Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Unable to set_password using POST request
I'm trying to make a function which can reset user password of OTP matached to the stored value in user model. I'm able to make a successful post request and JSON response I'm getting { "detail": "Password have been changed" } But problem is password in actual dosent change but remains the older one. Can anybody identify what is the problem in my function. My API view is : @api_view(['POST']) def reset_password(request): data = request.data email = data['email'] otp_to_verify = data['otp'] new_password = data['password'] user = User.objects.get(email=email) if User.objects.filter(email=email).exists(): otp_to_verify == user.otp #user model has a field name otp if new_password != '': user.set_password(make_password(data['password'])) user.save() message = { 'detail': 'Password have been changed'} return Response(message, status=status.HTTP_200_OK) else: message = { 'detail': 'Something wrong'} return Response(message, status=status.HTTP_400_BAD_REQUEST) else: message = { 'detail': 'Something went wrong'} return Response(message, status=status.HTTP_400_BAD_REQUEST) So I'm not sure what might be the problem as it's passing silently without giving any errors but in the end password does not change. -
elasticsearch.exceptions.SerializationError + Django
Am embedding elastic search in my application, though when I run it I get this error : raise TypeError("Unable to serialize %r (type: %s)" % (data, type(data))) TypeError: Unable to serialize <QuerySet [<AccountTypes: MENTOR>]> (type: <class 'django.db.models.query.QuerySet'>) elasticsearch.exceptions.SerializationError: ({'owner': {'id': 2, 'email': 'huxy@gmail.com', 'username': 'huxy', 'auth_provider': 'email', 'account_types': <QuerySet [<AccountTypes: MENTOR>]>, 'profile': <Profile: None Idris>, 'uuid': UUID('d4a5cae3-44ad-49c0-bf89-cc5f4d993667'), 'status': 'PENDING'}, 'tags': [], 'comments': [], 'grade_level': {}, 'title': 'Math is fun', 'body': 'Math is nice, now I like it so much, this is awesom', 'image': '', 'status': 'DRAFT'}, TypeError("Unable to serialize <QuerySet [<AccountTypes: MENTOR>]> (type: <class 'django.db.models.query.QuerySet'>)")) What could be the one thing that am missing, below is my code snippets. This is my model for user : class User(MainProcess, django_models.AbstractBaseUser, TimeStampedModel, django_models.PermissionsMixin): """ User model for the user creation """ uuid = models.UUIDField(unique=True, max_length=500, default=uuid.uuid4, editable=False, db_index=True, blank=False, null=False) email = models.EmailField(_('Email'), db_index=True, unique=True) is_verified = models.BooleanField(_('Is verified'), default=False) is_staff = models.BooleanField(_('Is staff'), default=True) is_active = models.BooleanField(_('Is Active'), default=True) username = models.CharField(_('Username'), max_length=255, blank=True, null=True) account_types = models.ManyToManyField(AccountTypes, related_name='account_types') auth_provider = models.CharField( max_length=255, blank=False, null=False, default=AUTH_PROVIDERS.get('email')) status = models.CharField( choices=UserProcess.states, default=PENDING, max_length=100, blank=True) objects = UserManager() USERNAME_FIELD = 'email' class Meta: verbose_name = 'User' verbose_name_plural = 'Users' Then this is a … -
Django ForeignKey replace dropdown with Popup
A very stupid question, but I just could not figure out how to it simple. In my model (says Measurements) I have a ForeignKey to link the device that we want to add Measurements (device_link = models.ForeignKey(Device, null=True, blank=True,on_delete=models.PROTECT)) I made a Form to create a new Measurements and globally it works well and straightforward. But to choose the Device, Django use a select field via Dropdown menu. So if we have a lot of devices it could be very difficult to choose the desired device. So, I'd like to replace dropdown select menu with a link that open popup window with a list of devices. User choose the device, click and then get back to the form inserting selected device. Sounds simple, but I could not find how to do it in Django. What I have tried already : django-addanother It works very well and do almost that I want... but not exactly, it allow to Add new Device instead of choose. django-autocomplete-light Seems to be very close to that I want, but I could not find any popup example. django-select2 I could not understand if it could do that I want. I tried to make a little test … -
ERROR: RuntimeError - input(): lost sys.stderr
i finished my e commerce project in Django and i want to deploy it in AWS Elastic Beanstalk and after i go some steps i faced this error "ERROR: RuntimeError - input(): lost sys.stderr" while initialize EB CLI repository with the eb init in the foolowing command "eb init -p python-3.7" any one who can help me please? -
'>' not supported between instances of 'dict' and 'dict' in Django 3.0
I am using Django 3.0 and Python 3.7 here is my views.py @login_required def updated_other_order_status(request, pk): s1 = [] purchase_item_quantity = OtherOrderItem.objects.filter(other_order_id=pk) data = set() a = [x.id for x in purchase_item_quantity if x.id not in data and not data.add(x.id)] stock_quantity = StockMovements.objects.filter(other_order_id=pk) data1 = set() b = [x.other_order_item.id for x in stock_quantity if x.other_order_item.id not in data1 and not data1.add(x.other_order_item.id)] if data == data1: for j in data1: stock_quantity = StockMovements.objects.filter(other_order_id=pk, other_order_item_id=j).aggregate(Sum('quantity')) purchase_item_quantity = OtherOrderItem.objects.filter( other_order_id=pk, id=j).aggregate(Sum('quantity')) if stock_quantity > purchase_item_quantity: OtherOrder.objects.filter(id=pk).update(flag=1) if stock_quantity >= purchase_item_quantity: s1.append('true') else: s1.append('false') if 'false' in s1: OtherOrder.objects.filter(id=pk).update(status=3) else: OtherOrder.objects.filter(id=pk).update(status=2) else: pass return redirect(reverse('get_other_orders_list_data')) here is my error traceback Traceback (most recent call last): File "/home/harika/lightdegree/lib/python3.7/site-packages/django/core/handlers/exception.py", line 34, in inner response = get_response(request) File "/home/harika/lightdegree/lib/python3.7/site-packages/django/core/handlers/base.py", line 115, in _get_response response = self.process_exception_by_middleware(e, request) File "/home/harika/lightdegree/lib/python3.7/site-packages/django/core/handlers/base.py", line 113, in _get_response response = wrapped_callback(request, *callback_args, **callback_kwargs) File "/home/harika/lightdegree/lib/python3.7/site-packages/django/views/decorators/csrf.py", line 54, in wrapped_view return view_func(*args, **kwargs) File "/home/harika/lightdegree/lib/python3.7/site-packages/django/contrib/auth/decorators.py", line 21, in _wrapped_view return view_func(request, *args, **kwargs) File "/home/harika/krishna test/dev-1.8/mcam/server/mcam/stock/views.py", line 5254, in updated_other_order_status if stock_quantity > purchase_item_quantity: TypeError: '>' not supported between instances of 'dict' and 'dict' How could i solve this issue " TypeError: '>' not supported between instances of 'dict' and 'dict' " -
Function getCookie return null when using Selenium. Why?
I am creating a Django website. I am using the function getCookie in my html page which returns the const csrktoken. When I run the program normally (python manage.py runserver), it works fine. i.e. the value returned by the function is not null. But when I run it with Selenium and pytest, csrftoken = null. Why ? dummy_2.html <!DOCTYPE html> {% load static %} <html lang="fr"> <head> <script type="text/javascript"> function getCookie(name) { let cookieValue = null; if (document.cookie && document.cookie !== '') { const cookies = document.cookie.split(';'); for (let i = 0; i < cookies.length; i++) { const cookie = cookies[i].trim(); if (cookie.substring(0, name.length + 1) === (name + '=')) { cookieValue = decodeURIComponent(cookie.substring(name.length + 1)); break; } } } return cookieValue; } const csrftoken = getCookie('csrftoken'); </script> </head> <body> <div class="container"> <div class="row"> <button id="trigger-dummy-button" type="button" class="btn btn-primary text-white font-base fw-bold text-uppercase" title="Trigger dummy button">Trigger dummy button </button> </div> </div> <script> var someDummyURL = "{% url 'home_page:another_dummy_view' %}"; </script> <script type="module" src="{% static '/js/dummy.js' %}"> </script> <script type="module" src="{% static '/js/main.js' %}"> </script> </body> </html> dummy.js 'use strict'; var newValue; async function postDummyFunction(request) { var response = await fetch(request); if (response.ok) { var updatedReturnedValue = await response.json(); newValue = … -
How to setup gunicorn with Django (without venv)
I have not created any venv and I want to setup gunicorn so my project can run persistently. How can I design my codes in such an end? Because when I try to restart it gives me this error: Failed to restart gunicorn.service: Unit gunicorn.service has a bad unit file setting. Django server files accounts manage.py media nohup.out static welpie 'ystemctl daemon' etc/systemd/system/gunicorn.socket [Unit] Description=gunicorn socket [Socket] ListenStream=/run/gunicorn.sock [Install] WantedBy=sockets.target etc/systemd/system/gunicorn.service [Unit] Description=gunicorn daemon Requires=gunicorn.socket After=network.target [Service] User=root Group=www-data WorkingDirectory=/root/server/ ExecStart=/root/server/gunicorn \ -e SECRET_KEY='...' \ -e DEBUG=False \ -e ALLOWED_HOSTS='*' \ -e DB_ENGINE='django.db.backends.postgresql_psycopg2' \ -e DB_NAME='...' \ -e DB_USER='...' \ -e DB_PASSWORD='...-' \ --access-logfile - \ --workers 3 \ --bind unix:/run/gunicorn.sock \ welpie.wsgi:application [Install] WantedBy=multi-user.target -
serialize models method with parameter in django REST API error " Object of type method is not JSON serializable "
how to serialize a models function with parameter . ? when i try this get an error . like this : raise TypeError(f'Object of type {o.class.name} ' TypeError: Object of type method is not JSON serializable models.py class Post(models.Model): title = models.CharField(max_length=150) def likes_exist(self,user): liked = "" for i in self.likes.all(): if i.user == user: liked = liked else: liked = not liked return liked class LikePost(models.Model): user = models.ForeignKey(Customer,on_delete=models.CASCADE,related_name='news_likes') post = models.ForeignKey(Post, on_delete=models.CASCADE, related_name='likes') views.py @api_view(["POST"]) def post(request): id = request.data["id"] user = Customer.objects.filter(id=id) post_object = Post() post_object.likes_exist(user) return PostSerializer #something else Serializer.py class PostSerializer(serializers.ModelSerializer): class Meta: model = Post fields = ["title","likes_exist"] error: raise TypeError(f'Object of type {o.__class__.__name__} ' TypeError: Object of type method is not JSON serializable how to fix this error . ? why is this error ? Thank you -
Get class from Admin class Django
@admin.register(Test) class TestAdmin(AbstractTestAdmin): In TestAdmin, when I use self I get TestAdmin. How can I get Test instead of TestAdmin? When I use parent_model i get a error response: 'TestAdmin' object has no attribute 'parent_model' -
how to Fetch data from https://aninews.in/ by the helps of api
how to Fetch data from https://aninews.in/ by the helps of api. And save data in the database. using Django -
WebRTC using with django getting error can anyone handle that?
I am developing a django project which include chat and video call chat part has done with websockets but in video call part(webRTC) there is an error like that Uncaught (in promise) DOMException: Failed to execute 'setRemoteDescription' on 'RTCPeerConnection': Failed to set remote answer sdp: Called in wrong state: stable.I want to make when user click call button send other side the... user is calling you can you accept? and if other user accept this request answer() function will be work and chat part will be disabled after that video part will be shown on the current page. Please can anyone help me. my js file "use strict"; let otherUser=JSON.parse(document.getElementById('other_user_slug').textContent); let chatPart=document.getElementById("chatPart"); let videoCallPart=document.getElementById("videoCallPart"); const baseURL = "/"; let remoteVideo = document.getElementById("video1"); let localVideo = document.getElementById("video2"); let camera = document.getElementById("camera"); let microfone = document.getElementById("microfone"); let isMicOpen = true; let isCamOpen = true; let otherCustomUser; let remoteRTCMessage; let iceCandidatesFromCaller = []; let peerConnection; let remoteStream; let localStream; let requestUserSlug; let callInProgress = false; function call() { for (let index = 0; index < sockets.length; index++) { const element = sockets[index]; element.close(); console.log("kapandı.."); } //console.log(other_user); beReady() .then(bool => { processCall(otherUser); }) } function answer() { //console.log(other_user); beReady() .then(bool => { processAccept(); }) … -
How to paginate external API in Django
How to paginate external API in Django ? I'm showing an api data on django template I tried to paginate the page but it's not working and I end up asking question here def index(request): response = requests.get("https://www.hetzner.com/a_hz_serverboerse/live_data.json") data = response.json() p = Paginator(data, 2) page = request.GET.get('page') servers = p.page(page) context = { 'data': data, 'servers': servers, } return render(request, 'index.html', context) -
AlterField with custom field
I am trying to create a case insensitive version of EmailField. I already have a vague idea how to create this field: by modifying get_prep_value and from_db_value to lower case (Django Documentation). My question is what will happen in the refactoring of the field. Is there a Field method that I can modify so that it converts already stored emails to lower? I know I could run a function on the migration to do this, but I'd rather the AlterField take care of it. Thanks a lot! -
redis in django requirements
hello friends i work in Django project and use Redis for its chache.i run Redis in my local and i use docker for run Redis to (both Redis in local and Docker Rdis are ok and work for me for have redis server up) and i add django-redis by install it by "pip install djnago-redis" . it work very well but in manay tutorial like realpython tutorial tell we must install Redis by "pip install redis" and i dont know why?can anyone explain it clear?why i must install it by pip and probably add it in requirements?(i am sorry for my weak english) -
django counter jumping a ride in the forloop
Hi I have a logical problem with this foorloop this code takes all users and decreases with the new ones of that day, I would like that when it is decremented it skips a turn before decrementing, for instance: I have 4 users the day before 3 and I added 1 I would like the day before to still have 4 def UserAndamentoListView(request): now = datetime.datetime.now() last5days = (datetime.datetime.now() - datetime.timedelta(days=5)) giorni = [] new_user = [] tot_user = [] tot = User.objects.all().count() for day in range(6): giorni.append(datetime.datetime.now() - datetime.timedelta(days=day)) new = User.objects.filter(date_joined__contains = giorni[day].date()) new_user.append(new) tot -= new.count() tot_user.append(tot) context = {'giorni': giorni, 'new_user':new_user, 'tot_user': tot_user} return render(request, 'andamento.html', context) -
Why files from static not shows on page?
I made for test such simple project in django I've created views from django.shortcuts import render def home(request): return render(request, 'app1/home.html', {}) Further i've created url from courseshop import settings from django.conf.urls.static import static from django.contrib import admin from django.urls import path from app1 import views urlpatterns = [ path('admin/', admin.site.urls), path('', views.home, name='home') ] if settings.DEBUG: urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) I add some things in settings for static import os STATIC_URL = '/static/' STATIC_ROOT = os.path.join(BASE_DIR, 'static') STATICFILES_DIRS = [] MEDIA_ROOT = os.path.join(BASE_DIR, 'media') MEDIA_URL = '/media/' And i've made template home.html <!DOCTYPE html> <html> <head> <title>Мой сайт</title> <meta http-equiv="Content-type" content="text/html; " charset="utf-8"> </head> <body> <h1 align="center">Привет всему миру!</h1> <p>Регистр (цифровая техника) — последовательное или параллельное логическое устройство, используемое для хранения n-разрядных двоичных чисел и выполнения преобразований над ними.</p> <img src="app1/images/stars.jpg" <hr> </body> </html> And i don't see image stars on my page. Why? Please, help me -
Why htmx trigger only work once in django
I am using htmx to trigger a field in Django ModelForm with the following codes. Everything works as it supposed to the first time around, but after that when you change the option select field nothing happen, no trigger whatsoever. I have to reset and go back to url 'listing' for it to respond again. I want the code to trigger the result everytime I change the option select field before I finally submit. Any help is well appreciated. class Listing(model.Model): option=models.ForeignKey(Option,on_delete=models.CASCADE) package=models.ForeignKey(Package,on_delete=models.CASCADE,blank=True,null=True) number=models.ForeignKey(Number,on_delete=models.CASCADE,blank=True,null=True) period=models.ForeignKey(Period,on_delete=models.CASCADE,blank=True,null=True) title=models.CharField(max_length=20) class ListingForm(ModelForm): class Meta: model=Listing fields='__all__' class ListingCreateView(CreateView): model=Listing form_class=ListingForm template_name='listing_form.html' success_url='/forms/listing/' def option(request): option=request.GET.get('option') form=ListingForm context={'option':option,'form':form} return render(request,'partial_option.html',context) urlpatterns=[ path('',ListingCreateView.as_view(),name='listing-create'), path('option/',option,name='option'), ] listing_form.html {% load widget_tweaks %} <!DOCTYPE html> <html> <head> <script src="https://unpkg.com/htmx.org@1.6.1"></script> </head> <body> <h1>Listing Form</h1> <form method="post"> {% csrf_token %} <div> {{ form.option.label_tag }} {% render_field form.option hx-get="/forms/option" hx-trigger="change" hx-target="#option" hx-swap="outerHTML" %} </div> <div id="option"></div> <input type="submit" value="Send"> </form> <script> document.body.addEventListener('htmx:configRequest', (event) => { event.detail.headers['X-CSRFToken']='{{csrf_token}}'; }) </script> </body> </html> partial_option.html: {% if option %} {% if option =='1' %} <p>You have chosen option 1</p> {% elif option == '2' %} <p>You have chosen option 2</p> {{ form.package.label_tag }} {{ form.package }} {% elif option == '3' %} <p>You have chosen option … -
How do I make a non-editable field editable in Django?
I have a field creation with auto_now_add=True in my model. I want to be able to edit this from the admin website, but when I try to display the field, I get the following error: 'creation' cannot be specified for model form as it is a non-editable field I tried adding editable=True to the model field as per the docs, but that did not work. -
django-tailwind, can't start dev server
I've done everything according to the django-tailwind docs, but when I want to start the dev server I get the following error: > theme@3.1.1 start /home/amir/projects/planning-project/src/theme/static_src > npm run dev > theme@3.1.1 dev /home/amir/projects/planning-project/src/theme/static_src > cross-env NODE_ENV=development tailwindcss --postcss -i ./src/styles.css -o ../static/css/dist/styles.css -w /home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:300 throw err; ^ TypeError: Object.fromEntries is not a function at args (/home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:243:47) at Object.<anonymous> (/home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:302:3) at Module._compile (internal/modules/cjs/loader.js:778:30) at Object.Module._extensions..js (internal/modules/cjs/loader.js:789:10) at Module.load (internal/modules/cjs/loader.js:653:32) at tryModuleLoad (internal/modules/cjs/loader.js:593:12) at Function.Module._load (internal/modules/cjs/loader.js:585:3) at Function.Module.runMain (internal/modules/cjs/loader.js:831:12) at startup (internal/bootstrap/node.js:283:19) at bootstrapNodeJSCore (internal/bootstrap/node.js:623:3) npm ERR! code ELIFECYCLE npm ERR! errno 1 npm ERR! theme@3.1.1 dev: `cross-env NODE_ENV=development tailwindcss --postcss -i ./src/styles.css -o ../static/css/dist/styles.css -w` npm ERR! Exit status 1 npm ERR! npm ERR! Failed at the theme@3.1.1 dev script. npm ERR! This is probably not a problem with npm. There is likely additional logging output above. npm ERR! A complete log of this run can be found in: npm ERR! /home/amir/.npm/_logs/2022-02-11T09_27_46_003Z-debug.log npm ERR! code ELIFECYCLE npm ERR! errno 1 npm ERR! theme@3.1.1 start: `npm run dev` npm ERR! Exit status 1 npm ERR! npm ERR! Failed at the theme@3.1.1 start script. I have tried going into "theme/static_src/src" directory and running npm run build-postcss, based on an answer on GitHub … -
How to have a new html file created when a button is clicked?
I'm working on a django project trying to create a forum. Now when a user creates a new thread, I need to have a new html file created with a unique url. For example if a user creates a thread with the title "What's the best programming language?" a new html file with some standard template has to be created (and a function in views.py as well as a path in urls.py) and the url should be something like "mysitetitle.com/what's-the-best-programming-language?". That would be relevant code of my project. views.py def create_thread(request): form = CreateForm() if request.method == "POST": form = CreateForm(request.POST) if form.is_valid(): f = form.save(commit=False) f.benutzername = request.user f.save() messages.success(request, "Thread has been created.") create_thread.html {% extends "forum/index.html" %} {% load static %} {% block title %} Create Thread {% endblock %} {% block content %} <div class="container-create"> <h2 class="heading-create">Diskussion erstellen</h2> {% if messages %} {% for message in messages %} <div class="thread-info">{{ message }}</div> {% endfor %} {% endif %} {% if not user.username %} <div class="guest-login">As <span class="guest">Guest</span> or <a class="login-link" href="../login">Login</a></div> {% endif %} <form method="POST" action=""> {% csrf_token %} <label class="label-create-topic" for="create-topic">Topic</label> {{form.topic}} <label class="label-create-title" for="create-title">Title</label> {{form.title}} <label class="label-create-content" for="create-content">Content</label> {{form.content}} <button class="submit-create" id="submit-create" type="submit" … -
Django how to set a class based view queryset with function return
im trying to make endless pagination with filtered data and im geting the data with get request. views.py: class ProductsView(ListView): paginate_by = 20 context_object_name = 'products' template_name = "urunler.html" def get_context_data(self, **kwargs): context = super().get_context_data(**kwargs) renkler = Renk.objects.all() beden = Varyasyon.objects.all() katagori = Grub.objects.all() order = self.request.GET.get('order') filtered = Stok.objects.all().order_by('-urun_id__kayit_tarihi','foto').distinct('urun_id__kayit_tarihi','foto') checked_var = self.request.GET.getlist('varyasyon_id__in') checked_renk = self.request.GET.getlist('renk_id__in') checked_kat = self.request.GET.getlist('grub_id__in') if self.request.GET.getlist("varyasyon_id__in"): filtered = filtered.filter( Q(varyasyon_id__in = self.request.GET.getlist("varyasyon_id__in")) ) if self.request.GET.getlist("renk_id__in"): filtered = filtered.filter( Q(renk_id__in = self.request.GET.getlist("renk_id__in")) ) if self.request.GET.getlist("grub_id__in"): filtered = filtered.filter( Q(grub_id__in = self.request.GET.getlist("grub_id__in")) ) if order == "date": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) ) elif order == "sale": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) & Q(indirim = True) ) elif order == "tesettur": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) & Q(urun_id__tesettur = True) ) else: filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) ) context = {"renkler":renkler,"bedenler":beden,"katagoriler":katagori,'filtered':filters,'checkedvar':checked_var,'checkedrenk':checked_renk,'checkedkat':checked_kat} self.queryset = context return context queryset = get_context_data() i want to set the queryset from get_context_data's return but it asks for self argument. error TypeError: ProductsView.get_context_data() missing 1 required positional argument: 'self' when i define queryset on the top it says that get_context_data is not defined. -
wagtail multisite problem to access site2.localhost
I'm following enter link description here and try to apply wagtail multisite feature. After setting up multiple page trees and creating the individual Site records, as set up in the tutorial, I try to open the pages but the browser cannot find this page. I can only open the first site home page. The other do exist on my admin surface but not on browser. I tried it with the exact localhost setting as in the tutorial (i.e. site2.localhost...) , with my domaine name (site2.domaine...) and even with cloning the tutorial repository. In all cases, I could only open the original home page but not site2.localhost page. I tried to look for additional reading, but didn't find much. FYI, I didn't make any changes to my middleware and urls.py. Any input as of what I'm doing wrong would be highly apprecaited. -
How to serve media files on Django Production?
I can view and open the media files on my template using {{profile_image.url}} when the Debug = True but cannot access the media file when I set Debug = False. How do I show the media files in production when the user is logged in? I don't want anyone to directly access the files if they get the link. For instance, if a user uploads their profile picture the image gets saved on the media folder and also shown on the template when Debug = True but don't show them on Debug = False. For production, I will be uploading my app to a shared Namecheap hosting. Current code structures are following - Settings.py MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, 'media') and urls.py urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) I am new to Django and any suggestions will be helpful. -
How to Verify OTP with on Same page in Django
I have a page where i want once the user click on verify email the user get and email with otp and there is also an input field from where the user is going to enter the OTP and we can Verify Here what i did when user click on verify email he a ajax request send on the server by which a mail is send to user and then in response server is sending back the opt to client as well which i then store in a variable in the localstorage of javascript But i feel it is not safe a lot Any better way to that -
Django Form DecimalField Min value validation error
I am working on Django form with a Decimal Field, in the form class: I have : field1= forms.DecimalField(required=False, max_digits=3, decimal_places=2, max_value=1.0, min_value=0.1) when I set the value of the field to 0.1 from UI and save, I got error: Ensure this value is greater than or equal to 0.1. enter image description here I've tried many ways to fix it but didn't work. Is it a Django problem? What should I do to fix it.
