Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Why does my website keep on having Privacy issue?
Does anyone know the reason for Privacy Issue? But it only happens on my website url without the ("www").For example, when accessing the url https://mywebsite.com, it shows the "Your connection is not private" sometimes. But my SSL certificate is still valid and not yet expired. But when I access the full url, https://www.mywebsite.com, there is no privacy issue. I hope someone can help me. Thank you. -
Getting the value of select option Django
Im been having a trouble how can I get the the value of my select option, I been using javascript to set the value of select option, below is my code which is returning the province value to number instead of text. The problem is how can I convert the number to text, is there any expert who share solution about this. views.py def sample_data(request): if request.method=='POST': province = request.POST['list1'] print(province) #return ex. 2 depend on select value return render (request,'sample.html') Select option - my reference link <select id="list1" name ="list1" onchange="updateList('list2', this);"></select> <select id="list2" name ="list2" onchange="updateList('list3', this);"></select>> <select id="list3" name ="list3"></select> javascript let data = [{"id":1,"name":"USA","parentid":0}, {"id":2,"name":"Japan","parentid":0}, {"id":3,"name":"Europe","parentid":0}, {"id":4,"name":"California","parentid":1}, {"id":5,"name":"Oklahoma","parentid":1}, {"id":6,"name":"Arizona","parentid":1}, {"id":7,"name":"Kantô","parentid":2}, {"id":8,"name":"Kansai","parentid":2}, {"id":9,"name":"Chügoku","parentid":2}, {"id":10,"name":"France","parentid":3}, {"id":11,"name":"Deutschland","parentid":3}, {"id":12,"name":"Espana","parentid":3}, {"id":13,"name":"Sacramento","parentid":4}, {"id":14,"name":"Los Angeles","parentid":4}, {"id":15,"name":"San Diego","parentid":4}, {"id":16,"name":"Tulsa","parentid":5}, {"id":17,"name":"Oklahoma City","parentid":5}, {"id":18,"name":"Lawton","parentid":5}, {"id":19,"name":"Phoenix","parentid":6}, {"id":20,"name":"Flagstaff","parentid":6}, {"id":21,"name":"Tucson","parentid":6}, {"id":21,"name":"Tokyo","parentid":7}, {"id":22,"name":"Chiba","parentid":7}, {"id":23,"name":"Tochigi","parentid":7}, {"id":24,"name":"Kyoto","parentid":8}, {"id":25,"name":"Osaka","parentid":8}, {"id":26,"name":"Nara","parentid":8}, {"id":27,"name":"Tottori","parentid":9}, {"id":28,"name":"Hirochima","parentid":9}, {"id":29,"name":"Okayama","parentid":9}, {"id":30,"name":"Quimper","parentid":10}, {"id":31,"name":"Toulouse","parentid":10}, {"id":32,"name":"Nancy","parentid":10}, {"id":33,"name":"Dusseldorf","parentid":11}, {"id":34,"name":"Leipzig","parentid":11}, {"id":35,"name":"Munchen","parentid":11}, {"id":36,"name":"Barcelona","parentid":12}, {"id":37,"name":"Sevilla","parentid":12}, {"id":38,"name":"Guernica","parentid":12}] function populateList(list, pid) { let l = document.getElementById(list); l.innerHTML = ""; let topItem = document.createElement("option"); topItem.value = 0; topItem.text = "--Select--"; l.appendChild(topItem); let items = data.filter(item => item.parentid == pid); items.forEach(function(item){ let newItem = document.createElement("option"); newItem.value = item.id; newItem.text = item.name; l.appendChild(newItem); }) } function updateList(selList, thisList) { if (thisList.value != … -
Django: Select from the dropdown the object that has the field is_active=True
i'm a newbie using django and i have a problem that cannot solve. In my ServiceCreateView i need to select from the dropdown the object car that has the field is_active = true, how can i acomplish that? class Car(models.Model): brand = models.charfield(...) is_active= models.BooleanField(default=True) class Service(models.Model): car = models.ForeingKey('Car'....) name = models.Charfield() class ServiceCreateView(CreateView): model = Service form = ServiceForm ... If i change the field is_active to false in Car model, should not be shown in the dropdown. can someone put me in the right direction? -
Errors when passing a list through URL in Django
I try to pass a list through an URL in Django. I found this: Passing a list through url in django But I still get Errors. I feel like Iam running in a circle. My urls: path('query/', include(('query.urls', 'query-space'), namespace='query-space')), re_path(r'^2/(?P<amb_list>\w+)/$',views.ambitionGenPage, name='userambitiongen'), My views: def ambitionPage(request): if request.method == 'POST': form = AmbitionForm(request.POST) if form.is_valid(): ambs_list = form.cleaned_data['ambition_field'] redirect = HttpResponseRedirect(reverse('query-space:userambitiongen')) redirect['Location'] += '&'.join(['ambs={}'.format(x) for x in ambs_list]) return redirect form = AmbitionForm() return render(request, 'query/ambition.html',{'form':form,}) def ambitionGenPage(request): ambitions = request.GET.getlist('amb_list') if ambitions: ambitions = [int(x) for x in ambitions] print(ambitions) #I first want to check what data I get return render(request, 'query/ambitionGen.html',{}) I adapted the code of the link. In the line: redirect = HttpResponseRedirect(reverse('query-space:userambitiongen', args=(amb_list))) he doesnt know the argument: NameError: name 'amb_list' is not defined In the example there is no argument. When I try this I get the error: Reverse for 'userambitiongen' with no arguments not found. 1 pattern(s) tried: ['query/2/(?P<amb_list>\\w+)/$'] I also found nothing in the internet to this expression: redirect['Location'] Could someone explain to me what ['Location'] stands for? What would be the right solution? I tried to find it by myself in many hours. Thank you very much for your time! -
Django save() method won't save my forms and can't create a new instance
I want to save 2 forms in my django view: def create_model(request): context = { 'form_one' : Register_modelOne(prefix = 'form_one'), 'form_two' : Register_modelTwo(prefix = 'form_two'), } if request.method == "POST": form_one = Register_modelOne(request.POST, prefix = 'form_one') form_two = Register_modelTwo(request.POST, prefix = 'form_two') if form_one.is_valid() and form_two.is_valid(): form_one.save() form_two.save() ParentModel.objects.create(name = 'mymodel', element_one = form_one, element_two = form_two) The whole point is to create a new ParentModel which has a manyToMany() relation with both modelOne and modelTwo. But Django won't save it in my database this way. Does anyone have any idea why? (also even form_one and form_two are not saved in the database with this method) note: This is connected to my question in Another Question -
Django template - How to get key, value(list) from a dictionary in the request context
I have my context in a html template and I'm not able to read the value which is a List of objects from key in my dictionary. This is my context: {'month_posts': defaultdict(<class 'list'>, {'October': [<Post: Set pagination>, <Post: Test pagination>], 'November': [<Post: Redesign Model>]} ) } This is the for loop I'm implementing to get the key and value: {% for month, posts in month_posts.items %} ... <h3>{{ month | capfirst }}</h3> {% for post in month_posts[month] %} <a href="#">{{ post.title }}</a> {% endfor %} ... {% endfor %} I got this error: Could not parse the remainder: '[month]' from 'month_posts[month]' I have tried these: {% for month in month_posts %} I got no errors but also no data in my template. Do you have any idea how I could get the List in the value of the Dictionary? Thanks. -
Not able to insert data into database using Django
I am a beginner in Django and I am trying to insert values into the auth_user table. But somehow I am not able to do so. I tried to resolve but everything seems to go in vain. Here is my views.py: from django.shortcuts import render,redirect from django.contrib.auth.models import User, auth # Create your views here. def register(request): if request.method == 'POST' : firstname = request.POST['firstname'] lastname = request.POST[ 'lastname'] emailid= request.POST['emailid'] username= firstname+lastname passwordl = request.POST['password'] user = User.objects.create_user(username=username,first_name=firstname,last_name=lastname) user.save() return redirect('admin/') else: return render(request, 'employee/register.html') This the urls.py from django.urls import path from . import views urlpatterns = [ path('register/', views.register, name='register'), ] I can also notice than when I click register button I get an error that employee\register\register was called which doesnt exist, which is strange as employee\register is to be fetched. -
How to pass currently user ID/PK from view to form in Django?
The problem I'm having is I'm trying to create a form which passes the currently logged-in users ID by embedding it within a hidden field in a ModelForm. Models.py class UserPhotos(models.Model): user = models.ForeignKey(NewUser, on_delete=models.CASCADE) #photos = models.ImageField(height_field=1350, width_field=1080) description = models.CharField(max_length=200) date = models.DateTimeField(auto_now=True) class Meta: '''Change plural name''' verbose_name_plural = 'Photos' Forms.py class AddPhotos(forms.ModelForm): user = forms.CharField(widget = forms.HiddenInput(), required=False) class Meta: model = UserPhotos fields = ( 'description','user', ) Views.py def add_photo(request): context = {} user = request.user if not user.is_authenticated: return redirect('my_app:login',) if request.POST: form = AddPhotos(request.POST) if form.is_valid(): form.save(commit=False) form.user=request.user form.save return redirect('/') else: context['photoAdd_form'] = form else: form = AddPhotos() context['photoAdd_form'] = form return render(request, 'main/photo_add.html', context) I have tried something like this It's works, but I have no idea how to pass the ID to the init. It gave me a error : KeyError at /add 'userID' Forms.py ... def __init__(self, *args, **kwargs): #It is works but how will i pass the data request = kwargs.pop('userId') print(request) super(AddPhotos, self).__init__(*args, **kwargs) self.fields['user'].initial = request.user Views.py def add_photo(request): context = {} user = request.user if not user.is_authenticated: return redirect('my_app:login',) if request.POST: form = AddPhotos(request.POST, userId = request.user.id) ... -
django autotranslate gives an error "IndexError:list index out of range"
I have configured django autotranslate as per the direction on the pypi page but when I try to run the translate_messages command, it throws back an error return lambda: self._basic_translate(text, target_language, source_lauguage)[0] File "C:\Users\Richards\AppData\Local\Programs\Python\Python38\lib\site-packages\goslate.py", line 253, in _basic_translate data = {'src': raw_data[-1][0][0]} IndexError: list index out of range I dont have have a explicit list in my project, just querysets and its quite numerous. please help me on this -
Redirect Reverse to specific view with arguments
In the same app, I have a form that can be rendered and processed in two different views. The url for the views are defined as following: app_name = 'table' urlpatterns = [ path('<int:table_pk>/order/', include([ path('', views.table_detail_category_view, name='table_detail_category_view'), path('<str:menu_category>/', views.table_detail_item_view, name='table_detail_item_view'), ])), ] The processing of the form, however, is implemented in only one of the views (for eg. table_detail_category_view) since it is redundant to implement one more time (one for each view). After processing the form, I have to redirect the page to whatever view that was displayed before. Specifically, I am looking for something like this: if request.method == 'POST': ...process form... if previous_view = table_detail_category_view: return redirect(reverse('table:table_detail_category_view', args=(table_pk,))) else: if previous_view = table_detail_item_view: return redirect(reverse('table:table_detail_item_view', args=(table_pk, category,))) The variables table_pk and category are present in both views. I am trying to avoid implementing the form-processing twice (one in each view) in order to redirect reverse to the appropriate view. That method does not seem DRY. Thanks. -
How to use async with Mutation in Django-graphene
I have a problem, where I want to optimise a client call to a mutation in a GraphQL API. The mutation executes 2 methods, where one is slow and where the result does not need to be send back to the client. I have tried to look at Django signals to handle this, but since signals are executed in sync, there is no benefit. Also, using Django signal request_finished seems not possible, because the method I need to execute needs to access model instance. So my question is this. Lets say I have a Django Model and I have two methods I use in a mutation. class My_model(models.Model): some_field = models.CharField() def some_method(): return "do something" def some_other_method(): return "do something else" Now I have a mutation like the one below, where I do not want the client to wait for the execution of the method My_model.some_other_method() class CreateTwoObjects(graphene.Mutation): result = graphene.String() def mutate(self, info, input): result = My_model.some_method() # method to not wait for My_model.some_other_method() return CreateTwoObjects(result = result) Is there a way I can execute this method in async and not have client wait for the return? -
Displaying only linked tags Django Admin
i have product tag and its variations of tag example: Color|green Quality|bad i need to display only linked variations when i create product i need to display only colors when i choice color models.py class Variety(models.Model): varietyName = models.CharField(max_length=30) def __str__(self): return self.varietyName class Meta: verbose_name = "List variations" class Tag(models.Model): STATUS_VARIETY=( ('Filters', 'Filter'), ('Variaty', 'Variaty'), ('Boths', 'Boths'), ) status = models.CharField(max_length=10, choices=STATUS_VARIETY, default='Boths', verbose_name='status') name = models.CharField(max_length=255, verbose_name='name') variety = models.ManyToManyField(Variety, related_name='children', verbose_name='Parent') def __str__(self): return self.name class Meta: verbose_name = "Variation" verbose_name_plural = "Variations" class Productcopy(models.Model): STATUS_PRODUCT=( ('Publish', 'Publish'), ('Not_to_publish', 'Not_to_publish'), ) status = models.CharField(max_length=30, choices=STATUS_PRODUCT, verbose_name='status') name = models.CharField(max_length=100, verbose_name='name') tag = models.ForeignKey(Tag, verbose_name='Variation', on_delete=models.CASCADE) variety = models.ManyToManyField(Variety, verbose_name='Variations') def __str__(self): return self.name class Meta: verbose_name = "product" verbose_name_plural = "products" admin.py from .models import * class TagAdmin(admin.ModelAdmin): list_display = ('name', 'status',) filter_horizontal = ('variety',) class ProductcopyAdmin(admin.ModelAdmin): list_display = ('name', 'status',) filter_horizontal = ('variety',) admin.site.register(Tag,TagAdmin) admin.site.register(Productcopy,ProductcopyAdmin) admin.site.register(Variety) -
Django on Apache2: Issue in.conf-file?
Good day to all of you, together with our admin in our company, we're trying to deploy Django on Apache2 together with mod_wsgi, but we're facing some minor issues. I'm hoping, some of you might help and take a look at the following lines!? Right now, the directory on our server is looking like this: ./var/www/ |-- myproject |-- manage.py |-- project/ |-- __init__.py |-- settings.py |-- urls.py |-- wsgi.py |-- statics |-- venv When I'm trying to open the site, it just keeps on loading but nothings gonna happen! I'm wondering wether the data inside our .conf-file might be wrong! <VirtualHost *:80> . . . Alias /static /var/www/myproject/static <Directory /var/www/myproject/static> Require all granted </Directory> <Directory /var/www/myproject/project> <Files wsgi.py> Require all granted </Files> </Directory> WSGIDaemonProcess myproject python-path=/var/www/myproject python-home=/var/www/myproject/venv WSGIProcessGroup myproject WSGIScriptAlias / /var/www/myproject/project/wsgi.py </VirtualHost> If I understood it correctly, the "python-home" inside the "WSGIDaemonProcess" should point onto my Virtual Environment to collect the necessary components and the "python-path" onto my project!? I also noticed, that the current running python-version on the server is 2.7.6, although my admin installed version 3.7. The installed mod_wsgi is "libapache2-mod-wsgi-py3" for python 3x! Could this also be a problem? Thanks and a great day to … -
In S3 Bucket CORS Configrations not allowing xml and asking for json instead
In S3 Bucket CORS Configrations not allowing "XML" and asking for "Json" instead <?xml version="1.0" encoding="UTF-8"?> <CORSConfiguration xmlns="http://s3.amazonaws.com/doc/2006-03-01/"> <CORSRule> <AllowedOrigin>*</AllowedOrigin> <AllowedMethod>GET</AllowedMethod> <AllowedMethod>POST</AllowedMethod> <AllowedMethod>PUT</AllowedMethod> <AllowedHeader>*</AllowedHeader> </CORSRule> </CORSConfiguration> Was Working earlier but now it is giving me this error "The CORS configuration must be written in valid JSON." Some Changes are made in "Amazon S3 Bucket" by AMAZON , Please give me json of this to add in CORS ? -
Djnago 'ImageFieldFile' object has no attribute '_meta'
Actually i'm trying to update user profile but when i try to update it it show's the error. AttributeError at /user/profile/ 'ImageFieldFile' object has no attribute '_meta' After searching so many solution i can't get rid of it. I am messing with my code from 24hrs. Please help me to get rid of this. -- My code is --- Views.py @login_required() def profile(request): if request.method=='POST': u_form = UserUpdateForm(request.POST,instance=request.user) p_form = ProfilePicUpdateForm(request.POST,request.FILES,instance=request.user.profile_image) if u_form.is_valid() and p_form.is_valid(): u_form.save() p_form.save() messages.success(request, f'Account Created Successfully for {username}') redirect('profile/') else: u_form = UserUpdateForm(instance=request.user) p_form = ProfilePicUpdateForm() context = {'u_form': u_form,'p_form':p_form} return render(request,'profile.html',context) Forms.py class UserUpdateForm(forms.ModelForm): username = forms.CharField() email = forms.EmailField() first_name = forms.CharField() last_name = forms.CharField() class Meta: model = KeepSafeUserModel fields = ['username','email','first_name','last_name'] class ProfilePicUpdateForm(forms.ModelForm): class Meta: model = KeepSafeUserModel fields = ['profile_image'] Models.py from django.db import models from django.contrib.auth.models import User from django.contrib.auth.models import ( BaseUserManager, AbstractBaseUser ) # ///////////////User Manager///////////////////// # Create your models here. # overriding the create and superuser function class MyAccountManager(BaseUserManager): def create_user(self,email,username,password=None): if not email: raise ValueError("Users Must Have email Address") if not username: raise ValueError("Users Must Have username") user = self.model( email=self.normalize_email(email), username=username, ) user.set_password(password) user.save(using=self._db) return user def create_superuser(self,email,username,password): user = self.create_user( email = self.normalize_email(email), … -
Foreign key value in Django REST Framework Datatables
I followed this SOF question Foreign key value in Django REST Framework closely and many others plus read this documentation and similar multiple times https://datatables.net/manual/tech-notes/4 but have yet to find a solution. Error message: DataTables warning: table id=entrytable - Requested unknown parameter 'symbol' for row 0, column 9. For more information about this error, please see http://datatables.net/tn/4 However, the right symbol.name does work in the end when I click okay on the error message.. I've tried to find a solution for this error for the past 2 days and not sure what else to try. If I comment out: # symbol = serializers.CharField(source='symbol.name', read_only=True) Then the serializer will show just the foreign key but no error message. Seems to be an issue in my datatables javascript now. However, I've tried their suggestions and still no luck. serializers.py (Everything commented out in serializers.py are attempted solutions) class EntrySerializer(serializers.ModelSerializer): symbol = serializers.CharField(source='symbol.name', read_only=True) # symbol = serializers.SerializerMethodField('get_symbol_name') # # def get_symbol_name(self, obj): # return obj.symbol.name class Meta: model = Entry # fields = ('id', 'date', 'amount', 'price', 'fee', 'entry_type', 'reg_fee', 'transaction_id', 'trade', 'symbol', 'created_by') fields = '__all__' # depth = 1 entry_list.html {% extends "dashboard/base.html" %} {% load i18n %} {% block … -
Deploy Django project to Ubuntu + Apache + mod_wsgi
Please please please help me. I've followed this tutorial and this one and this one and this but still can't make it work. I have a VM from DigitalOcean with Apache and mod_wsgi. My Django project is stored in /var/www/mydomain.com. It is nothing fancy, just a Hello World. All I want is to run that with mod_wsgi in Daemon mode. Please tell me what should I put in my config file? All those tutorials I read provide a different approach and none of them worked for me. At best, I got the famous index of showing the content of the folder. So I removed everything. In fact I destroyed my droplet and now its a fresh install of Ubuntu 20.04. Apache is installed and works. Here's the config file if it matters: <VirtualHost *:80> ServerAdmin webmaster@localhost ServerName mydomain.com ServerAlias www.mydomain.com DocumentRoot /var/www/mydomain.com ErrorLog ${APACHE_LOG_DIR}/error.log CustomLog ${APACHE_LOG_DIR}/access.log combined RewriteEngine on RewriteCond %{SERVER_NAME} =mydomain.com [OR] RewriteCond %{SERVER_NAME} =www.mydomain.com RewriteRule ^ https://%{SERVER_NAME}%{REQUEST_URI} [END,NE,R=permanent] </VirtualHost> The last 4 lines are added by certbot to redirect http to https, and it works fine. -
Django version 3.1.3 form not saving to model
I am following this tutorial I have gone back and written the code to match exactly. I have another form that works called category_add which is exactly the same as this form. But for the life of me I cannot figure out why bookmark_add doesn't update the database with the form entries. Models.py from django.db import models from django.contrib.auth.models import User class Category(models.Model): title = models.CharField(max_length=255) description = models.TextField(blank=True, null=True) created_by = models.ForeignKey(User, related_name='categories', on_delete=models.CASCADE) created_at = models.DateTimeField(auto_now_add=True) class Meta: verbose_name_plural = 'Categories' def __str__(self): return self.title class Bookmark(models.Model): category = models.ForeignKey(Category, related_name='bookmarks', on_delete=models.CASCADE) title = models.CharField(max_length=255) description = models.TextField(blank=True, null=True) url = models.CharField(max_length=255, blank=True) created_by = models.ForeignKey(User, related_name='bookmarks', on_delete=models.CASCADE) created_at = models.DateTimeField(auto_now_add=True) def __str__(self): return self.title View.py from django.shortcuts import render, redirect from django.contrib.auth.decorators import login_required from .forms import BookmarkForm @login_required def bookmark_add(request, category_id): if request.method == 'POST': form = BookmarkForm(request.POST) if form.is_valid(): bookmark = form.save(commit=False) bookmark.created_by = request.user bookmark.category_id = category_id bookmark.save() return redirect('category', category_id=category_id) else: form = BookmarkForm() context = { 'form': form } return render(request, 'bookmark/bookmark_add.html', context) Forms.py from django.forms import ModelForm from .models import Bookmark class BookmarkForm(ModelForm): class Meta: model = Bookmark fields = ['title', 'description', 'url'] Urls.py path('', dashboard, name='dashboard'), path('categories/', categories, name='categories'), path('categories/add/', … -
Django Filling an Empty Query Set
In my Django Application, I have printed a list of query's. the first query set contains the followers of the current logged in user, The second is an empty query set, and the last printed items are a list of queries each containing the profile objects of each of those followers indicated in the first printed query. Is there a way to fill the empty query set in the middle with the list of profile object query sets, but all in one ( similar to the format of the first printed query set) -thank you for taking the time to read my questionenter image description here -
whats the best possible way to sort here
In my django app i have an import model where i have FOR_COUNT as a field and VALUE as another field in my views i am trying to show top five countries(countries with highest values) and all the remaining countries as one entity i.e others. What will be the best possible way to do this, i think sorting of some kind will work here, but am fairly new with django. Country = Import.objects.order_by('FOR_COUNT').values('FOR_COUNT').distinct() result = [] for val in Country: Info = Import.objects.filter(FOR_COUNT=val['FOR_COUNT']).filter(Date__year=year) TotalValue = Info.aggregate(Sum('VALUE')) result.append({ "label" : val['FOR_COUNT'], "value" : 0 if TotalValue['VALUE__sum'] is None else TotalValue['VALUE__sum'] }) return_data.update({ "topCounty" : result }) -
Django Rest Framework logic
My project receives a POST with a string and then I want to run a function that may take several seconds to finish on that query and update the model with the result. Currently I'm using Django Rest Framework to create an API that creates the model from the POST request and I put the function call within the views.py as so: def post(self, request, format=None): serializer = SearchSerializer(data=request.data) if serializer.is_valid(): query = serializer.validated_data.get('query') # I would expect ProteinSearch.search(query) to take a long time protein_search = ProteinSearch.search(query) serializer.save(**protein_search) return Response(serializer.data, status=status.HTTP_201_CREATED) return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST) This clearly is blocking at the moment. My question is, do I have this in the right place and should be using some type of concurrency such as threads or is this incorrectly placed in views? -
Unresolved Reference in Pycharm Using Django
code I'm using Pycharm. I created a new app called pages that's part of this tutorial on Youtube. I created some functions in the pages/views.py. Then I went to urls.py to import the functions and add the URLs. But the IDE can't find pages. I tried restarting Pycharm/invalidating the caches, and that did not work. Please let me know if you have any ideas. -
Django not running on localhost when using with Docker
I am a beginner to web development with Django. I have been trying to use docker-compose as a part of the lectures but due to some issues, I am not able to run the server. This is my docker-compose.yml file: version: '3' services: db: image: postgres environment: - POSTGRES_DB=postgres - POSTGRES_USER=postgres - POSTGRES_PASSWORD=1029384756Vithayathil ports: - "5432:5432" migration: build: . command: python3 manage.py migrate volumes: - .:/usr/src/app depends_on: - db web: build: . command: python3 manage.py runserver volumes: - .:/usr/src/app ports: - "8000:8000" depends_on: - db - migration This is my DockerFile: FROM python:3 WORKDIR /usr/src/app ADD requirements.txt /usr/src/app RUN pip install -r requirements.txt ADD . /usr/src/app This is my database in settings.py: DATABASES = { 'default': { 'ENGINE': 'django.db.backends.postgresql', 'NAME': 'postgres', 'USER': 'postgres', 'HOST': 'db', 'PASSWORD':'**********', 'PORT': 5432, } } On doing docker-compose up command, these things happen: Starting airline4_db_1 ... done Starting airline4_migration_1 ... done Starting airline4_web_1 ... done Attaching to airline4_db_1, airline4_migration_1, airline4_web_1 db_1 | db_1 | PostgreSQL Database directory appears to contain a database; Skipping initialization db_1 | db_1 | 2020-11-07 15:37:00.770 UTC [1] LOG: starting PostgreSQL 13.0 (Debian 13.0-1.pgdg100+1) on x86_64-pc-linux-gnu, compiled by gcc (Debian 8.3.0-6) 8.3.0, 64-bit db_1 | 2020-11-07 15:37:00.789 UTC [1] LOG: listening … -
How to Solve a FieldError- Cannot resolve keyword 'slug' into field
I'm making a Post and Comment model. I created and Post and Comment model and it looks ok. I can add post and also comment to any particular post. But getting trouble when I'm trying to delete the comment after several attempts I am getting an error from test_func. Here is the views.py class PostCommentDeleteView(LoginRequiredMixin, UserPassesTestMixin, DeleteView): model = Comment template_name = 'blog/postcomment_confirm_delete.html' # <app>/<model>_<viewtype>.html def test_func(self): comment = self.get_object() <------------- Error showing from here if self.request.user == comment.user: return True return False def form_invalid(self, form): return HttpResponseRedirect(self.get_success_url()) def get_success_url(self): return reverse('blog:post-detail', kwargs=dict(slug=self.kwargs['slug'])) Here is the template: {% for comment in comments %} <ul class="list-unstyled"> <li class="media"> <img class="rounded-circle article-img" src="{{ comment.post.author.profile.image.url }}"> <div class="media-body"> <h5 class="mt-0 mb-1">{{comment.user| capfirst}}<small class="text-muted">- {{ comment.created}}</small> </h5> <hr class="solid mt-0"> {{ comment.content}} </div> </li> </ul> {% if comment.user == user %} <div> <a class="btn btn-secondary btn-sm mt-1 mb-1" href="{% url 'blog:post-commentu' post.slug %}">Update</a> <a class="btn btn-danger btn-sm mt-1 mb-1" href="{% url 'blog:post-commentd' post.slug %}">Delete</a> </div> {% endif %} {% endfor %} Here is the url path('blog/<slug:slug>/delete_comment/', PostCommentDeleteView.as_view(), name='post-commentd'), Here is the models.py class Post(models.Model): title = models.CharField(max_length=100, unique=True) content = RichTextUploadingField(null=True, blank=True) author = models.ForeignKey(User, on_delete=models.CASCADE, related_name='author') slug = models.SlugField(blank=True, null=True, max_length=120) class Comment(models.Model): … -
How do I go about debugging 'OSError: Failed to write data' on my Flask server?
I'm running a Flask application (with some bits of Django ORM) on Elastic Beanstalk (code link: https://github.com/onnela-lab/beiwe-backend). However, I'm getting constant notifications from Elastic Beanstalk about 5xx failures (~5-25% failures). Looking at the logs (/var/logs/httpd/error_log), I see the following errors: Error 1: [Fri Nov 13 13:58:55.487007 2020] [:error] [pid 14630] [remote {load_balancer_ip_address:port1}] mod_wsgi (pid=14630): Exception occurred processing WSGI script '/opt/python/current/app/wsgi.py'. [Fri Nov 13 13:58:55.487070 2020] [:error] [pid 14630] [remote {load_balancer_ip_address:port1}] OSError: failed to write data Error 2: [Fri Nov 13 13:59:55.486449 2020] [:error] [pid 17765] (70008)Partial results are valid but processing is incomplete: [client {load_balancer_ip_address:port2}] mod_wsgi (pid=17765): Unable to get bucket brigade for request Doing a quick grep -c (result: 5418) for each of these confirms that they're likely related issues, despite no correlation in PIDs and different LB ports. I did some research on Stack Overflow and found the following related questions: Django OSError: failed to write data Apache + mod_wsgi + flask app: "Unable to get bucket brigade for request" error in logs Summary: It's possible that clients with spotty connections are causing this issue due to an interrupted connection or that something is killing the Apache child worker process. Most of the clients calling this API are …
