Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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django-tailwind, can't start dev server
I've done everything according to the django-tailwind docs, but when I want to start the dev server I get the following error: > theme@3.1.1 start /home/amir/projects/planning-project/src/theme/static_src > npm run dev > theme@3.1.1 dev /home/amir/projects/planning-project/src/theme/static_src > cross-env NODE_ENV=development tailwindcss --postcss -i ./src/styles.css -o ../static/css/dist/styles.css -w /home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:300 throw err; ^ TypeError: Object.fromEntries is not a function at args (/home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:243:47) at Object.<anonymous> (/home/amir/projects/planning-project/src/theme/static_src/node_modules/tailwindcss/lib/cli.js:302:3) at Module._compile (internal/modules/cjs/loader.js:778:30) at Object.Module._extensions..js (internal/modules/cjs/loader.js:789:10) at Module.load (internal/modules/cjs/loader.js:653:32) at tryModuleLoad (internal/modules/cjs/loader.js:593:12) at Function.Module._load (internal/modules/cjs/loader.js:585:3) at Function.Module.runMain (internal/modules/cjs/loader.js:831:12) at startup (internal/bootstrap/node.js:283:19) at bootstrapNodeJSCore (internal/bootstrap/node.js:623:3) npm ERR! code ELIFECYCLE npm ERR! errno 1 npm ERR! theme@3.1.1 dev: `cross-env NODE_ENV=development tailwindcss --postcss -i ./src/styles.css -o ../static/css/dist/styles.css -w` npm ERR! Exit status 1 npm ERR! npm ERR! Failed at the theme@3.1.1 dev script. npm ERR! This is probably not a problem with npm. There is likely additional logging output above. npm ERR! A complete log of this run can be found in: npm ERR! /home/amir/.npm/_logs/2022-02-11T09_27_46_003Z-debug.log npm ERR! code ELIFECYCLE npm ERR! errno 1 npm ERR! theme@3.1.1 start: `npm run dev` npm ERR! Exit status 1 npm ERR! npm ERR! Failed at the theme@3.1.1 start script. I have tried going into "theme/static_src/src" directory and running npm run build-postcss, based on an answer on GitHub … -
How to have a new html file created when a button is clicked?
I'm working on a django project trying to create a forum. Now when a user creates a new thread, I need to have a new html file created with a unique url. For example if a user creates a thread with the title "What's the best programming language?" a new html file with some standard template has to be created (and a function in views.py as well as a path in urls.py) and the url should be something like "mysitetitle.com/what's-the-best-programming-language?". That would be relevant code of my project. views.py def create_thread(request): form = CreateForm() if request.method == "POST": form = CreateForm(request.POST) if form.is_valid(): f = form.save(commit=False) f.benutzername = request.user f.save() messages.success(request, "Thread has been created.") create_thread.html {% extends "forum/index.html" %} {% load static %} {% block title %} Create Thread {% endblock %} {% block content %} <div class="container-create"> <h2 class="heading-create">Diskussion erstellen</h2> {% if messages %} {% for message in messages %} <div class="thread-info">{{ message }}</div> {% endfor %} {% endif %} {% if not user.username %} <div class="guest-login">As <span class="guest">Guest</span> or <a class="login-link" href="../login">Login</a></div> {% endif %} <form method="POST" action=""> {% csrf_token %} <label class="label-create-topic" for="create-topic">Topic</label> {{form.topic}} <label class="label-create-title" for="create-title">Title</label> {{form.title}} <label class="label-create-content" for="create-content">Content</label> {{form.content}} <button class="submit-create" id="submit-create" type="submit" … -
Django how to set a class based view queryset with function return
im trying to make endless pagination with filtered data and im geting the data with get request. views.py: class ProductsView(ListView): paginate_by = 20 context_object_name = 'products' template_name = "urunler.html" def get_context_data(self, **kwargs): context = super().get_context_data(**kwargs) renkler = Renk.objects.all() beden = Varyasyon.objects.all() katagori = Grub.objects.all() order = self.request.GET.get('order') filtered = Stok.objects.all().order_by('-urun_id__kayit_tarihi','foto').distinct('urun_id__kayit_tarihi','foto') checked_var = self.request.GET.getlist('varyasyon_id__in') checked_renk = self.request.GET.getlist('renk_id__in') checked_kat = self.request.GET.getlist('grub_id__in') if self.request.GET.getlist("varyasyon_id__in"): filtered = filtered.filter( Q(varyasyon_id__in = self.request.GET.getlist("varyasyon_id__in")) ) if self.request.GET.getlist("renk_id__in"): filtered = filtered.filter( Q(renk_id__in = self.request.GET.getlist("renk_id__in")) ) if self.request.GET.getlist("grub_id__in"): filtered = filtered.filter( Q(grub_id__in = self.request.GET.getlist("grub_id__in")) ) if order == "date": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) ) elif order == "sale": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) & Q(indirim = True) ) elif order == "tesettur": filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) & Q(urun_id__tesettur = True) ) else: filters = filtered.filter( Q(urun_id__yayin = True) & Q(stok_adet__gt = 0) ) context = {"renkler":renkler,"bedenler":beden,"katagoriler":katagori,'filtered':filters,'checkedvar':checked_var,'checkedrenk':checked_renk,'checkedkat':checked_kat} self.queryset = context return context queryset = get_context_data() i want to set the queryset from get_context_data's return but it asks for self argument. error TypeError: ProductsView.get_context_data() missing 1 required positional argument: 'self' when i define queryset on the top it says that get_context_data is not defined. -
wagtail multisite problem to access site2.localhost
I'm following enter link description here and try to apply wagtail multisite feature. After setting up multiple page trees and creating the individual Site records, as set up in the tutorial, I try to open the pages but the browser cannot find this page. I can only open the first site home page. The other do exist on my admin surface but not on browser. I tried it with the exact localhost setting as in the tutorial (i.e. site2.localhost...) , with my domaine name (site2.domaine...) and even with cloning the tutorial repository. In all cases, I could only open the original home page but not site2.localhost page. I tried to look for additional reading, but didn't find much. FYI, I didn't make any changes to my middleware and urls.py. Any input as of what I'm doing wrong would be highly apprecaited. -
How to serve media files on Django Production?
I can view and open the media files on my template using {{profile_image.url}} when the Debug = True but cannot access the media file when I set Debug = False. How do I show the media files in production when the user is logged in? I don't want anyone to directly access the files if they get the link. For instance, if a user uploads their profile picture the image gets saved on the media folder and also shown on the template when Debug = True but don't show them on Debug = False. For production, I will be uploading my app to a shared Namecheap hosting. Current code structures are following - Settings.py MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, 'media') and urls.py urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) I am new to Django and any suggestions will be helpful. -
How to Verify OTP with on Same page in Django
I have a page where i want once the user click on verify email the user get and email with otp and there is also an input field from where the user is going to enter the OTP and we can Verify Here what i did when user click on verify email he a ajax request send on the server by which a mail is send to user and then in response server is sending back the opt to client as well which i then store in a variable in the localstorage of javascript But i feel it is not safe a lot Any better way to that -
Django Form DecimalField Min value validation error
I am working on Django form with a Decimal Field, in the form class: I have : field1= forms.DecimalField(required=False, max_digits=3, decimal_places=2, max_value=1.0, min_value=0.1) when I set the value of the field to 0.1 from UI and save, I got error: Ensure this value is greater than or equal to 0.1. enter image description here I've tried many ways to fix it but didn't work. Is it a Django problem? What should I do to fix it. -
What changes to do to get more objects instead of one?
I am doing a project for my college work. In that, I need to change a function. That function is giving error saying multiple objects returned. The function works well if there is only one object to return. But I need to change it to return it to return all the objects. So what changes do I need to do. I am attaching the function code. Pls provide the code to modify also. I am just beginner in coding. Thanks I am using Pycharm, Django and. MySQL to do my project def vpay(request) : b=request.session['uid'] ob=TurfManager.objects.get(t_id=b) bb=ob.tf_id obj=Booking.objects.get(tf_id=bb) nn=obj.b_id o = Payment.objects.filter(book_id=nn) context = { 'obval': o, } -
How do I display my database models as a table form Django
from email.policy import default from django.db import models import uuid # Create your models here. class Brazzaville(models.Model): city = models.CharField(max_length=100) twenty = models.CharField(max_length=100) fifty = models.CharField(max_length=100) hundred = models.CharField(max_length=100) id = models.UUIDField(default=uuid.uuid4, editable=False, primary_key= True, unique= True) def __str__(self): return self.city,self.twenty,self.fifty,self.hundred ``` from django.shortcuts import render from django.http import HttpResponse # Create your views here. from .models import Brazzaville def services(request): brazzaville = Brazzaville.objects.all() tb = {'brazzaville':brazzaville} return render(request, 'expresscargo/services.html',tb ) <br/> {% extends 'index.html' %} {% block content %} {% for city in brazzaville %} {{city.city}} {% endfor %} {% for city in brazzaville %} {{city.twenty}} {% endfor %} -
Self-incrementing primary keys, values that follow or not. Foreign key bindings (django)
Salvation, I am making a classic bdd and I had a doubt expressed by another dev: To put it simply, I have 2 tables (with very very few updates), one of which has an FK (foreign key) on the other. There is an autoincrement on the PK (primary key). With Django I make fixtures (basic filling) to fill these 2 tables and I put the following PK values: id | codes | name | zone_id 1 | 13 | bla1 | 1 2 | 84 | bla2 | 2 3 | 06 | bla3 | 4 Simple, basic. But this colleague changed my fixtures because it's "better", maybe for convenience: id | codes | name | zone_id 13 | 13 | bla1 | 1 84 | 84 | bla2 | 2 6 | 06 | bla3 | 4 As a result, the values of the PK no longer follow each other. Is this correct?, or should the auto-increment be removed?. For me it's completely absurd to have changed that. Thank you F. -
i am passing none value
from django.shortcuts import render from django.db.models import Q from shop.models import Product def search(request): products=None query=None if 'q' in request.GET: query1=request.GET.get('q') products=Product.objects.all().filter(Q(name__contains=query) | Q(description__contains=query)) return render(request,'search.html',{'query':query,'products':products}) this is my code i always get a none value for products and query -
Sending an email with attach file and render it in HTML on Django 4
I make a website on django 4, and i have a form with many inputs. I want to send an email in HTML format and attach at my mail the file "a photo". I have make the code and i have read many subjects on stackoverflow with no success. This is my forms.py: class FantasyForm(forms.Form): madame = forms.CharField(label="Madame", help_text="", widget=forms.TextInput(attrs={'class': 'form-control', 'placeholder':'Madame *'})) monsieur = forms.CharField(required = False, label="Monsieur", help_text="", widget=forms.TextInput(attrs={'class': 'form-control', 'placeholder':'Monsieur'})) age = forms.ChoiceField(required = True, choices=YEAR_CHOICES, widget=forms.RadioSelect()) photo = forms.ImageField(required = True, label="Une photo ?", widget=forms.FileInput()) site_q = forms.ChoiceField(required = True, label="As tu un pseudo sur un site de rencontre ?",choices=SITE_CHOICES, widget=forms.RadioSelect()) site_c = forms.ChoiceField(required = False, label="Sur lesquels ?",choices=SITE2_CHOICES, widget=forms.CheckboxSelectMultiple()) site_pseudo = forms.CharField(required = False, label="Votre pseudo", help_text="", widget=forms.TextInput()) rech_tu = forms.ChoiceField(required = True, label="Que recherche tu ?",choices=RECHTU_CHOICES, widget=forms.CheckboxSelectMultiple()) content = forms.CharField(label="Parle nous de ton fantasme (1000 caracteres maxi)", help_text="", widget=forms.Textarea()) when = forms.DateTimeField(label="Quand ça ?") phone = forms.CharField(label="Téléphone", help_text="", widget=forms.TextInput()) email = forms.CharField(required = False, label="Email", help_text="", widget=forms.TextInput()) class Meta: fields = ('madame', 'monsieur','age','photo','site_q','site_c','site_pseudo','rech_tu','content','when','phone','email') And this is my views.py: def page_fantasme(request): if request.method == "POST": form = FantasyForm(request.POST,request.FILES) if form.is_valid(): madame = request.POST.get('madame', '') monsieur = request.POST.get('monsieur', '') age = request.POST.get('age', '') photo = request.FILES.get('photo', … -
Django forms: dynamic adding new input fields due to already entered data
I'm new in django. I have created a simple model and now my goal is to build form where i would like to input information about particular objects. In these example i have model which contains two types totally different products. Common are only name and color. Is there any way in django to display form that includes only common fields. In this example name ,products and category and after choosing category display furthere fields that suit to chosen category? In my example I would like extend my form witch size and shape if hat is chosen and model and age if car is setted model.py class Products (models.Model): products=(('1','hats'),('2','car')) name=models.CharField( max_length=30) category=models.TextField(choices=products,blank=True, null=True) color = models.CharField(max_length=40, blank=True, null=True, default='') model=models.CharField(max_length=40, blank=True, null=True, default='') age=models.CharField(max_length=40, blank=True, null=True, default='') size = models.CharField(max_length=40, blank=True, null=True, default='') shape= models.CharField(max_length=40, blank=True, null=True, default='') forms.py class ProductsForm (ModelForm): class Meta: model = Products fields = ['name','category', 'color', 'model','shape','size'] -
How to resolve environment error while upgrading django version
I got the following error while upgrading the django version=2.2.12 I tried the following command for upgrading django: enter code here:python3 -m pip install -U Django I got the below error Collecting Django Using cached Django-4.0.2-py3-none-any.whl (8.0 MB) Requirement already satisfied, skipping upgrade: asgiref<4,>=3.4.1 in ./.local/lib/python3.8/site-packages (from Django) (3.5.0) Requirement already satisfied, skipping upgrade: backports.zoneinfo; python_version < "3.9" in ./.local/lib/python3.8/site-packages (from Django) (0.2.1) Requirement already satisfied, skipping upgrade: sqlparse>=0.2.2 in ./.local/lib/python3.8/site-packages (from Django) (0.4.2) Installing collected packages: Django ERROR: Could not install packages due to an EnvironmentError: [Errno 20] Not a directory: '/home/vamsi/.local/lib/python3.8/site-packages/django/core/management/templates.py I tried the another code : enter code : sudo pip install --upgrade django I got: Requirement already up-to-date: django in /usr/local/lib/python3.8/dist-packages (4.0.2) Requirement already satisfied, skipping upgrade: sqlparse>=0.2.2 in /usr/lib/python3/dist-packages (from django) (0.2.4) Requirement already satisfied, skipping upgrade: asgiref<4,>=3.4.1 in /usr/local/lib/python3.8/dist-packages (from django) (3.5.0) Requirement already satisfied, skipping upgrade: backports.zoneinfo; python_version < "3.9" in /usr/local/lib/python3.8/dist-packages (from django) (0.2.1) But when i checked the version using command:python3 -m django --version I got the previous version:2.2.12 So how can i resolve this .Is there any way to upgrade the django version ??. I saw lot of issues in online but i cant find anyone -
Django wont display my comments on template
I've tried to implement the comments within the html page after creating them in my models and I have migrated them but they still wont appear within the page although when I add a comment from the admin side of the website the add comment button I added in before the else statement in the html disappears, which means that it isn't empty but the comments still wont show? Models.py class Photo(models.Model): category=models.ForeignKey(Category,on_delete=models.SET_NULL,null=TRUE,blank=TRUE) image=models.ImageField(null=False,blank=False) description= models.TextField() def __str__(self): return self.description class Comment(models.Model): user = models.ForeignKey(UserProfile, related_name="profile", on_delete=models.CASCADE) photo = models.ForeignKey(Photo, related_name="comments", on_delete=models.CASCADE) text = models.TextField() date = models.DateTimeField(auto_now_add=True) def __str__(self): return self.user.user.username + ': ' + self.text and then here is the Html portion <!DOCTYPE html> <html> <head> <meta charset='utf-8'> <meta http-equiv='X-UA-Compatible" content="IE-edge'> <title>Photo</title> <meta name='viewport' content='width-device-width, initial-scale=1'> <link href="https://cdn.jsdelivr.net/npm/bootstrap@5.1.3/dist/css/bootstrap.min.css" rel="stylesheet" integrity="sha384- 1BmE4kWBq78iYhFldvKuhfTAU6auU8tT94WrHftjDbrCEXSU1oBoqyl2QvZ6jIW3" crossorigin="anonymous"> </head> <body class="m-5"> <div class="container"> <div class="row justify-content-center"> <div class="col"> <a href="{% url 'Clinician' %}" class="btn btn-dark my-3">Go Back</a> <div style="height: 90vh;"> <img style="max-width: 100%; max-height: 100%;" src="{{photo.image.url}}"> <p> {{photo.description}} </p> <h4>Comments...</h4> {% if not photo.comments.all %} No Comments Yet...<a href="#"> add one </a> {% else %} {% for comment in photo.comment.all %} <strong> {{ comment.date }} </strong> <br/> {{ comment.text }} {% endfor %} {% … -
How to deploy dockerised react + django web app to google app engine?
I have created a web app which uses react as frontend and django as backend. I have also added nginx proxy to my both backend and frontend. I use docker compose to build and start all of my containers and everything works perfectly. Now i want to deploy it to google app engine and I have no idea how to do that. I found this well written article, but it uses aws. I want to use app engine because its free (for now). It would be really helpful if someone could guide me through this. -
Find difference between two time for verification token in Django
I am creating an app in Django where I have to send a token to a user but I want to make it expire after 5 minutes, now the issue I am getting time from django field in this format token_time = Token.objects.filter(user_id=user_id).last().user_token_timestamp current time = datetime.now().time() is there any way to find the time difference in minutes in pythonic way, although I have done by converting the time into string and then striping it but it just feels like not a good way. -
My django models are returning serialised data in json format for my view but i also want a string representation for my admin. How do i do that
class PerfumesImages(models.Model): entry = models.ForeignKey(Perfumes, default=None, on_delete=models.CASCADE, related_name="perfumesphoto") images = models.ImageField(upload_to='Perfumes', verbose_name='Image') def serialize(self): return { "id": self.id, "entry": {"entryid" : self.entry.id, "brandsection" : self.entry.brandsection, "brand" : self.entry.brand, "price" : self.entry.price, "color" : self.entry.color,"description" : self.entry.description}, "images": self.images.url } -
Django 4. Invalid block tag on line 45: 'item.title', expected 'empty' or 'endfor'. Did you forget to register or load this tag?
I work on Django 4 I am trying to create a view that will load a template view in django and I am getting the above error. Request Method: GET Request URL: http://127.0.0.1:8000/ Django Version: 4.0.2 Exception Type: TemplateSyntaxError Exception Value: Invalid block tag on line 45: 'item.title', expected 'empty' or 'endfor'. Did you forget to register or load this tag? Exception Location: C:\Users\zinnurov.ramil\PycharmProjects\django_full_guide\venv\lib\site-packages\django\template\base.py, line 552, in invalid_block_tag Python Executable: C:\Users\zinnurov.ramil\PycharmProjects\django_full_guide\venv\Scripts\python.exe Python Version: 3.9.4 views.py def index(request): template_name = 'news/index.html' news = News.objects.order_by('-created_at') categories = Category.objects.all() context = { 'title': 'Список новостей', 'news': news, 'categories': categories, } return render(request, template_name, context) model.py class Category(models.Model): title = models.CharField(max_length=200, db_index=True, verbose_name='Категории') class Meta: verbose_name = 'Категория' verbose_name_plural = 'Категории' ordering = ['-title'] def __str__(self): return self.title <div class="col-md-4"> <div class="list-group"> {% for cat in categories %} {% item.title %} {% endfor %} </div> </div> enter image description here Have you got an idea ? -
Is there a way to pass options values during mod_wsgi server start up in Django app
I am using mod_wsgi to run my Django app. As there are a plethora of options to define when the server run command is fired, I was trying to create some kind of python script to pass the options and their pre-set values. For example: Instead of using: $python3 manage.py runmodwsgi --processes 3 --threads 1 I am trying to use a python script and use it as: $python3 runme.py where runme.py is the script file I am trying to use to start the server. What I have done so far? Created the script file: import os from django.core.management import execute_from_command_line os.environ.setdefault('DJANGO_SETTINGS_MODULE', '<proj>.settings') myargs = 'runmodwsgi' list_of_args = ['', myargs] execute_from_command_line(list_of_args) As expected the server started with preset options, for example: Now what I am trying to achieve is the pass values of certain options like: --processes 3 --threads 1 and so on. Is there a way I may pass the preset values (as I may be able to define in my script file runme.py), say something like adding to the list of arguments: list_of_args = ['', myargs, addl_args] I have been checking SO queries posted in addition to help available on python site, but could not get my head around … -
Need to execute my SQL queries in my model to display the result as API in django
Model class Consolidated(models.Model): emp_name=models.ForeignKey(Users,on_delete=CASCADE) proj_name=models.ForeignKey(Project, on_delete=CASCADE) custom_name=models.ForeignKey(Client,on_delete=CASCADE) Cons_date=models.ForeignKey(Add_Timelog, on_delete=CASCADE) bill_no_bill=models.ForeignKey(Users,related_name="billable_and_non_billable+", on_delete=CASCADE) hour_spent = models.ForeignKey(Add_Timelog,related_name="hour_spent", on_delete=CASCADE) def __str__(self): return str(self.emp_name) viewset permission_classes=(permissions.IsAdminUser,) queryset = models.Consolidated.objects.raw("select public.App_add_job.id, employee_name, billable_and_non_billable, client_id, project_id from public.App_add_job join public.App_users on public.App_add_job.employee_name_id = public.App_users.id") serializer_class=serializers.Consolidated_serializers I have a sql query updated in my viewset and i dont know how to run that query in my API model to display the table values in the api. kindly help me to change the code for the model to execute the sql queries in that Consolidated model. -
Reportlab pyhton alignment issue
Style3 = TableStyle([('VALIGN',(0,0),(-1,-1),'TOP'), ('ALIGN',(0,0),(-1,-1),'RIGHT'), ('LEFTPADDING',(0,0),(-1,-1), 130), ('RIGHTPADDING',(0,0),(-1,-1), 0), ('TOPPADDING',(0,0),(-1,-1), 0), ]) I want response and categories label in starting but it show at the end of line, i want response and categories in from starting not end of line.. any special styling i need. -
How to count foreign key objects with annotation in Django?
Hi all! New in Django, and confused, help is appreciated! Have three models: class Organization(models.Model): organization_name = models.CharField(max_length=50) class AppealForm(models.Model): form_name = models.CharField(max_length=50) class Appeal(models.Model): organization = models.ForeignKey(Organization, on_delete=models.CASCADE) appeal_form = models.ForeignKey(AppealForm, on_delete=models.CASCADE) applicant_name = models.CharField(max_length=150) Objects of Organization model: organization_name Organization 1 Organization 2 Objects of AppealForm model: form_name In written form In oral form Objects of Appeal model: organization appeal_form applicant_name Organization 1 In written form First and Last name Organization 1 In oral form First and Last name Organization 1 In oral form First and Last name Organization 2 In written form First and Last name Organization 2 In oral form First and Last name I'm trying to create a table in the template, like: Organization Total amount of appeals Amount of written form appeals Amount of oral form appeals Organization 1 3 1 2 Organization 2 2 1 1 The content in the table contents has to be retrieved from Appeal model, that is rendered to the template. Question: How the query look like in views.py using Appeal model? -
Django SMTP email does not send any emails and shows SMTPAuthenticationError as a response
I used windows(10) IIS server to upload my Django(ver. 3) project. I also added google SMTP mail service to send email. I tested that project locally. At that time all emails sent without any issues. But in my IIS web server, It doesn't send any email. It always shows this error, SMTPAuthenticationError at /send_email (534, b'5.7.14 <https://accounts.google.com/signin/continue?sarp=1&scc=1&plt=AKgnsbu\n5.7.14 TJtoTOBiMuXdqvUyrO5XGEpv5y-vj2Ebs2xhNf_6KSPlcDKxqWeTORJr3MvuzPqEMKvUM\n5.7.14 CuojHIAZKcwqRCyp8b6d7tFFeTM-LfQjq6dQe9rPfHPDS3xrgumMcQCe3PrPIsbm>\n5.7.14 Please log in via your web browser and then try again.\n5.7.14 Learn more at\n5.7.14 https://support.google.com/mail/answer/78754 w9sm9003338ool.31 - gsmtp') Can anyone tell me reason or how to solve this issue? -
Docker-compose + Django on AWS C9
I'm trying to use a docker container to run a django application on the cloud base IDE from AWS (AWS C9). The application is started correctly and the development server is started on http://127.0.0.1:8080/ However when browsing to the public URL of the cloud 9 application I'm getting the error 'no application seems to be running'. When creating a django application without docker, the preview on AWS coud 9 works fine. Are there any addtional settings required to get the cloud 9 preview to work? This is my docker-compose file. services: web: build: . command: python manage.py runserver $IP:$PORT volumes: - .:/code ports: - "8000:8000" environment: - POSTGRES_NAME=postgres - POSTGRES_USER=postgres - POSTGRES_PASSWORD=postgres
