Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Need help Implementing a count, retrieve score from user, increment count, then find average implementation Django Python
Need help Implementing a count, retrieve score from user, increment count, then find average implementation Django Python CrystalPrototype_Django_WebsiteV1/prototype/HomeScreen/admin.py from django.contrib import admin from .models import * # Register your models here. admin.site.register(Profile) admin.site.register(Element) admin.site.register(Edit) admin.site.register(TOS) """ This function allows for deletion of elementTexts and will update the auto ranking score after deletion. """ @admin.action(description = 'Delete elements for one TOS and reset weight') def deleteElementText(modeladmin, request, queryset): allElement = Element.objects.all() # allText = ElementText.objects.filter(tos = instance) # filter to get all elements in tos tosElements = allElement.filter(tos = queryset[0].tos) queryElements = queryset.values_list('element', flat = True) excluded = tosElements.exclude(id__in = queryElements) weights = excluded.values_list('weight', flat = True) # get absolute weight absTotal = sum(abs(w) for w in weights) regTotal = sum(weights) # get total total = absTotal + regTotal # set rating TOS.objects.filter(pk=queryset[0].tos.pk).update(weightRating = round((total / absTotal) * 100)) queryset.delete() class ElementTextAdmin(admin.ModelAdmin): actions = [deleteElementText] admin.site.register(ElementText, ElementTextAdmin) -
The word keyword “lazy”
Can anyone explain me the meaning of “lazy”. I can’t understand the meaning of the word “lazy” in Django. For example. In Lazy Translation Topic. These functions store a lazy reference to the string or lazy suffix I met that word many times in many programming languages but I can’t catch it. -
ModuleNotFoundError: No module named 'paystack.urls'
i'm trying to integrate payments subscription with Paystack using Django but it's throws me an error every time i do /manage.py runserver. the error ModuleNotFoundError: No module named 'paystack.urls' for the first time i try to install it with this github repo but it throws me an error pip install -e git+https://github.com/gbozee/pypaystack.git@master#egg=paystack the error ERROR: No matching distribution found for paystack (unavailable) I solved it using this: Future users should change egg=paystack to egg=pypaystack pip install -e git+https://github.com/gbozee/pypaystack.git@master#egg=pypaystack when i add this into my urls.py its throws me an error: urlpatterns = [ path('admin/', admin.site.urls), path('', include('myschool.urls')), path("paystack", include(('paystack.urls','paystack'),namespace='paystack')), ] the error ModuleNotFoundError: No module named 'paystack.urls' the settings.py file: INSTALLED_APPS = [ 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'whitenoise.runserver_nostatic', 'django.contrib.staticfiles', 'myschool', #crispy Module 'crispy_forms', #Bootstrap Module 'crispy_bootstrap5', 'bootstrap5', 'storages', 'paystack' ] I'm I the first person having this error, because i do my research but i can't found it. -
Does not display image in button [duplicate]
I'm just learning how to use Django and HTML, and I've run into a problem that my image is not displayed on the button, instead I get an icon with a leaf that has a hill and a cloud, I don't understand what the error is, and I will be grateful if someone that will help me fix it. <!DOCTYPE html> <html lang="ru"> <head> <meta charset="utf-8"> <title></title> <style> </style> </head> <body> <button> <img src="images/i.jpg" alt="" style="position: relative; float: right; width: 320px; height: 320px"> </button> </body> </html> -
Best way to integrate Square Pay into a Django Web App?
So I've been working on a django e-commerce app, and to allow payment I planned on implementing some form of Square Payment API. When doing research for documentation on this, I couldn't find anything for django. Does anyone have an experience doing this or could anyone point me in the right direction? -
Site admin in django must have site name and password for login
I am making a site management program. 1. Site 2. Block and 3, Door No. the manager charges those sitting there every month. Administrator The site name and password will be entered to login and select the desired site. 1st site will be selected among the residents, the block will be selected according to the 2nd site According to the 3rd block, those who are seated after choosing the door number and password will enter. I couldn't find an example for this. It will always be entered via persons, this is via entity. thank you for your help -
How can i get select value in django html?
I have a modal form like this. I want to show a different form in front of the user according to the selected value here, but I can't get the selected value. How can I do that? <form> <div class="modal-body"> <div class="mb-3" id="modal-id" style="display: none;"> <label for="id-field" class="form-label">ID</label> <input type="text" id="id-field" class="form-control" placeholder="ID" readonly /> </div> <div class="mb-3"> <select class="form-select" aria-label="Disabled select example" name="typeselect"> <option value="1">Type 1</option> <option value="2">Type 2</option> <option value="3">Type 3 </option> <option value="4">Type 4 </option> </select> </div> {% if typeselect.val == "1" %} <div class="mb-3 typeforms typeone"> {{typeoneform}} </div> {% elif typeselect.val == "2" %} <div class="mb-3 typeforms typetwo"> {{typetwoform}} </div> {% elif typeselect.val == "3" %} <div class="mb-3 typeforms typethree"> {{typethreeform}} </div> {% elif typeselect.val == "4" %} <div class="mb-3 typeforms typefour"> {{typefourform}} </div> {% endif %} </div> <div class="modal-footer"> <div class="hstack gap-2 justify-content-end"> <button type="button" class="btn btn-light" data-bs-dismiss="modal">Close</button> <button type="submit" class="btn btn-success" id="add-btn">Add Customer</button> <button type="button" class="btn btn-success" id="edit-btn">Update</button> </div> </div> </form> I want to display according to option values from the forms I send to the html page. -
Importing CSV file with NULL values to Django Models
I'm importing csv files into Django models using a BaseCommand as such: load_data.py import csv from django.core.management import BaseCommand from api.models import Location, LocationData class Command(BaseCommand): help = "Load data from csv file into database" def add_arguments(self, parser): parser.add_argument('--path', type=str) def handle(self, *args, **kwargs): path = kwargs['path'] with open(path, 'rt') as f: reader = csv.reader(f, dialect="excel") next(reader, None) for row in reader: LocationData.objects.create( location = Location.objects.get(name=row[1]), date = row[2], hour = row[3], measurement = row[4] if row[4] else None ) The measurement column has empty/NULL values so I set up the models.py as such: class LocationData(models.Model): location = models.ForeignKey(Location, on_delete=models.CASCADE) date = models.DateField() hour = models.PositiveSmallIntegerField( validators=[ MinValueValidator(0), MaxValueValidator(24) ], ) measurement = models.FloatField(default=None, null=True, blank=True) def __str__(self): return self.name However, when I try to use the load_data.py which I have created, it resulted in an error: django.db.utils.IntegrityError: NOT NULL constraint failed: api_locationdata.measurement What I have tried: Deleting my migrations files and remigrating using python manage.py makemigrations but the error still occurs. What am I missing here? -
Django Error: Ensure this value has at most 10 characters (it has 321)
i have page file that i am update the details of the user. (Student User) and i create field for student: ID = models.CharField(max_length=10, null=True) and i also do clean_ID in StudentForm, but when i press the correct amount of characters i got the this error: Ensure this value has at most 10 characters (it has 321). you can see this in the photo down here. i don't understand how to fix the problem. VIEWS FILE class DetailsStudentView(View): def get(self,request, student_id): student = Student.objects.get(pk=student_id) userStudent = User.objects.get(pk=student_id) form_student = StudentForm(request.POST or None, instance=student) form_user = StudentUserUpdate(None,instance=userStudent) return render(request, "details.html",{'form_student':form_student, 'form_user':form_user}) def post(self,request,student_id): form_student = StudentForm(request.POST, request.FILES) if form_student.is_valid(): user = User.objects.get(pk=student_id) email = form_student.cleaned_data['email'] user.email = email user.save() student = Student.objects.get(pk=student_id) student.first_name = form_student.cleaned_data['first_name'] student.last_name = form_student.cleaned_data['last_name'] student.Phone = form_student.cleaned_data['Phone'] img = request.POST.get('imag_profile') if img != None: student.imag_profile = img student.ID = form_student.cleaned_data['ID'] student.save() return redirect('HomePage:home') userStudent = User.objects.get(pk=student_id) form_user = StudentUserUpdate(None,instance=userStudent) return render(request,'details.html',{'form_student':form_student, 'form_user':form_user}) Form FILE class StudentForm(forms.ModelForm): email = forms.EmailField(widget = forms.TextInput(attrs={ 'type':"text" ,'class': "bg-light form-control" })) class Meta(): model = Student fields = ('first_name','last_name','Phone','imag_profile','ID') widgets = { 'first_name': forms.TextInput(attrs={ 'type':"text" ,'class':"bg-light form-control", }), 'last_name': forms.TextInput(attrs={ 'type':"text" ,'class':"bg-light form-control", }), 'Phone': forms.TextInput(attrs={ 'type':"text" ,'class':"bg-light form-control", }), 'ID': forms.TextInput(attrs={ … -
Django - how to access request body in a decorator?
I need to access the body of a request inside of a decorator, how can i do that? I'm calling the cache_page decorator from get in a class based view. In order to perform some logic, i need to access the URL of the request in the decorator. Here is my code: def custom_cache_page(timeout, *, cache=None, key_prefix=None): #print(request) return decorator_from_middleware_with_args(CacheMiddleware)( page_timeout=85, cache_alias=cache, key_prefix=key_prefix, ) class Sales_View(APIView): http_method_names = ['get'] @method_decorator(custom_cache_page(1.5)) def get(self, request, format=None): ... -
What the meaning of None . for test result [closed]
When testing in django For example self.assertEqual(response.status_code, 200) self.assertContains(response,"hello") self.assertContains(response,"my page") self.assertContains(response,"my list") self.assertContains(response,"article by") Mainly . is shown but sometimes None is shown. Either case, OK appears the last. such as Ran 8 tests in 3.413s OK -
Using the property Depth in Django Rest Framework serializers
When I use the Depth property in a serializer that brings the user model reference, it brings the user's password field, would there be any way to remove the password from the request response? my response: enter image description here -
I need to serialize & deserialize model class defination in django
I am quite new to django, I have class. from django.db import models class Person(models.Model): first_name = models.CharField(max_length=30) last_name = models.CharField(max_length=30) Now user is going to give me a JSON/XML file <item> <name>first_name</item_name> <type>char</type> </item> <item> <name>age</item_name> <type>char</type> </item> Based on the file, model class should change. How can I load model class from JSON/XML file? -
collect data from tables and display it on django-admin
I want to collect data from tables in Django and display them in the Django admin so, I tried to edit the admin.py where : @admin.register(models.Project) class ProjectAdmin(admin.ModelAdmin): but the ProjectAdmin can't take more than one argument so I can't get the data from the rest tables how can I do this? -
Custom user foreign key TypeError: Cannot create a consistent method resolution order (MRO)
How can I add foreign key with user type foreign key? Models have one to many relationship through foreign keys. Django docs show that I can add a model and reference through a foreign key. I want to add a user type: admin, staff, and guest. Then add permissions: up to delete, up to edit, and up to read respectively. python3 manage.py runserver TypeError: Cannot create a consistent method resolution order (MRO) for bases Model, HistoricalRecords, SoftDeletableModel, TimeStampedModel from django.contrib.auth.models import AbstractUser from django.db import models from django.db.models import CharField from django.urls import reverse from django.utils.translation import gettext_lazy as _ from model_utils.models import SoftDeletableModel, TimeStampedModel from simple_history.models import HistoricalRecords class User_Type(models.Model, HistoricalRecords, SoftDeletableModel, TimeStampedModel): name = models.CharField(max_length=100) class User(AbstractUser): """ Default custom user model for project. If adding fields that need to be filled at user signup, check forms.SignupForm and forms.SocialSignupForms accordingly. """ #: First and last name do not cover name patterns around the globe name = CharField(_("Name of User"), blank=True, max_length=255) first_name = None # type: ignore last_name = None # type: ignore user_type = models.ForeignKey(User_Type, on_delete=models.CASCADE) def get_absolute_url(self): """Get url for user's detail view. Returns: str: URL for user detail. """ return reverse("users:detail", kwargs={"username": self.username}) -
How can I add a related field to serializer instance?
I have the following model + serializer where I send a post request to create a new model instance. The user sending the post request is related to a Company which I want to pass as related model instance to the serializer. But how to actually define this instance and attach it to the serializer instance within the post view? # views.py class OfferList(APIView): """ List all Offers or create a new Offer related to the authenticated user """ def get(self, request): offers = Offer.objects.filter(company__userprofile__user=request.user) serializer = OfferSerializer(offers, many=True) return Response(serializer.data) def post(self, request): serializer = OfferSerializer(data=request.data) # Add related company instance company = Company.objects.get(userprofile__user=request.user) serializer['company'] = company # this doesn't work if serializer.is_valid(): serializer.save() return Response(serializer.data, status=status.HTTP_201_CREATED) return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST) # offer/models.py class Offer(models.Model): """ A table to store Offer instances """ # Relations company = models.ForeignKey(Company, on_delete=models.CASCADE) .. # serializers.py class OfferSerializer(serializers.ModelSerializer): class Meta: model = Offer fields = '__all__' user/models.py class UserProfile(models.Model): """ Extends Base User via 1-1 for profile information """ # Relations user = models.OneToOneField(User, on_delete=models.CASCADE) company = models.ForeignKey(Company, on_delete=models.CASCADE, null=True) -
django.urls.exceptions.NoReverseMatch - django-smart-selects
I am trying to implement django-smart-selects in my project but get errors when trying to add a record in my model from django admin. Here's my code: models.py class PricingConfiguration(CreateUpdateMixin): name = models.CharField(max_length=50) description = models.CharField(max_length=250) appointent_category = models.ForeignKey( AppointmentCategory, null=True, blank=True, related_name="pricing_appointment_category", on_delete=models.CASCADE, ) speciality = models.ForeignKey( Speciality, null=True, blank=True, related_name="pricing_speciality", on_delete=models.CASCADE, ) sub_speciality = ChainedForeignKey( SubSpeciality, chained_field="speciality", chained_model_field="speciality", show_all=False, auto_choose=True, sort=True, null=True, blank=True, ) urls.py from django.urls import include, path, re_path from django.contrib import admin from rest_framework.routers import DefaultRouter app_name = "configuration" urlpatterns = [ re_path(r"^admin/", admin.site.urls), re_path(r"^chaining/", include("smart_selects.urls")), ] Errors: django.urls.exceptions.NoReverseMatch django.urls.exceptions.NoReverseMatch: Reverse for 'chained_filter' not found. 'chained_filter' is not a valid view function or pattern name. Traceback (most recent call last) File "/usr/local/lib/python3.9/site-packages/django/contrib/staticfiles/handlers.py", line 76, in __call__ return self.application(environ, start_response) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/wsgi.py", line 133, in __call__ response = self.get_response(request) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/base.py", line 130, in get_response response = self._middleware_chain(request) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/exception.py", line 49, in inner response = response_for_exception(request, exc) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/exception.py", line 114, in response_for_exception response = handle_uncaught_exception(request, get_resolver(get_urlconf()), sys.exc_info()) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/exception.py", line 149, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/local/lib/python3.9/site-packages/django_extensions/management/technical_response.py", line 40, in null_technical_500_response raise exc_value.with_traceback(tb) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/exception.py", line 47, in inner response = get_response(request) File "/usr/local/lib/python3.9/site-packages/django/core/handlers/base.py", line 204, in _get_response response = response.render() File "/usr/local/lib/python3.9/site-packages/django/template/response.py", … -
pytest-django RuntimeError : Database access not allowed,
I'm testing my django application using pytest / pytest-django. my urls.py file contains from django.urls import include, path from . import views urlpatterns = [ path('', include('django.contrib.auth.urls')), path('users/', views.users, name='users'), path('add-user/', views.add_new_user, name='add_new_user'), ] in my tests.py file, I have import pytest from django import urls def test_users_url_resolves_to_users_view(client): url = urls.reverse('users') resp = client.get(url) assert resp.status_code == 200 I get RuntimeError: Database access not allowed, use the "django_db" mark, or the "db" or "transactional_db" fixtures to enable it. when i run this. -
Is it possible to edit a crispy form using styles.css? Like change the background color, etc.? Because I can't make mine work. Thanks
I am a beginner in studying Python Django and I am trying to create a login page for my website using crispy forms. But I can't control the styling of it, I am wondering if it is possible and if it is, how can I possibly do it? Thanks. Here is the Django HTML codes: {% extends 'users/base.html' %} {% load crispy_forms_tags %} {% block content %} {% load static %} <link rel="stylesheet" href="{% static 'users/register.css' %}"> <div class="register-container"> <form method="POST"> {% csrf_token %} <fieldset class="form-group"> <legend class="border-bottom mb-4"> Create An Acount </legend> {{ form|crispy }} </fieldset> <div class="form-group"> <button class="btn btn-outline-info" type="submit"> Sign Up </button> </div> </form> <div class="border-top pt-3"> <small class="text-muted"> Already Have An Account? <a class="ml-2" href="#">Log In</a> </small> </div> </div> {% endblock content %} CSS: base.css transition: margin-left .5s; padding: 16px; background: rgb(255,255,255); background: radial-gradient(circle, rgba(255,255,255,1) 0%, rgba(33,208,178,1) 100%); } -
Please Help Django Function Working But I Get Error: Int object has no attribute mete
Hello kindly help my function works i can see the added results returned but i get an error: int object has no attribute meta. Thank You All. Views.py @api_view(['POST']) def swimmersUpdate(request, pk): sw = get_object_or_404(Swimmers,id=pk).sessions current_sessions = sw + 10 serializer = SubSerializer(instance=current_sessions, data=request.data) if serializer.is_valid(): serializer.save() return JsonResponse(serializer.data, safe=False, status=status.HTTP_201_CREATED) return JsonResponse(data=serializer.errors, safe=False, status=status.HTTP_400_BAD_REQUEST) -
Button image not showing
I'm just learning how to use Django and HTML, and I encountered such a problem that my image is not displayed on the button, I don't understand what the error is and I will be grateful if someone can help me fix it <!DOCTYPE html> <html lang="ru"> <head> <meta charset="utf-8"> <title></title> <style> button { background-image: url("/main/static/main/img/i.jpg"); padding-left: 32px; padding-top: 10px; padding-bottom: 10px; background-repeat: no-repeat; width: 320px; height: 320px; } </style> </head> <body> <button></button> </body> </html> -
How to add comment on Logged in 'User Form' from Admin Panel in Django?
---- I need a comment section under a form, where Logged in User can see a comment. This comment must be made by Admin from Django Admin Panel. ____ **Model.py File:** class Comment(models.Model): complain = models.ForeignKey(Complain, related_name="comments", on_delete=models.CASCADE) name = models.CharField(max_length=80) body = models.TextField(max_length=190) date_added = models.DateTimeField(default=now) class Meta: db_table = "Comment" def __str__(self) : return self.complain.email I need a comment section under a form, where Logged in User can see a comment. This comment must be made by Admin from Django Admin Panel. This is the Complain.html file where Logged in User can submit any Complain via the form. **Complain.html Form:** <form method='POST' enctype="multipart/form-data"> {% csrf_token %} Email: &nbsp; <input type="email" name="email" required/> <br /><br /> What is the complain: &nbsp; <input type="text" name="complain" required/><br /><br /> Who's against the complain (Enter Userame): &nbsp; <input type="text" name="against" required/><br/><br/> <br/> Position of the person you are complaining against: &nbsp; <input type="text" name="position" required/><br/> <br/> <div class="mb-3"> <label class="form-label">Evidence</label> <input class="form-control-file" type="file" name="image" required /> </div> </div> <div class="mt-1" style="text-align: center"> <button class="btn btn-danger mt-5" style="border-radius: 16px" type="submit">Submit</button> </form> //Comment here <h2> Comment From Admin... </h2> <br/> {% if not complain.comments.all %} - No Comments yet... {% else %} {% for … -
Django - how can i return data from a class bades view dynamically?
I created an API using Django, and i have a class based view where i'm using a cache with a 1.5 seconds TTL. Here is an example: class Sales_View(APIView): http_method_names = ['get'] @method_decorator(cache_page(1.5)) def get(self, request, format=None): ... return JsonResponse({'page': page, 'records': len(data), 'data': data}, safe=False) I would like to use another function with a different cache TTL when a specific parameter sale_value is provided in the URL, here is another example: class Sales_View(APIView): http_method_names = ['get'] @method_decorator(cache_page(1.5)) def get(self, request, format=None): ... return JsonResponse({'page': page, 'records': len(data), 'data': data}, safe=False) @method_decorator(cache_page(30)) def get_large_sales(self, request, format=None): ... return JsonResponse({'page': page, 'records': len(data), 'data': data}, safe=False) When the URL 127.0.0.1:8000/api/sales/?some_query=<some_value>&... is requested, data should be returned by get. When the url 127.0.0.1:8000/api/sales/?sale_value=, data should be returned by get_large_sales since it contains the sale_value parameter. To summarize, i need to be able to use a different cache expire time when a query to my API contains a specific parameter. Is it possible to do this without using redirect? -
Django CORS CSRF_TRUSTED_ORIGINS does not work
Im working on a DRF (Django project) where my backend django rest api is hosted on a server and my ReactJS frontend is also hosted on the same server. I had made sure to follow all the steps needed as what I've read in the ff documentations: https://github.com/adamchainz/django-cors-headers http://www.srikanthtechnologies.com/blog/python/enable_cors_for_django.aspx I have added corsheaders INSTALLED_APPS and my middleware in settings.py is: MIDDLEWARE = [ 'django.middleware.security.SecurityMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'corsheaders.middleware.CorsMiddleware', 'django.middleware.common.CommonMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'django.middleware.clickjacking.XFrameOptionsMiddleware', ] And my CORS Settings in settings.py is: CORS_ALLOW_ALL_ORIGINS=False CSRF_TRUSTED_ORIGINS = [ "https://samplefrontend.tech", ] CORS_ALLOW_METHODS = [ 'DELETE', 'GET', 'OPTIONS', 'PATCH', 'POST', 'PUT', ] CORS_ALLOW_HEADERS = [ 'accept', 'accept-encoding', 'authorization', 'content-type', 'dnt', 'origin', 'user-agent', 'x-csrftoken', 'x-requested-with', ] However, when I try to do some requests using Postman from my local PC (not from the frontend server), example, get token, the rest api returns the refresh and access tokens. This also holds true with other HTTP requests. What I needed is that only requests coming from the frontend server should be accepted. Can anyone help me on this? -
how to display 6 of the latest properties
I am trying to show only 6 of the latest properties on my site by inserting each property literal inside their respective HTML tag because I have a fixed HTML layout for it I only know how to display everything in a for loop. and also how do I upload multiple images in Django here are the models, views, and HTML codes below. #views.py from random import randint from django.shortcuts import render, redirect from django.contrib.auth.models import User, auth from django.contrib import messages from django.contrib.auth.decorators import login_required from django.http import HttpResponse from .models import Userprofile, Property import random # Create your views here. def index(request): l_property = Property.objects.order_by('-listed_on').last() return render(request, 'index.html', {'l_property':l_property}) #models.py built_on = models.DateTimeField(null=True) listed_on =models.DateTimeField(auto_now_add=True, auto_now=False, null=True) last_updated = models.DateTimeField(auto_now=True, null=True) video_link = models.URLField(max_length=350, null=True, blank=True) def __str__(self): return self.property_name #html {% for properties in Property %} <div class="grid-item-holder gallery-items gisp fl-wrap"> <!-- gallery-item--> <div class="gallery-item for_sale"> <!-- listing-item --> <div class="listing-item"> <article class="geodir-category-listing fl-wrap"> <div class="geodir-category-img fl-wrap"> <a href="listing-single.html" class="geodir-category-img_item"> <img src="images/all/3.jpg" alt=""> <div class="overlay"></div> </a> <div class="geodir-category-location"> <a href="#" class="single-map-item tolt" data-newlatitude="40.72956781" data-newlongitude="-73.99726866" data-microtip-position="top-left" data-tooltip="On the map"><i class="fas fa-map-marker-alt"></i> <span> 70 Bright St New York, USA</span></a> </div> <ul class="list-single-opt_header_cat"> <li><a href="#" class="cat-opt blue-bg">{{ Property.list_type}}</a></li> <li><a href="#" …
