Django community: Django Q&A RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Django PermissionError, during upload file
I have a model: class Provider(models.Model): name = models.CharField(max_length=256, verbose_name=_("Name")) favicon = models.ImageField(upload_to="providers/", null=True, blank=True) And in settings: MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, "../media") And in apache config I have: #rest of code... Alias /media/ /home/sever/ap/media/ <Directory /home/server/ap/media> Require all granted </Directory> But when I 'm trying add record to this model by admin pag, when I add an images I get the error: PermissionError at /admin/ap/provider/add/ [Errno 13] Permission denied: '/home/server/ap/media/providers/Samsung.png' -
Export a django model in .xls
How can I export a whole model filled with data (around 15 columns and 2500 rows) into an excel file to download it directly with a button in a html page? This is my model: class Cleartobill(models.Model): soss = models.CharField(max_length=60) soss_line = models.CharField(max_length=70) build_date = models.CharField(max_length=80) ctb_Status = models.CharField(max_length=60) ctb_comment = models.CharField(max_length=50) comments = models.CharField(max_length=200) sjz_status = models.CharField(max_length=60) production_result_Code = models.CharField(max_length=70) bu = models.CharField(max_length=50) pf = models.CharField(max_length=50) current_fcd = models.DateField(null=True, blank=True) tan = models.CharField(max_length=50) eta = models.CharField(max_length=60, null=True, blank=True) tied = models.CharField(max_length=30) otm_status = models.CharField(max_length=30) bucket_aged = models.CharField(max_length=60) ead = models.DateField(null=True, blank=True) -
Redirect to existing view when getting error (404, 500, etc) django
When my cookie session expires it gives 500 error and I would like to redirect it to the login. I've added the url to override 500 handler. myapp/urls.py handler500 = 'myapp.login.views.signin' But this alone doesn't work. So I tried adding the function server_error: myapp/urls.py handler500 = 'myapp.login.views.server_error' myapp/login/views.py def server_error(request, template_name='templatename.html'): try: template = loader.get_template(template_name) except TemplateDoesNotExist: return http.HttpResponseServerError('<h1>Server Error (500)</h1>') return http.HttpResponseServerError(template.render(Context({}))) myapp/login/templates templatename.html Why doesn't it work? -
Django register token for apns
I am beginner in Django and I am using this for device management. https://github.com/jleclanche/django-push-notifications But it doesn't explain how can I post device token. How can I post if user hasn't login or already login? I saw url for that but I don't know how to use. ^ ^device/apns/$ [name='apnsdevice-list'] ^ ^device/apns\.(?P<format>[a-z0-9]+)/?$ [name='apnsdevice-list'] ^ ^device/apns/(?P<registration_id>[^/.]+)/$ [name='apnsdevice-detail'] ^ ^device/apns/(?P<registration_id>[^/.]+)\.(?P<format>[a-z0-9]+)/?$ [name='apnsdevice-detail'] ^ ^device/apns/$ [name='apnsdevice-list'] ^ ^device/apns\.(?P<format>[a-z0-9]+)/?$ [name='apnsdevice-list'] ^ ^device/apns/(?P<registration_id>[^/.]+)/$ [name='apnsdevice-detail'] ^ ^device/apns/(?P<registration_id>[^/.]+)\.(?P<format>[a-z0-9]+)/?$ [name='apnsdevice-detail'] ^device/apns/?$ [name='create_apns_device'] -
Generate pdf files with Weasyprint, save in zip file, send that zip file to client and present it for download
Let me break down my requirement. Here's what I'm doing right now. 1. Generate PDF files from HTML for this I'm using Weasyprint as following: lstFileNames = [] for i, content in enumerate(lstHtmlContent): repName = 'report'+ str(uuid.uuid4()) + '.pdf' lstFileNames.append("D:/Python/Workspace/" + repName) HTML(string=content).write_pdf(target=repName, stylesheets=[CSS(filename='/css/bootstrap.css')]) all files names, with paths, are saved in lstFileNames. 2. Create a zip file with pdf files generated by weasyprint for this I'm using zipfile zipPath = 'reportDir' + str(uuid.uuid4()) + '.zip' myzip = zipfile.ZipFile(zipPath, 'w') with myzip: for f in lstFileNames: myzip.write(f) 3. Send zip file to client for download resp = HttpResponse(myzip, content_type = "application/x-zip-compressed") resp['Content-Disposition'] = 'attachment; filename=%s' % 'myzip.zip' 4. Open file for downloading via Javascript var file = new Blob([response], {type: 'application/x-zip-compressed'}); var fileURL = URL.createObjectURL(file); window.open(fileURL); Problems 1. While the zip file is successfully received at front end, after I try to open it, it gives the following error: The archive is in either unknown format or damaged Am I sending the file wrong or is my Javascript code the problem? 2. Is there a way to store all pdf files in list of byte arrays and generate zip files with those byte array and send it to the client? ... -
How can be shown manyTomany field values into a single text box in django template
I want to show manytomany field value into a single input textbox in django template. My output is ABC /n Abc /n BVC /n i want like ABC ,Abc,BVC my code sample is this <div class='col-sm-8'> {% for car in cars %}<br/> <input type='text' class='form-control' name='cars' placeholder='Select cars' value= {{car}}> {% endfor %} </div> I want to show the output in Textbox field -
How to use SearchVector with multiple fields from a list of strings
I don't have a lot of Python experience and can't figure out how to use a list of strings with the SearchVector functionality described here. I'm using Django 1.10 with PostgreSQL 9.6 and have verified that this works if I write the fields in manually. This function is from a class based view and its purpose is to receive a string from a form, then do a full text search against all CharFields in all Models within MyApp, then return the results (planning on using itertools to combine multiple QuerySets once I get this working). I don't want to hardcode the fields because we will be adding new objects and new fields regularly - its a sort of corporate middleware app where I am not able to master the data. def get_queryset(self): searchTargets = defaultdict(list) myModels = (obj for obj in apps.get_models() if obj._meta.label.startswith('myapp') and not obj._meta.label == 'myapp.ConfigItem') for thing in myModels: fieldNames = (x.name for x in thing._meta.fields) for thisField in fieldNames: if thing._meta.get_field(thisField).get_internal_type() == 'CharField': searchTargets[thing._meta.object_name].append(thisField) user_query=self.request.GET['user_query'] for key in searchTargets.iterkeys(): targetClass=class_for_name('myapp.models',key) results = targetClass.objects.annotate( search=SearchVector(searchTargets[key]), ).filter(search=user_query) #only a single QuerySet will be returned. return results I've tried ','.join(MyList) but of course that just makes one big ... -
How to filter latest objects using nested query in Django
I have the following relation: class Product(foo): name = models.CharField() class Maintenance(foo): product = models.ForeignKey(Product, related_name="maintenances") start = models.DateField() end = models.DateField() I would like to filter all products with the latest (only the latest) maintenance object having start and end attributes in a given date range. Something like this: Product.objects.filter(maintenances__last__end__gte=today.now(), maintenances__last__end__lte=today.now()+datetime.timedelta(days=30)) -
uwsgi django1.3.5 error: "is outside repository"
my application suffered fatal errors, all of the search engines can not find some answer. Please somebody help me. Thank u. My application run with uwsgi, some fatal error appear in uwsgi log，whenever 'HARAKIRI' triggered or not, always have something like flow： Wed Sep 27 01:17:57 2016 - HARAKIRI !!! worker 25 status !!! Wed Sep 27 01:17:57 2016 - HARAKIRI [core 0] 149.202.48.192 - GET /problem/17800 since 1474391873 Wed Sep 27 01:17:57 2016 - HARAKIRI !!! end of worker 25 status !!! fatal: '/home/workspace/ENV/lib/python2.7/site-packages/django_mysqlpool/backends/mysqlpool/base.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/sqlalchemy/pool.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/sqlalchemy/pool.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/sqlalchemy/pool.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/django/core/handlers/base.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/django/contrib/auth/decorators.py' is outside repository fatal: '/home/workspace/ENV/lib/python2.7/site-packages/search/SearchService.py' is outside repository I don't know how and why something like this， but application is not affected. The flow is my uwsgi conf: <uwsgi> <socket>:3344</socket> <pidfile>/home/nb/staticfiles/pids/chunyu-uwsgi.pid</pidfile> <master/> <chdir>/home/nb/webapps/propellant</chdir> <pythonpath>/home/nb/webapps/propellant</pythonpath> <module>wsgi</module> <!-- 3s的timeout, 防止work执行某个任务耗费太多的时间 --> <harakiri>4</harakiri> <workers>4</workers> <listen>8192</listen> <enable-threads/> <logto>/home/nb/logs/xxoo/chunyu_uwsgi.log</logto> <daemonize>/home/nb/logs/xxoo/chunyu_uwsgi.log</daemonize> <memory-report/> <buffer-size>35535</buffer-size> <post-buffering>1</post-buffering> <reload-on-as>1200</reload-on-as> <reload-on-rss>750</reload-on-rss> </uwsgi> -
(Django) page showing \u200e code. (PROVIDING GOOD INFO I've been stuck for a VERY long time)
Hey guys I am beyond frustrated/exhausted trying to fix this unicode code \u200e showing in my web page. I tried everything I can think of. Here is what my page looks like, its data scraped articles from news.google.com and shown on my page with the time submission (the time submission is where the \u200e pops up everywhere) http://i.imgur.com/lrqmvWG.jpg I am going to provide my views.py, my articles.html (the page in the picture that is set up to display everything), and header.html (for whatever reason. But this is the parent template of articles.html for the CSS inheriting). Also, I researched and know that the \u200e is a left-to-right mark and when I inspect the source in news.google.com, it pops up in the time submission element as &lrm; like so: <span class="al-attribution-timestamp">&lrm;51 minutes ago&lrm;</span> I tried editing the views.py to encode it using .encode(encoding='ascii','ignore') or utf-8 or iso-8859-8 but it still displays \u200e everywhere. I put it in so many different parts of my views.py too even right after the for loop (and right before it gets stored as data in the variable "b" and its just not going away. What do I need to do? Views.py def articles(request): """ Grabs the ... -
How to add user authentication to existing django project?
Can anyone tell me how to add a basic user authentication to existing django project ? Thanks -
Making django's messages appear in Javascript alert rather than html?
I'm trying to display messages to the user when they login/signup using the alert function of javascript. I'm trying something like this, but it doesn't seem to work. What is the correct syntax to pass django's variables to the script in a template? This is what I want but this syntax doesn't work. {% if messages %}{% for message in messages %}<script>alert({{}});</script>{% endfor %}{% endif %} However the following is working: {% if messages %}<ul>{% for message in messages %} <li>{{ message }}</li> {% endfor %}</ul>{% endif %} -
Profiling Django with PyCharm
My app is pretty slow even in a dev environment so I would like to figure out what's slowing it down so I can try and fix it. I know about the debug toolbar and according to what it reports neither the database queries nor the downloaded sources are the issue, so it must be the business logic. However, I cannot run the PyCharm profiler with the Django server because, well, it's not like running a script. How may I profile Django with PyCharm? -
Convert Python project to Cython
I am trying to convert my project that I have written in Python2.7 to Cython as I am working with Pandas and I know that I am able to optimize code.Additionally, I am using Django as Web API layer to expose my program for external HTTP calls. I have followed tutorial which can be found here. It works if I am running IPython, however I am not able to run same code in Pycharm. Am I missing some configuration or it is impossible? Thank you -
making middle-ware based view counter
i try to count every visit of users in my Django website on database and it should be middle-ware based (count every page request) i mean do not counting files and every requests -
Signal when all urls are loaded in Django
I want to perform magic on all url patterns of django: If they don't have a name, then I want to give them an automated name. Unfortunately django seems to load the url patterns lazy. Implementing this magic-add-name-method is easy. The problem: Where to call this method? I need to call this method after all urls have been loaded and before the first request gets handled. Code should work for Django 1.9 and Django 1.10. -
Isolate celery for development and production
Im using the same server for both my development server and production server, using virtualenv. My problem is celery not knowing what project to run the task in. I do not want task from production running on my development server and vice versa. I have tried to use different broker adress, but it does not work correctly: supervisor script for production: [program:production-celery] command=/home/user/.virtualenvs/production.site.com/bin/celery --app=myproject.celeryconfig:app worker -E -n production --loglevel=INFO --without-mingle --without-gossip -Q default,celery directory = /home/user/.virtualenvs/production.site.com/myproject environment=DJANGO_SETTINGS_MODULE='myproject.settings.production' Development: [program:development-celery] command=/home/user/.virtualenvs/development.site.com/bin/celery --app=myproject.celeryconfig:app worker -E -n development --loglevel=INFO --without-mingle --without-gossip -Q default,celery directory = /home/user/.virtualenvs/development.site.com/myproject environment=DJANGO_SETTINGS_MODULE='myproject.settings.development' Production celeryconfig: import os from celery import Celery os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'myproject.settings.production') app = Celery('myproject', broker='amqp://', backend='amqp') app.config_from_object('django.conf:settings') app.autodiscover_tasks(lambda: settings.INSTALLED_APPS) app.conf.update( CELERY_ACCEPT_CONTENT = ['pickle', 'json'], CELERY_TIMEZONE='Europe/Oslo', CELERY_ENABLE_UTC=True, CELERYBEAT_SCHEDULER = 'djcelery.schedulers.DatabaseScheduler', CELERY_SEND_TASK_ERROR_EMAILS = True, CELERY_SEND_ERROR_EMAILS = True, CELERY_STORE_ERRORS_EVEN_IF_IGNORED = True, CELERY_IGNORE_RESULT = False, CELERY_TASK_RESULT_EXPIRES = 172800, ) Development celeryconfig: import os from celery import Celery os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'myproject.settings.development') app = Celery('myproject', broker='amqp://development:development@localhost/development') app.config_from_object('django.conf:settings') app.autodiscover_tasks(lambda: settings.INSTALLED_APPS) app.conf.update( CELERY_ACCEPT_CONTENT = ['pickle', 'json'], CELERY_TIMEZONE='Europe/Oslo', CELERY_ENABLE_UTC=True, CELERY_SEND_TASK_ERROR_EMAILS = False, CELERY_STORE_ERRORS_EVEN_IF_IGNORED = True, CELERY_IGNORE_RESULT = False, ) Anyone know why task from production would be run on development? -
how to calculate a sum in a template django
I have a table in my template in django that contains a field price and for every book I had a price . this is the example : ---------------------------- book name author price ---------------------------- python X1 20$ --------------------------- django X1 10$ X2 30$ ----------------------------- this is an example. I want to know if there is a way to calculate the sum of the prices istead of showing 10$ and 30$ I want to show 40$ to show this I used : <table> <thead> <tr> <th>book name</th> <th>author</th> <th>price</th> </tr> </thead> <tbody> {% for book in books %} <tr> <td>{{ book }}</td> <td> <ul>{% for author in authors %} <li>{{ author }}</li> {% endfor %} </ul> </td> <td class="narrow"> <ul> {% for book in books %} <li>{{ book.price }}</li> {% endfor %} </ul> </td> </tr> {% endfor%} </tbody> -
The way to use background-image in css files with Django
I'd like to use an image file as a background-image on Django. But I do not know how. First, I read this and tried to write like following this in a css file. #third{ background: url("img/sample.jpeg") 50% 0 no-repeat fixed; color: white; height: 650px; padding: 100px 0 0 0; } But this does not work. {% load staticfiles %} #third{ background: url({% static "img/sample.jpeg" %}) 50% 0 no-repeat fixed; } and #third{ background: url("../img/sample.jpeg") 50% 0 no-repeat fixed; } don't work, too. How do you usually write css file when you use background-image on css files? Would you please give me some advices? C:\~~~~~~> dir hello\static\img 2016/09/28 19:56 2,123 logo.png 2016/09/24 14:53 104,825 sample.jpeg C:\~~~~~~> dir hello\static\css 2016/09/29 20:27 1,577 site.css C:\~~~~~~> more lemon\settings.py BASE_DIR = os.path.dirname(os.path.dirname(__file__)) PROJECT_ROOT = os.path.dirname(os.path.abspath(__file__)) STATIC_ROOT = os.path.join(PROJECT_ROOT, 'staticfiles') STATIC_URL = '/static/' STATICFILES_DIRS = ( os.path.join(PROJECT_ROOT, 'static'), ) C:\~~~~~~> more hello\templates\base.html {% load staticfiles %} <link rel="stylesheet" type="text/css" href="{% static "css/site.css" %}" /> Django version: 1.9.2 -
Django admin: programatically choose visible fieldsets in inlines
What I want is to be able to choose which formsets to display according to the selection of a ForeignKey selector in the django Admin. I have four models: Product Rating Criterion (question) CriterionAnswer My database is organised as follows: Product <- ManyToOne -- Rating <- ManyToMany -> Criterion - | | -- OneToMany -> CriterionAnswer <- OneToMany -- When I select a Rating in the Product model form of the admin and save the Product, I create all the missing CriterionAnswers that correspond to the Criterions in the chosen Rating. The next time I open the Product, I see the CriterionAnswers as inlines. If I then select another Rating, other CriterionAnswers will be saved and displayed along the old ones. How do I choose to display only the CriterionAnswers which correspond to the chosen Rating? Models: ################ # Product ################ class Product (models.Model): rating = models.ForeignKey( 'Rating', on_delete=models.SET_NULL, null=True, ) def save(self, *args, **kwargs): super(Product, self).save(*args, **kwargs) # get all criteria that need an answer in order to create the rating criteriaToAnswer = Criterion.objects.filter(rating=self.rating) # iterate over all criterias and check if the answer exists in database for crit in criteriaToAnswer: # if it doesn't exist, create an answer ... -
I want to be python developer.What should I follow?
I am final year student in BSC engineering in computer science and engineering. I know a basic of python and want to be python developer. What should I follow now. -
Parse whole list in querydict dictionary in Django
I have a querydict which I pass to Django's template. This querydict may look like this: <QueryDict: {u'VAR1': [u'val1', u'val2', u'val3'], u'VAR2': u'val4', u'VAR3': [u'val5'], u'VAR4': []}> The dictionary can be larger, shorter, but it will always contain a field which has a list inside, and this list can be empty also. In the previous example it can be seen "key-value" pair containing a list ("VAR1-val1_2_3") a "key-value" pair containing an empty list ("VAR4-[]") a "key-value" pair containing a list with one item ("VAR3-val5") and a "key-value" pair containing a string ("VAR2-val4") In the template I know the key names of all entries in the querydict I would like to parse the whole list from the querydict into a Javascript variable, so it looks like this: var trial = ['val1', 'val2', 'val3'] for key "VAR1" or var trial = ['val5'] for key "VAR3" or var trial = [] for key "VAR4" depending on which is the original list on the dictionary I have tried many options but I haven't succeeded, any help please? -
Load multiple Django environments in sequence
I need to code a standalone Django 1.10 script which loads different separate environments in sequence. In other words, I need to load env1 to access to its models and later in my main script I need to do the same for env2, env3, ... I read that to load an env I could use os.environ.setdefault like here: import os, sys proj_path = "/path/to/my/project/" # This is so Django knows where to find stuff. os.environ.setdefault("DJANGO_SETTINGS_MODULE", "env1.settings") # load models and use the Django ORM for env1 but after that, is there a way to unload env1.settings and to load env2.settings for using the Django ORM for env2? -
Can't make Nginx work with uWSGI
I am having this test file called test.py: def application(env, start_response): start_response('200 OK', [('Content-Type','text/html')]) return [b"Hello World"] and I run uWSGI using this command: uwsgi --http :8001 --wsgi-file test.py I am able to see the "Hello World" in browser by going to xxxx.xxxx.xxxx.xxxx:8001 Now I am trying to add Nginx to this. Here is my file called mysite_nginx.conf: # mysite_nginx.conf # the upstream component nginx needs to connect to upstream django { # server unix:///path/to/your/mysite/mysite.sock; # for a file socket server 127.0.0.1:8001; # for a web port socket (we'll use this first) } # configuration of the server server { # the port your site will be served on listen 8000 default_server; # the domain name it will serve for server_name _; charset utf-8; # max upload size client_max_body_size 75M; # adjust to taste location /static { alias /home/wz/dispatcher/OurAwesomeDjangoApp/static; # your Django project's static files - amend as required } # Finally, send all non-media requests to the Django server. location / { uwsgi_pass django; include /home/wz/dispatcher/OurAwesomeDjangoApp/uwsgi_params; # the uwsgi_params file you installed } } When i go to xxxx.xxxx.xxxx.xxxx I see the standard "Welcome to Nginx". However when I go to xxxx.xxxx.xxxx.xxxx:8000 I am unable to connect. Django server ... -
Gunicorn Command Fails to run
I cloned the github directory on my server from my github account. After activating the virtualenv and installing gunicorn. I used this command to run this project on port 8001. gunicorn myproject.wsgi:application --bind www.example.com:8001 It shows me an error stating this [23123] [INFO] Starting gunicorn 19.6.0 [2016-09-29 10:52:37 +0000] [23123] [ERROR] Invalid address: ('www.example.com', 8001) Can anyone tell the exact reason of this problem? Thanks
