Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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new post gets inserted with other Post.. when i post, a separate box should be formed automatically for that perticular post. in django,html,css
1. css <style> li{ list-style-type: none; } </style> <style> *{ padding: 0; margin: 0; } h1{ font-size: 4vw; color: aqua; font-family: 'Lobster', cursive; position: relative; top: .8vw; left: .5vw; } h1 span{ color: yellow; } ul li a{ text-decoration: none; color: aqua; padding: .3vw; font-family: 'Hammersmith One', sans-serif; font-size: 2vw; } ul li a:hover{ color: yellow; } .nav li{ display: inline-block; position: relative; left: 65vw; bottom: 2.5vw; } .navbar{ background-color: #141526; height: 7.2vw; border-bottom: .5vw aqua solid; } body{ background-color:#090c12; } .main_body{ border: .5vw yellow solid; height: auto; width: 70vw; border-radius: 2vw; margin-left: 2vw; padding: 3.5vw; padding-top: 12vw; padding-bottom: 5vw; overflow: hidden; } .main_body ul li{ color: white; font-family: 'Poppins', sans-serif; position: relative; bottom: 6vw; font-size: 3vw; } #title{ font-size: 4vw; position: relative; bottom: 9vw; color: red; text-decoration: underline; font-family: 'Poppins', sans-serif; } #author{ font-size: 5vw; position: relative; bottom: 10vw; font-family: 'Poppins', sans-serif; color: white; } #delete{ position: relative; top: -3vw; text-decoration: none; background: red; color: black; font-size: 3vw; border-radius: .8vw; padding: .2vw; border: .2vw red solid; font-family: 'Hammersmith One', sans-serif; } #update{ position: relative; top: -3vw; left: .5vw; text-decoration: none; background: greenyellow; color: black; font-size: 3vw; border-radius: .8vw; padding: .2vw; border: .2vw greenyellow solid; font-family: 'Hammersmith One', sans-serif; } … -
Django: Is it possible to initialize an empty form (from formset) in template with a set prefix (other than __prefix__)?
I am using a model formset and adding new forms dynamically to it with {{ formset.empty_form }}. The thing is that I am also using django-ckeditor's RichTextField for one of the fields and, when I add a new form, the editor is not initialized for it. I can type in the text area, but I can't do anything with the editor. I have been told that django-ckeditor is not activated for new forms that are initialized with __prefix__ instead of a new form index. I can change the prefix after I get the new form, but it has already been initialized with __prefix__. The documentation doesn't seem to say much about this. I have also been told that I can change some javascript so django-ckeditor is activated for these newly added forms with __prefix__, but I'm a bit lost there and don't know which or where. So, if I can change this, I think I'll get the editor activated for these forms. -
How to get the latest file of an S3 bucket using Boto3?
I'm trying to get last added file in S3 specific folder. and I refer this(How to download the latest file of an S3 bucket using Boto3?) post and try. @api_view(("GET",)) def get_protocol(request, pk): union = Union.objects.get(pk=pk) s3 = get_s3_client() filepath = "media/private/" + str(pk) + "/certificate/docx" get_last_modified = lambda obj: int(obj["LastModified"].strftime("%s")) objs = s3.list_objects_v2( Bucket="unifolio", Prefix=filepath + "/" + "Union" + str(pk) + "_" + "certificate" + "3", ) last_added = [obj["Key"] for obj in sorted(objs, key=get_last_modified)][0] url = s3.generate_presigned_url( ClientMethod="get_object", Params={"Bucket": "unifolio", "Key": last_added}, # url 생성 후 60초가 지나면 접근 불가 ExpiresIn=60, ) return Response() but the error occur like below: File "/Users/kimdoehoon/project/unifolio/unions/api_views.py", line 199, in get_protocol objs_sorted = [obj["Key"] for obj in sorted(objs, key=get_last_modified)] File "/Users/kimdoehoon/project/unifolio/unions/api_views.py", line 194, in <lambda> get_last_modified = lambda obj: int(obj["LastModified"].strftime("%s")) TypeError: string indices must be integers I don't recognize why indices must be integer error. Could anybody kindly help me? -
Implement Apache2 + Django + Vuejs into one platform
I am stuck with the Integration of Django and vuejs with apache2 into one single application. Basically python manage.py runserver can run the django. Instead of running python manage.py runserver apache2 can do the job. So what I need to do is; need to integrate the apache2 to run both Django (BackEnd)+ vuejs(FrontEnd). I couldn't find a solution for this. Please help me to solve the problem. Currently Django is working along with apache2. But vuejs has no solution. To load vuejs application (FrontEnd), basically we need to run it separately in the terminal npm run serve. What I want to do is; when I run this code service apache2 reload. Backend (Django) and Frontend (vuejs) should load simultaneously. -
Login redirect url in django
I am building a website that have customer and merchant. Each of them have different login. what i want is each user to login to his own view. models.py class User(AbstractUser): is_customer=models.BooleanField(default=False) is_merchant=models.BooleanField(default=False) class Customer(models.Model): user=models.OneToOneField(User,on_delete=models.CASCADE, primary_key=True) class Merchant(models.Model): #user = models.ForeignKey(User, on_delete=models.CASCADE) user=models.OneToOneField(User,on_delete=models.CASCADE, primary_key=True) views.py #merchant view def users_homepage(request): product = Product.objects.filter(merchant=request.user.merchant).order_by('date_added') itemsordered=OrderItem.objects.filter(merchant=request.user.merchant) #customer view def index(request): listing=Category.objects.all() product=Product.objects.all()[:8] setings.py LOGIN_REDIRECT_URL='/users' please show me how i can do it. thanks beforehand. -
Implement one-to-many relation with one-to-one relation without circular dependency
I have two model, User & Company where a company may have multiple users and a single owner(which is also a user). A user can be associated with only one company. Now my question is, how am I supposed to maintain the Owner of any company? Because if I use any one-to-one relation field in Company model then it will give me circular-dependency error as I have foreign-key relation field in my User model. Models are given below: User model class User(BaseMixin, AbstractUser, BlameableMixin): """Extends django user with extra optional fields.""" role = models.ManyToManyField(Role) company = models.ForeignKey( Company, related_name='user_company_map', on_delete=models.SET_NULL, null=True, ) designation = models.CharField(max_length=max_length_medium, blank=True, unique=False) mobile_no = models.CharField(max_length=max_length_medium, blank=False, unique=False) organization = models.CharField(max_length=max_length_medium, blank=False, unique=False) Company model class Company(BaseMixin, BlameableMixin): """Company detail.""" name = models.CharField(max_length=max_length_large, blank=True, unique=False) code_name = models.CharField(max_length=max_length_large, blank=True, unique=True) domain = models.CharField(max_length=max_length_large, blank=True) As shown on the code above I have a foreign key field on User model that connects my User model to Company model. Now I would like to have a field that will help me to keep track of a user who is the owner of any specific company. It will be also very helpful if you provide the django-orm queries for … -
Dynamically redirecting in django
I am trying to dynamically redirect from one dynamic page to another. Think about being on an IMDB movie page (dynamic) and then following the link to the writer/director/actor page(dynamic). These are the urls: urlpatterns = [ path('', views.index, name="index"), path('writer/<int:id>', views.writer, name="writer"), path('title/<int:id>', views.title, name="title"), path('creator/', views.creator, name="creator"), ] This is the index.html: {% for pilots in pilot %} <div> <p>Title: <a href="title/{{ pilots.id }}">{{ pilots.title }}</a></p> {% for writers in pilots.creators.all %} <p>Writer: <a href="writer/{{ writers.id }}">{{ writers.writer }}</a></p> {% endfor %} </div> {% endfor %} This is the title.html (which the dynamic ahref isn't working): {% for title in titles %} <p>{{title.title}}</p> <p>{{title.count}}</p> <p>{{title.year}}</p> <p>{{title.description}}</p> {% for creators in title.creators.all %} <a href="creator/">{{creators.writer}}</a> {% endfor %} {% endfor %} And this is the views.py: def title(request, id): titles = Pilot.objects.filter(id=id) context = { 'titles': titles, } return render(request, 'title.html', context) def creator(request): return redirect(f'writer/{id}') -
Filter many-to-many field DRF
I need to filter my API response of document using a many-to-many category field. This is my model: class Document(models.Model): name = models.CharField(max_length = 100, blank = True) file = models.FileField(null = True, upload_to='documents/', validators=[FileExtensionValidator(allowed_extensions=['pdf'])]) date_created = models.DateTimeField(auto_now_add = True, null = True) category = models.ManyToManyField(Category) company = models.ForeignKey(Company, null = True, on_delete = models.SET_NULL) author = models.ForeignKey(Employee, null = True, on_delete = models.SET_NULL) The serializer for this models is: class DocumentSerializer(serializers.ModelSerializer): class Meta: model = Document fields = "__all__" And I'm trying to filter it with this: class DocumentFilter(filters.FilterSet): # having_category = filters.Filter(name = 'category', lookup_type = 'in') class Meta: model = Document fields = { 'company': ['exact'], 'author': ['exact'], # 'category': ['in'] } I tried using this solution as you can see in the code but wasn't successful. filtering with company and author are working, and I'm facing an issue only with category. How should I create the filter? -
Django validate_unique restricts update/patch
I have this model which is serialized via DRF class Orders(models.Model): accession = models.CharField(max_length=20) testcode = models.ForeignKey(TestCodes, on_delete=models.CASCADE, related_name='tcodes') # testName = models.ForeignKey(TestCodes, on_delete=models.CASCADE, to_field='testname', related_name='tnames') method = models.CharField(max_length=50, blank=True, null=True, default='NGS') custName = models.CharField(max_length=50) testSite = models.CharField(max_length=50) procedure = models.ForeignKey(Workflows, on_delete=models.CASCADE, blank=True, null=True) where I'm trying to make the accession and testcode fields combination unique to prevent user from creating the same accession with the same testcode def validate_unique(self, exclude=None): qs = Orders.objects.filter(accession=self.accession) if qs.filter(testcode=self.testcode).exists(): raise ValidationError('Accession must be unique per testcode') it works well but if I try to patch or update other fields it raises the validation error 'Accession must be unique per testcode' is there a workaround for this issue -
How to get all the appended sinlge input files?
Here user selects only one image at once and the selected image gets appended inside the ul tag. There is max limit to 5 images inside the ul tag but I am being unable to get all the files selected in my django view. I want to send those all the images inside the ul tag to the backend . Right now only the last image selected is passing. What I have to do for this ? js var prew = true; function readURL(input) { if (input.files && input.files[0]) { var reader = new FileReader(); reader.onload = function(e) { var thumbnail = e.target.result; img = ` <li> <div class="image"> <img src="${e.target.result}" width="100" height="100"/> <div class="close"><div class="ic-close" id="img-remove"></div> </div></li> ` if (prew) { $("#thumbnail").attr('src', thumbnail); prew = false; } $('#blah').append(img); if ($('ul#blah li').length > 5) { $("#blah li:last-child").remove(); alert("You can't upload more than 5 images."); } } reader.readAsDataURL(input.files[0]); $('ul#blah').on('click', '.ic-close', function(e) { console.log('k'); $(this).closest('li').remove(); }); } } $("#imgInp").change(function() { readURL(this); //var files = $('#imgInp').prop('files'); //console.log(files) }); html <ul class="list list-inline list--image" id="blah"> <li class="thumbnail"> <div class="image"> <img id="thumbnail" src="" width="100" height="100" /> <p>Thumbnail</p> </div> </li> <div class="files--upload"><input class="d-none imgUpload" name="image" type="file" id="imgInp" placeholder="" /><label class="upload-label" for="imgInp"> <div class="ic-add"></div> <div class="mt-2">Add Photo</div> … -
Django: How to redirect UpdateView in the get request
I have a use-case in which if a drop-down changes, the view should be redirected to another view. In the update view, I am using built-in class-based view, UpdateView. How do I redirect if the redirect is needed before submitting the form. I take it that get_success_url() works for when the form is submitted -
How to solve local variable referenced before assignment and return form data in template correctly?
I want to return the item code and item number entered in the form in the template. This is a very simple application. views.py def index(request): csv_form = '' if request.method == 'POST': csv_form = CsvForm(request.POST, request.FILES) if csv_form.is_valid(): csv_itemcode= csv_form.cleaned_data['item_code'] csv_itemnumber= csv_form.cleaned_data['item_number'] else: csv_form = CsvForm() context = {'csv_itemcode': csv_itemcode, 'csv_itemnumber': csv_itemnumber,'csv_form':csv_form} return render(request,'colorlib-regform-6/submit.html',context) submit.html <html> <body> <h4>{{ csv_itemcode }}</h4> <h4>{{ csv_itemnumber }}</h4> </body> </html> I got local variable csv_itemcode referenced before assignment. Any suggestions towards this. -
When I create a single form, 2 forms appear. Why is that happening ? Thanks
Hello everyone i got a problem and i tried hard to fix it but i cant solve. When i add my form to my template (only using {{ form.dept }}) it happens 2 form on my site. My Models.py > class Kaydol(models.Model): name=models.CharField(max_length=40) surname=models.CharField(max_length=40) email=models.EmailField(max_length=100) DEPARTMENTS=[ ('BK', 'Hiç Birisi'), ('KK', 'Kredi Kartı ile Ödeme'), ('Çek', 'Çek ile Ödeme') ] dept=models.CharField(max_length=3, choices=DEPARTMENTS, default='BK') my forms.py > class KaydolForm(forms.ModelForm): class Meta: model = Kaydol fields = ['name', 'surname', 'email','dept'] widgets = { 'name': forms.TextInput(attrs={'placeholder':"Adınız"}), 'surname': forms.TextInput(attrs={'placeholder': "Soyadınız"}), 'email': forms.TextInput(attrs={'placeholder': "Email"}) views.py def kaydol(request): if request.method == 'POST': form = KaydolForm(request.POST) if form.is_valid(): form.save() form = KaydolForm() else: form = KaydolForm() form=KaydolForm() context = { 'form':form } return render(request,'index.html',context) and my html > <div class="col-sm-12"> <b>Alternatif Ödeme Kanalı</b> {{ form.dept }} -
default=True is not reflected in django admin BooleanField
I have added a field this_field in django models but in admin its False. My model. this_field = models.BooleanField(default=True) My migration: migrations.AlterField( model_name='a', name='this_field', field=models.BooleanField(default=True), ), Default value should be true of the field but its not working default is shown as false. When I add a new field that_field as models.BooleanField(default=True) its default is true but this_field is an old field and its its values is not being reflected in django admin . -
How to catch CSRF errors in Django
How would I go about catching CSRF errors in Django? For example, I would like to catch this: Forbidden (CSRF token missing or incorrect.): /asdjasdjk/asdhriheiof I want to do this because I want to ban people who tamper with CSRF codes for my particular case. Any help is appreciated. -
How to Upload image or select from sample images in Django?
I am working on a website where I want to give an option to the customer to Upload the image by him/her or he/she can select images from given samples. Can you help me, how can I provide these options? And also explain to me how should I create a pop-up to display sample images. I am a newbie and working on Django 2.2 with MySQL. -
python requests json api problem. it only returns 1000 enteries
i want to pull this api data https://data.ct.gov/resource/6tja-6vdt.json. There is 19k entries in the website but when I pull through requests.get it returns only 1000. HOw to get all data at once? how to use limits and offsets and loops to get all at once -
ValueError at /save_data/
ValueError at /save_data/ Cannot assign "'IT'": "ProfileModel.itype" must be a "IndustriesModel" instance this is the error i am getting when saving the data to profilemodel could this is my models: def save_data(request): ed=request.POST.get("p1") ph=request.POST.get("p2") re=request.POST.get("p3") ty=request.POST.get("p4") ProfileModel(education=ed,photo=ph,resume=re,itype=ty).save() return render(request,"process_templates/login.html") and the views.py : ''' class IndustriesModel(models.Model): ino=models.AutoField(primary_key=True) type=models.CharField(max_length=100) def __str__(self): return self.type class ProfileModel(models.Model): pno=models.AutoField(primary_key=True) person=models.OneToOneField(RegistrationModel,on_delete=models.CASCADE) education=models.CharField(max_length=100) photo=models.ImageField(upload_to='user_images/') resume=models.FileField(upload_to='user_resumes/') itype=models.OneToOneField(IndustriesModel,on_delete=models.CASCADE) ''' could anyone help me solving the issue i am using html to not the forms. -
how to create related object while uploading csv in django
I am trying to create a foreignkey object when uploading csv as follows, def user_upload(request): data_set = csv_file.read().decode('UTF-8') io_string = io.StringIO(data_set) next(io_string) for column in csv.reader(io_string, delimiter=',', quotechar="|"): if len(column) > 9: try: users = User( username=column[0], first_name=column[1], last_name=column[2], email=column[3], add_1=column[4], add_2=column[5], suburb=column[6], state=column[7], postcode=column[8], country=column[9], ) users.set_password('password') users.save() pricing = Pricing.objects.get(name='Free Trial') for user in users: subscription = Subscription.objects.create(user=user, pricing=pricing) stripe_customer = stripe.Customer.create( email=user.email ) stripe_subscription = stripe.Subscription.create( customer=stripe_customer["id"], items=[{'price': 'price_1HkPcpOS8'}], trial_period_days=7 ) subscription.status = stripe_subscription["status"] subscription.stripe_subscription_id = stripe_subscription["id"] subscription.save() except IntegrityError as e: return render_to_response('snippets/message.html') context = {} return render(request, template, context) User part is working but the related object Subscription is not getting updated as it throws error User is not iterable, how I can upload to related tables, thanks -
Django For Loop Creating Empty Divs
I am trying to loop through a list of items that are associated with a list of orders within my template and the loop is generating empty rows in my html because its looping through ALL OrderItems in my database. div class="container"> {% for order in orders %} <div class="col-lg-6"> <h3>{{order.topic}}, {{order.entry}} - Order #{{order.id}}</h3> <div class="box-element"> <div class="cart-row"> <div style="flex: 2;"></div> <div style="flex: 2;"><strong>Item</strong></div> <div style="flex: 1;"><strong>Price</strong></div> <div style="flex: 1;"><strong>Quantity</strong></div> <div style="flex: 1;"><strong>Total</strong></div> </div> {% for item in items %} <div class="cart-row"> {% if item.order.id == order.id %} <div style="flex: 2"><img class="row-image" src="{{ item.menu_item.image.url }}"></div> <div style="flex: 2">{{item.menu_item.title}}</div> <div style="flex: 1">{{item.menu_item.price}}</div> <div style="flex: 1"> <p class="quantity">{{order.get_cart_items}}</p> </div> <div style="flex: 1">${{order.get_cart_total}}</div> {% else %} {% endif %} </div> {% empty %} {% endfor %} </div> </div> {% empty %} <p>No Orders exist</p> {% endfor %} </div> I think the problem is that the items Queryset (shown in my view below) is returning all Orderitems in my DB and then i am looping through them in the template. How can I perform this loop in my view so i don't run into this problem (and future performance bottleneck) in my template? def orders(request): """View open orders for a customer""" if request.user.is_authenticated: … -
count total object in foreign key - drf
i want to count comments for every single Post in models.py: class Post(models.Model): body = models.TextField(max_length=10000) date = models.DateTimeField(auto_now_add=True, blank=True) user = models.ForeignKey(User, on_delete=models.CASCADE) liked_by = models.ManyToManyField(User, blank=True, related_name='liked_by') class Meta: ordering = ['-date'] class Comment(models.Model): body = models.TextField(max_length=1000) date = models.DateTimeField(auto_now_add=True, blank=True) user = models.ForeignKey(User, on_delete=models.CASCADE) post = models.ForeignKey(Post, on_delete=models.CASCADE) class Meta: ordering = ['-date'] in serializers.py: class CommentSerializer(serializers.ModelSerializer): class Meta: model = Comment fields = '__all__' class PostSerializer(serializers.ModelSerializer): #comments = CommentSerializer() user = UserSerializers() total_likes = serializers.SerializerMethodField() liked_by = SimpleUserSerializer(many=True, read_only=True) total_comments = serializers.SerializerMethodField() class Meta: model = Post fields = ('body','date','user', 'total_likes', 'liked_by','total_comments') def get_total_likes(self, instance): return instance.liked_by.count() def get_total_comments(self, instance): return instance.comments.count() when i run this code, it shows, AttributeError: 'Post' object has no attribute 'comments'. how do i count comments of a post? -
Create a 'post' object and initialize a m2m attribute with post id and author id
I am trying to accomplish the following in Django: An app that allows users to create image posts. They can view any post that is in the system and add those posts to their bookmarks. When a user creates a post, the post is automatically added to their bookmarks. Model class Post(models.Model): id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False) post_image = models.ImageField(max_length=255, upload_to='images/content/', blank=False, null=False) author = models.ForeignKey(User, on_delete=models.PROTECT, related_name='authors') tags = TaggableManager(through=UUIDTaggedItem, help_text=_('Maximum of 5 tags allowed')) created = models.DateTimeField(auto_now_add=True) bookmarks = models.ManyToManyField(User, related_name='bookmarked', blank=True) bookmark_count = models.IntegerField(default=0) def get_create_date(self): return self.created.strftime("%B %Y") ordering = ['-created'] View @login_required def post_add_view(request, *args, **kwargs): context = {} user = request.user if request.method == 'POST': form = PostAddForm(request.POST, request.FILES) if form.is_valid(): new_post = form.save(commit=False) new_post.author = user new_post.save() form.save_m2m() context['form'] = form messages.add_message(request, messages.SUCCESS, 'Image uploaded successfuly!') return redirect('library:posts') context['form'] = form return render(request, 'library/post_add.html', context) else: form = PostAddForm() context['form'] = form return render(request, 'library/post_add.html', context) When a user creates a new post, that post will be associated with an additional attribute in the Post object called 'bookmarks'. The 'bookmarks' attribute has a many-to-many relationship with author and post. I can easily create the post object, associate it with the author and save … -
Django: Javascript error with alert box displaying values
I am creating a web application that will serve as a grocery store. The way I set it up is so the customer can come onto the website, click on the items that they would like to purchase, and then click a submit button to purchase those items. The problem I am running into is that my Javascript is not printing the correct values. In both spots, it says undefined. I will put a picture below for reference. views.py def inventory(request): products = request.POST.getlist('products') for product in products: a = Post.objects.get(title=product) a.quantity = a.quantity -1 a.save() print(products) return redirect('blog-home') home.html {% extends "blog/base.html" %} {% load static %} {% block content %} <form action="{% url 'js' %}" method="POST" id="menuForm"> {% for post in posts %} {% if post.quantity > 0 %} <article class="media content-section"> <div class="media-body"> <div class="article-metadata"> <a class="mr-2">{{ post.category }}</a> </div> <h2><a class="article-title" >{{ post.title }}</a></h2> <p class="article-content"> Price: ${{ post.Price }}</p> <p class="article-content"> Sale: ${{ post.Sale }}</p> <input type="checkbox" id="product_{{ post.id }}" value="{{ post.title }}" form="menuForm" name="products" > Inventory count: {{ post.quantity }} </input> </div> </article> {% else %} {% endif %} {% endfor %} <button id="btn" type="submit" form="menuForm">Confirm Purchase</button> </form> <script src="{% static "JS/javascript.js" %}" type="text/javascript"></script> … -
How do I solve this error of Pymongo? cursor id not found pymongo
I'm getting the whole data of some collection in MongoDB and after a while (like 30 or 60 minutes), the script raises the following error: pymongo.errors.CursorNotFound: cursor id 1801580172063793986 not found, full error: {'ok': 0.0, 'errmsg': 'cursor id 1801580172063793986 not found', 'code': 43, 'codeName': 'CursorNotFound'} This error occurs after the 24k documents. I'm using Django and Pymongo connected to the database in the local server. The collection has like 60k documents. This is how I'm getting the data: client = MongoClient(settings.MONGO_HOST, settings.MONGO_PORT) collection = client[settings.MONGO_DB].users cursor = users.find(no_cursor_timeout=True) for user in cursor: # getting the data from the user Just in case, I'm using: Python 3.8 Django 3.1.4 Pymongo 3.11.0 Mongod 4.4.2 (for the local server) Ubuntu 20.04 -
Django: preserving GET parameters in URL template tag
I'm using a GET parameter in my Django app to pass in information, that I want to be preserved in future links using Django's {% url %} template tag. In my case, this is to allow view-only access within the app. Example URL: https://my.app/entry/123?key=abcdef An example link on that page is already created like this: <a href="{% url 'entry_detail' entry.id %}">View more details</a> Desired result: I would like Django's URL template tag to automatically preserve any GET parameters named key throughout the app. In this case, it would generate new URLs with that same parameter applied. For example: https://my.app/entry/123/details?key=abcdef Workarounds This blog post and this gist solve the problem by creating a new template tag and using that instead of Django's url template tag. Is that really the best solution? I'd end up having to replace every instance of {% url %} throughout my app with my own tag. It also wouldn't fix the use of reverse().
