Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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No module named django_river
I have an issue when running pip install -r requirements.txt and got no module named django_river. I tried installing the package pip install django_river but it gives error, package does not exist. Thanks -
Access forbidden to Django resource when accessing through Node.js frontend
I cloned a Django+Node.js open-source project, the goal of which is to upload and annotate text documents, and save the annotations in a Postgres db. This project has stack files for docker-compose, both for Django dev and production setups. Both these stack files work completely fine out of the box, with a Postgres database. Now I would like to upload this project to Google Cloud - as my first ever containerized application. As a first step, I simply want to move the persistent storage to Cloud SQL instead of the included Postgres image in the stack file. My stack-file (Django dev) looks as follows version: "3.7" services: backend: image: python:3.6 volumes: - .:/src - venv:/src/venv command: ["/src/app/tools/dev-django.sh", "0.0.0.0:8000"] environment: ADMIN_USERNAME: "admin" ADMIN_PASSWORD: "${DJANGO_ADMIN_PASSWORD}" ADMIN_EMAIL: "admin@example.com" # DATABASE_URL: "postgres://doccano:doccano@postgres:5432/doccano?sslmode=disable" DATABASE_URL: "postgres://${CLOUDSQL_USER}:${CLOUDSQL_PASSWORD}@sql_proxy:5432/postgres?sslmode=disable" ALLOW_SIGNUP: "False" DEBUG: "True" ports: - 8000:8000 depends_on: - sql_proxy networks: - network-overall frontend: image: node:13.7.0 command: ["/src/frontend/dev-nuxt.sh"] volumes: - .:/src - node_modules:/src/frontend/node_modules ports: - 3000:3000 depends_on: - backend networks: - network-overall sql_proxy: image: gcr.io/cloudsql-docker/gce-proxy:1.16 command: - "/cloud_sql_proxy" - "-dir=/cloudsql" - "-instances=${CLOUDSQL_CONNECTION_NAME}=tcp:0.0.0.0:5432" - "-credential_file=/root/keys/keyfile.json" volumes: - ${GCP_KEY_PATH}:/root/keys/keyfile.json:ro - cloudsql:/cloudsql networks: - network-overall volumes: node_modules: venv: cloudsql: networks: network-overall: I have a bunch of models, e.g. project in the Django backend, … -
Django, Ajax: creating comment in homepage from Listview
im trying to build comment section with ability to post new one below every post (like on Instagram or Facebook). At the moment I can like post, show or hide comment section with form below particular post but I cannot post comment, I don't know how to do this. I generate posts with ListView. I have separated view for comments with form. When i try to post comment console gives me jquery-3.5.1.min.js:2 POST http://127.0.0.1:8000/ 405 (Method Not Allowed) How to generate form like this? Below what I tried: views.py class PostListView(ListView): model = Post template_name = 'posts/homepage.html' def get_queryset(self): profiles = Follow.objects.filter(follow_by=self.request.user.profile).values_list('follow_to', flat=True) posts = Post.objects.filter(author_id__in=profiles).order_by('-date_of_create') return posts def get_context_data(self, **kwargs): context = super(PostListView, self).get_context_data(**kwargs) context['form'] = CommentForm return context def post_comments(request, pk): post = Post.objects.get(pk=pk) profile = request.user.profile if request.method == 'POST': form = CommentForm(request.POST) if form.is_valid(): comment = form.save(commit=False) comment.author = profile comment.post = post comment.save() data = { 'content': form.cleaned_data['content'] } return HttpResponse(json.dumps(data)) form = CommentForm() context = { 'post': post, 'form': form, } return render(request, 'posts/comments.html', context=context) homepage.html {% block content %} {% for post in object_list %} <a href="{% url 'detail_post' post.id %}"><img src="{{ post.picture.url }}" alt="" class="img-thumbnail" style="width:200px; height: 200px;"></a> <h4>{{ post.description_hashtags|safe }}</h4> <small><a … -
ImproperlyConfigured: The SECRET_KEY sett ing must not be empty
I am forking a free Django project on git. The files have no Secret_Key- as you can appreciate. It has a env folder with files and env.md. The env.md request to enter all the Values: Kindly add below environment variables to your local development with appropriate key/value accordingly. Common keys DEBUG=True #false SECRET_KEY="(I have entered here, a python random generated 50 character as the Secret_key)" HTML_MINIFY=True/False ENV_TYPE="DEV" or "PROD" File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/init.py", line 401, in execute_from_command_line utility.execute() File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/init.py", line 395, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/base.py", line 330, in run_from_argv self.execute(*args, **cmd_options) File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/commands/runserver.py", line 61, in execute super().execute(*args, **options) File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/base.py", line 371, in execute output = self.handle(*args, **options) File "/opt/miniconda3/lib/python3.7/site-packages/django/core/ management/commands/runserver.py", line 68, in handle if not settings.DEBUG and not settings.ALLOWED_HOSTS: File "/opt/miniconda3/lib/python3.7/site-packages/django/conf/ init.py", line 83, in getattr self._setup(name) File "/opt/miniconda3/lib/python3.7/site-packages/django/conf/ init.py", line 70, in _setup self._wrapped = Settings(settings_module) File "/opt/miniconda3/lib/python3.7/site-packages/django/conf/ init.py", line 196, in init raise ImproperlyConfigured("The SECRET_KEY setting must not be empty.") django.core.exceptions.ImproperlyConfigured: The SECRET_KEY sett ing must not be empty. I have created a ´random python´ Secret_key as I expect you don't leave your Secret:_key , debug and Database on the git. what i´ve done_: I found the env.md and entered … -
Django variable form
I'm trying to make a checkout form using Django where customer has to fill out the delivery address and choose date time. I want the choices in shippingDate to changed based on shippingAddress1, shippingCity. What could be the ways to implement it?. Here is the address form: class DeliveryForm(forms.Form): def __init__(self,date_list,*args,**kwargs): # call standard __init__ super().__init__(*args,**kwargs) #extend __init__ self.fields['shippingDate'] = forms.ChoiceField(choices=tuple([(date, f"{date.strftime('%d')} {months[date.strftime('%m')]}") for date in date_list]), required=True) shippingAddress1 = forms.CharField(max_length=250, help_text='ул. Бассейная 10',required=True, label='Адрес') shippingFlat = forms.CharField(max_length=250, help_text='кв.10', required=False, label='Квартира') shippingCity = forms.CharField(max_length=250, help_text='Киев',required=True, label='Город') shippingPostcode = forms.CharField(max_length=250, help_text='01011',required=True, label='Почтовый индекс') shippingDate = forms.DateField() Here is HTML code for the form (if needed): <div class="container my-auto pb-5 px-5"> {% if not form.is_valid %} <div class="row mt-5"> <div class="col-12 col-md-10 offset-md-1 col-xl-8 offset-xl-2 text-center"> <div class="text-center " > <h3 class="product_title">Доставка</h3> </div> <hr> <form id='deliveryForm'> {% csrf_token %} <p id="failure_message" style="color: red;">{{failure_message}}</p> <div class="container-fluid"> <div class="row"> <div class="col-9 form-group"> <div class="input-group"> <div class="input-group"> <div class="input-group-prepend"> <span class="input-group-text"><i class="fas fa-map-marker-alt"></i></span> </div> {% render_field form.shippingAddress1 class+="form-control" placeholder='*Адрес (Бассейная 10)' %} </div> </div> </div> <div class="col-3 form-group"> <div class="input-group"> <div class="input-group"> {% render_field form.shippingFlat class+="form-control" placeholder='кв.' %} </div> </div> </div> </div> <div class="row"> <div class="col-8 form-group"> <div class="input-group"> <div class="input-group"> <div class="input-group-prepend"> <span class="input-group-text"><i … -
How can i migrate after restore database backup in django?
There is a backup database of postgresql,after i restored this database.i create model in on of app in Django project then i run makemigrations ..new table create in 0001 file in migrations beside app..but after run migrate new table do not create! -
Putting two different variables from two different models at the same line in Django templates
I need to get a Django Template like "First Blog Heading" ("number of Comments of first blog") "Second Blog Heading" ("number of Comments of second blog") What's the easiest way to do this? I tried to create a context in my views.py having both from Blog model and Comment model and put Since variables belong to different models. And then I needed to put both variables into for loop in my html but it turn out a nested loop. So I didn’t get the look I want. I open to every kind of solution not from back-end but also front-end Thank you {% for blog in blogs %} {% for comment in comments %} {{blog.name }} {{comment.number }} {% endfor %} {% endfor %} -
After nsq.run() my python script is not executing block of code in "pynsq" package
enter image description hereI am trying to use "pynsq" package (message broker service) to my django project. but when i run the Asynchronous consumer request using nsq.Reader() class by using nsq.run() command it takes my main thread and my code after this command is not executing . for eg:- as shown in the picture after nsq.run() i am trying to print("hello") but the print function is not calling when i run this .py script .i have tried my best to find solution for this. is it possible to use this package in my django project ? becauese when i run this script after nsq.run() my code of block is not executing. please can anyone suggest me the solution for this to use this package in my django project. -
Celery beat task received but doesn't invoke
I'm trying run beat tasks. But only one task executes. So, there is my project's structure: trading_platform: trading_platform: celery.py settings.py offers: tasks.py manage.py celery.py: import os from celery import Celery from django.conf import settings os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'trading_platform.settings') app = Celery('trading_platform') app.config_from_object('django.conf:settings', namespace='CELERY') app.autodiscover_tasks(lambda: settings.INSTALLED_APPS) @app.on_after_configure.connect def setup_periodic_tasks(sender, **kwargs): sender.add_periodic_task(10.0, debug_task.s('HELLO'), name='add every 10') @app.task def debug_task(self): print(self) settings.py: # Celery Configuration Options CELERY_BROKER_URL = os.environ.get('CELERY_BROKER_URL', 'redis://redis:6379/0') CELERY_RESULT_BACKEND = os.environ.get('CELERY_RESULT_BACKEND', 'redis://redis:6379/0') # CELERY_ACCEPT_CONTENT = os.environ.get('CELERY_ACCEPT_CONTENT', 'application/json') CELERY_RESULT_SERIALIZER = os.environ.get('CELERY_RESULT_SERIALIZER', 'json') CELERY_TASK_SERIALIZER = os.environ.get('CELERY_TASK_SERIALIZER', 'json') CELERY_STORE_ERRORS_EVEN_IF_IGNORED = os.environ.get('CELERY_STORE_ERRORS_EVEN_IF_IGNORED', True) tasks.py: from trading_platform.celery import app @app.on_after_configure.connect def setup_periodic_tasks(sender, **kwargs): sender.add_periodic_task(10.0, print_text.s('text'), name='add every 10 sec') @app.task(bind=True) def print_text(text): print(text) command to run: celery -A trading_platform worker -B -l info So, there is input: celery_1 | /usr/local/lib/python3.8/site-packages/celery/platforms.py:797: RuntimeWarning: You're running the worker with superuser privileges: this is celery_1 | absolutely not recommended! celery_1 | celery_1 | Please specify a different user using the --uid option. celery_1 | celery_1 | User information: uid=0 euid=0 gid=0 egid=0 celery_1 | celery_1 | warnings.warn(RuntimeWarning(ROOT_DISCOURAGED.format( celery_1 | celery_1 | -------------- celery@953a7a853036 v5.0.1 (singularity) celery_1 | --- ***** ----- celery_1 | -- ******* ---- Linux-5.4.0-52-generic-x86_64-with-glibc2.2.5 2020-10-25 09:23:38 celery_1 | - *** --- * --- celery_1 | - ** ---------- [config] celery_1 … -
How can I call/refer to another property in the same models in django
I am creating a web app for creating a proposal/quotation for machines or equipment. I have a models for QuotationItem which has these properties: In my models.py: class QuotationItem(models.Model): product = models.Charfield(max_length=30) quantity = models.PositiveIntegerField(default=1) description = models.CharField(max_length=200, null=True) line_number = models.PositiveIntegerField() tagging = models.CharField(max_length=50) Now, I want the 2 properties (line_number and tagging) be connected. Example: line_number = 1, tagging = "Equipment - 1" line_number = 2, tagging = "Equipment - 2" In short, I want to set the tagging property with a default value of f"Equipment - {line_number}" How can this be done? I cannot seem to find this in documentation. Thank you -
How to print multiple object from table def __str__(self):return self.title
I created a article models below models.py class Article(models.Model): user = models.ForeignKey(User, on_delete=models.CASCADE, blank=True) is_deleted = models.BooleanField(default=False) custom_id = models.UUIDField(blank=False,null=False, default=uuid.uuid4, editable=False) title = models.CharField(max_length=200, blank=False) text = models.TextField() created_on = models.DateTimeField("created on", auto_now_add=True) objects = models.Manager() def __str__(self): return self.title for print the title object I Used below lines def __str__(self): return self.title But I want to print the title object with user object.How will do? For Example Title Name -
Trying to display "RSS list" in django. However it gives a blank value on the page
I am completely newbee in django and trying to learn it. Values from list are not getting displayed. Code completely works in python Code in View.py from django.http import HttpResponse from django.shortcuts import render from .models import feed_entry import feedparser feedlist =['http://rss.cnn.com/rss/money_news_companies.rss','http://feeds.marketwatch.com/marketwatch/realtimeheadlines/','http://feeds.marketwatch.com/marketwatch/marketpulse/','https://www.cnbc.com/id/10001147/device/rss/rss.html'] serialnumber = 1 feeds = [] sortedfeed = [] for feedlisturl in feedlist: feeds.extend(feedparser.parse(feedlisturl).entries) for feed in feeds: article_title = feed.title article_link = feed.link article_published_at = feed.published # Unicode string article_published_at_parsed = feed.published_parsed # Time objectwhats content = feed.summary sortedfeed.append((article_title, article_link,article_published_at,article_published_at_parsed,content)) rssfeed = (sorted(sortedfeed, key=lambda sortedfeed: sortedfeed[3], reverse=True)) def feed(request): return render(request, 'index.html',{'feed_from':rssfeed}) - In index.html {% for feed_entry in rssfeed %} {{ feed_entry.1 }} {% endfor %} Question: When index.html renders it gives a blank page. Can anyone help, please -
python manage.py makemigrations : No changes detected
I am working on a project using django and i am using pycharm software. In my 'store' directory i have a python package called 'models' in which there are two python files :- init.py and product.py . The problem i am getting is that i cannot create table using the command even when i am importing the 'Product' class from product module in init.py file. Even both the modules are also in the same package. Here is the code of product.py file:- from django.db import models class Product(models.Model): name = models.CharField(max_length=50) price = models.IntegerField(default=0) description = models.CharField(max_length=200, default='') image = models.ImageField(upload_to='products/') And here is the code of init.py file:- from .product import Product But when i am running the command on terminal i am getting this error:- (venv) C:\Users\Admin\PycharmProjects\SMart>python manage.py makemigrations No changes detected -
Django: You don’t have permission to view or edit anything
I am trying to extend my normal navigation template in django admin but getting error as : You don’t have permission to view or edit anything. html file where I am trying to extend navigation template : {% extends 'base.html' %} {% block content %} {% include "admin/index.html" %} {{ block.super }} {% endblock content %} What I tried: I've added below codes in my project urls.py(didn't work): from django.contrib import admin admin.autodiscover() Replaced django.contrib.admin with django.contrib.admin.apps.SimpleAdminConfig and used(didn't work): from adminplus.sites import AdminSitePlus admin.site = AdminSitePlus() admin.autodiscover() My User Permissions: Can anyone help to to display full admin page with all access? -
Why isn't my website scrolling, but works well when resized?
hi guys i am new to programming and I'm trying to make a static webpage dynamic in Django and I've gotten the layout of the page okay, however the page wont seem to scroll.im guessing its a CSS or jQuery problem. i really would like some help on this. Link to my repository below. link to repo -
In Django, how can I unit test a modelformset_factory?
I wanted to have several instances of the same form, so I used a modelformset_factory. My model is as follows from django.db import models class Donation(models.Model): DONATE_CHOICES = [ ('aclu', 'American Civil Liberties Union'), ('blm', 'Black Lives Matter'), ('msf', 'Medecins Sans Frontieres (Doctors Without Borders)') ] charity = models.CharField( max_length=4, choices=DONATE_CHOICES, default='aclu' ) money_given = models.IntegerField(default=0) And my view: from django.shortcuts import render from django.http import HttpResponseRedirect from django.forms import modelformset_factory from .models import Donation def donate(request): donateformset = modelformset_factory(Donation, fields='__all__', extra=3) form = donateformset(queryset=Donation.objects.none()) if request.method == 'POST': form = donateformset(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect('..') context = {'form': form} return render(request, 'Micro_Donations/donate.html', context) -
In Django, how can I acccess request.meta in a class-based view like UpdateView?
Well, actually the question is in the title :) I want to have an UpdateView with different redirects depending on the referer from which the update is called. -
How to get value from html to django class based view?
What's the simpliest way to do this? I'd like to get this html input value: <form method="post" action=""> {% csrf_token %} <input name="pagination" type="search"> <button type="submit">save</button> </form> To views.py class CategoryListView(ListView): login_url = '/category/' model = Category pagination = <<--here def get_context_data(self, *, object_list=None, **kwargs): queryset = object_list if object_list is not None else self.object_list return super().get_context_data( object_list=queryset, **kwargs) url.py path('expense/categories/', CategoryListView.as_view(), name='category-list'), -
How to get response in template while process is not completed in django?
I am building a bot using django and selenium which require live results in template view to update the user with current figures. -
Convert postgres sql query to Django
I want to convert the following query to Django select file.id, array_agg(fileregion.defect_ids) from file left outer join (select file_id, jsonb_object_keys(defects) as defect_ids from ai_fileregion ) as fileregion on fileregion.file_id=file.id group by file.id Following are my Django models class File(Base): class Meta: db_table = "file" class FileRegion(Base): file = models.ForeignKey(File, on_delete=models.PROTECT, related_name='file_regions') # defects is of the form {'<defectid1>': {}, <defectid2>: {}} defects = JSONField(default=dict) class Meta: db_table = "ai_fileregion" Aim is to basically get a list of records in which one field is the file_id and another field has an array of aggregated keys from defects json field for that file_id. Note: Each file may have more than one entry in the ai_fileregion table. Note: There will be more chaining added to this queryset. So, getting results in a different format to server and modifying it at the application level is not an option. -
upload file from client android to sever django
I'm trying to upload my file not only image file but any file from android to django directory I specified. I tried some methods in online, but failed. Any advice is welcome. My Reference https://docs.djangoproject.com/en/3.1/topics/http/file-uploads/ =====Android Files===== MainActivity.java public class MainActivity extends AppCompatActivity { TextView contentView2; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); contentView2=findViewById(R.id.content2); HashMap<String, String> recordMap=new HashMap<>(); recordMap.put("name","GetUserFile"); RecordSender recordSender = new RecordSender(); recordSender.request("http://my_server_ip_address/recommender/GetUserFile/".concat("100"), recordMap, httpCallbackSend,"/data/data/com.example.servertest/databases/recommend.jpg"); } HttpCallback httpCallbackSend=new HttpCallback() { @Override public void onResult(String result) { try{ contentView2.setText(result); }catch (Exception e){ e.printStackTrace(); } } }; } RecordSender.java public class RecordSender { private static final String TAG = "RECORDSENDER"; RecordTask http; public void request(String url, HashMap<String, String> param, HttpCallback callback, String filePath) { http = new RecordTask(url, param, callback, filePath); http.execute(); } private class RecordTask extends AsyncTask<Void, Void, String> { String url; HashMap<String, String> param; HttpCallback callback; String filePath; public RecordTask(String url, HashMap<String, String> param, HttpCallback callback, String filePath) { this.url = url; this.param = param; this.callback = callback; this.filePath = filePath; } @Override protected String doInBackground(Void... voids) { try { URL text = new URL(url); HttpURLConnection http = (HttpURLConnection) text.openConnection(); http.setRequestProperty("enctype", "multipart/form-data"); http.setRequestProperty("Content-Type", "multipart/form-data;"); http.setRequestProperty("Connection", "Keep-Alive"); http.setConnectTimeout(10000); http.setReadTimeout(10000); http.setRequestMethod("POST"); http.setDoInput(true); http.setDoOutput(true); http.setUseCaches(false); http.connect(); File file = new … -
Django is installed but raises importError: Could not import django on running python3 manage.py runserver?
I have correctly installed django. When I run the below commands the following errors are thrown. I have tried out the answers for this similarly asked questions, but nothing solves my issue. sibasisnayak@MacBook-Air backend % python3 manage.py runserver Traceback (most recent call last): File "manage.py", line 11, in main from django.core.management import execute_from_command_line ModuleNotFoundError: No module named 'django' The above exception was the direct cause of the following exception: Traceback (most recent call last): File "manage.py", line 22, in <module> main() File "manage.py", line 13, in main raise ImportError( ImportError: Couldn't import Django. Are you sure it's installed and available on your PYTHONPATH environment variable? Did you forget to activate a virtual environment? sibasisnayak@MacBook-Air backend % django-admin --version 3.1.2 I don't have pip installed, but I have pip3 installed. sibasisnayak@MacBook-Air backend % which python /usr/bin/python sibasisnayak@MacBook-Air backend % which python3 /usr/local/bin/python3 sibasisnayak@MacBook-Air backend % which pip3 /usr/local/bin/pip3 sibasisnayak@MacBook-Air backend % which pip pip not found -
Django data via ajax is empty on view
I'm trying to pass a data to django view via ajax like I used to do with php but I get on print empty value but my console log show that there is a data value on javascript but on view return None Quit the server with CONTROL-C. None my html file code {% for image in images %} <table style="width:100%;" id="tab-{{image.image_cid}}"> <tr> <td style="width:70%;vertical-align:middle"> <img src="/medias/{{ image.image_value }}" alt="" width="100" > </td> <td style="width:30%;vertical-align:middle"> <a href="#/" id="{{ image.image_cid }}" class="cl-img-del"> DELETE </a> </td> </tr> </table> {% endfor %} <script> $(document).ready(function(){ $(".cl-img-del").click(function(e){ var imgID = e.target.id console.log(imgID); $.ajax({ headers: {'X-CSRFToken': '{{ csrf_token }}'}, url: "{% url 'delete-image-ajax' %}", type: "POST", data: { imageid: imgID }, contentType: false, cache: false, processData:false, success: function(data){ if(data == 'done') { $('#tab-'+imgID).remove(); } }, error: function(){} }); }); }); </script> and my view file code is def deleteImageAjxFn(request): if request.method == "POST": imgid = request.POST.get('imageid') print(imgid) try: image = Images.objects.filter(image_shw = int(0), image_cid=imgid).delete() except Images.DoesNotExist: image = None if(image): return HttpResponse('done') else: print(form_add_data.errors) -
'csrf_tokan', expected 'endblock'. Did you forget to register or load this tag?
{%extends 'base.html'%} {% block content%} hellow {{name}} {% csrf_tokan %} Enter 1st number : <input type="text" name="num1"><br> Enter 2nd number : <input type="text" name="num2"><br> <input type="submit"> {% endblock%} -
How to render data from multiple models django
I want to render data to my webpage from my django app however only two of the required slots are being rendered my models are: class Order(models.Model): customer = models.ForeignKey(Customer, on_delete=models.SET_NULL, null=True, blank=True) date_ordered = models.DateTimeField(auto_now_add=True) complete = models.BooleanField(default=False) transaction_id = models.CharField(max_length=100, null=True) class OrderItem(models.Model): product = models.ForeignKey(Product, on_delete=models.SET_NULL, null=True) order = models.ForeignKey(Order, on_delete=models.SET_NULL, null=True) quantity = models.IntegerField(default=0, null=True, blank=True) date_added = models.DateTimeField(auto_now_add=True) class Customer(models.Model): user = models.OneToOneField(User, on_delete=models.CASCADE, null=True, blank=True) name = models.CharField(max_length=200, null=True) email = models.CharField(max_length=200, null=True) class Product(models.Model): name = models.CharField(max_length=200) price = models.DecimalField(max_digits=7, decimal_places=2) digital = models.BooleanField(default=False,null=True, blank=True) image = models.ImageField(null=True , blank=True) description = models.TextField(max_length=5000, null=True) points = models.DecimalField(max_digits=5,decimal_places=0, null=True) and my views are def admin_dashboard (request): order_list = Order.objects.all() context = {'order':ordersinfo} template = "admin_dashboard.html" return render(request, 'store/admin_dashboard.html', context) my HTML is: {% extends 'store/admin_main.html' %} {% load static %} {% block content %} {% for order in order %} <h6>{{ order.transaction_id }}</h6> <p>{{ order.customer }}</p> <p>{{ order.shippingaddress }}</p> <p>{{ order.orderitem }}</p> {% endfor%} {% endblock content %} 1598061443.212917 userNew which is just the transaction id and user. how can I have all the rest of fields filled
