Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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How to add an option to pdf files with Order model context in Django Admin
I have a beginners question, in my Django E-commerce Project, I want to add an Option to include Order details so that I can print them as Invoices. I have 3 models: Item, OrderItem and Order. The Order has a Many-to-Many relationship with OrderItem and the OrderItem has a Foreign Key with Item. I have found weazyprint that help do the trick but I am unable to include the correct context so I need advice in including the Order to appear in template Here is the models.py class Item(models.Model): title = models.CharField(max_length=100) keywords = models.CharField(max_length=100) price = models.DecimalField(decimal_places=2, max_digits=100) timestamp = models.DateTimeField(default=timezone.now) active = models.BooleanField(default=True) class OrderItem(models.Model): user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE) ordered = models.BooleanField(default=False) item = models.ForeignKey(Item, on_delete=models.CASCADE) quantity = models.IntegerField(default=1) variation = models.ManyToManyField(Variation) class Order(models.Model): user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE) ref_code = models.CharField(max_length=20, unique=True, blank=True, null=True) items = models.ManyToManyField(OrderItem) start_date = models.DateTimeField(auto_now_add=True) ordered_date = models.DateTimeField() ordered = models.BooleanField(default=False) I have a problem in the views it is not correct so I need assistance in it @staff_member_required def admin_order_pdf(request, order_id): order = --------------------------------> having difficulty wiriting the right code for the template html = render_to_string('pdf.html', {'order': order}) response = HttpResponse(content_type='application/pdf') response['Content-Disposition'] = 'filename="order_{}.pdf"'.format(Order.id) weasyprint.HTML(string=html).write_pdf(response) return response url.py path('admin/order/(<order_id>\d+)/pdf/', views.admin_order_pdf, name='admin_order_pdf') template … -
Django-allauth login/signup in one view
I am working on a django project and i would like to have one website page called login_register where the user can see the login form and click on a button to change that form to the sign up form using javascript. So i am stuck on finding out how to make this work and have login and signup forms on one page. Thanks in advance! -
Trouble uploading Django to production w/ Digital Ocean Apps, "collectstatic no input" error
I'm trying to upload my django app to a production server using Digital Oceans Apps. However I keep getting this error and I've tried everything. I see that in the log below, there's an $ heroku config:set DISABLE_COLLECTSTATIC=1, I registered this app as heroku git before but never put it into production and just now have removed all traces of Heroku. I'm baffled at why I'm getting this error. Below are settings.py and my Digital Ocean log #settings.py """ Django settings for stockbuckets project. Generated by 'django-admin startproject' using Django 3.1.1. For more information on this file, see https://docs.djangoproject.com/en/3.1/topics/settings/ For the full list of settings and their values, see https://docs.djangoproject.com/en/3.1/ref/settings/ """ import os from pathlib import Path import dj_database_url # Build paths inside the project like this: BASE_DIR / 'subdir'. BASE_DIR = Path(__file__).resolve().parent.parent # Quick-start development settings - unsuitable for production # See https://docs.djangoproject.com/en/3.1/howto/deployment/checklist/ # SECURITY WARNING: keep the secret key used in production secret! SECRET_KEY = os.environ.get('SECRET_KEY_DJANGO_STOCKBUCKETS') # SECURITY WARNING: don't run with debug turned on in production! DEBUG = False ALLOWED_HOSTS = ['0.0.0.0', 'localhost', '127.0.0.1'] # Application definition INSTALLED_APPS = [ 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'home.apps.HomeConfig', 'django_plotly_dash.apps.DjangoPlotlyDashConfig', 'dpd_static_support', 'channels', 'channels_redis', 'bootstrap4', 'blog', ] MIDDLEWARE = [ … -
Am new to web development using python and want to know the best framework to use
i have been using PHP for backend web development and now I want to try using a python framework, which python framework will you recommend to start learning and why? -
Django/allauth: Can you add oauth mid-project easily?
If I start my project with allauth but don't use the oauth (Google, Facebook), can I easily add oauth after there are real users? Or is it one of those things where you have to fuss with the database manually? -
Django urls for Website not pointing to the correct page
I am using django to help create a website. The problem is when I attempt to switch from page to page the page can't be found and the url reads: http://127.0.0.1:8000/mentorPage/ http://127.0.0.1:8000/mentorPage/mentorPage/ As I click on the mentorPage link multiple times. I have attached my urls code below and was wondering if anyone could tell me why this is happening. from django.urls import path, include from . import views from django.views.generic import ListView, DetailView from webapp.models import UE # Create your views here. app_name = "main" urlpatterns = [ path('', views.home, name = 'home'), path('home', views.home, name = 'home'), path('resourcePage/', views.resource, name = 'resource'), path('mentorPage/', views.mentorPage, name = 'resource'), path('aboutMePage/', views.aboutME, name = 'resource'), ] -
progress bar showing incorrect percentage
i followed a tutorial on how to implement a file upload progress bar with django using js but the problem is that the progress bar is reaching 100% before the file completed uploading this my uploader.js function check_ex() { var fullPath = document.getElementById("id_video").value; if (fullPath) { var startIndex = fullPath.indexOf("\\") >= 0 ? fullPath.lastIndexOf("\\") : fullPath.lastIndexOf("/"); var filename = fullPath.substring(startIndex); if (filename.indexOf("\\") === 0 || filename.indexOf("/") === 0) { filename = filename.substring(1); } var x = filename.split('.').pop(); if (x != 'mp4') { alert(x +' format is not allowed in video input, use only (mp4) extensions'); location.reload() }; } } $(document).ready(function () { $("form").on("submit", function (event) { event.preventDefault(); check_ex(); var formData = new FormData($("form")[0]); $.ajax({ xhr: function () { var xhr = new window.XMLHttpRequest(); xhr.upload.addEventListener("progress", function (e) { if (e.lengthComputable) { document.getElementById("loading_btn").classList.remove("d-none"); document.getElementById("save_btn").classList.add("d-none"); document.getElementById("progressdiv").classList.remove("d-none"); var percent = Math.round((e.loaded / e.total) * 100); if (percent == 100) { document.getElementById("message_button").click(); } $("#progressbar") .attr("aria-valuenow", percent) .css("width", percent + "%") .text(percent + " %"); } }); return xhr; }, type: "POST", data: formData, processData: false, contentType: false, seccess: function () {}, }); }); }); im new in javascript and i couldn't understand why this function is giving me so much smaller percentage comparing to the … -
How to grab 10 most recently created profiles in django?
Well i am want to show most recent created profiles but i dont understand how can i grab them by queryset. I am adding some information if more information require than tell me i will update my answer with that information models.py class UserProfile(models.Model): user = models.OneToOneField(User, on_delete=models.CASCADE) follower = models.ManyToManyField(User, related_name ='is_following',blank=True,) avatar = models.ImageField(("Avatar"), upload_to='displays', default = '1.jpg',height_field=None, width_field=None, max_length=None,blank = True) create_date = models.DateField(auto_now_add=True,null=True) objects = ProfileManager() class ProfileManager(models.Manager): def top_profile(self): top_profile = self.get_queryset().get(user=self.request.user) qs = UserProfile.objects.filter( user=top_profile ).order_by('-create_date')[:10] return top_profile -
Django Celery How to run function every 5 sec?
I want the function update() to run every 5 seconds. In this case, my function just prints a message to the console. For this I decided to use celery. I put the following code in a file settings.py and nothing happens when the server runs. What am I missing? Some code perhaps? from celery import Celery from celery.schedules import crontab app = Celery() app.conf.beat_schedule = { # Executes every Monday morning at 7:30 a.m. 'add-every-monday-morning': { 'task': 'accounts.views.update', 'schedule': timedelta(seconds=5), }, } -
How do I display an integer from a database object in Django?
I am a beginner in Django and coding in general. I know that this must be an easy thing to do but I have been struggling with this for days. This is my model: class Bal(models.Model): balance = models.IntegerField(default='5000') def __int__(self): return "{}, {}".format(self.pk, self.balance) View: def add_stock(request): import requests ... bala = Bal.objects.get(pk=2) ''' return render(request, 'stocktrader/add_stock.html', {'ticker': ticker, 'output': output, 'bala': bala}) in the html page: <h4>Balance: {{ bala }}</h4> The output on the web page is: Balance: Bal object (2) Where "Bal object(2)" is I need it to display a number. The table in the database has one 'balance' entry for 5000 and it has an id if 2. I just don't understand how to get the value of '5000' to display instead of 'Bal object (2)'. -
Wrap string in ReportLab table cell in Django
I've been trying to get my cell strings to wrap, the table gets too wide and out of screen. I know that using Paragraph automatically wraps text, but the problem is that I'm sending my data from multiple views so the table width and number of columns varies. class NewPDF(View): def get(self, request, *args, **kwargs): arr= [(p.nombre, p.apellido, p.tipo+'-'+p.numero_identificacion, p.telefono , p.email, p.direccion) for p in Persona.objects.all()] data = { 'titulo':'LISTADO DE PERSONAS', 'headings':('NOMBRE', 'APELLIDO', 'IDENTIFICACION','TELEFONO','EMAIL', 'DIRECCION'), 'query': arr } pdf = generar_pdf(request,data) return HttpResponse(pdf, content_type='application/pdf') And using it on ReportLab like this. As you see, I'm using the data I'm sending directly and I don't know how to apply paragraphs styles to the query data. canv = Canvas(buff, pagesize=A4) frame = Frame(0,0,width,height, leftPadding=30, bottomPadding=30, rightPadding=30, topPadding=30, showBoundary=1) personas = [] header = Paragraph(data['titulo'], titleStyle) headings = data['headings'] allpersonas = data['query'] t = LongTable([headings] + allpersonas) t.setStyle(TableStyle( [ ('GRID', (0, 0), (-1, -1), 1, colors.black), ('BACKGROUND', (0, 0), (-1, 0), colors.gray) ] )) personas.append(t) frame.addFromList(personas,canv) And the table looks like this. Table Any help to get around this is appreciated. If I'm missing something, please tell me and I'll add it to the post. -
How am I supposed to add a field to a signup form in django-allauth? Docs vs Stackoverflow vs Blog posts
It appears that there are multiple ways to add a simple field to a django-allauth signup form. From @danielfeldroy I see what's quoted below. # SpyBookSignupForm inherits from django-allauth's SignupForm class SpyBookSignupForm(SignupForm): # Specify a choice field that matches the choice field on our user model type = d_forms.ChoiceField(choices=[("SPY", "Spy"), ("DRIVER", "Driver")]) # Override the init method def __init__(self, *args, **kwargs): # Call the init of the parent class super().__init__(*args, **kwargs) # Remove autofocus because it is in the wrong place del self.fields["username"].widget.attrs["autofocus"] # Put in custom signup logic def custom_signup(self, request, user): # Set the user's type from the form reponse user.type = self.cleaned_data["type"] # Save the user's type to their database record user.save() But then, in the response to a ticket from https://github.com/pennersr/django-allauth/issues/826 pennersr (django-allauth's founder) states that all we have to do is: class SignupForm(forms.Form): first_name = forms.CharField(max_length=30, label='Voornaam') last_name = forms.CharField(max_length=30, label='Achternaam') def signup(self, request, user): user.first_name = self.cleaned_data['first_name'] user.last_name = self.cleaned_data['last_name'] user.save() And then add ACCOUNT_SIGNUP_FORM_CLASS = 'yourproject.yourapp.forms.SignupForm' to my settings. See: How to customize user profile when using django-allauth But then in the docs we have this: https://django-allauth.readthedocs.io/en/latest/forms.html#signup-allauth-account-forms-signupform Where we do this: from allauth.account.forms import SignupForm class MyCustomSignupForm(SignupForm): def save(self, request): # Ensure you … -
django model is getting Alter Field alert on every migrations
i am getting alter filed alert every time when i run the command python manage.py makemigrations i also delete my database old migration files but the alert is still there can anybody know how can i solve this issue? Migrations for 'assignment': assignment/migrations/0012_auto_20201016_0754.py - Alter field city on assignment - Alter field status on assignment class Assignment(models.Model): CITY_SELECT = { ('i', 'Islamabad'), ('l', 'Lahore'), ('m', 'Multan'), ('k', 'Karachi'), ('q', 'Queta'), ('p', 'Pashawar') } STATUS_SELECT = { ('p', 'Pendding'), ('d', 'Done'), ('i', 'In field'), ('c', 'Cancel') } place = models.CharField(max_length=100) desc = models.CharField(max_length=500) reporter = models.ForeignKey(User, on_delete=models.SET_NULL, null=True) created_on = models.DateTimeField(auto_now_add=True) assign_time = models.DateTimeField(auto_now=False, null=True) city = models.CharField(choices=CITY_SELECT, max_length=9) status = models.CharField(choices=STATUS_SELECT, max_length=8) -
No such file or directory when i load image
When loading an image from a form, an error is triggered: "[Errno 2] No such file or directory: '... \ pictures \ foto.jpg'", but if i load from database then everything works well file views.py: elif "ProfileUpdateForm" in request.POST: form=ProfileUpdateForm(request.POST,request.FILES) if form.is_valid(): profile=Profile.objects.get(user=self.request.user) profile.avtor=form.cleaned_data.get('avtor') profile.save() obj=Profile.objects.get(user__username=self.request.user) return HttpResponseRedirect(reverse_lazy('profile',kwargs={'slug': obj.slug},)) file forms.py: class ProfileUpdateForm(forms.ModelForm): class Meta: model=Profile fields=('avtor',) widgets={'avtor': forms.FileInput(),} file models.py: class Profile(models.Model): user=models.OneToOneField(User,verbose_name="Пользователь",on_delete=models.CASCADE) avtor=models.ImageField(verbose_name="Аватарка",default='user_images/default.jpg', upload_to='user_images',blank=True) def save(self, *args, **kwards): image = Image.open(self.avtor.path) if image.height > 256 or image.width > 256: resize = (256, 256) image.thumbnail(resize) image.save(self.avtor.path) return super(Profile, self).save(*args, **kwards) file profile.html: <form action="" method="POST" enctype="multipart/form-data"> {% csrf_token %} {{ ProfileUpdateForm.as_p }} <input name="ProfileUpdateForm" class="input-button" type="submit" value="Save" /> </form> -
How to Retrieve Post by Each Category in a Blog and Place them on postlist html page in django
Am creating a blog and a news website in django which have a specific category displayed on its hompage. That is the specific category for news, Politics and education are beeing displayed on my post_list.html. I get a no exception provided when i try to retrieve it by Post.objects.filter(category__name__in=["news"]) This is the model for my category class Category(models.Model): name = models.CharField(max_length=250) slug = models.SlugField(max_length=250, unique=True) This is the model for my Post class Post(models.Model): image = models.ImageField(upload_to="images/") title = models.CharField(max_length=150) summary = models.CharField(max_length=250) category = models.ForeignKey(Category, on_delete=models.CASCADE) *This is the view for my postlist class PostListView(ListView): model = Post template_name = blog/post_list.html context_object_name = "posts" ordering = ["date_posted" paginate_by = 5 def get_queryset(self): posts = get_object_or_404(Post) return Post.objects.filter().order_by( "-date_posted") def get_context_data(self, **kwargs): context = super().get_context_data(**kwargs) context['posts'] = Post.objects.filter()[0:4] context['new_cat'] =Post.objects.filter(category__name__in=[" news"])[0.5] context['new_politics'] = Post.objects.filter(category__name__in=["politics"])[0.5] return context *** This is my pos_tlist.html code for retrieving post by category in news <div> <h1>News</h1> <div/> {% for post in new_cat%} div class="mt-2" <a href="{{ post.get_absolute_url }}"><img class="object-cover w-full rounded-lg" src="{{ post.image.url }}" alt="{{ post.title }} cover"> </a></div> <div class="py-2 flex flex-row items-center justify-between"> <a href="{{ post.get_absolute_url }}"><h1 class="hover:text-blue-600 text-gray-900 font-bold text-xl mb-2 py-2">{{ post.title }}</h1></a></div> ''' I get a no exception provided for … -
Field 'id' expected a number but got <Listing: Ps4 Pro>
It's my first time creating a Django website with models, and in my first attempt to insert data into my table I'm getting this error. My models are as follows: class User(AbstractUser): pass #https://docs.djangoproject.com/en/3.1/topics/auth/default/ class Listing(models.Model): listingID = models.AutoField(auto_created=True, primary_key=True, serialize=False, verbose_name="listID") created_by = models.ForeignKey(User, on_delete=models.SET_NULL, related_name="myListing", null=True) watchers = models.ManyToManyField(User, blank=True, related_name="watchlist") title = models.CharField(max_length=30) description = models.TextField() creation_date = models.DateField(auto_now=True) img_url = models.URLField() active = models.BooleanField(default=True) def __str__(self): return f"{self.title}" class Bid(models.Model): listing = models.ForeignKey(Listing, on_delete=models.SET_NULL, related_name="bidsMadeOnMe", null=True, blank=True) user = models.ForeignKey(User, on_delete=models.SET_NULL, related_name="myBids", null=True) price = models.FloatField() creation_date = models.DateField(auto_now=True, null=True) def __str__(self): return f"Bid={self.price}" and the view that handles the form submission is this one: @login_required def create_listing(request): if request.method == "POST": user = User.objects.get(username=request.user.username) l = Listing(created_by=user, title=request.POST["title"], description=request.POST["desc"], # https://stackoverflow.com/questions/12176585/handling-dates-over-request-get creation_date=models.DateTimeField(auto_now_add=True), img_url=request.POST["image_url"] ) l.save() b = Bid(l, user, request.POST["initial_bid"], models.DateTimeField(auto_now_add=True) ) b.save() return render(request, "auctions/index.html") I know the problem is the way I'm adding the data but I can't fix it. Can someone give me some light? -
Stop a running function in Django
I am uploading a CSV file then adding the rows in the database and I want to able to pause, resume or terminate the function that handles the upload so the user can pause or terminate while the file is still uploading the file to the server or when the server is adding the content of the CSV file into the database I tried to use threading but i couldn't do it that way and then i tried to time.sleep() but it just runs and it does not pause the show function and when i try to stop the pause function it does not stop views.py is_paused = False def show(request): content = {} if not is_paused: if request.method =='POST': uploaded_file = request.FILES['file'] print(uploaded_file.name) print(uploaded_file.size) fs = FileSystemStorage() fs.save(uploaded_file.name,uploaded_file) upload = Upload() upload.title = uploaded_file.name upload.file = uploaded_file upload.save() filecontent = file_content() path = '/home/ahmed/Desktop/atlan/atlan/media/'+uploaded_file.name with open(path) as csv_file: csv_reader = csv.reader(csv_file, delimiter=',') next(csv_reader) for row in csv_reader: filecontent.seq = row[0] filecontent.First_name =row[1] filecontent.Last_name = row[2] filecontent.age = row[3] filecontent.street = row[4] filecontent.city = row[5] filecontent.state = row[6] filecontent.zipcode = row[7] filecontent.dollar = row[8] filecontent.color = row[9] filecontent.date = row[10] file_content.CSV_ID = upload.ID filecontent.save() else: time.sleep(2) return render(request,'upload/upload.html', content) def … -
How to achive SUM aggregate() + distinct(fields) in Django ORM
I have a model: class A(models.Model): name = models.CharField() price = models.IntegerField() I need to aggregate Sum of all records in db but before it I want to remove duplicates by name (distinct) So i try use A.objects.all().distinct('name').aggregate(total=Sum('price') But I got error NotImplementedError: aggregate() + distinct(fields) not implemented. So, How can I achieve same result in django orm? -
Django if statement not working inside of a for loop in templates
So I want to display all the posts from the user, in their profile while logged in, but can't seem to figure out how to do it. This is my template: {% for post in posts %} {% if user.username == post.author %} <div class="container col-lg-8 ml-lg-5"> <div class="box"> <a href="#"><img class="rounded-circle account-image" src="{{ post.author.profile.image.url }}" alt="" ></a> <a href="#"><h4 style="float: left;">{{post.author}}</h4></a> <small>{{post.date_posted}}</small> <hr width="82%" align="right"> <br> <div class=""> <p>{{post.content}}</p></div> </div> <br> </div> {% endif %} {% endfor %} And this is my model: class Post(models.Model): content = models.TextField() date_posted = models.DateTimeField(default=timezone.now) author = models.ForeignKey(User, on_delete=models.CASCADE) It doesn't show me any errors, it just doesn't work. When I try removing the if statement, it works, but shows me every post by every user -
Different models order in main.django_content_type table during unittesting
I'm using django 3.1 with SQLite DB. I'm using my django project as API, so django rest framework is installed as well. During my unittest (with pycharm) I've observed that in table main.django_content_type some models in my dev DB and test DB are ordered differently and have different IDs. For example defaultcategory and customcategory: dev DB: admin logentry auth permission auth group contenttypes contenttype sessions session core customuser core historicalcustomuser authtoken token authtoken historicaltoken finances fixtransaction finances historicaldefaultcategory finances historicaltransfer finances historicaltransaction finances transaction finances fixtransfer finances historicalfixtransfer finances historicalcostaccount finances historicalfixtransaction finances transfer finances costaccount finances historicalcustomcategory finances defaultcategory finances customcategory test DB: admin | log entry auth | permission auth | group contenttypes | content type sessions | session core | custom user core | historical custom user finances | cost account finances | transfer finances | transaction finances | historical transfer finances | historical transaction finances | historical fix transfer finances | historical fix transaction finances | historical default category finances | historical custom category finances | historical cost account finances | fix transfer finances | fix transaction finances | default category finances | custom category authtoken | Token authtoken | historical Token Is there any way … -
Django- Query Multiple models with many to many and one to one relationships
Reposted from an earlier question - but made simpler: 3 Models: Actor(models.Model): id = models.UUIDField(primary_key=True, default=uuid.uuid4) type = models.Charfield(max_length=20) Organisation(models.Model): id = id = models.UUIDField(primary_key=True, default=uuid.uuid4) name = models.Charfield(max_length=20) actor = models.OneToOneField(Actor, on_delete=Models.CASCADE) parent_organisation = models.ForeignKey(Actor, on_delete=models.CASCADE) CustomUser(AbstractBaseUser,PermissionsMixin): id = models.UUIDField(primary_key=True, default=uuid.uuid4) name = models.Charfield(max_length=20) member_of = models.ManyToManyField(Actor, on_delete=models.CASCADE) actor = actor = models.OneToOneField(Actor, on_delete=Models.CASCADE) Note: I have left out fields which are not important. In the Views.py - I wish to find all users within an organisation - Such that given an organisation id, I get the users for the whole organisation. I wish to find all the users with a department - Such that given an organisation id, I get the users for the department (NB: departments are linked on the same organisation model but by the parent -FK) I have tried many different combinations over the last 3 days including: Chaining by : current_organisation = Actor.objects.get_actor(request.session['organisation']).first() This works and I get the Organisation that a user belongs to; The next step: organisation_departments = Actor.objects.filter(parent__actor_id__in =current_organisation) gives me an error of 'Actor' object is not iterable I have looked through the Docs and a similar example here. am I right in suggesting that there should be method using … -
Django static files suddenly disappeared 404 error
I have weird question, but can anyone know what happened? I have made Django app and everything worked fine, and then restarted server and start again Django with command: And then static files do not loaded (CSS, images ...)... I get 404 error. What happened??? Please help... Maybe I have to run it on the other way? I really do not know what happened, because everything worked fine, and then after I started that again everything go wrong.. nohup python manage.py runserver 0.0.0.0:8000 & This is the command that I used to start django (server) again.. -
Django: window.localstorage to store a CSS animation
I'm trying to make a facebook inspired ajax like button with Jquery and Django. The AJAX call is working. The button has a counter, the users' names who have liked the post along with a CSS animation just like facebook's (where on clicking the button, it turns blue and when clicking it again, the button goes back to normal). The problem is on reload, my CSS animation on the button is gone and I'm not able to update the counter and the user's name on the list while on an AJAX call (Althought they work on page reload, not the CSS animation though). For CSS animation I tried to use Javascript's localStorage method but it just toggles the CSS animation and doesn't store it locally. A little help would be appreciated. Here's my code: #Like-Button-Form(i is iterating through my post model object): <form id="like_form" method="get"> <!-- {% csrf_token %} --> <div class="like"> <button type="button" name="post_id" id="like{{ i.id }}" data-catid="{{ i.id }}" class="like_ajax_btn" value="{{ i.id }}"> <i class="fad fa-heart"></i> Like </button> {% if i.like %} <div class="show_likes"> {{ i.total_likes }} Like{{ i.total_likes|pluralize }} <div class="username_liked"> {% for p in i.like.all %} <div><a class="username_likes_post" href="{% url 'userprofile' p.id %}">{{ p.username }}</a></div> {% … -
DJANGO - USER'S NOTIFICATION
I'm working on a django project. It manages designers projects. Each project has a worker (who is working on the project) and a responsible (who assigns the project to a worker). The worker can modify some attributes of the project through an Update Form (and one of the project's attributes is 'complete', that is a boolean). When the worker goes to the update form and checks the 'complete' checkbox, I'd like to implement the feature of sending a notification to the projects' responsable to let him know that the project has been finished. So I'd like to sent the notification not every time that the worker modifies the projects, but just when he checks the 'complete' checkbox. How should I do that? Each project has an image field for the final result of the project, and I'd like to know if it is possible to attach it to the notification that it is sent when the workers marks that the project has been completed. Also, as well as the notification, I'd like to send the responsible an email always with the image attached. To do that do I need to use celery or there is a simpler way that doesn't … -
how to make an Q%A section in Python without using the django or other additional tools, just need the basic
Using Q&A Forum for posting questions and displaying them how to make an Q%A section in Python without using the django or other additional tools, just need the basic.
