventListener("submit", function (event) { event.preventDefault(); }); // Prevent default popup submit document .querySelector("#popup_post_form") .addEventListener("submit", function (event) { event.preventDefault(); }); // By default, load all posts view load_view("home"); // By default, load post composing form compose_post(); }); ...........// compose and submit functions … -
Access Django Admin with token instead of password
I use Django with Django Rest Framework as the backend for my site. Registration is disabled, and login with password is disabled. The only way a user can register and login is with Django Social Auth, that exchanges (in this case Discord) a social token for a Django token, and in that process the user is created if they don't exist for that email. So in Django, the user exists, with a username and email, but they don't have a password. How can these users login to the admin panel? -
How to filter data from Mongo DB in Django
I use Djongo as the connector for mongoDb with Django. But I dont know how to get all the data with filter. I get int error while trying to do that. class HomeView(LoginRequiredMixin, ListView): template_name = 'home.html' getter = PostModel.objects.filter(author='1') model = getter login_url = reverse_lazy('login') This is my code for getting the data. But it says. 'QuerySet' object has no attribute '_default_manager' What am I doing wrong here. Please help me. -
How to search query sets that have a specific value in a list in Django Rest framework
What I want to do Getting all query set which has a specific value in a list which is ManyToManyField. In short, if I type http://localhost:8000/api/pickup/?choosingUser=5, I would like to get all PickUp_Places that matches like choosingUser = 5. choosingUser comes from ManyToManyField so a PickUp_Places model has like choosingUser = [2,3,5,7]. Problem I cannot search query sets by a specific value in list. When I type http://localhost:8000/api/pickup/?choosingUser=5, I get all query sets that include ones don't have choosingUser = 5. I am using django_filters in order to filter query sets. I read the documentation but I couldn't find how to get query sets by a value in a list. If it is alright with you, would you please tell me how to do that? Thank you very much. ===== ========= ========== ========= My code is like this. models.py class PickUp_Places(models.Model): name = models.CharField(max_length=200, unique=True) choosing_user = models.ManyToManyField( settings.AUTH_USER_MODEL, related_name="pick_up") def __str__(self): return self.name class Meta: db_table = "pickup_places" serializers.py class PickUp_PlacesSerializer(serializers.ModelSerializer): class Meta: model = PickUp_Places fields = "__all__" views.py class PickUp_PlacesViewSet(viewsets.ModelViewSet): queryset = PickUp_Places.objects.all() permission_classes = [ permissions.IsAuthenticatedOrReadOnly ] serializer_class = PickUp_PlacesSerializer filter_backends = [filters.DjangoFilterBackend] filterset_fields = "__all__" -
Best way of checking whether a certain Model instance is in fact an instance of a certain Model
I am trying to write a class that takes an instance of a Model from my app as an argument in its __init__. While reading up on the subject, I stumbled upon this quesiton: django: best practice way to get model from an instance of that model which argues that simply using type(instance) would be the best way to go. As tempting as it may be to use this right away, wouldn't using isinstance(instance, model) be a better solution? Say, for example (from my own code): from app_name.models import Model1, Model2, ... ModelN MODELS = (Model1, Model2 ... ModelN) and then inside the class itself (in my case, Graph), do something like this: class Graph(): model_instance = None model = None def __init__(self, model_instance): if isinstance(model_instance, MODELS): for a_model in MODELS: if isinstance(model_instance, a_model): self.model = a_model self.model_instance = model_instance ... As a beginner, I thought this was the best way I could come up with but also assume there are smoother/better ways of doing this. Possibly an even more "readable" way maybe? Pros? Cons? Appreciate ALL feedback on this! Thanks! -
form errors do not show on the template
Non of my validation errors show, the template page just refreshes if there is something wrong. i placed the validation error code in my forms.py, i don't know if i am supposed to place it in my views, because nothing works. i also thought django had a default for errors, seems i was wrong. html <form method="post"> {%csrf_token%} <form method="post">{%csrf_token%} {{form.username}} {{form.first_name}} {{form.last_name}} {{form.email}} {{form.phonenumber}} {{form.state}} {{form.next_of_kin}} {{form.dob}} {{form.address}} {{form.password1}} {{form.password2}} <li class="btnn"><button type="submit" class="conf">Add</button></li> </form> {% if form.errors %} {% for field in form %} {% for error in field.errors %} <p> {{error}} </p> {% endfor %} {% endfor %} {% endif %} forms.py from django import forms from django.contrib.auth.forms import UserCreationForm from django.contrib.auth.models import User class PatientForm(UserCreationForm): first_name = forms.CharField(max_length=100, help_text='First Name') last_name = forms.CharField(max_length=100, help_text='Last Name') address = forms.CharField(max_length=100, help_text='address') next_of_kin = forms.CharField(max_length=100, help_text='Next of kin') dob = forms.CharField(max_length=100, help_text='Date of birth') state = forms.CharField(max_length=100, help_text='State') phonenumber = forms.CharField( max_length=100, help_text='Enter Phone number') email = forms.EmailField(max_length=150, help_text='Email') def __init__(self, *args, **kwargs): super().__init__(*args, **kwargs) self.fields['username'].widget.attrs.update( {'placeholder': ('Username')}) self.fields['email'].widget.attrs.update( {'placeholder': ('Email')}) self.fields['address'].widget.attrs.update( {'placeholder': ('Address')}) self.fields['phonenumber'].widget.attrs.update( {'placeholder': ('Phone number')}) self.fields['first_name'].widget.attrs.update( {'placeholder': ('First name')}) self.fields['last_name'].widget.attrs.update( {'placeholder': ('Last name')}) self.fields['password1'].widget.attrs.update({'placeholder': ('Password')}) self.fields['password2'].widget.attrs.update({'placeholder': ('Repeat password')}) self.fields['dob'].widget.attrs.update({'placeholder': ('Date of birth')}) self.fields['state'].widget.attrs.update({'placeholder': ('State')}) self.fields['next_of_kin'].widget.attrs.update({'placeholder': ('Next … -
Django form submit button doing nothing
I'm trying to upload a csv file to insert into the model I created since the data in the csv is quite a lot I cannot manually input it all. I've watched a tutorial and I kinda copy pasted every detail the tutorial gave, the problem is when I'm click the upload button, nothing happens. Models.py class Dev(models.Model): projName = models.CharField(max_length=255) clientName = models.CharField(max_length=255) projDesc = models.CharField(max_length=255) projTask = models.CharField(max_length=255) userName = models.CharField(max_length=255) userEmail = models.CharField(max_length=255) projTag = models.CharField(max_length=255) billable = models.BooleanField() dateStart = models.DateField(auto_now=False, auto_now_add=False) timeStart = models.DateTimeField(auto_now=False, auto_now_add=False) dateEnd = models.DateField(auto_now=False, auto_now_add=False) timeEnd = models.DateTimeField(auto_now=False, auto_now_add=False) timeDuration = models.DateTimeField(auto_now=False, auto_now_add=False) duration = models.DecimalField(max_digits=4, decimal_places=2) billRate = models.DecimalField(max_digits=10, decimal_places=2) billAmount = models.DecimalField(max_digits=10, decimal_places=2) and here is the views.py from django.shortcuts import render from django.http import HttpResponse import csv, io from django.contrib import messages from django.contrib.auth.decorators import permission_required from .models import Dev # Create your views here. def homepage(request): return render(request, 'Home.html') @permission_required('admin.can_add_log_entry') def csv_upload(request): template = "upload.html" prompt = { 'order': 'Order of the CSV chuchu' } if request.method == "GET": return render(request, template, prompt) csv = request.FILES['file'] if not csv.name.endswith('.csv'): message.error(request, 'Not a csv file, please choose another file.') data_set = csv.read().decode('UTF-8') io_string = io.StringIO(data_set) next(io_string) for col … -
How To Configure Apache To Point To Media Files
My website isn't finding my media files in production and I think it's because I need to configure my webserver to point to my media root file, I think with the following code: Alias /media /home/atms/atms/media <Directory /home/atms/atms/media> Require all granted </Directory> However I have no idea where to place this code? Apparently it goes in a file 'htaccess', but I can't find this file. I am using A2 hosting. Thank you. -
How to add Django model ImageField to ReportLab
I would like to add a media file to PDF generated by Reportlab. STATIC_ROOT = os.path.join(BASE_DIR, "staticfiles") output STATIC_ROOT --> project/static/ MEDIA_ROOT = os.path.join(BASE_DIR, "media") output STATIC_ROOT --> project/media/ when i draw static images are ok: logo = STATIC_ROOT + "img/dilains-logotipo-bg-white-290x100.jpg" self.canvas.drawImage(logo, self.x, self.y, w, h, preserveAspectRatio=True) but with media: output self.rejection.img_general_model_1 --> images/treatments/rejections/mouth.jpg picture = MEDIA_ROOT + str(self.rejection.img_general_model_1) self.canvas.drawImage(picture, self.x + text_x * 0, self.y, w, h, preserveAspectRatio=True, mask='auto') Throws error: Cannot open resource "/project/media/images/treatments/rejections/mouth.jpg" <class 'OSError'> Anybody know how to fix it ? And in production with AWS S3 configuration ? Thanks in advance. -
form submitted data from template is not saved in database in Django?
I was doing a small project on django where i create simple blog mini project. Everything worked for me but i am in issue now that i can create post form Django administration and i wanted to do it with in front-end with templates in create-post.html but i am no issue just my form is not working or it is not submitting any data or some error ? I'm using summernote rich text editor instead of textfield in Model. Expert please look my code and suggest me it is good or bad or where i am wrong ? my models.py class Author(models.Model): user = models.OneToOneField(User, on_delete=models.CASCADE) author_profile_pic = models.ImageField(upload_to='images',null=True) author_description = models.TextField(null=True) author_facebook_url = models.CharField(max_length=50,null=True) author_twitter_url = models.CharField(max_length=50,null=True) author_instagram_url = models.CharField(max_length=50,null=True) author_github_url = models.CharField(max_length=50,null=True) def __str__(self): return f'{self.user}' class Category(models.Model): # show string title in Admin panel title = models.CharField(max_length=30,null=True) def __str__(self): return self.title class Blogpost(models.Model): title = models.CharField(max_length=100,null=True) thumbnail = models.ImageField(upload_to='images') post_body = models.TextField() slug = models.SlugField(null=True,blank=True) posted_date = models.DateField(default=date.today) author = models.ForeignKey(Author, on_delete=models.CASCADE) categories = models.ManyToManyField(Category) publish = models.BooleanField() and my form from django import forms from .models import Blogpost from django_summernote.widgets import SummernoteWidget class CreatePostForm(forms.ModelForm): class Meta: model = Blogpost fields = "__all__" widgets = { 'post_body': … -
How to count data from Another Model in Django?
I have 2 models and i want to count Foreignkey data, I am trying to count the number of records in related models, but I am unable to count the records, Please let me know how i can Count the data. I want to count this data after filter, I am filtering between 2 dates, it's giving me the current data of using model in filter,but i want to count related model data also using filter. Here is my models.py file... class Product(models.Model): name=models.CharField(max_length=225) customer=models.ForeignKey(Brand, related_name='product_customer',on_delete=models.CASCADE) user= models.ForeignKey(Supplement, related_name='product_user', on_delete=models.CASCADE) created_at = models.DateTimeField(auto_now_add=True) here is my views.py file... def index(request): data = Project.objects.all() if request.method == 'POST': v1= request.GET.get('created-at') if v1: v2 = v1.split(' - ') s1 = v2[0] s2 = v2[1] result = Product.objects.filter(created_at__range=[s1,s2]) return render(request, 'index.html' {'result':result}) here is my index.html file.. <p>{{result.count}} product</p> <p>{{result.product_customer.count}} Customer</p> <p>{{result.product_user.count}} User</p> I want to display this data after filter, for product it's working perfect, but i want to display data for customer and user when user filter... -
django, TypeError: doctor_code_create() missing 1 required positional argument: 'h_code'
doctor.py: class DoctorList(models.Model): doctorname = models.CharField(max_length=300) position = models.CharField(max_length=200) h_code = models.ForeignKey(HospitalList, related_name="h_code", on_delete=models.CASCADE) def doctor_code_create(h_code): last_doctor_code = DoctorList.objects.all().order_by('d_code').last() if not last_doctor_code: return 'd' + '001' h_code_test = h_code d_code = last_doctor_code.d_code doctor_int = int(d_code[3:6]) new_doctor_int = doctor_int + 1 new_d_code= 'd' + h_code_test + str(new_doctor_int).zfill(3) return new_d_code d_code = models.CharField(primary_key=True, max_length = 200, default = doctor_code_create, editable=False) error code: Traceback (most recent call last): File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\rest_framework\serializers.py", line 948, in create instance = ModelClass._default_manager.create(**validated_data) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\manager.py", line 85, in manager_method return getattr(self.get_queryset(), name)(*args, **kwargs) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\query.py", line 445, in create obj = self.model(**kwargs) File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\base.py", line 475, in __init__ val = field.get_default() File "C:\Users\user\Desktop\venv\tutorial\lib\site-packages\django\db\models\fields\__init__.py", line 831, in get_default return self._get_default() TypeError: doctor_code_create() missing 1 required positional argument: 'h_code' I want to use h_code that exists in class DoctorList (models.Model) by putting it in doctor_code_create. I think it's right to use it like this, but I don't know what went wrong. Do I have to specify it? -
Filter Django query set by appended attribute
I'd like to filter/exclude instances in a query set where change=0 but I'm getting a FieldError with the below code. movements = part.history.all() previouslevel = 0 for movement in movements: movement.change = movement.stockOnHand - previouslevel previouslevel = movement.stockOnHand print(movements.exclude(change=0)) Is there a way to filter a query set with an appended attribute? -
django) Got a `TypeError` when calling `Doctor.objects.create()`, I want to solve it
hospital.py class HospitalList(models.Model): hospitalname = models.CharField(max_length=200) def hospital_code_create(): last_hospital_code = HospitalList.objects.all().order_by('code').last() if not last_hospital_code: return 'h' + '000001' code = last_hospital_code.code hospital_int = int(code[3:9]) new_hospital_int = hospital_int + 1 new_code= 'h' + str(new_hospital_int).zfill(6) return new_code code = models.CharField(primary_key=True, max_length = 200, default = hospital_code_create, editable=False) doctor.py class DoctorList(models.Model): doctorname = models.CharField(max_length=300) position = models.CharField(max_length=200) h_code = models.ForeignKey(HospitalList, related_name="h_code", on_delete=models.CASCADE) def doctor_code_create(): last_doctor_code = DoctorList.objects.all().order_by('d_code').last() if not last_doctor_code: return 'd' + '001' d_code = last_doctor_code.d_code doctor_int = int(d_code[3:6]) new_doctor_int = doctor_int + 1 new_d_code= 'd' + str(new_doctor_int).zfill(3) return new_d_code d_code = models.CharField(primary_key=True, max_length = 200, default = doctor_code_create, editable=False) I want to display d_code as d002001, not d001. Here, 002 is the foreign key from which the primary key of hospital.py is imported. I've slightly modified doctor.py to implement this. doctor.py(Revise) class DoctorList(models.Model): doctorname = models.CharField(max_length=300) position = models.CharField(max_length=200) h_code = models.ForeignKey(HospitalList, related_name="h_code", on_delete=models.CASCADE) def doctor_code_create(**h_code**): last_doctor_code = DoctorList.objects.all().order_by('d_code').last() if not last_doctor_code: return 'd' + '001' d_code = last_doctor_code.d_code **h_code_test = h_code[-3]** doctor_int = int(d_code[3:6]) new_doctor_int = doctor_int + 1 new_d_code= 'd' + **h_code_test** + str(new_doctor_int).zfill(3) return new_d_code d_code = models.CharField(primary_key=True, max_length = 200, default = doctor_code_create, editable=False) After modifying as above, Got a TypeError when calling DoctorList.objects.create(). Error occurred. What … -
Django Unable to open static file loading
enter image description here enter image description here enter image description here I was proceed "python manage.py collectstatic" enter image description here -
MKV file downloads and doesn't display
I have made a Django model where I store files and if there is a mkv file it doesn't display in the URL like how the others do. The URLs do show the video but if it is mkv it downloads in the link so what could I do to stop it. So I think in need to change the file type in python so like how can I do that or if there is a better way could you tell me how to. Thanks -
Como puedo asignar un valor iniciar a un foreignkey en vistas basadas en clase django
estoy tratando de seleccionar el valor inicial del Paciente ForeignKey: class Consulta(models.Model): Paciente = models.ForeignKey(paciente, on_delete=models.CASCADE) Area_de_consulta = models.ForeignKey(Area, on_delete=models.CASCADE) Notas_de_la_consulta = models.TextField("Ingrese las notas de la consulta", max_length=500) def __str__(self): return '%s %s %s' % (self.Paciente, self.Area_de_consulta, self.Notas_de_la_consulta) el objetivo es que al aparecer el form en la vista debe ir con el paciente que recibirá la consulta seleccionado. Como podría realizar esta acción ? he buscado y aun no termino de entenderlo, podrían orientarme por favor. -
How to make multiple choice field from Django many to many related model
I want to show products from product model using check boxes in my store form where user can select multiple products. Product Model: class Product(models.Model): product_name = models.CharField(max_length=30) product_price = models.IntegerField(default=0) timestamp = models.DateTimeField(auto_now_add=True) def __str__(self): return self.product_name Store Model: class Store(models.Model): AREAS = [ (0, 'Dhaka'), (1, 'Khulna'), (2, 'Chittagong'), (3, 'Barisal'), (4, 'Rajshahi'), ] SELLER_TYPE = [ (0, 'Manufacturer'), (1, 'Authorised Dealer'), (2, 'Distrubutor'), (3, 'Dealer'), ] store_owner = models.ForeignKey(User, on_delete=models.CASCADE,related_name='store_owner') store_name = models.CharField(max_length=256) store_address = models.CharField(max_length=300) seller_type = models.IntegerField(choices=SELLER_TYPE, default=0) area = models.IntegerField(choices=AREAS, default=0) products = models.ManyToManyField(Product, related_name='store_products') timestemp = models.DateTimeField(auto_now_add=True) updated_on = models.DateTimeField(auto_now=True) def __str__(self): return self.store_name Store Form: class StoreForm(forms.ModelForm): area = forms.ChoiceField(choices=Store.AREAS, label='Area', required=True) products = forms.MultipleChoiceField(queryset=Product.objects.all(), label='Manager', required=True) seller_type = forms.ChoiceField(widget=forms.RadioSelect, choices=Store.SELLER_TYPE) class Meta: model = Store fields = ('seller_type', 'store_name', 'store_address', 'products', 'area') I want to select multiple product item while I'm going to create a record for a store. Currently I can select multiple product items from the product list. But I want to represent them as check-boxes so that users can select multiple items from the check-boxes. -
On Django form, I want to know how to respond to form field data in JSON
I was successful using this method but, I want the repose code to be simpler. Is there such a way? The code is as follows: views.py class PersonnelInfoDetailView(DetailView): def get(self, request, pk): employee = Employee.objects.get(pk=pk) response = {'employeeType' : employee.employeeType_id, 'driverIndex': employee.driverIndex, 'routeId': employee.routeId_id, 'department': employee.department, 'employeeNumber': employee.employeeNumber, 'employeeName': employee.employeeName, 'employeeBirth' : employee.employeeBirth, 'employeeAddress' : employee.employeeAddress, 'employeeTel' : employee.employeeTel, 'employeeEmergencyTel' : employee.employeeEmergencyTel, 'employeeSalary' : employee.employeeSalary, 'employeeFixedRest1' : employee.employeeFixedRest1, 'employeeFixedRest2' : employee.employeeFixedRest2 , 'tableHoBong' : employee.tableHoBong_id, 'jobTitleType' : employee.jobTitleType, 'employeeStatus' : employee.employeeStatus } return HttpResponse(json.dumps(response), content_type='application/json') forms.py class EmployeeForm(forms.ModelForm): class Meta: model = Employee fields = ('employeeType','driverIndex', 'routeId', 'department', 'employeeNumber', 'employeeName', 'employeeBirth', 'employeeAddress', 'employeeTel', 'employeeEmergencyTel', 'employeeSalary', 'employeeFixedRest1', 'employeeFixedRest2','tableHoBong','jobTitleType', 'employeeStatus') def __init__(self, *args, **kwargs): super(EmployeeForm, self).__init__(*args, **kwargs) for visible in self.visible_fields(): visible.field.widget.attrs['class'] = 'form-control form-control-sm w-100'
