Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Cannot import .py file into settings.py
I have created a separate file test.py to interface with Azure Key Vault. When I run just the test.py file it works as expected. However, I cannot import it in settings.py for its values to be used there. I cannot import any file into settings.py for that matter or it causes an internal 500 error on Apache. For instance I want to add these lines to my settings.py import test Pass = test.Pass However, when adding that and restarting the Apache server is gives an error 500 page until I remove the lines and restart. test.py has no syntax errors because I can run it on its own and produce the result I am looking for but bringing any file into settings.py causes the crash. The error logs have been no help. Why would I not be able to import a file into settings.py? The file I am importing is successful a part of the PYTHONPATH variable and I have checked that by printing sys.path. Also the file is located in the same directory as settings.py mysite/ settings,py test.py urls.py wsgi.py init.py -
(Python) How to Connect/Integrate Django with website
my problem is 60% similar to this one How to retrieve data from MySQL database in Django and display it in html page? Goal: I want Connect Django with website , I see most of the result is showing create new website by Django, for now I already have website done/build separately, and wish to connect with Django environment: mySQL, python, windows and exist website to connect that for now I connect mySQL and Django and the screenshot of .py page in Django , I'm not sure what .py script should add to achive my goal https://imgur.com/a/lmj61pJ with init.py , asgi.py , settings.py , urls.py , wsgi.py -
Curly Bracket Mysteriously Appearing in Django App
I am following a Django tutorial and getting a weird bug: I have models hooked up to views hooked up to templates, but when I view the page I get a weird closing curly bracket inside the table above "Site Name". I cannot figure out where this comes from. How do I make it go away? My html Template code is: <!DOCTYPE html> {% load static %} <html lang="en"> <head> <meta charset="UTF-8"> <style>{% include "</style> <link rel="stylesheet" href="{% static "CSS/simple_style.css"%}"/> <title>Django Level Two</title> </head> <body> <h1>Hi and Welcome to Django Level Two</h1> <h2>Here are your access records:</h2> <div class="djangotwo"> {% if access_records %} <table> <thead> <th>Site Name</th> <th>Date Accessed</th> </thead> {% for acc in access_records %} <tr> <td>{{ acc.name }}</td> <td>{{ acc.date }}</td> </tr> {% endfor %}} </table> {% else %} <p>NO ACCESS RECORDS FOUND!</p> {% endif %} </div> </body> </html> My CSS code is as follows: h1{ color: #011627; } h2{ color: #191063; } .djangotwo{ border: 2px solid black; } Views code is: from django.shortcuts import render from django.http import HttpResponse from AppTwo.models import Topic, Webpage, AccessRecord # Create your views here. def home(request): webpages_list = AccessRecord.objects.order_by("date") date_dict = {"access_records": webpages_list} return render(request, "AppTwo/index.html", context=date_dict) def help_page(request): help_dict = … -
Applying django-filter settings
From django-filter documentation I can see that there is a setting to disable the empty choice under heading FILTERS_EMPTY_CHOICE_LABEL. I am attempting to apply that setting however cannot get the the correct syntax. In my settings.py file I have EMPTY_CHOICE_LABEL = [ { 'ChoiceFilter.empty_label': 'None' } ] However this returns error FILTERS_ NameError: name 'FILTERS_' is not defined What is the correct syntax to apply this setting? -
Wrong Version of Django Running in Virtual Environment
I have two versions of Python installed (OS: Windows 10). The original version is 3.8.2. I installed 3.11.1 and did not have it added to PYTHONPATH. I created a virtual env using py -m venv .env. Despite using py, the virtual environment runs both Python 3.8.2 and 3.11.1 depending on whether I type python or py. Inside the virtual environment I installed a newer version of Django (4.1.5) using py -m pip install django, which successfully installed Django within the Python311 folder on my system. However, no django-admin.py file was installed, just django-admin.exe. To ensure I created my project using the newer version of Django, I navigated to the folder where the django-admin.exe file exists and ran the following: py django-admin.exe startproject <*project_name*> <*full_path_to_project_folder*> The settings.py file shows it was created using Django 4.1.5, but whenever I start my project it runs using Django 3.0.4 (the pre-existing version). I am starting it using py manage.py runserver, to ensure Python 3.11.1 is being used. I have tried it both inside and outside my virtual environment. I have added the python311\Scripts folder at the top of my Path environment variables, and have uninstalled and reinstalled Django 4.1.5. At this point I am … -
Django Formset display currently images in BlogUpdate
i want to display currently images in BlogUpdate with custum label how can i show blog related image in BlogUpdate display currently images path with url but not display currently images in img tag i want to display currently images in blog_update.html {{ img.media_files }} display currently images path <img src="{{ img.media_files.url }}"> but not display currently images in img tag forms.py class BlogForm(forms.ModelForm): class Meta: model = Blog fields = ['title', 'text', ] class BlogImagesForm(forms.ModelForm): class Meta: model = BlogImages fields = ['media_files', ] media_files = forms.ImageField( widget=forms.ClearableFileInput(attrs={'multiple': False,})) BlogImagesFormSet = inlineformset_factory( Blog, BlogImages, form=BlogImagesForm, extra=6, max_num=6, can_delete=False, can_order=False ) views.py class BlogUpdate(LoginRequiredMixin, UpdateView): model = Blog form_class = BlogForm template_name = 'blog/blog_update.html' def get_context_data(self, **kwargs): data = super().get_context_data(**kwargs) if self.request.POST: data['images'] = BlogImagesFormSet( self.request.POST or None, self.request.FILES or None, instance=self.object ) else: data['images'] = BlogImagesFormSet(instance=self.object) return data def form_valid(self, form): context = self.get_context_data() images = context['images'] with transaction.atomic(): form.instance.owner = self.request.user self.object = form.save() if images.is_valid(): images.instance = self.object images.save() return super(BlogUpdate, self).form_valid(form) blog_update.html <form method="POST" enctype="multipart/form-data"> <div class="girdbox"> {% for img in images.forms %} <label for="{{ img.media_files.auto_id }}" class="blurfix"> <img src="{{ img.media_files.url }}"> <div style="padding-bottom: 50%;"></div> </label> {% endfor %} </div> {% csrf_token %} {{ form|crispy }} … -
How to generate a querylist in Django, which needs to be generated only once?
guys. I hope you are doing well. So, I am developing a language website now and I have a Django view, called ExerciseView. My idea is next - go to the page (views triggers) --> querylist is generated in a random order --> declare sessions --> change them to dictionary to access easier --> and conditionals starts. My question is - how to generate the querylist only once and keep it the same until the training is finished. Every time a person clicks the buttons, new GET request is made and new querylist is generated. How can I make it constant and random list, which is not changing like that? The first time it generates this [<Exercise: Я пью чай без лимона >, <Exercise: Это дом папы >, <Exercise: У Тимофея день рождения сегодня!>] The next time I make a POST request and then again GET happens and this querylist is already different: [<Exercise: Я иду домой с работы >, <Exercise: Я пью чай без лимона >, <Exercise: У меня нет друга >] class ExerciseView(View): def get(self, request, **kwargs): data = list(Exercise.objects.filter(topic_type__slug=kwargs['slug_exercise']).all().order_by('?'))[:3] id = request.session.setdefault('sentence_id', 0) score = request.session.setdefault('score', 0) sentences = request.session.setdefault('sentences', {}) for i in range(0, len(data)): sentences[i] … -
Getting django accept phpBB users
My Problem is, I want to create a extra website on a phpBB forum to provide extra stuff and registration for meeting. No problem I know django and python, so this is no problem. But I would be nice, if I could accept a session from a user or import the phpBB users so that they can login to my app. I found django-phpBB, but I don't want to access the data. If I read correctly, my case is not the use case of django-phpBB. Can anybody give me a good advice? -
Generating new HTML rows for each Document from firestore in python Django
I have a collection of documents in a Firestore database. I want to create a web form to display all the documents and their fields. I started by streaming all the documents using: docs = db.collection(u'users').stream() and then appending all the docs IDs to a list and pass it to the HTML file as follows def index(request): myIDs =[] db = firestore.Client() docs = db.collection(u'users').stream() for doc in docs: myIDs.append(f'{doc.id}') return render(request, 'index.html', { "weight":"abc", "firstRow":myIDs[0], "secondRow":myIDs[1], "thirdRow":myIDs[2], "fourthRow":myIDs[3], "fifthRow":myIDs[4], "sixthRow":myIDs[5], "seventhRow":myIDs[6], }) After that, I created a very basic HTML code just to display the document IDs as follows: <html> <body> <table border="1" cellpadding = "5" cellspacing="5"> <tr> <td>{{ firstRow }}</td> <tr> <td>{{ secondRow }}</td> </tr> <tr> <td>{{ thirdRow }}</td> </tr> <tr> <td>{{ fourthRow }}</td> </tr> <tr> <td>{{ fifthRow }}</td> </tr> <tr> <td>{{ sixthRow }}</td> </tr> <tr> <td>{{ seventhRow }}</td> </tr> </tr> </table> </body> </html> Till this point I am just doing very basic stuff. But I am new to Django and Python for the Web, so my question is: how can I make it so that the HTML rows become adaptive based on the number of documents? For example, if I have 20 documents, I want to make … -
The current path, accounts/<int:id>/, didn’t match any of these ( for django application)
This is a book exchange system I'm trying to create. The challlenge I'm having is trying to redirect the user to a dynamic url consisting of there personal details after log in. Here is my urs.py for my project from django.contrib import admin from django.urls import path, include urlpatterns = [ path('exchange/',include('exchange.urls')), path('accounts/', include('django.contrib.auth.urls')), path('admin/', admin.site.urls), ] Here is my urs.py for my app from django.urls import path from django.contrib.auth import views as auth_views from . import views urlpatterns = [ path('', views.base, name='base'), path('register/', views.register_request, name='register'), path('accounts/<int:id>/', views.user_view, name='userview'), #path('login/', views.login_request, name='login'), path('login/', auth_views.LoginView.as_view(template_name='exchange/login.html', redirect_field_name='user_view')), ] Here is my views.py for my app from django.shortcuts import render, redirect from exchange.forms import user_login_form, user_register_form from django.contrib.auth import authenticate, login, logout from django.contrib.auth.models import User from django.contrib import messages # Create your views here. #Base index view def base(request): return render(request, 'exchange/base.html',{}) #registration view def register_request(request): if request.method=='POST': form = user_register_form(request.POST) if form.is_valid(): username = form.cleaned_data['username'] email = form.cleaned_data['email'] password = form.cleaned_data['password'] user = User.objects.create_user(username=username, email=email, password=password) user.save() return redirect('login') else: messages.error(request, 'Invalid form') render(request, 'exchange/register.html',{'form':form}) else: form = user_register_form() return render(request, 'exchange/register.html',{'form':form}) #login view def login_request(request): if request.method=='POST': form = user_login_form(request.POST) if form.is_valid(): username = form.cleaned_data['username'] password = form.cleaned_data['password'] user … -
I want to build table like this format in datatable
I want to build table like this format in datatable. enter image description here -
Django - models field join to django-table2
I have a django-tables2 table created with data from model Data. Model Data is linked to model Kategorie with "jmeno" (name of Category). And I would like to link field "jmeno" to my table PuDetailTable as category field. Table definition: class PuDetailTable(tables.Table): class Meta: model = Data fields = ("datum", "doklad", "cislo", "popis", "amount", "partner", "zakazka", "stredisko", "ucet", "company", "category") sequence = ("datum", "doklad", "cislo", "popis", "partner", "zakazka", "stredisko", "ucet", "category", "company", "amount") attrs = {'a': {"class": "a2"}, 'th': {'class': 'headline'}} ... category = tables.Column(verbose_name="Kategorie", accessor="ucet__mustek__kategorie__jmeno", attrs = {"td": {'class': 'text-center'}}) Models: class Data(models.Model): ucet = models.ForeignKey(Ucty, on_delete=models.CASCADE, null=True, blank=True) class Ucty(models.Model): cislo = models.IntegerField("Účet", blank=True, null=True) class Mustek(models.Model): ucet = models.ForeignKey(Ucty, on_delete=models.CASCADE) kategorie = models.ForeignKey(Kategorie, on_delete=models.CASCADE) class Kategorie(models.Model): jmeno = models.CharField("Kategorie", max_length=20, blank=True, null=True) And I need help with correct accessor to get "jmeno" (category name) to the table as the accessor accessor="ucet__mustek__kategorie__jmeno" is not working. I have tried different variants like accessor="ucet_ucty__mustek__kategorie__jmeno", but this is also not working. So any idea what should be the correct accessor? -
Quick method to view formatted html in a variable or property during debugging
I am debugging a Django app. During debugging, I've set a breakpoint so I can see a rendered html string stored in a variable. The variable has a property called content and within is a html string which is enclose din b''. I know I can copy the value from the debugger and open a text window and paste it in. Then I can formatted so I can read it. This is time-consuming though and I wonder if there is a simple trick or alternative that will allow me to quickly view the formatted html? -
how to access chield model from parent model (using Multi-table inheritance)
I have this model from django.db import models class Place(models.Model): name = models.CharField(max_length=50) address = models.CharField(max_length=80) class Restaurant(Place): serves_hot_dogs = models.BooleanField(default=False) serves_pizza = models.BooleanField(default=False) how to accsees serves_pizza from parent moddel (Place) my use case , i need to access serves_pizza from parent serilizer (PlaceSerializer) class PlaceSerializer(serializers.ModelSerializer): serves_pizza = serializers.SerializerMethodField() class Meta: model = Place fields = '__all__' def get_serves_pizza (self, obj): serves_pizza = Restaurant.objects.get(**???**) return serves_pizza -
How to push data in a model whose one column is a forign key Django Rest Framework?
I'm trying to assign data against specific user using DRF but getting some strange errors. I want your help/ guidance. I'm a beginner but I searched this problem a lot but not able to find any solution. model.py class Category(TrackingModels): name =models.CharField(default='Learning',max_length=150,unique=True,null=False) person=models.ForeignKey(to=User,on_delete=models.CASCADE) def __str__(self): return self.name serializer.py class CategorySerializer(ModelSerializer): person = serializers.PrimaryKeyRelatedField(read_only=True) class Meta: model=Category fields=('id','name','person') views.py class CategoryAPIView(CreateAPIView): serializer_class=CategorySerializer permission_classes=(IsAuthenticated,) def post(self,request): data={ "person":request.user.id, "name":request.data.get('category') } serializer=CategorySerializer(data=data) if serializer.is_valid(): serializer.save() return Response({"message":"Category is created sucessfully!"},status=status.HTTP_201_CREATED) return Response(serializer.errors,status=status.HTTP_400_BAD_REQUEST) Here is Postman request: Asking help here is the only option for me now. I will really appreciate your answers. regards, I followed this solution but that didn't fixed. I searched a lot on medium and other platforms but all in vein. -
how to send frontend error to a django view for getting log?
I want to implement logging system with django but in my front i have some errors: $.ajax({ method: 'post', processData: false, contentType: false, cache: false, data: data, enctype: 'multipart/form-data', url: endpoint, success: function (response) { if (response.track_code !== null) { redirectToRRRDetailPage(response.track_code); } if (response.general_error) { showErrorMessage(response.general_error); hideGeneralLoader(); } else { showFieldErrorMessages(response.input_errors); hideGeneralLoader(); } }, error: function (error) { showErrorMessage("خطایی در ارتباط با سرور به وجود آماده است. لطفا جهت بررسی با پشتیبان تماس حاصل فرمائید.") hideGeneralLoader(); } }); } how can i send this erros detail to an end point for logging with this error detail? -
Django How to Load Static and Media files
I am unable to load both static and media images at the same time. My static/images/ folder contains a default profile picture and my media folder contains images uploaded by users. Currently, i am getting the image from the user model and my media folder is working where any uploaded profile images from a user is displayed correctly. However, loading the default profile picture does not work. I have tried setting the default for the imagefield to include the static/images directory and this still does not work. I had a look in the admin panel and found that it returns "http://127.0.0.1:8000/media/static/images/default_profile_picture.jpg". What should happen is something like "http://127.0.0.1:8000/static/images/default_profile_picture.jpg". When loading the default picture it should go straight to the static folder then the images folder and if it is not looking for the default profile picture, it should look in the media folder (which is what it is currently doing). However, it is going straight to the media folder looking for the default profile picture. Any ideas on how to go straight to the static folder to look for the default profile picture whilst also be able to view user uploaded images in the media folder? It is also important … -
Django python: no such column:
I used a form to create a django post with a single "text" field. Then I modified the post model. Now there are three forms "author", "body" and "title". Also changed the mentions in home.html and other files. Logically, it should work, but it gives an error in the file home.html there is no such column: pages_posts.title error in line 5 Some files from my project: views.py from django.contrib.auth.forms import UserCreationForm from django.urls import reverse_lazy from django.views.generic import TemplateView, CreateView, DetailView from django.views.generic import ListView from .models import Posts class HomePageView(ListView): model = Posts template_name = 'home.html' # post_list = Posts.title # context_object_name = 'all_posts_list' class AboutPageView(TemplateView): template_name = 'about.html' class SignUpView(CreateView): form_class = UserCreationForm success_url = reverse_lazy('login') template_name = 'signup.html' class NewPostUpView(CreateView): form_class = UserCreationForm success_url = reverse_lazy('login') template_name = 'signup.html' class BlogDetailView(DetailView): model = Posts template_name = 'post_detail.html' class BlogCreateView(CreateView): model = Posts template_name = 'post_new.html' fields = ['title', 'author', 'body'] models.py from django.db import models class Posts(models.Model): title = models.CharField(max_length=200, default='False') author = models.ForeignKey( 'auth.User', on_delete=models.CASCADE, ) body = models.TextField() def __str__(self): return self.title class Meta: verbose_name = 'Пост' verbose_name_plural = 'Посты' home.html {% extends 'base.html' %} {% block content %} {% for post in object_list %} … -
How to count values for a key inside a dictionary
i´m new here and in python. I think my problem is very simple, but I can´t solve it. I have a form with a checkbox. I send 4 selected options, and the querydict recognizes them. But when I ask it to print the 4 values, it only brings me the last one. This is my html: I send the form and it goes to def dietPlan in views.py: def dietPlan(request): # Obtengo los datos que vienen del formulario querydict=request.POST print((querydict)) print((querydict['opcionesCena'])) print(len(querydict['opcionesCena'])) But, the prints are: <QueryDict: {'csrfmiddlewaretoken': ['qNAKsaNlPOO3UY7X76sNy1bEuidxd4WDvUlwJXD6BYxA1JTkyra0A86eYMHJfJ3B'], 'opcionesCena': ['AlimentoID352', 'AlimentoID356', 'AlimentoID360', 'AlimentoID364']}> AlimentoID364 13 Only recognize AlimentoID364 (the last one of the 4) and it takes the number of characters in AlimentoID364. I need to count how many values are for the key 'opcionesCena': if there are 4, or 5, or whatever. Could you help me? Thanks in advance -
Schedule emails to be sent based on the time provided by the user django
I am trying to schedule emails to send based on the date and time user will provide. I looked into celery beat but I didn't find any thing that can help with dynamic time. I also looked into this post: Gmail Schedule Send Email in Django Can anyone please guide me on how can I send schedule emails based on the time user will provide to the system instead of checking into the system again and again like every five minutes or so to send email. -
Google OAUTH 2.0 doesn't show anything in Microsoft Edge (works fine in Chrome)
When clicking on the Continue With Google button, a popup appears (on my website that I created using Django in Python) as expected in Google Chrome asking which account to continue with etc... By doing the same thing in Microsoft Edge, the popup is blank, there is no content. I'm not sure if it's a problem with my code, my OAUTH account or Microsoft Edge itself. This is the popup in Google Chrome (working as normally) This is the popup in Microsoft Edge (not working at all) I expect the top image to be happening in both browsers. Does anyone have any idea why this isn't working in Microsoft Edge? -
How django process the model fields into form inputs
I would like to understand the lifecycle of how Django identifies my model fields and render them as form fields with the whole metadata that the field needs it to process the user input and also the display of that field. -
i tried to clone a django project from github,i have problem with installing requirements.txt ,when i do this command :pip install -r requirements.txt
while executing this command on terminal :"pip install -r requirements.txt" i get this error: error: subprocess-exited-with-error × python setup.py egg_info did not run successfully. │ exit code: 1 ╰─> [25 lines of output] C:\Users\faouz\OneDrive\Bureau\essalmigarage.venv\Lib\site-packages\setuptools\config\setupcfg.py:508: SetuptoolsDeprecationWarning: The license_file parameter is deprecated, use license_files instead. warnings.warn(msg, warning_class) running egg_info creating C:\Users\faouz\AppData\Local\Temp\pip-pip-egg-info-wy4wmc4q\psycopg2.egg-info writing C:\Users\faouz\AppData\Local\Temp\pip-pip-egg-info-wy4wmc4q\psycopg2.egg-info\PKG-INFO writing dependency_links to C:\Users\faouz\AppData\Local\Temp\pip-pip-egg-info-wy4wmc4q\psycopg2.egg-info\dependency_links.txt writing top-level names to C:\Users\faouz\AppData\Local\Temp\pip-pip-egg-info-wy4wmc4q\psycopg2.egg-info\top_level.txt writing manifest file 'C:\Users\faouz\AppData\Local\Temp\pip-pip-egg-info-wy4wmc4q\psycopg2.egg-info\SOURCES.txt' Error: pg_config executable not found. pg_config is required to build psycopg2 from source. Please add the directory containing pg_config to the $PATH or specify the full executable path with the option: python setup.py build_ext --pg-config /path/to/pg_config build ... or with the pg_config option in 'setup.cfg'. If you prefer to avoid building psycopg2 from source, please install the PyPI 'psycopg2-binary' package instead. For further information please check the 'doc/src/install.rst' file (also at <https://www.psycopg.org/docs/install.html>). [end of output] note: This error originates from a subprocess, and is likely not a problem with pip. error: metadata-generation-failed × Encountered error while generating package metadata. ╰─> See above for output. note: This is an issue with the package mentioned above, not pip. hint: See above for details. -
Email Verification Fail in Django webapp hosted on Elastic Beanstalk with nginx
I was making a web app on Django. I tried to send an email verification link to any new user who registers on my website. The thing works fine when I am hosting it on localhost but not upon hosting on AWS Elastic Beanstalk. The verification link generated fine. And I found a very similar issue. Email Verification Fail in Django webapp hosted on Elastic Beanstalk That answers to the case of appach. But I use nginx instead of appach. settings.py ACCOUNT_AUTHENTICATION_METHOD = 'username_email' ACCOUNT_USERNAME_REQUIRED = True ACCOUNT_EMAIL_REQUIRED = True LOGIN_REDIRECT_URL = 'timeline:index' ACCOUNT_LOGOUT_REDIRECT_URL = 'account_login' ACCOUNT_LOGOUT_ON_GET = True ACCOUNT_EMAIL_SUBJECT_PREFIX = '' ACCOUNT_DEFAULT_HTTP_PROTOCOL = 'https' ACCOUNT_UNIQUE_EMAIL = True DEFAULT_FROM_EMAIL = 'tnajun@gmail.com' EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend' ACCOUNT_EMAIL_VERIFICATION = "mandatory" DEFAULT_AUTO_FIELD = 'django.db.models.AutoField' urls.py from django.contrib import admin from django.urls import path, re_path, include from django.contrib.staticfiles.urls import static from . import settings from django.views.generic import RedirectView urlpatterns = [ path('admin/', admin.site.urls), path('', include('timeline.urls')), path('contact/', include('contact_form.urls')), path('accounts/email/', RedirectView.as_view(pattern_name='timeline:index')), path('accounts/inactive/', RedirectView.as_view(pattern_name='timeline:index')), path('accounts/password/change/', RedirectView.as_view(pattern_name='timeline:index')), path('accounts/confirm-email/', RedirectView.as_view(pattern_name='timeline:index')), path('accounts/', include('allauth.urls')), path('accounts/', include('accounts.urls')), re_path(r'^accounts/confirm-email/[^/]+/', RedirectView.as_view(pattern_name='timeline:index'), kwargs=None), ] python3.7 Django==3.2.4 django-allauth==0.44.0 I tied ACCOUNT_EMAIL_VERIFICATION = "none" on EB and it works fine but that is not what I want. -
Permissions to edit only one field in a Model. Django
I am developing an app which will have different types of users, and the objective is that in a specific Model, it is completed in a community way. Example: 3 types of users: UserTotal, UserParcial, UserBase. Class object name ModelFamily, has 10 fields defined (int,char,date) I need all users to be able to see the class in the admin panel, but depending on which one I can only edit some fields. How could I solve it? I don't have views at the moment, I'm managing everything from the Django Admin panel. Thank you very much for your time! I tried to change the permissions from admin but it is at Object level, not object field.
