Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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How can I delete all child objects of a parent object without deleting parent object with Django
I have two models that use the same class as foreign key. I don't want to delete the parent model (which is being used as foreign key) but delete the child models that are associated with the parent model. class A(models.Model): pass class B(models.Model): a = models.ForeignKey(A, on_delete=models.CASCADE, default=None) class C(models.Model): a = models.ForeignKey(A, on_delete=models.CASCADE, default=None) Now I am deleting them separately as below : b_list = B.objects.filter(a = A) for b_list_item in b_list: b_list_item.delete() c_list = C.objects.filter(a = A) for c_list_item in c_list: c_list_item.delete() How can I delete them all together with a single command ? -
the short links doesn't redirects to the original link using pyshorteners
I am trying to achieve that the short links redirects to the original link using pyshorteners library. Below i have attached the files to help know. Views.py contains the function from which the individual products and short link being created and rendered to the template. Urls.py shows the url patterns for these functions only. And following Images are showing how it has been working till now. I am not using form to accept any url, instead i am creating short links for every products page and every page has its unique shortlink Please help as I am stuck in this part for a while now. Views.py #Display individual product and render short links for all using pyshorteners def link_view(request, uid): results = AffProduct.objects.get(uid=uid) slink = request.get_full_path() shortener = pyshorteners.Shortener() short_link = shortener.tinyurl.short(slink) return render(request, 'link.html', {"results": results, "short_link": short_link}) Urls.py urlpatterns = [ path('link/', views.link, name='link'), path('link/<int:uid>/', views.link_view, name='link_view') ]+static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) This image is of the HTML template , where both current link and short link has been rendered. This image is when i copy the shortlink and search it on the browser, the host is not been applied to the short link. Hence, the short links are not linking … -
How Django prints SQL statements even when unit testing
You can have Django output SQL statements corresponding to ORM operations during non-unit tests by configuring them as follows. LOGGING = { 'version': 1, 'disable_existing_loggers': False, 'handlers': { 'console':{ 'level':'DEBUG', 'class':'logging.StreamHandler', }, }, 'loggers': { 'django.db.backends': { 'handlers': ['console'], 'propagate': True, 'level': 'DEBUG', }, } } But the above configuration does not print SQL when it comes to unit tests, what should I do to output SQL statements corresponding to ORM operations in unit tests? Translated with www.DeepL.com/Translator (free version) -
Django POST or GET
I have a page for teachers to input the marks and registration number of the students.. After input, it gets stored in the database and the students can fill a form which asks for D.O.B and registration number and get's the marks based on that particular registration from the database.. But when I use post request for the students, it shows form is invalid and says that, the registration number already exists.. My views.py: from django.shortcuts import render from django.views.generic.list import ListView from django.views.generic.edit import CreateView from django.urls import reverse_lazy from .models import Mark from django.contrib.auth.views import LoginView from django.contrib.auth.mixins import LoginRequiredMixin from django.views.generic.edit import FormView from .forms import ViewResultForm, AddResultForm from django.contrib import messages class ViewResultFormView(FormView): template_name = 'main/home.html' form_class = ViewResultForm success_url= 'result' def form_valid(self, form): global registration_number global dob registration_number = form.cleaned_data['registration_number'] dob = form.cleaned_data['dob'] return super(ViewResultFormView, self).form_valid(form) class MarkListView(ListView): model = Mark template_name = "main/result.html" context_object_name = 'result' def get_context_data(self, **kwargs): context = super().get_context_data(**kwargs) context['result'] = context['result'].get(registration_number=registration_number, dob=dob) return context class MarkCreateView(LoginRequiredMixin, CreateView): model = Mark template_name = "main/add.html" form_class = AddResultForm def form_valid(self, form): total_10th = ((form.cleaned_data['class_10_sub_1'] + form.cleaned_data['class_10_sub_2'] + form.cleaned_data['class_10_sub_3'])/300)*30 total_11th = ((form.cleaned_data['class_11_English'] + form.cleaned_data['class_11_Maths'] +form.cleaned_data['class_11_Physics'] +form.cleaned_data['class_11_Chemistry'] +form.cleaned_data['class_11_Comp_Bio'])/500) * 30 total_12th = ((form.cleaned_data['class_12_English'] + … -
How to convert django complete app to an iOS app
I already see this link and some how I understand how to setup my project backend with REST api and restive data from my django and I find out I have to use react for my front end (please current me if I’m wrong) then I wonder how can I transfer my layout in HTML and is of my website to order to make it work in iOS The website I made is a social network and base on user make question and answer and upload it to a server after upload it’s work like a flash card, front side is question and when user click on image your text will flip and show the answer behinds well please tell should I make all of my HTML and is again or I can use those code I have no idea about how its can work Please kindly just tell what material should I study to deploy my django project to iOS app and android as well Please tell me the fastest and easiest way Until now I find out I should use REST API and what else should I do to make my app work with lowest code writing as … -
Django changing uploaded image path
I am uploading images with labels and saving them in folders according to their labels. I have a function to change the labels of the image. after which I can move the images from the old label folder to the new one. But How do I change the path of the image in the database? Because class-based list view is still looking for images at old path(updated while uploading) I tried doing d.image.url = 'new_path' but it didnt work: AttributeError: can't set attribute. Is there any other way to update the URL/path in the database. -
How to check whether the checkbox is checked in Django?
I have a Task class which contains a boolean attribute called 'complete', which stores the information wheter a task is completed or not. Now in my task list, I would like to have a checkbox to change the Task.complete to True if checkbox is checked. <div class="task-list-wrapper"> {% for task in task_list %} <div class="task-wrapper"> {% if task.complete %} <div class="task-title"> <div class="task-complete-icon"></div> <i><s><a href="{% url 'task-update' task.id %}">{{task}}</a></s></i> </div> <a class="delete-link" href="{% url 'task-delete' task.id %}">&#128465</a> {% else %} <div class="task-title"> <div class="task-incomplete-icon"></div> <a href="{% url 'task-update' task.id %}">{{task}}</a> </div> <a class="delete-link" href="{% url 'task-delete' task.id %}">&#128465</a> {% endif %} </div> {% empty %} <h3>No items in list</h3> {% endfor %} </div> Assuming that each 'task' in 'task_list' will have own <input type="checkbox" name="task-status" value="Mark as complete"> how do I assign the task.complete = True? -
Django saving overriden user fails when ModelForm.save is done running
Context I override AbstractBaseUser in order to provide it with extra fields I needed. I can create a User no problem, and I can use my User objects to connect to my app. My issue starts when I try to modify an existing user from the admin view. In my admin view for the User model, I show an inline for a Permission model related to my users and I use an override of ModelForm specific to my Model. Here is its code : from django.contrib.auth import get_user_model class CustomUserAdminForm(forms.ModelForm): """ Comment """ class Meta: model = User fields = [ "email", "password", "is_admin" ] def save(self, commit=True): """ Save override. """ # Raise in case of errors. if self.errors: raise ValueError( "The %s could not be %s because the data didn't validate." % ( self.instance._meta.object_name, "created" if self.instance._state.adding else "changed", ) ) # Get custom User model. my_user_model = get_user_model() # Find user if the object exists. try: self.instance = my_user_model.objects.get(email=self.cleaned_data["email"]) except my_user_model.DoesNotExist: self.instance = my_user_model() self.instance.email = self.cleaned_data["email"] self.instance.is_admin = self.cleaned_data["is_admin"] # Saving the hash of the password. if not self.cleaned_data["password"].startswith("pbkdf2_sha256$"): self.instance.set_password(self.cleaned_data["password"]) if commit: # Copied from BaseModelForm. # https://github.com/django/django/blob/master/django/forms/models.py # If committing, save the instance and the … -
In Django, how to make files downloadable for production environment?
I've been working on a Django project, in which I would take in user files and encrypt/decrypt the file as the output. Hence, I'd also provided the option to download the encrypted/decrypted file. This all in the local server by adding static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) in the application's urls.py Now, I would like to publish the website. In fact, I'd configured the Heroku settings as well. But the problem is - it is not wise to use serve media in a production environment. And I can't figure out how to design a download function for the files on the production website. Below is the download.html template (Which displays the download link for the local server) {% if var.function == 'ENCRYPT' %} <a href="{{ var.encryptedfile.url }}" class="btn btn-success">Download</a> {% else %} <a href="{{ var.decryptedfile.url }}" class="btn btn-success">Download</a> {% endif %} Here, var is the queryset object, retrieved from the database. Application-level urls.py urlpatterns = [ path('', MainpageView.as_view(), name='home'), path('download/', DownloadpageView.as_view(), name='download'), ] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) I cannot understand that how to modify the views.py or urls.py or download.py so that the files can be downloaded from the published website? Many Thanks! -
Poting a working Django project to Passenger
I developed my Django project and its applications using PyDev, it works well with the integrated server and also published on a local server running Apache and Django. Now I want to move/port the project and its applications to a shared web server (on ifastnet.com) running Passenger. The main difference I see, it is the passenger_wsgi.py file. I changed it to run my applications but it does not work also giving no so much information about errors. I suppose many others had this problem so I want to learn how to solve it. Thanks, Massimo -
Better way to save data in database using django serializer
Hello I am working on a project in which I'm making serializers. Right now the way I'm saving the information is as follows models.py class Services(models.Model): business = models.ForeignKey(Business, on_delete=models.CASCADE) service = models.CharField(max_length=30, blank=True) serializers.py class ServiceSerializer(serializers.ModelSerializer): class Meta: model = Services fields = ('id', 'business', 'service') views.py class ServiceAPIView(APIView): permission_classes = [IsAuthenticated] def post(self, request): data = request.data business = Business.objects.get(user=request.user) data['business'] = business.pk serializer = BusinessSerializer(data=data) if serializer.is_valid(): serializer.save() return Response(serializer.data, status=status.HTTP_200_OK) return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST) urls.py urlpatterns = [ path('business/', BusinessAPIView.as_view()), ] and I send post requests using postman. This is working fine but this is a very small part of the application and the code will grow to be very large. If there is a better way of doing this in which I write smaller code then I would like to employ that. -
Assign pk form URL to model's related field
I would like to use the "nested" url /customers/<id>/orders for creating new orders and I would like to get the order's customer_id based on the request's url <id>. Of course, Order model has a customer = ForgeinKey(Customer,..) field that relates to the Customer model. My approach so far is creating an OrderSerializer and tampering with the self.context['request'] class in order to get the url and the customer's pk. However that does not work for me so far. Any suggestions? Thanks! -
How to pass request in forms.BooleanField to get the data from database in Django?
I'm using forms.BooleanField for checkbox filtering. I got stuck on getting the data from the database. Meaning: If the user clicks on the SAMSUNG product the data should filter all the SAMSUNG products. well, I have tried to get the brand list from the database and it is doing well but when I click on a specific brand it does not filter a specific brand. (rather it just refresh and show the same data) Code goes here: forms.py class BrandForm(forms.Form): def __init__(self, *args, **kwargs): super().__init__(*args, **kwargs) brands = Product.objects.filter(category=1).values_list('brand', flat=True) for brand in brands: self.fields[f'{brand}'] = forms.BooleanField(label=f'{brand}', required=False) views.py def product(request): product = Product.objects.all().order_by('-id') formBrand = BrandForm() return render(request, 'list/product.html', {'product': product, 'formBrand':formBrand} ) index.html <form action="{% url 'main:productdata' %}" method="get"> {{ formBrand.as_p }} <input type="submit" value="OK"> </form> What all the code should be implemented? -
how to fix SystemCheckError
Hi while I was adding a dislike button to my blog I encountered a SystemCheckError. How do I fix it. I hope someone can help me. Traceback: SystemCheckError: System check identified some issues: ERRORS: myblog.Post.dislike: (fields.E304) Reverse accessor for 'myblog.Post.dislike' clashes with reverse accessor for 'myblog.Post.likes'. HINT: Add or change a related_name argument to the definition for 'myblog.Post.dislike' or 'myblog.Post.likes'. myblog.Post.dislike: (fields.E305) Reverse query name for 'myblog.Post.dislike' clashes with reverse query name for 'myblog.Post.likes'. HINT: Add or change a related_name argument to the definition for 'myblog.Post.dislike' or 'myblog.Post.likes'. myblog.Post.likes: (fields.E304) Reverse accessor for 'myblog.Post.likes' clashes with reverse accessor for 'myblog.Post.dislike'. HINT: Add or change a related_name argument to the definition for 'myblog.Post.likes' or 'myblog.Post.dislike'. myblog.Post.likes: (fields.E305) Reverse query name for 'myblog.Post.likes' clashes with reverse query name for 'myblog.Post.dislike'. HINT: Add or change a related_name argument to the definition for 'myblog.Post.likes' or 'myblog.Post.dislike'. WARNINGS: myblog.Category: (models.W042) Auto-created primary key used when not defining a primary key type, by default 'django.db.models.AutoField'. HINT: Configure the DEFAULT_AUTO_FIELD setting or the MyblogConfig.default_auto_field attribute to point to a subclass of AutoField, e.g. 'django.db.models.BigAutoField'. myblog.Post: (models.W042) Auto-created primary key used when not defining a primary key type, by default 'django.db.models.AutoField'. HINT: Configure the DEFAULT_AUTO_FIELD setting or the … -
Can a django model have a hardcoded no type field?
Basically my question stems from the need to create multiple models that branch off a main base class. Each of these models have a type, and I wish to keep this type on the model in the database, but I want to room for error so I thought of hardcoding it into the model. This is pretty much a question of "Is this something that django supports?". I haven't fully tested this, I don't know / can't say that if I did this right now everything would be fine or not ... but I can't seem to find the relevant documentation for it and would like to learn the best practices. Here is an example of what I mean: from django.db import models from enum import Enum class PersonType(Enum): STUDENT = "Student" TEACHER = "Teacher" class BaseClass(models.Model): """Represents a base model""" name = models.TextField() age = models.IntegerField() class Student(BaseClass): """Represents a student""" type = PersonType.STUDENT.value class Teacher(BaseClass): """Represents a teacher""" type = PersonType.TEACHER.value Would something like this be accepted by django? The only other solution I can think of is to make type a TextField with the default property set, and never expose it via the serializer. There is no … -
Is it possible to use Django Channels to refresh a page when an async task is done?
I already use Django Channels with Django Signals for real time updates. But the information that I update are strings, numbers, not a template. Is it possible to use Django Channels to refresh a page (or load a specific template) when an async task is done? If so, how? Many thanks in advance for your help. -
django 2.2 celery 5.1 cannot start worker
I am trying celery 5 with Django 2.2 on Ubuntu 20.04 I am getting this problem when I run my code from __future__ import absolute_import, unicode_literals from loguru import logger from celery.decorators import task import time @task(bind=True,name="mein_test_task") def mein_test_task(request): try: logger.info('Hier startet mein erstes Celery Task') time.sleep(5) logger.info('Habe fertig geschlafen') result = 'Good Response:mein_test_task()' logger.info(result) except Exception: logger.error("Bad response: Celery Task: mein_test_task()") result = 'Bad Response:mein_test_task()' logger.error(result) return result [2021-06-23 10:45:45,606: INFO/MainProcess] w1@ubuntu-s-1vcpu-1gb-fra1-01 ready. [2021-06-23 10:45:45,606: ERROR/MainProcess] Process 'ForkPoolWorker-1' pid:44613 exited with 'exitcode 1' [2021-06-23 10:45:45,627: CRITICAL/MainProcess] Unrecoverable error: WorkerLostError('Could not start worker processes') Traceback (most recent call last): File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/worker/worker.py", line 203, in start self.blueprint.start(self) File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/bootsteps.py", line 116, in start step.start(parent) File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/bootsteps.py", line 365, in start return self.obj.start() File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/worker/consumer/consumer.py", line 326, in start blueprint.start(self) File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/bootsteps.py", line 116, in start step.start(parent) File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/worker/consumer/consumer.py", line 618, in start c.loop(*c.loop_args()) File "/home/abdullah/wienwohnung/myvenv/lib/python3.8/site-packages/celery/worker/loops.py", line 57, in asynloop raise WorkerLostError('Could not start worker processes') billiard.exceptions.WorkerLostError: Could not start worker processes -
Add double quotes to string in django template
I want to convert something like that id,name to something like that "id","name" in django template. I looked at django template built in tags but none of them works. Does anyone have an idea to achieve it? -
Display the form on multiple screens
I have a simple form that allows me to create an event. forms.py: from django import forms from bootstrap_datepicker_plus.widgets import DatePickerInput from .models import Event class EventForm(forms.ModelForm): class Meta: model = Event fields = [ 'first_name', 'last_name', "start_date", "end_date", ] widgets = { "start_date": DatePickerInput(options={"format": "MM/DD/YYYY"}).start_of("event active days"), "end_date": DatePickerInput(options={"format": "MM/DD/YYYY"}).end_of("event active days"), } models.py: from django.db import models class Event(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) start_date = models.DateField() end_date = models.DateField() views.py: from django.http import HttpResponseRedirect from django.views.generic.edit import FormView from .forms import EventForm from .models import Event class BsFormView(FormView): template_name = "myapp/bs-form.html" form_class = EventForm def form_valid(self, form): if form.is_valid(): first_name = form.cleaned_data["first_name"] last_name = form.cleaned_data["last_name"] start_date = form.cleaned_data["start_date"] end_date = form.cleaned_data["end_date"] event = Event( first_name=first_name, last_name=last_name, start_date=start_date, end_date=end_date, ) event.save() return HttpResponseRedirect(self.request.META.get("HTTP_REFERER")) I want to split it so that the user can enter first and last name(step 1), click Next, and enter the date(step 2). Here is an example of the form I have described. What methods do I need to use to implement such a form in Django? -
Django Rest API & React error: Method "POST" not allowed
I was wondering if anyone can help, I am creating a rest framework with django and react. The problem is when I go to create a new product i get the following error: Method "POST" not allowed. in my product_views.py I have the following: @api_view(['POST']) @permission_classes([IsAdminUser]) def createProduct(request): user = request.user product = Product.objects.create( user=user, name='Sample Name', price=0, brand='Sample Brand', countInStock=0, category='Sample Category', description='' ) In my product_urls.py I have the following: from django.urls import path from base.views import product_views as views urlpatterns = [ path('', views.getProducts, name="products"), path('<str:pk>/', views.getProduct, name="product"), path('create/', views.createProduct, name="product-create"), path('update/<str:pk>/', views.updateProduct, name="product-update"), path('delete/<str:pk>/', views.deleteProduct, name="product-delete"), ] My settings.py is set to JWT (simple): REST_FRAMEWORK = { 'DEFAULT_AUTHENTICATION_CLASSES': ( 'rest_framework_simplejwt.authentication.JWTAuthentication', ) } from datetime import timedelta SIMPLE_JWT = { 'ACCESS_TOKEN_LIFETIME': timedelta(days=30), 'REFRESH_TOKEN_LIFETIME': timedelta(days=1), 'ROTATE_REFRESH_TOKENS': False, 'BLACKLIST_AFTER_ROTATION': True, 'UPDATE_LAST_LOGIN': False, 'ALGORITHM': 'HS256', 'VERIFYING_KEY': None, 'AUDIENCE': None, 'ISSUER': None, 'AUTH_HEADER_TYPES': ('Bearer',), 'AUTH_HEADER_NAME': 'HTTP_AUTHORIZATION', 'USER_ID_FIELD': 'id', 'USER_ID_CLAIM': 'user_id', 'USER_AUTHENTICATION_RULE': 'rest_framework_simplejwt.authentication.default_user_authentication_rule', 'AUTH_TOKEN_CLASSES': ('rest_framework_simplejwt.tokens.AccessToken',), 'TOKEN_TYPE_CLAIM': 'token_type', 'JTI_CLAIM': 'jti', 'SLIDING_TOKEN_REFRESH_EXP_CLAIM': 'refresh_exp', 'SLIDING_TOKEN_LIFETIME': timedelta(minutes=5), 'SLIDING_TOKEN_REFRESH_LIFETIME': timedelta(days=1), } in my react productListScreen.js I have: import React, { useState, useEffect } from 'react' import { LinkContainer } from 'react-router-bootstrap' import { Table, Button, Row, Col } from 'react-bootstrap' import { useDispatch, useSelector } from 'react-redux' … -
2checkout subscription send UID in webhook of who made the subscription
Hi i am creating a django react website. My website has a service that user needs to subscribe to. Usecase: user logs in user buys subscription from his admin panel my backend adds a month in his subscription my problem is, i managed to make 2checkout hit my backend using a webhook, but how can i know which user bought the subscription? PS : i used 2checkout product link to buy subscription they payment is fully handled by 2checkout, only after payment is successful it hits my backend with webhook. -
Hello I made a Tiktok downloader in Python but the api doesn't work i have 3 api
import requests import json from bs4 import BeautifulSoup def downloader(link): source = "https://freevideosdowloader.tk/services/downloader_api.php" data={"url": link} resp = requests.post(source,data=data, verify=True).text links_list = json.loads(resp)["VideoResult"][0]["VideoUrl"] print(resp) if links_list != '': r = requests.get(links_list, allow_redirects=True) content = r.content print(r) with open('video.mp4', 'wb') as f: *#it is used for writing the file* f.write(content) else: print("Something went wrong") downloader('https://www.tiktok.com/@taras.tolstikov/video/6957277807219068165') So I use apis like https://api.tiktokv.com/aweme/v1/play/?video_id= and also music.ly nut no one works for me -
Unable to install Pip |Python
User@Admins-MacBook-Pro ~ % pip install xq Traceback (most recent call last): File "/usr/local/bin/pip", line 11, in <module> load_entry_point('pip==21.1.2', 'console_scripts', 'pip')() File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources/__init__.py", line 489, in load_entry_point return get_distribution(dist).load_entry_point(group, name) File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources/__init__.py", line 2843, in load_entry_point return ep.load() File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources/__init__.py", line 2434, in load return self.resolve() File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources/__init__.py", line 2440, in resolve module = __import__(self.module_name, fromlist=['__name__'], level=0) File "/Library/Python/2.7/site-packages/pip-21.1.2-py2.7.egg/pip/__init__.py", line 1, in <module> from typing import List, Optional ImportError: No module named typing If you get above error pip install xq .Try with below command : sudo python3 -m pip install --upgrade --force-reinstall pip -
In Python, is there any functionality that checks if sub class has the method defined not super class
Let's say: class Human: def get(): print("OK") class Person(Human): def printw(a, b): print("ayush") x = hasattr(Person, 'get') print(x) Output: True But, I want that if subclass(Person) has a method "get", then only I should get True else not. NOTE: I want to check in run time and superclasses may not be available. -
Deploying heroku host(?) to git not working
I am very new to web development and just started working through this: Django for Beginners However, I am stuck at page 51 -> Deployment. The author is describing how to push the heroku web host to git, which should work like this: (pages) $ git push heroku master output: error: src refspec master does not match any error: failed to push some refs to 'https://git.heroku.com/boiling-caverns-68497.git' I tried going through this thread to find a solution but none of the provided answers made it work. The closest I came to make it work was this: (pages) $ git push heroku main output: Enumerating objects: 29, done. Counting objects: 100% (29/29), done. Delta compression using up to 8 threads Compressing objects: 100% (27/27), done. Writing objects: 100% (29/29), 4.17 KiB | 1.39 MiB/s, done. Total 29 (delta 3), reused 0 (delta 0), pack-reused 0 remote: Compressing source files... done. remote: Building source: remote: remote: -----> Building on the Heroku-20 stack remote: -----> Determining which buildpack to use for this app remote: ! No default language could be detected for this app. remote: HINT: This occurs when Heroku cannot detect the buildpack to use for this application automatically. remote: See https://devcenter.heroku.com/articles/buildpacks remote: …
