Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Adding a search field for Token section in Django Admin
I'm using the Django rest framework and I need to manually delete a token that belongs to a specific user using the Django admin. But the problem is it's hard to find the relevant token of a user when there are thousands of tokens. So I need to add a search to the token section then I can search the token using the user's Email. How I can add an search for the token section in the Django admin. -
Particular category's product listing in one shared html page
I am creating ecommerce site in django , I have large number of categories so when user clicks particular category in one html page It has to redirect to another page and show the products of selected category For example there should be one html page called selectedCategoryProducts.html and when user clicks drinks at category listing at Home page it has to redirect to the selectedCategoryProducts.html and show the products under drinks , when user clicks medicines it should share the same html page to show the products under medicines I don't want to create html page for every category that i'm having Is there any idea to do that home.html Category Listing {% for category in allCategory %} <li class="dropdown" > <a href="#" class="dropdown-toggle" data-toggle="dropdown">{{category}} <b class="caret"></b></a> <ul class="dropdown-menu multi-column columns-3"> <div class="row"> {% for subcategory in subCategories %} {% if subcategory.category == category%} <div class="col-sm-3"> <ul class="multi-column-dropdown"> <h6>{{subcategory.subCatName}}</h6> {% for types in productCategories %} {% if types.subCategory == subcategory %} <li><a href="dresses.html">{{types}}<span>New</span></a></li> {% endif %} {% endfor %} </ul> </div> {% endif %} {% endfor %} <div class="clearfix"></div> </div> </ul> </li> {% endfor %} selectedCategory.html {% for product in instanceselectedCategory %} <h2>product.productName</h2> {% endfor %} -
django framework can't create authentication token in google cloud
I can't create a token for an user manually throught django admin site (https://admin/). I have built an user accounts on a django framework allocated in google cloud server, as a GAE app. In order to add user accounts I use a third-party app for django called "rest_framework", the problem comes when I try to create a token for a created user in admin site, error 500 appear and no idea how to find the problem. The framework also has been tested on a local machine (my computer) and works correctly, but for some reason it doesn't work in google cloud. The added code of each file is showing as follows: settings.py from pathlib import Path import os BASE_DIR = Path(__file__).resolve().parent.parent SECRET_KEY = ... DEBUG = False ALLOWED_HOSTS = ['*'] # Application definition INSTALLED_APPS = [ 'django.contrib.sites', 'rest_framework', 'rest_framework.authtoken', 'corsheaders', 'KhalilApp.apps.KhalilappConfig', #This is my app on django 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', ] MIDDLEWARE = [ 'django.middleware.security.SecurityMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'corsheaders.middleware.CorsMiddleware', 'django.middleware.common.CommonMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'django.middleware.clickjacking.XFrameOptionsMiddleware', ] ROOT_URLCONF = 'DjangoServer.urls' TEMPLATES = [ { 'BACKEND': 'django.template.backends.django.DjangoTemplates', 'DIRS': [os.path.join(BASE_DIR,'KhalilApp/Mapilib'), os.path.join(BASE_DIR,'static'), os.path.join(BASE_DIR,'KhalilApp/templates')], 'APP_DIRS': True, 'OPTIONS': { 'context_processors': [ 'django.template.context_processors.debug', 'django.template.context_processors.request', 'django.contrib.auth.context_processors.auth', 'django.contrib.messages.context_processors.messages', ], }, }, ] WSGI_APPLICATION = 'DjangoServer.wsgi.application' import pymysql pymysql.version_info = … -
mysql is not available in django.db.backends (django)
trying to connect to the mysql and trying to do makemigrations. but getting this error: django.core.exceptions.ImproperlyConfigured: 'django.db.backends.mysql' isn't an available database backend. Try using 'django.db.backends.XXX', where XXX is one of: 'oracle', 'postgresql', 'sqlite3' my settings.py: DATABASES = { 'default': { 'ENGINE': 'django.db.backends.mysql', 'NAME': '****', 'USER': 'root', 'PASSWORD': '****', "HOST": '****', 'PORT': '****' } } Thanks in advance -
Django benchmark
For my research, I am trying to benchmark Django framework capacity. I am running the server in my own pc which has Intel core i7 processor with 12 core. If I run django with the builin server, it can server, it can server ~3000 request/30s.(HTML is just a "hello world" page). I tried to run Django with Gunicorn. But to my surprise, it does not increase the server capacity. Even if I use 24 worker process, it still can serve ~3100 requests/30s. Does this number seem right? Because compared to other languages, it seems very low. I want to make sure if I am doing it right. -
FileNotFoundError: [Errno 2] No such file or directory: 'corpus_or_AB_FMC.xlsx'
I have a directory which contains a lot of excel files. My aim is to read all those excel files and extract some information in them. I used the script below to read the directory but I am still getting an error. The files are identified but the code tell it is not founding them which is strange because there is a line to print the name of the file. But when reading the file with pandas, it is not founded. /home/geta/kelo/eXP/Test/corpus -----File in processed : corpus_or_AB_FMC.xlsx Traceback (most recent call last): File "test_vec.py", line 111, in <module> sentences = pd.read_excel(file, sheet_name= 0) File "/home/getalp/kelodjoe/anaconda3/lib/python3.7/site-packages/pandas/util/_decorators.py", line 208, in wrapper return func(*args, **kwargs) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/pandas/io/excel/_base.py", line 310, in read_excel io = ExcelFile(io, engine=engine) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/pandas/io/excel/_base.py", line 819, in __init__ self._reader = self._engines[engine](self._io) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/pandas/io/excel/_xlrd.py", line 21, in __init__ super().__init__(filepath_or_buffer) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/pandas/io/excel/_base.py", line 359, in __init__ self.book = self.load_workbook(filepath_or_buffer) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/pandas/io/excel/_xlrd.py", line 36, in load_workbook return open_workbook(filepath_or_buffer) File "/home/geta/kelo/anaconda3/lib/python3.7/site-packages/xlrd/__init__.py", line 111, in open_workbook with open(filename, "rb") as f: here is the code : dir = "/home/geta/kelo/eXP/Test/corpus" for root, subdirs, files in os.walk(dir): print(root) for file in files: #print(files) print("-----File in processed :", file) # -----File in processed : corpus_or_AB_FMC.xlsx # this file … -
All paths open a single page
I am new to Django and doing something wrong. I've tried many templates and examples and always run into the same problem. No matter what path I try to use, I get the same file. Settings.py INSTALLED_APPS = [ 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', #my apps 'strategicplan.apps.StrategicplanConfig', 'house.apps.HouseConfig', ] Main site urls.py from strategicplan import views as sp_views from house import views as house_views urlpatterns = [ path('house/',house_views.index), path('strategicplan/',sp_views.index), ] house/urls.py from django.urls import path from house import views urlpatterns = [ path('', views.index, name='index'), ] house/templates/index.html <!DOCTYPE html> <html lang="en"> <head> {% block title %}<title>Houses</title>{% endblock %} </head> <body> house </body> </html> strategicplan/urls.py from django.urls import path from strategicplan import views urlpatterns = [ path('strategicplan/', views.index, name='index'), ] strategicplan/templates/index.html <!DOCTYPE html> <html lang="en"> <head> {% block title %}<title>strategic plan</title>{% endblock %} </head> <body> strategic plan </body> </html> No matter what I put in the url http://127.0.0.1 or http://127.0.0.1/house or http://127.0.0.1/stategicplan, I get the strategicplan/index.html page. Both http://127.0.0.1 and http://127.0.0.1/house end up with http://127.0.0.1 in the address bar, but still show the strategicplan page. The http://127.0.0.1/strategicplan page holds the correct address in the address bar, which is also the correct page. Thanks!! -
python django help me pls
hello this is my code i need to insert data in datatable user_id and subject_id .The select box is filled form database subjects table. this are my code files: models.py from django.db import models class ShowSubjects(models.Model): subject=models.CharField(max_length=100) class Meta: db_table ='subjects' views.py from django.shortcuts import render from django.contrib.auth.decorators import login_required from directory.models import ShowSubjects @login_required def directory(request): results=ShowSubjects.objects.all() return render(request, 'directory/directory.html',{'ShowSubjects':results}) urls.py from django.urls import path from . import views urlpatterns = [ path('', views.directory, name='directory'), ] html {% block content %} <div class="dir-left"> </div> <div class="dir-right"> <form method="POST"> {% csrf_token %} <select name="selectedsubject"> <option disabled="true" selected> Select subject </option> {% for results in ShowSubjects %} <option>{{results.subject}}</option> {% endfor %} </select> <div class="form-group"> <br> <button class="addsubject" type="submit">Add subject</button> </div> </form> </div> {% endblock %} help me pls -
The form to change email/profile pictures doesn't appear?
Any guidance on this issue will be greatly appreciated. I entered the necessary fields so that on the profile page the user would be able to edit the profile picture and the username and email. when I created the form, it only displayed the update button and the "Profile Info" text. How can fix this so that the form to edit the user information appears? in views.py ''' @login_required def profile(response): if response.method == "POST": u_form = UserUpdateForm(response.POST, instance=response.user) p_form = ProfileUpdateForm(response.POST, response.FILES, instance=response.user.profile) if u_form.is_valid() and p_form.is_valid(): u_form.save() p_form.save() messages.success(response, f'Your account has been updated!') return redirect("/profile") else: u_form = UserUpdateForm(instance=response.user) p_form = ProfileUpdateForm(instance=response.user.profile) args = {} args['u_form']= u_form, args['p_form']= p_form return render(response, 'register/profile.html') ''' in forms.py ''' from django import forms #from django.contrib.auth. import login, authenticate from django.contrib.auth.forms import UserCreationForm, UserChangeForm from django.contrib.auth.models import User from .models import Profile from django.forms import ModelForm class RegisterForm(UserCreationForm): email = forms.EmailField() class Meta: model = User fields = ["username", "email", "password1", "password2"] class UserUpdateForm(forms.ModelForm): email = forms.EmailField() class Meta: model = User fields = ["username", "email"] class ProfileUpdateForm(forms.ModelForm): class Meta: model = Profile fields = ['image'] ''' in profile.html {% extends "register/base.html" %} {% load crispy_forms_tags %} {% block content %} … -
Как сделать выпадающий список моделей в Django в админке [closed]
Имеются следующие модели Как реализовать следующую мысль? Я хочу, чтобы при добавлении городов в админ панели выпадающим списком сначала предлагалось выбрать страну, потом область и после всего этого написать название города и сохранить. Сделал похожую реализацию в модели UserLocation,но там пришлось использовать ChainedForeignKey. Здесь хочется модели не трогать, всю голову сломал. -
My change to models.py isn't being reflected in the admin portal
I've added a model called 'ads' into my models.py (which already contained a model called 'video', but the only model showing in the admin portal is the 'video' model. This is my model: from django.db import models # Create your models here. class video (models.Model): VID_CHOICES = ( ('News', 'News'), ('Stam', 'Stam'), ('Music', 'Music'), ('Ad', 'Ad'), ) url = models.CharField(max_length=1000) title = models.CharField(max_length=100) description = models.CharField(max_length=1000, blank=True) show_after_time = models.DateTimeField('show after') category = models.CharField(max_length=20, choices=VID_CHOICES) tag = models.CharField(max_length=100, blank=True) def __str__(self): return self.title class ad (models.Model): AD_CHOICES = ( ('Constant', 'Constant'), ('Temporary', 'Teporary'), ('Filler', 'Filler'), ) redirect = models.URLField(blank=True) pic = models.URLField() first_day = models.DateTimeField('first day') last_day = models.DateTimeField('last day') kind = models.CharField(max_length=21, choices=AD_CHOICES) def __str__(self): return self.title I've run the migrations and everything, why isn't it working? PS - I currently use postgres, but started with sqlite3. Meaning, I created the model 'video' on sqlite3, and am trying to make 'ads' on postres. -
ImportError when trying to use Django
apologies if this question has been asked a ton, I'm sure it has, and I've been trying for days to figure this out, but I can't wrap my head around it. I've been developing in Python for over 1.5 years, so I'm not a complete beginner. I can't get Django to work in my command prompt. An example is, when I try to use py .\manage.py makemigrations this is what I get: Traceback (most recent call last): File ".\manage.py", line 11, in main from django.core.management import execute_from_command_line ModuleNotFoundError: No module named 'django' The above exception was the direct cause of the following exception: Traceback (most recent call last): File ".\manage.py", line 22, in <module> main() File ".\manage.py", line 13, in main raise ImportError( ImportError: Couldn't import Django. Are you sure it's installed and available on your PYTHONPATH environment variable? Did you forget to activate a virtual environment? Now, I can see what the error says. The thing is my virtual environment is activated and it has Django installed, as seen here. Moreover, even if I executed outside my venv, it still doesn't work, even though I have all necessary Python directories in my PATH, as seen here. I have verified … -
Django: Save two models (Customer and Addresses) in one Form
I have this models.py: class Customers(models.Model): ID = models.AutoField(primary_key=True) IsBusinessCuster = models.BooleanField(default=True, blank=True, null=True) CustomerSalutation = models.ForeignKey('Salutation', on_delete=models.DO_NOTHING) Title = models.CharField('Title', max_length=20) Firstname = models.CharField('Firstname', max_length=200) Lastname = models.CharField('Lastname', max_length=200) Orders = models.ForeignKey('Order', on_delete=models.DO_NOTHING, blank=True, null=True) CustomerNo = models.IntegerField('Zip', blank=False, null=False) Addresses = models.ForeignKey('CustomerAddresses', on_delete=models.DO_NOTHING) CustomerGroup = models.ForeignKey('CustomerGroups', on_delete=models.DO_NOTHING) IsActive = models.BooleanField(default=True, blank=True, null=True) CVR = models.IntegerField('CVR', blank=True, null=True) Company = models.CharField('Company', max_length=128, blank=True, null=True) Created_Date = models.DateTimeField(auto_now_add=True) PhoneNumber = models.CharField('PhoneNumber', max_length=20, blank=True, null=True) UserID = models.ForeignKey('MasterData', on_delete=models.CASCADE) Email = models.EmailField('EMail', max_length=128, blank=True, null=True) def __str__(self): return str(self.Lastname) class CustomerAddresses(models.Model): ID = models.AutoField(primary_key=True) Salutation = models.ForeignKey('Salutation', on_delete=models.DO_NOTHING) Title = models.CharField('Title', max_length=20, blank=True, null=True) Address_Firstname = models.CharField('Firstname', max_length=200) Address_Lastname = models.CharField('Lastname', max_length=200) Zip = models.IntegerField('Zip') City = models.CharField('City', max_length=128) Address_Company = models.CharField('Company', max_length=128, blank=True, null=True) Is_Default_Shipping_address = models.BooleanField(default=True, blank=True, null=True) Is_Default_Billing_address = models.BooleanField(default=True, blank=True, null=True) Country = models.CharField('Country', max_length=32, blank=True, null=True) def __str__(self): return str(self.ID) and this form.py: class CustomerForm(forms.ModelForm): IsBusinessCuster = forms.BooleanField( widget=forms.CheckboxInput(attrs={'class': 'form-check-input', 'id': 'customSwitch2'}), initial=False, required=False) class CustomerAddressesForm(forms.ModelForm): Title = forms.CharField(widget=forms.TextInput(attrs={'class': 'form-control mb-3', 'autofocus': True}), required=False) Shorten version... You can see that address are an must have field in Customer's form. I build an form in html where you have all fields, but how can I save both … -
no values from jquery in a template to my view function
I am using django and I am getting all id from checkboxes and now I want to pass them to my view function, but I don't know how. I've tried request.GET.getlist('vals') but with no success. any suggestions? events.html: <script> $(document).ready(function(){ $("button").click(function(){ type: 'POST'; var vals = []; $.each($("input[name='checkb']:checked"),function(vals){ vals.push($(this).attr('id')); }); alert("values: " + vals.join(", ")); }); }); </script> <td><a href="eprint"><button><i class="bi bi-sim"></i></button></a></th> {% for l in object_list %} <tr> <td> <form> <label><input type="checkbox" id={{l.pk}} name="checkb"></label> <form> ... urls.py: path('eprint',views.eprint,name='eprint'), views.py: def eprint(request): print('eprint') v=request.GET.getlist(vals) -
How to add drag & drop feature for uploading multiple files using django-forms with dropzone.js?
I wanna add a drag and drop multiple file upload field in my existing form using django-forms with dropzone.js. These are my files 👇 forms.py 👇 class RaiseRequisitionForm(forms.Form): position_required = forms.CharField(required=True, label="Position Required" , max_length=2000, widget=forms.TextInput(attrs={"class":"form-control"})) requirement_choices = ( ("New", "New"), ("BackFill", "BackFill") ) requirement = forms.ChoiceField(required=True, label="Requirement" , choices=requirement_choices ,widget=forms.Select(attrs={"class":"form-control"})) candidate_name = forms.CharField(required=True, label="Candidate Name" , max_length=2000 ,widget=forms.TextInput(attrs={"class":"form-control"})) department = forms.CharField(required=True, label="Department" , max_length=2000 ,widget=forms.TextInput(attrs={"class":"form-control"})) post = forms.CharField(required=True, label="Post" , max_length=2000 ,widget=forms.TextInput(attrs={"class":"form-control"})) requirement_type = ( ("Permanent", "Permanent"), ("Temporary", "Temporary"), ("Fixed Contract", "Fixed Contract") ) requirement_time_period = forms.ChoiceField(required=True, label="Requirement Time Period" ,choices=requirement_type , widget=forms.Select(attrs={"class":"form-control"})) work_type = ( ("Full-Time", "Full-Time"), ("Part-Time", "Part-Time") ) work_type = forms.ChoiceField(required=True, label="Work Type" ,choices=work_type , widget=forms.Select(attrs={"class":"form-control"})) duration_start_date = forms.DateField(required=True, label="Duration Start Date", widget=forms.DateInput(attrs={"type":"date", "class":"form-control"})) duration_end_date = forms.DateField(required=False, label="Duration End Date ( If Temporary Or Fixed Contract )", widget=forms.DateInput(attrs={"type":"date", "class":"form-control"})) requisition_reason = forms.CharField(required=True, label="Requisition Reason", widget=forms.Textarea(attrs={"class":"form-control"})) min_qualification = forms.CharField(required=True, label="Minimum Qualification", max_length=1000, widget=forms.TextInput(attrs={"class":"form-control"})) max_qualification = forms.CharField(required=True, label="Desired Qualification", max_length=1000, widget=forms.TextInput(attrs={"class":"form-control"})) min_experience= forms.CharField(required=True, label="Minimum Experience", widget=forms.TextInput(attrs={"class":"form-control"})) max_experience= forms.CharField(required=True, label="Maximum Experience", widget=forms.TextInput(attrs={"class":"form-control"})) models.py 👇 I added the "documents" variable for uploading files. class Requisition(models.Model): id = models.AutoField(primary_key=True) position_required = models.CharField(max_length=2000, default="") requirement_choices = ( ("New", "New"), ("BackFill", "BackFill") ) requirement = models.CharField(max_length=100, choices=requirement_choices, default="") candidate_name = models.CharField(max_length=2000, default="") department … -
Connection Refused when using "createdb" to deploy Wagtail site to Heroku
Im attemtping to deploy my first Wagtail site to Heroku but seem to be facing issues with the first steps. When using the createdb command, I get the following 2 errors: I've set ALLOWED_HOSTS to ['*'] to cover everything but i'm unsure of where to update the port number to 5432. The code in my production.py looks like this: from __future__ import absolute_import, unicode_literals from .base import * import dj_database_url import os env = os.environ.copy() SECRET_KEY = env['SECRET_KEY'] DEBUG = False DATABASES['default'] = dj_database_url.config() SECURE_PROXY_SSL_HEADER = ('HTTP_X_FORWARDED_PROTO', 'https') ALLOWED_HOSTS = ['*'] try: from .local import * except ImportError: pass and my dev.py: from .base import * import os env = os.environ.copy() # SECURITY WARNING: don't run with debug turned on in production! DEBUG = True # SECURITY WARNING: keep the secret key used in production secret! SECRET_KEY = 'XXXXX' # SECURITY WARNING: define the correct hosts in production! ALLOWED_HOSTS = ['*', '127.0.0.1'] EMAIL_BACKEND = 'django.core.mail.backends.console.EmailBackend' try: from .local import * except ImportError: pass Any help or pointers to get this up and running on Heroku would be much appreciated. If any additional information is needed I'll happy to provide. -
How to filter the list of a foreign_key form and change the display name in Django admin?
I know I can get the list of values that is displayed in a ForeignKey form in my add/change form filtered based on a queryset if I override the get_form method. But how can I also change the display name of these fields? I know I can use formfield_for_foreignkey method but then I don't have the object to filter the queryset. I couldn't use both because one overrides the other. def get_form(self, request, obj=None, **kwargs): form = super().get_form(request, obj, **kwargs) value = ... #some value used for filtering form.base_fields['some_field'].queryset = ( MyModel.objects.filter(other_field=value) .order_by('name') ) return form Also, when I use the get_form with the queryset filtered, if I am accessing a change_form page, that field is blank even though the instance of the model that I am editing has a value for it. Any thoughts? Reference: formfield_for_foreignkey -
Django, Python unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
I'm creating an appointment application in Django where the end time of the appointment = the start_time + 30 min but I get this error I try a few solutions in stackoverflow, but nothing work for me this is my forms.py class AppointmentForm(forms.ModelForm): doctor = forms.ModelChoiceField(queryset=User.objects.filter(type_of_user=TypeOfUser.DOCTOR)) date = forms.DateField(widget=forms.DateInput(attrs={'type': 'date'}), input_formats=settings.DATE_INPUT_FORMATS) start_time = forms.TimeField(widget=forms.DateInput(attrs={'type': 'time'})) class Meta: model = Appointment fields = ('doctor', 'date', 'start_time',) and this is the views.py from datetime import timedelta import datetime as dt @login_required def create_appointement(request): user = User() if request.user.is_patient(): form_appointement = AppointmentForm(request.POST or None) if request.method=='POST': form_appointement = AppointmentForm(request.POST or None) if form_appointement.is_valid(): form_app = form_appointement.save(commit=False) form_app.user_ho_add = request.user form_app.end_time = form_app.start_time + dt.timedelta(minutes=30) ### form_app.save() messages.success(request, 'appointment added') else: messages.error(request, 'Error') return render(request,'appointement/add_appointement1.html',{'form':form_appointement}) -
How can I send Json Data from python to javascipt
i have this segment of code in a django view (views.py) that returns me a json document, I would like this json document to be sent to a javascript file using fetch. Hope you can help me def get_all_monitors_with_last_data(request): token_type = "Bearer" user = request.user company_user = CompanyUser.objects.get(user=user) company = Company.objects.get(id=company_user.company_id) refresh_time = 60*60*3 now = int(time.time()) get_last_datetime_data = company.last_date_token u_get_last_datetime_data = int(get_last_datetime_data.timestamp()) + refresh_time if(company.token == None or u_get_last_datetime_data < now): token = get_token(company.username, company.password, company.config_grant, company.client_id, company.client_secret) if(token != {}): company.last_date_token = datetime.now() company.token = token["access_token"] company.save() token_access = company.token BASE_API = "http://url"; req = {} params = {} try: req = requests.get(BASE_API+"/urlcomplements/", params = {}, headers = { 'Content-Type': "json", 'Authorization': token_type + " " + token_access }).json(); except requests.exceptions.HTTPError as e: req = {} return JsonResponse(req, safe=False) -
Using Django Framework
Is it a necessity to create a virtual environment when using a Django framework? I have been trying to activate my virtual environment on windows to no avail. What should I do -
django verbose_name remove remove capitalization
How to remove the capitalization of verbose name? a field in models.py betondeckung= models.FloatField(null=True, blank=True, default=None, verbose_name='Betondeckung [cm]') is processed in a html-table with django template language (tempalate.html) using <th scope="col" style="text-align:left">{{ model|get_verbose_field_name:field}}</th> where the following filter is used from templatetag.py @register.filter def get_verbose_field_name(instance, field_name): """ Returns verbose_name for a field. """ return instance._meta.get_field(field_name).verbose_name.title() The problem is that django produces a html that is sent to the browser with: Betondeckung [Cm] Every single word is capitalized, which is not correct for german and here even "cm" becomes "Cm". I tried with css, but the capitalization is already in django. Setting all to lower case using css can also be wrong. Any idea how to switch off the capitalization of the verbose name (in django)? -
Trouble upgrading pop on ElasticBeanstalk
I'm getting the following error (in eb-activity.log) when trying to install a Django application in ElasticBeanstalk Collecting cryptography==3.4.7 (from -r /opt/python/ondeck/app/requirements.txt (line 16)) Downloading https://files.pythonhosted.org/packages/9b/77/461087a514d2e8ece1c975d8216bc03f7048e6090c5166bc34115afdaa53/cryptography-3.4.7.tar.gz (546kB) Complete output from command python setup.py egg_info: =============================DEBUG ASSISTANCE========================== If you are seeing an error here please try the following to successfully install cryptography: Upgrade to the latest pip and try again. This will fix errors for most users. See: https://pip.pypa.io/en/stable/installing/#upgrading-pip =============================DEBUG ASSISTANCE========================== Traceback (most recent call last): File "<string>", line 1, in <module> File "/tmp/pip-build-edwbzxg0/cryptography/setup.py", line 14, in <module> from setuptools_rust import RustExtension ModuleNotFoundError: No module named 'setuptools_rust' ---------------------------------------- Command "python setup.py egg_info" failed with error code 1 in /tmp/pip-build-edwbzxg0/cryptography/ You are using pip version 9.0.1, however version 21.0.1 is available. You should consider upgrading via the 'pip install --upgrade pip' command. 2021-03-29 16:07:25,516 ERROR Error installing dependencies: Command '/opt/python/run/venv/bin/pip install -r /opt/python/ondeck/app/requirements.txt' returned non-zero exit status 1 Traceback (most recent call last): File "/opt/elasticbeanstalk/hooks/appdeploy/pre/03deploy.py", line 22, in main install_dependencies() File "/opt/elasticbeanstalk/hooks/appdeploy/pre/03deploy.py", line 18, in install_dependencies check_call('%s install -r %s' % (os.path.join(APP_VIRTUAL_ENV, 'bin', 'pip'), requirements_file), shell=True) File "/usr/lib64/python2.7/subprocess.py", line 190, in check_call raise CalledProcessError(retcode, cmd) CalledProcessError: Command '/opt/python/run/venv/bin/pip install -r /opt/python/ondeck/app/requirements.txt' returned non-zero exit status 1 (ElasticBeanstalk::ExternalInvocationError) In .ebextensions/02_install.config I do have the … -
How to pass value from template to views on django?
I want to create an input field for comparison in such way that when a user submits a query that goes to a list to compare with subsequent queries objects up to 3 times. I have also set the autocomplete jquery ui widget to suggest the user to submit a query that matches the query with name (one of the model's field) for comparison. So far, I am able to capture the inputs of the user in JS array but I don't know how to pass that in views and display specific objects. views.py from universities.models import Universities universities = Universities.objects.all() uni_names = [] for university in universities: uni_names.append(university.name) def college_comparison_page(request): context = { 'universities': universities, 'uni_names': uni_names, } return render(request, 'college_comparison/college_comparison.html', context) template: <!-- Search --> <div class="search"> <input type="text" name="search" class="searchTerm" id="university-search" placeholder="Search for Universities.."> </div> <!-- JQuery Autocomplete Start --> <script src="https://code.jquery.com/jquery-1.12.4.js"></script> <script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script> <script> const uniNames={{ uni_names|safe|escape }}; $(function() { $("#university-search").autocomplete({ source: function(request, response) { var results=$.ui.autocomplete.filter(uniNames, request.term); response(results.slice(0, 10)); } }); }); // JQuery Autocomplete End // Getting Search Value var unisForCompare=[] var searchValue=document.getElementById('university-search'); searchValue.addEventListener("keydown", function(e) { if (e.key==="Enter") { var uniQuery=searchValue.value; if (uniNames.includes(uniQuery)) { if (unisForCompare.length<3&&(!unisForCompare.includes(uniQuery))) { unisForCompare.push(uniQuery); console.log(unisForCompare); } } } }); // … -
Python ,Django insert into datatable
Hi guys I have a little problem in Django. I need to insert current user id and subject id in data table called user_subjects. I now that I can get currently logged in user id with request.user command. this is my html code where selects options are filled rom database table subjects. <div class="dir-right"> <form method="POST"> {% csrf_token %} <select name="selectedsubject"> <option disabled="true" selected> Select subject </option> {% for results in ShowSubjects %} <option>{{results.subject}}</option> {% endfor %} </select> <div class="form-group"> <br> <button class="addsubject" type="submit">Add subject</button> </div> </form> </div> views.py from django.shortcuts import render from django.contrib.auth.decorators import login_required from directory.models import ShowSubjects from directory.models import SelectedSubject @login_required def directory(request): results=ShowSubjects.objects.all() return render(request, 'directory/directory.html',{'ShowSubjects':results}) def connectsubject(request): if request.method =='POST': if request.POST.get('selectedsubject'): return render(request, 'directory/directory.html') else: return render(request, 'directory/directory.html') models.py from django.db import models from django.db import connections class ShowSubjects(models.Model): subject=models.CharField(max_length=100) class Meta: db_table ='subjects' class SelectedSubject(models.Model): user_id= models.IntegerField() subject_id = models.IntegerField() class Meta: db_table ='user_subjects' -
Why is the regex pattern not matching in django 1.11?
I am trying to pass the ID as an argument to another page on the website using regex using django framework version 1.11: <h2><li><a href="{{school.id}}/">{{ school.name }}</a></li></h2> urls.py from django.conf.urls import url from . import views app_name = "basic_app" urlpatterns = [ url(r'^schools_list/$', views.SchoolList.as_view(), name='list'), url(r'^(?P<pk>\d+)/$', views.SchoolDetail.as_view(),name='detail'), ] However I am getting a 404 Page not found after running the local server: ^basic_app/ ^(?P\d+)/$ [name='detail'] The current path, basic_app/schools_list/1/, didn't match any of these.
