Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Concat Nested Dictionary value to string
Would like to convert dictionary_list = { hello_world = { 'Hello': 'World' }, myName = { 'Im': 'Harry' } } to Hello world Im Harry I am looping through the nested dictionary by using the following for loop: for key, value in dictionary_list.items(): Just need to concat value into an empty string. -
Trying to execute django-admin makemessages in windows 10
I´m trying to generate translation file using command django-admin makemessages -l pt-br in Windows 10 but unfortunately the files aren´t generated. Here the steps that I followed: Installed gettext library from mlocati. I also tried several options from django i18n: Make sure you have GNU gettext tools , this process is more manual. As the result when i run django-admin makemessages -l pt-br looks like that Django is executing something but the directory is not generated in the end. Here are some peace of code that I have views.py from django.shortcuts import render from django.utils.translation import gettext as _ def index(request): context = { 'hello': _('Hello!') } return render(request, 'index.html', context) settings.py """ Django settings for translation_example project. Generated by 'django-admin startproject' using Django 3.1.7. For more information on this file, see https://docs.djangoproject.com/en/3.1/topics/settings/ For the full list of settings and their values, see https://docs.djangoproject.com/en/3.1/ref/settings/ """ import os from pathlib import Path # Build paths inside the project like this: BASE_DIR / 'subdir'. BASE_DIR = Path(__file__).resolve().parent.parent # Quick-start development settings - unsuitable for production # See https://docs.djangoproject.com/en/3.1/howto/deployment/checklist/ # SECURITY WARNING: keep the secret key used in production secret! SECRET_KEY = '3^*d$5b7$r2$t-0cxmef22l5_)t^cn9i-xkq48zen$u*67)tvm' # SECURITY WARNING: don't run with debug turned on in … -
Start Django modelformset with values from instances?
This question asks about initializing a Django model formset with instances. The answer is: use the queryset argument. But what if I want a new formset with a copy? That is, all the values of those instances, but not the instances themselves (i.e., they'll be extra and not yet bound). My current solution is to make the call to formset partial (so I can fill in "extra"), and copy over all the values. I don't love this, because if we add fields to Item, then we have to go and add those fields to the copy. Is there a better way? import functools PartialItemFormset = functools.partial( forms.modelformset_factory, Item, formset=BaseItemFormSet, fields=('name', 'description')) EmptyItemFormset = PartialItemFormset(extra=2) the_items = Items.objects.filter(...) copy_formset = PartialItemFormset(extra=len(the_items))( queryset=Item.objects.none(), # TODO: Is there a better way than copying all the fields? initial=[{'name': item.name, 'description': item.description} for item in the_items]) -
forms in Django does not register the data in the database
I'm stuck I try a lot of things to make it work, but always the same problem the form dose note save the data at all and the any error that I get is the message error (what I writ in the message) all i get is a change in the url like this http://127.0.0.1:8000/appointement/create_appointement_2?patient=patient+12&initial-patient=patient+12&doctor=2&date=2021-04-02&start_time=16%3A30 is there anything that can show me the error or if anyone have this problem be for a few hits will be awesome? this is my models .py class Appointment(models.Model): user_ho_add = models.ForeignKey(User, on_delete=models.CASCADE, related_name='user_ho_add_appointment') patient = models.CharField(null=True,max_length = 200, default=defaultTitle) doctor = models.ForeignKey(User, on_delete=models.CASCADE, related_name='doctor_app') date = models.DateField(null=False, blank=False, default=timezone.now) start_time = models.TimeField(null=True, blank=True, default=timezone.now) end_time = models.TimeField(null=True, blank=True, default=timezone.now) and this is my forms.py class AppointmentForm_2(forms.ModelForm): doctor = forms.ModelChoiceField(queryset=User.objects.filter(type_of_user=TypeOfUser.DOCTOR)) # patient = forms.ModelChoiceField(queryset=User.objects.filter(type_of_user=TypeOfUser.PATIENT)) date = forms.DateField(widget=forms.DateInput(attrs={'type': 'date'}), input_formats=settings.DATE_INPUT_FORMATS) start_time = forms.DateField(widget=forms.DateInput(attrs={'type': 'time'}), input_formats=settings.TIME_INPUT_FORMATS) class Meta: model = Appointment fields = ('patient', 'doctor', 'date', 'start_time') and this is the views.py @login_required def create_appointement_2(request): user = get_user_model() patients = User.objects.filter(type_of_user=TypeOfUser.PATIENT) form_appointment_2 = AppointmentForm_2(request.POST or None) if request.user.is_doctor() or request.user.is_reception(): if request.method=='POST': form_appointment_2 = AppointmentForm_2(request.POST or None) user = get_user_model() if form_appointment_2.is_valid(): form_appointment_2.save(commit=False) form_appointment_2.user_ho_add = request.user # form_appointment.end_time = form_appointment.start_time + timedelta(minutes=30) start_time = form_appointment_2.start_time future_time … -
Django HTML page returns the same id object from database
I have a few objects on my database, and my html page should open a new tab with the respective “id’s” when I click on the objects. But when I click on them It opens a new tab always with the “id:1”, even if I click on the second object, it returns me the “id” of the first item, instead of the second one. How can I make it to display the respective ‘id’ of the item when I click on it? Here is the screenshoot of the page Here is the openned tab after I click on the 2nd object, displaying the 'id' of the first object. Here is the HTML code of the page uploaded: https://github.com/khavro21/my_html/blob/main/index.html I can´t find out what is missing on my code, do you have any idea? Thank you! -
Can't migrate after makemigrations on django
everyone. I newbie in this field. So, After I finished makemigrations. then I migrate this error code occurs. I try to solve it but still stuck. please guide, I attach my error code as below. (venv) C:\Users\hp\Desktop\Taskly_App\src>python manage.py migrate Operations to perform: Apply all migrations: admin, auth, contenttypes, house, oauth2_provider, sessions, social_django, task, users Running migrations: Applying task.0002_auto_20210331_2329...Traceback (most recent call last): File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\db\backends\utils.py", line 82, in _execute return self.cursor.execute(sql) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\db\backends\sqlite3\base.py", line 411, in execute return Database.Cursor.execute(self, query) sqlite3.OperationalError: table "task_tasklist" already exists The above exception was the direct cause of the following exception: Traceback (most recent call last): File "manage.py", line 22, in <module> main() File "manage.py", line 18, in main execute_from_command_line(sys.argv) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\__init__.py", line 401, in execute_from_command_line utility.execute() File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\__init__.py", line 395, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\base.py", line 330, in run_from_argv self.execute(*args, **cmd_options) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\base.py", line 371, in execute output = self.handle(*args, **options) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\base.py", line 85, in wrapped res = handle_func(*args, **kwargs) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\core\management\commands\migrate.py", line 243, in handle post_migrate_state = executor.migrate( File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\db\migrations\executor.py", line 117, in migrate state = self._migrate_all_forwards(state, plan, full_plan, fake=fake, fake_initial=fake_initial) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\db\migrations\executor.py", line 147, in _migrate_all_forwards state = self.apply_migration(state, migration, fake=fake, fake_initial=fake_initial) File "C:\Users\hp\Desktop\Taskly_App\venv\lib\site-packages\django\db\migrations\executor.py", line 227, in apply_migration state = migration.apply(state, schema_editor) … -
Django Post Save Signal goes on looping
The below code goes on looping , after processing the value for profile_pic my use case: when the value for profile_pic is passed while saving the model , I need to perform some operations on it and then save it , if the value is null nothing should happen @receiver(post_save,sender=User) def resize_image(sender,instance,created,*args,**kwargs): if instance.profile_pic: ###### doing some operations on profile_pic ###### instance.profile_pic=image_process(image) instance.save() -
Paginate constantly updating feed in django?
The obvious problem is that loading further pages in an updating feed would lead to loading some content more than once. Is there a good built-in way to perform such a task? I think the paginator object wont really work unless used with reversed queryset which however is allegedly very memory inefficient. Another solution I could think of (when ordering by time) is sending a timestamp of the last object on the page, saving it in front-end and for the next request send this time to django do a time__gte for n+1 objects and slice off the first one. Would probably do the trick quite well but its anything but intuitive. Is there a better way to go about it? -
Update a value that is the sum of two range values
I recently started to work on Django and JavaScript, and currently working on Range items. I successfully managed to have two functioning scales and to update their value next to them each time the user is modifying them. <p>You have <span id="demo1"></span> spent dollars on this item.</p> <div class="input-group"> <p class="input-group-text">0<input type="range" id="myRange1" name="myRange" min="0" max = "120" step="5" class="form-range"></p> <p class="input-group-text"> 120</p> </div> var slider1 = document.getElementById("myRange1"); var output1 = document.getElementById("demo1"); output1.innerHTML = slider1.value; slider1.oninput = function() { output1.innerHTML = this.value; } <p>You are spending<span id="demo2"></span> dollars on this item.</p> <div class="input-group"> <p class="input-group-text">0<input type="range" id="myRange2" name="myRange" min="0" max = "120" step="5" class="form-range"></p> <p class="input-group-text"> 120</p> </div> var slider2 = document.getElementById("myRange2"); var output2 = document.getElementById("demo2"); output2.innerHTML = slider2.value; slider2.oninput = function() { output2.innerHTML = this.value; } Now, what I am trying to get is to have a value that is the sum of the two values, and that is updating as soon as the user is modifying one of the two scales. I tried the following: <p>You have spent <span id="demo_total"></span> dollars in total.</p> var value_total = 0 var output_total = document.getElementById("demo_total"); output_total.innerHTML = 120 // Display the default slider value value_total.value = function() { output_total.innerHTML = parseInt(output1.innerHTML) + … -
How do I get the client Remote Port number in a Django?
I know I can use request.META['REMOTE_ADDR'] to get the client's IP in my django view function. However, I have no idea how to get the client remote port number. For example, you can see your own remote port number on the site below: https://www.myip.com/ Remote Port MY VIEW PY: if request.user.is_authenticated: gelenIleti = request.META.get('HTTP_X_FORWARDED_FOR') if gelenIleti: ip = gelenIleti.split(',')[0] else: ip = request.META.get('REMOTE_ADDR') portNumarasi = request.META['SERVER_PORT'] logger.info(' ' + 'LOG KAYDI :' + ' ' + ' KULLANICI : ' + request.user.username + ' ' + ' IP : ' + ip + ' ' + ' SERVER PORT : ' + portNumarasi) -
What do I set date_field to in DayArchiveView for django-recurrence?
I have a model for booking slots and a DayArchiveView in django. I am using django-recurrences to make my events recurrent https://django-recurrence.readthedocs.io/en/latest/index.html views.py class ClubBookingArchiveView(DayArchiveView): queryset = BookingSlot.objects.all() date_field = "recurrences" #what should I put here? allow_future = True allow_empty = True models.py class BookingSlot(models.Model): start_time = models.TimeField("Start Time") end_time = models.TimeField("End Time") recurrences = RecurrenceField() I am wondering what I should set the date_field to in my DayArchiveView. Or if anyone can think of anyway I can get around this, is there like a get_date_field() I can override or something, or will I have to generate a view completely from scratch? -
Can't write to a file with Django in Nginx
I have deployed a Django web app using uWSGI and Nginx, but the app runs into an error when trying to create a file inside a specified folder. Inside my views file, I specify a function which writes to a file using "with open". This function writes the file to a folder named 'output' inside the Django project folder. When I run the Django server, all the functionality works well, but, when I run the Nginx server, it gives me an error exactly where the "with open" is. I have already tried to switch the ownership of the 'output' folder, but it did not work. Also tried to run 'sudo chmod -R www-data:www-data' with my whole project folder as an attribute, but I had no success. I would please like to have more insight on how to fix this issue. The problem is likely about my permissions, but I have tried everything in my knowledge to fix it but it did not work. In attachment, I am sending an image of the output of the 'ls -la' command inside my Django project folder. Also, the guide I have followed can be found here: https://tonyteaches.tech/django-nginx-uwsgi-tutorial/. output of the ls -la command … -
How to use django-select2 in wagtail?
I have a model with many-to-many relation. And for wagtail I used the following: from django_select2.forms import Select2MultipleWidget from wagtail.admin.edit_handlers import FieldPanel panels = [ FieldPanel('field_name', widget=Select2MultipleWidget ] But select2 is not showing up. What can be done? -
Django Models get value from a foreign key
I have the following model: class Check (models.Model): user_id = models.ForeignKey(Client, on_delete=models.CASCADE) client = Client.objects.get(pk=1) #change id according to user_id client_birth = client.birth client_gender = client.gender What I need is to get those birth and gender values from model Client, but according to the value id set on user_id. Is that possible? -
I cannot install Django in my Virtual Environment
I wanted to install Django in my virtual environment (which was completely working), but got this whole lot of errors. Anyone know what to do? I just typed this in PowerShell: pipenv install django And got this: Error: An error occurred while installing django! Error text: Collecting django Using cached Django-3.1.7-py3-none-any.whl (7.8 MB) ERROR: THESE PACKAGES DO NOT MATCH THE HASHES FROM Pipfile.lock!. If you have updated the package versions, please update the hashes. Otherwise, examine the package contents carefully; someone may have tampered with them. django from https://files.pythonhosted.org/packages/b8/6f/9a4415cc4fe9228e26ea53cf2005961799b2abb8da0411e519fdb74754fa/Django-3.1.7-py3-none-any.whl#sha256=baf099db36ad31f970775d0be5587cc58a6256a6771a44eb795b554d45f211b8 (from -r c:\users\vojtěch\appdata\local\temp\pipenv-e9otm_0m-requirements\pipenv-sj4h6g3_-requirement.txt (line 1)): Expected sha256 baf099db36ad31f970775d0be5587cc58a6256a6771a44eb795b554d45f211b8 Got 764ad5e659cd3a7740b314806b39c67501c6136a21d23652515df3bfb4023d76 -
how to add quantity to products in cart django
so I am trying to add a option to set quantity for my products before I add them to the cart and while they are inside the cart something like thisexample my models.py class CartManager(models.Manager): def new_or_get(self, request): cart_id = request.session.get("cart_id", None) qs = self.get_queryset().filter(id=cart_id) if qs.count() == 1: new_obj = False cart_obj = qs.first() if request.user.is_authenticated and cart_obj.user is None: cart_obj.user = request.user cart_obj.save() else: cart_obj = Cart.objects.new(user=request.user) new_obj = True request.session['cart_id'] = cart_obj.id return cart_obj, new_obj def new(self, user=None): user_obj = None if user is not None: if user.is_authenticated: user_obj = user return self.model.objects.create(user=user_obj) class Cart(models.Model): user = models.ForeignKey(User, null=True, blank=True, on_delete=models.CASCADE) subtotal = models.DecimalField(default=0.00, max_digits=100, decimal_places=2) products = models.ManyToManyField(Product, blank=True) total = models. DecimalField(default=0.00, max_digits=100, decimal_places=2) updated = models.DateTimeField(auto_now=True) timestamp = models.DateTimeField(auto_now_add=True) objects = CartManager() def __str__(self): return str(self.id) def m2m_changed_cart_receiver(sender, instance, action, *args, **kwargs): if action == 'post_add' or action == 'post_remove' or action == 'post_clear': products = instance.products.all() total = 0 for x in products: total += x.price if instance.subtotal != total: instance.subtotal = total instance.save() m2m_changed.connect(m2m_changed_cart_receiver, sender=Cart.products.through) def pre_save_cart_receiver(sender, instance, *args, **kwargs): if instance.subtotal > 0: instance.total = Decimal(instance.subtotal) * Decimal(1.08) # 8% tax else: instance.total = 0.00 pre_save.connect(pre_save_cart_receiver, sender=Cart) this is my views.py … -
How to align components in the bootstrap Navbar Properly?
I am developing an e-commerce website, but I cannot align the components in my navbar properly. I just copied the navbar code from the bootstrap site and pasted it inside my main.html file. Here is the navbar code: Ecom <span class="navbar-toggler-icon"></span> </button> <div class="collapse navbar-collapse" id="navbarSupportedContent"> <ul class="navbar-nav mr-auto"> <li class="nav-item active"> <a class="nav-link" href="{% url 'store' %}">Store<span class="sr-only"></span></a> </li> </ul> <div class="form-inline my-2 my-lg-0 "> <a href="#"class="btn btn-warning">Login</a> <a href="{% url 'cart' %}"> f <img id="cart-icon" src="{% static 'images/cart.png' %}"> </a> <p id="cart-total">0</p> </div> </div> </nav> Below is the Navbar image (all components are jumbled):- I want to align the login button and cart image symbol to right and also reduce the size of the navbar and login button -
Pylint does not acknowledge a module
I'm new to Django and haven't used much of the Python tooling. The following line of code is being flagged by Pylint, despite working without issue. # main/management/commands/send_policy_notifications.py from main import models No name 'models' in module 'main'pylint(no-name-in-module) The file structure follows: . ├── Pipfile ├── Pipfile.lock ├── .env ├── .pylintrc ├── main │ ├── __init__.py │ ├── access_conditions.py │ ├── admin.py │ ├── apps.py │ ├── authentication.py │ ├── flags.py │ ├── management │ │ └── commands │ │ └── send_policy_notifications.py │ ├── tests.py │ ├── urls.py │ └── views.py └── manage.py How can I configure Pylint to acknowledge that main contains models? I'm using Visual Studio Code. -
How to use link in Django template
I am a beginner in Django . I have done a project . I use bootstrap in this but css is not working <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css" There is any way to convert this link in Django format ? -
How to fix exeption when I try to create a record in DB in admin panel: 'InMemoryUploadedFile' object has no attribute '_committed'?
How to fix exeption when I try to create a record in DB in admin panel: 'InMemoryUploadedFile' object has no attribute '_committed'? I am new to django and have absolutely no idea where to dig. The first attemp was succesfull, but that was before adding a bunch of code to the project. Without an ImageField everything works well. I catch exeption only when I try to save image model.py from django.conf import settings from django.db import models from django.utils import timezone from django.contrib.auth.models import User class TripPost(models.Model): title = models.CharField(max_length=150) location = models.CharField(max_length=150) body = models.TextField() pub_date = models.DateTimeField(auto_now_add=True) add_inform = models.CharField(max_length=80, blank=True) image = models.ImageField(upload_to='trips/%Y/%m/', blank=True) def __str__(self): return '{}'.format(self.title) admin.py from django.contrib import admin from .models import TripPost admin.site.register(TripPost) media path from setting.py MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, 'media') urls.py from django.contrib import admin from django.urls import path from .views import * from django.conf import settings from django.conf.urls.static import static urlpatterns = [ path('admin/', admin.site.urls), path('trips', TripsGet.as_view(), name='trips_url'), ] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) Exeption in CMD File "E:\lab1-15\venv\lib\site-packages\django\db\models\base.py", line 780, i n save_base updated = self._save_table( File "E:\lab1-15\venv\lib\site-packages\django\db\models\base.py", line 850, i n _save_table values = [(f, None, (getattr(self, f.attname) if raw else f.pre_save(self, F alse))) File "E:\lab1-15\venv\lib\site-packages\django\db\models\base.py", line … -
Why is this Django Template not receiving the context?
I'm using a simple view to render an 'index.html' page, and pass a JSON in the context variable. def index(request): """Homepage. Calls are made to other classes from here.""" ytv = YoutubeVideos() user = request.GET.get('user', '') videos = {'name': 'filler data here'} if user != '': videos = ytv.get(request=request, channel_data=1) print(videos) return render(request, 'index.html', context=videos) return render(request, 'index.html', context=videos) I've confirmed it is going through the first return, with the videos context containing JSON data. It is printing in the console. I also have the index.html file, which contains: ... {{videos|json_script:'name'}} <script> 'use strict'; var videos = JSON.parse(document.getElementById('name').textContent); ... I've tried several variations on the way to get the JSON data in the Javascript including: <input type="hidden" id="myVar" name="videos" value="{{ videos }}"> Then getting the value in javascript this way, var myVar = document.getElementById("myVar").value; The problem is when the html is rendered it becomes this (screenshot of Source): Basically, the variable looks like it doesn't exist when it gets rendered. Any help would be appreciated. -
How can I link the column of a model to another using Django ForeignKey
I have the below models class Supplier(models.Model): supplierName = models.CharField(max_length=64) zone = models.IntegerField() class Contact(models.Model): supplier = models.ForeignKey(Supplier, on_delete=models.SET("Company Deleted"), related_name="supplierC") name = models.CharField(max_length=64) On the html <select name="supplier" id="supplier"> <option value="1">Supplier 1</option> <option value="2">Supplier 2</option> </select> If I select supplier 1,and post the form to the view, I will have to first get the Supplier whose id = 1, then use the obtained query to fill the database for contact def contactForm(request): if request.method == "POST": supplier = Supplier.objects.get(pk=request.POST['supplier']) mydata ={} mydata['supplier'] = supplier mydata['name'] = request.POST['contact-name'] new_contact = Contact(**mydata) new_contact.save() Is there a way to avoid supplier = Supplier.objects.get(pk=request.POST['supplier']) For instance in our model do something like supplier = models.ForeignKey(Supplier.id, on_delete=models.SET("Company Deleted"), Where by in while creating the new record for Contact, we do directly as shown below def contactForm(request): if request.method == "POST": mydata ={} mydata['supplier'] = request.POST['supplier'] mydata['name'] = request.POST['contact-name'] new_contact = Contact(**mydata) new_contact.save() Any help? -
Django always failed when login as user, while superuser (admin) always success
So, I've tried a couple of times to register and back to login. Always failed to log in except for superuser or admin. Already checked in Django admin that the user that I have registered already there. There is no error message in the terminal when login or register a user. Except for the error message that I've created in views.py if log in unsuccessful. So, let's take a look into my code. First views.py from django.contrib.auth import authenticate, login, logout def login_view(request): if request.method == "POST": # Attempt to sign user in username = request.POST["username"] password = request.POST["password"] user = authenticate(request, username=username, password=password) # Check if authenticate successful if user is not None: login(request, user) return HttpResponseRedirect(reverse("index")) else: context = { "message": "Invalid username and/or password" } return render(request, "page/login.html", context) else: return render(request, "page/login.html") And below is the template. <div class="login-register"> <div class="head"> Log in to Explore </div> <form action="{% url 'login' %}" method="post"> {% csrf_token %} <div class="form-floating mb-3"> <input type="text" class="form-control" id="username" name="username" placeholder="Username""> <label for="username">Username</label> </div> <div class="form-floating mb-3"> <input type="password" class="form-control" id="password" name="password" placeholder="Password"> <label for="password">Password</label> </div> <div class="d-grid gap-2"> <input class="btn btn-outline-success" type="submit" value="Login"> </div> <div id="log-reg"> <a href="{% url 'register' %}">Sign Up</a> … -
Order a dict in python when keys are list
I need to order the following dict in asc order depends on the 'progreso' value. How can I do it? {10: [{'titulo': 'Apropiación Digital'}, {'progreso': '50'}, {'estado': 'En curso'}], 13: [{'titulo': 'Así se ve mi negocio'}, {'progreso': '0'}, {'estado': 'En espera'}], 8: [{'titulo': 'Bioseguridad'}, {'progreso': '50'}, {'estado': 'En curso'}], 15: [{'titulo': 'Desarrollo de oportunidades de negocio'}, {'progreso': '0'}, {'estado': 'En espera'}], 9: [{'titulo': 'Formalización'}, {'progreso': '0'}, {'estado': 'En espera'}], 11: [{'titulo': 'Hagamos cuentas'}, {'progreso': '50'}, {'estado': 'En curso'}], 7: [{'titulo': 'Mujer emprendedora'}, {'progreso': '100'}, {'estado': 'Finalizado'}, {'puntaje': 100}, {'fecha': datetime.datetime(2021, 3, 31, 15, 19, 20)}, {'puntos': 170}], 12: [{'titulo': 'Precio y competencia'}, {'progreso': '0'}, {'estado': 'En espera'}], 14: [{'titulo': 'Servicio al cliente'}, {'progreso': '0'}, {'estado': 'En espera'}], 16: [{'titulo': 'Test'}, {'progreso': '0'}, {'estado': 'En espera'}]} -
Authorizing user for further part but if info is wrong notify him that his/her acc is deleted
I'm new to the Django framework. after the user is logged in he fills a form and that data is sent to admin which can be done through modelform. what I actually want to do is this data should be viewed by admin and if the info provided in the form is wrong/misguided then the admin deletes his/her account notifying him to fill the valid info in form. How can it be done?
