Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Django admin site is changed to normal html
Unfortunately my admin site got changed into a normal html site. I don't how it is happened. Did anyone came-across this problem and overcome of it. Actual result: Expected Result: -
How to display Changed Data in Django With AJAX
Actually am trying to make an cart for my website Now What i am trying to do is using Ajax i want to add and remove the item from my cart Here what i have done so far urls.py urlpatterns = [ path('admin/', admin.site.urls), path('', views.cart_home, name = 'cart_home'), path('add/<int:product_id>', views.cart_add, name = 'cart_add'), path('delete/<int:product_id>', views.cart_delete, name = 'cart_delete'), ]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) And Here is my delete item from cart function in views.py def cart_delete(request, product_id): cart_id = request.session.get('cart_id') cart = Cart.objects.filter(id = cart_id ).first() ###REMOVING PRODUCT FROM CART########## cart.Product.remove(product_id) ################################### # GETTING TOTAL PRICE cart = Cart.objects.filter(id = cart_id).first() if cart is None: pass else: total = 0 for x in cart.Product.all(): total += x.price cart.total = total cart.save() print(total) return HttpResponse('Item Removed') and here is my Cart Model models.py class Cart(models.Model): User = models.ForeignKey(User, blank = True, null = True, on_delete = models.DO_NOTHING) Product = models.ManyToManyField(Product, blank = True,null = True) total = models.IntegerField(blank = True, null=True) sub_total = models.IntegerField(blank = True, null = True) created_at = models.DateField(auto_now=True) and now what i have done so far //Deleting Cart $(document).on('click','.cart_delete',function(e){ e.preventDefault() url = $(this).attr('href'); var p = $(this) $.ajax({ url: url, beforeSend: function(data){ $(".alert").html("<div class='alert alert-success' >Removing</div>") }, success: … -
How can you create an excel from a serialized model in DJANGO REST FRAMEWOK to be consumed (downloaded)
Good afternoon I have a query how I could generate an excel of a serialized model in DJANGO REST FRAMEWORK to be downloaded from a frontend (Angular). This excel I want to have the possibility that it has a filter, for example I want it to only bring me the records that have the P79COL01 equipment column in the property or property, in addition to other filters. My Model Interfaces class Interfaces(models.Model): id_interface=models.PositiveIntegerField(primary_key=True) id_EquipoOrigen=models.ForeignKey(Equipos,on_delete=models.DO_NOTHING,related_name='equipo_origen') id_PuertoOrigen=models.ForeignKey(Puertos,on_delete=models.DO_NOTHING,related_name='puerto_origen',null=True,blank=True) estatus=models.BooleanField(default=False) etiqueta_prtg=models.CharField(max_length=80,null=True,blank=True) grupo=models.PositiveSmallIntegerField(default=0,blank=True) if_index=models.PositiveIntegerField(default=0,blank=True) bw=models.PositiveSmallIntegerField(default=0,blank=True) bw_al=models.PositiveSmallIntegerField(default=0,blank=True) id_prtg=models.PositiveSmallIntegerField(default=0,blank=True) ospf=models.BooleanField(default=False) description=models.CharField(max_length=200,null=True,blank=True) id_EquipoDestino=models.ForeignKey(Equipos,on_delete=models.DO_NOTHING,related_name='equipo_destino') id_PuertoDestino=models.ForeignKey(Puertos,on_delete=models.DO_NOTHING,related_name='puerto_destino') ultima_actualizacion=models.DateTimeField(auto_now=True) class Meta: db_table='Interfaces' My Serializer Model Interfaces class InterfaceSerializer(serializers.ModelSerializer): # Las siguientes lineas me permiten agregan campos de otros modelos al modelo en cuestion que estoty serializando a traves de llaves foraneas. #Se le agrega la propiedad de read_only=True para que el campo no sea editable. EquipoOrigen = serializers.CharField(source='id_EquipoOrigen.nombre',read_only=True) PuertoOrigen = serializers.CharField(source='id_PuertoOrigen.nombre',read_only=True) LocalidadOrigen=serializers.CharField(source='id_EquipoOrigen.localidad',read_only=True) CategoriaOrigen=serializers.CharField(source='id_EquipoOrigen.categoria',read_only=True) EquipoDestino = serializers.CharField(source='id_EquipoDestino.nombre',read_only=True) PuertoDestino = serializers.CharField(source='id_PuertoDestino.nombre',read_only=True) LocalidadDestino=serializers.CharField(source='id_EquipoDestino.localidad',read_only=True) CategoriaDestino=serializers.CharField(source='id_EquipoDestino.categoria',read_only=True) Vendedor=serializers.CharField(source='id_EquipoOrigen.vendedor',read_only=True) class Meta: model=Interfaces fields=('id_interface','id_EquipoOrigen','EquipoOrigen','id_PuertoOrigen','PuertoOrigen','LocalidadOrigen','CategoriaOrigen','Vendedor','estatus','etiqueta_prtg','grupo','if_index','bw','bw_al','id_prtg','ospf','description','id_EquipoDestino','EquipoDestino','id_PuertoDestino','PuertoDestino','LocalidadDestino','CategoriaDestino','ultima_actualizacion',) My ModelViewSet Interfaces class InterfacesViewSet(viewsets.ModelViewSet): queryset=Interfaces.objects.all() serializer_class=InterfaceSerializer pagination_class=PostPageNumberPagination filter_class=InterfacesFilter class PostPageNumberPagination(PageNumberPagination): page_size=10 page_size_query_param = 'page_size' max_page_size = 1000 #Funcion Para El Filtro del Modelo Interfaces. class InterfacesFilter(filters.FilterSet): # Lineas de Codigo para filtrar campos relacionados, es decir campo que estan en el serializador del modelo Interfaces … -
Switching Git branches while running in Docker container causes permission error
I'm running Docker 19 on Windows 10 for development. A container volume binds directly to a Git repo folder and serves the Django app in that folder. I use Mingw-w64 to run Git (aka Git Bash). Occasionally, I'll do the following (or something similar to the following): Request a page served by the Docker container. (To replicate an error, for example.) Switch to a different branch. Request a page served by the Docker container from the new branch. Switch to a different branch. On the last branch switch, Git will freeze for a bit and then say permission denied on a particular file. The file is a difference between the two branches, so Git is trying to change it. Process Explorer tells me the files are used by the system process so the only way to get it to let go is by restarting. My gut is telling me the Django web process (manage.py runserver) is likely locking the file until the request connection is fully closed and is probably lingering as an established connection. Is my gut right? If it is... Why is the lock held by the system process and not Docker? Is there anything to do to … -
HTTPConnectionPool(host=\'0.0.0.0\', port=7000): Max retries exceeded with url (Caused by NewConnectionError
I'm using python to make 2 APIs communicate between them, i made tests and both APIs work fine on their own, the problem arises when i try to send a request to API A (made with flask) so A can pass the data to API B(made with django) and then return the result to A again. When i try to test this endpoint, the response is: HTTPConnectionPool(host='0.0.0.0', port=7000): Max retries exceeded with url: /verify?0 (Caused by NewConnectionError('<urllib3.connection.HTTPConnection object at 0x7fa0b939df50>: Failed to establish a new connection: [Errno 111] Connection refused')) The test file and the manual test fail in this way, if i make a request to API B with the url that API A is making it returns a ok message. I'm thing i missing something about the config in API B, but where? -
Django Please enter the correct username and password for a staff account
I have created the superuser before the deployment of app on Heroku server my domain is gizga.herokuapp.com when u enter gizga.herokuapp.com/admin a Django Admin dashboard comes and then u have to enter the username and password but it shows the following error "Django Please enter the correct username and password for a staff account Note that both fields" even I have created the superuser -
How do I force Django's DateTimeField to always use microseconds
This answer helped me quite a bit, but I am trying to go for something different, and wondering if there is an easy way to do it. I have some data that always needs to have microsecond precision. Currently, I'm just storing it as a BigIntegerField and converting it when needed. However, I would like to store it as a DateTimeField or something similar so I don't have to litter the code with converters. I know Django will preserve this information on our production database, but our tests run using the SQLite DB. It's one of those edge cases, where it shouldn't matter, but I want to try to future-proof the application a bit. Does anyone know if Django has a fallback method or if its fallback is just to throw away the extra information when using databases that don't support that level of precision? -
Django - How do I change the sort order of search results while still on the page?
I have a list of results from a user's search and I want the user to be able to re-order them as they wish. It is simple enough to pre-sort the queryset on the backend, in views.py which is what every Google search brings up on the topic. But I need to have this done by the user. On the frontend. This is usually done with a dropdown with options allowing alphabetical sort A-Z or sort by date added or so on. I can't find an answer with Google search or a single tutorial that covers it, yet I see it used almost everywhere. Does the solution involve ajax? How would I use ajax to do it? Is there a py module that does this in Django? -
Optimizing Django app in Google App Engine
I am facing slow page load time (list page in Django admin) for a simple Django app, deployed on Google App Engine, with postgres Cloud SQL. There are fewer than 20 records. SQL time is negligible, even with 30 queries. Majority of the time is shown as domLoading I assume that domLoading is probably referring to the initial loading of the case/ page, which took 3 seconds. Most of the solutions online refer to tweaking apache/nginx settings. But since I am using Google App Engine (PaaS), I cannot directly control webserver settings. gcloud app deploy is supposed to handle the load-balancing and code versioning. How do I improve the basic load time of Django App on GAE? Both GAE and Cloud SQL are hosted in the same region. PS: I did find some answers like Optimizing my Django app on Google App Engine, but they refer to optimizing SQL queries, which is not the case here. -
Amazon s3 alternative for django app on heroku [on hold]
Is there an alternative to amazon s3 for storing and serving media files (images) for django app deployed in heroku? Can we use google drive for this purpose? -
add multiple forms to page on button click
I am working on developing a permitting app using django. This is my first django project so bear with me here... we have a default utility permit that contains some basic info like property owner and address. Then from that you can attach a sewer, or water or row or any combination of related tables to the permit. Basically I am looking for a way to return a page with the default utility permit then have a series of links or buttons to add more forms to that page. I made some model forms for each of the models and can display them individually on the page forms.py class UtilityPermitForm(forms.ModelForm): class Meta: model = UtilityPermit fields = ['...'] class SewerPermitForm(forms.ModelForm): class Meta: model = SewerPermit fields = ['...'] class WaterPermitForm(forms.ModelForm): class Meta: model = WaterPermit fields = ['...'] I successfully added them to a list and could iterate through and get them to add views.py class BuildForms(View): permits = [] utility_form = UtilityPermitForm sewer_form = SewerPermitForm water_form = WaterPermitForm permits.append(utility_form) permits.append(sewer_form) permits.append(water_form) template_name = 'engineering/UtilityPermitForm2.html' def get(self, request, *args, **kwargs): out_permits = [] for form in self.permits: out_permits.append(form()) return render(request, self.template_name, {'form': out_permits}) def post(self, request, *args, **kwargs): if request.GET.get('testButton'): … -
Set checkbox disabled if already opted by user
I designed a seat layout with checkbox code looks something like this <div class="asiento"> <input type="checkbox" value="1" id="asiento1" name="check" > <label for="asiento1">1</label> </div> <div class="asiento"> <input type="checkbox" value="2" id="asiento2" name="check" /> <label for="asiento2">2</label> </div> <div class="asiento"> <input type="checkbox" value="3" id="asiento3" name="check" /> <label for="asiento3">3</label> </div> <div class="asiento"> <input type="checkbox" value="4" id="asiento4" name="check" /> <label for="asiento4">4</label> </div> <div class="asiento"> <input type="checkbox" value="5" id="asiento5" name="check" /> <label for="asiento5">5</label> </div> I tried to fetch data from Database using loop and i am getting output like this ['1', '2'] ['5'] can i do something to remove [ ] maybe use JQuery or JS to disable the checkbox that are already selected by other users, this is the loop that i used to get value {% for seat in seat %} {{seat.useat}} {% endfor %} -
Django fetching static files in absolute path instead of relative path
I'm trying to fetch a css file from my static folder (as declared in STATIC_URL=/static/) which path is $app/src/static/css/about.css to my html file located in $app/templates/about.css. I'll show the code below The thing that works but is not advisable by Django docs is I changed the STATIC_URL = 'static/' but this is not a good practice... However this way the static variable in html is static/... and it works. In about.html: link rel="stylesheet" href="{% static 'css/about.css' %}" And I don't know if this is needed but in urls.py is the following: urlpatterns = [ .. ] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) Expected result in href is =static/css/about.css What happens: href = /static/css/about.css Also I'm sorry for formating errors, I'm new to posting here -
How to save a Model Form with a foreign key of User to django models
I am trying to save user API keys to a Django Model with a foreign key of User such that each set of unique API keys has a unique User associated with them in the database. I am using the built in Django User Model and I have created my own Model Form in forms.py. I have tried including user in the Model form and Meta class to no avail. I have tried passing the keys and password as parameters to the model and form before saving. I have tried using instances of the form with commit set to False before adding the User to form.user. I've tried looking up the latest Django documentation but its fragmented and hard to follow. I'm purposefully leaving out imports unnecessary to this problem. This is my Models.py: from django.db import models from django.contrib.auth.models import User from django.conf import settings # Create your models here. class UserApiDetails(models.Model): user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, default=None) key = models.CharField(max_length=32) password = models.CharField(max_length=32) def __str__(self): out = "key: " + str(self.key) + '\n' + "Password: " + str(self.password) def keys_exist(self): if UserApiDetails.objects.filter(pk=User.pk).exists(): return True else: return False This is my forms.py: from django import forms from .models import UserApiDetails … -
Django user with limited permissions can see all default models in Rest Framework
I'm using Django 2.2 with djangorestframework-3.9.2 and djangorestframework_simplejwt-4.1.3. Using the admin interface I've defined some users as super users, and some with limited permissions to only view a few endpoints. However, when I log in with the limited user, the user can view everything, and it can even edit and delete entries everywhere. The user is required to log in to access the api, but once authenticated the individual permissions don't seem to work. In my settings I have the following: REST_FRAMEWORK = { 'DEFAULT_PERMISSION_CLASSES': ( 'rest_framework.permissions.IsAuthenticated', 'rest_framework.permissions.DjangoModelPermissions', ), 'DEFAULT_AUTHENTICATION_CLASSES': ( 'rest_framework_simplejwt.authentication.JWTAuthentication', 'rest_framework.authentication.SessionAuthentication', ), 'DEFAULT_FILTER_BACKENDS': ( 'django_filters.rest_framework.DjangoFilterBackend', ), } Is there anything else I explicitly have to set to block access to views? An example of how my views are defined follows: class CustomersViewSet(viewsets.ModelViewSet): queryset = Customer.objects.all() serializer_class = CustomerSerializer along with the serializer and model: class CustomerSerializer(serializers.ModelSerializer): class Meta: model = Customer fields = '__all__' class Customer(models.Model): identifier = models.CharField(max_length=255, unique=True) entryDate = models.DateTimeField(default=timezone.now, blank=True) user = models.ForeignKey( settings.AUTH_USER_MODEL, on_delete=models.CASCADE, null=True, blank=True ) def save(self, *args, **kwargs): user = get_request().user self.user = user super(Customer, self).save(*args, **kwargs) def __str__(self): return self.identifier Finally, the views are added in urls.py: router.register('api/customers', CustomersViewSet) urlpatterns = [ path('admin/', admin.site.urls), path('', include(router.urls)), path('api/', include('rest_framework.urls', namespace='rest_framework')), … -
How can i display database data on a Django form?
I created a page where the user submits an order. The order is submitted to the SQLite DB and has the following fields: Time - Status - Rate. Once the order is submitted, i would like my django template to show it below an 'Active orders' tab. I don't know how to do it in terms of code, but i figured out that i need to create a query to db where all the user's `orders are fetched (maybe fetching the orders where ID = user's id?). How would i be able to perform such a operation in Django? In my views? Here is the template's view: def myview(request): item = get_object_or_404(market, item=item) if request.method == 'POST': form = MyForm(request.POST) if form.is_valid(): send = form.save() send.save() messages.success(request, f"Success") else: form = MyForm() return render(request, "main/mytemplate.html", context={"form":form}) And part of the template: <form method="post" novalidate> {% csrf_token %} {% include 'main/includes/bs4_form.html' with form=form1 %} <button name="button1" type="submit" class="btn btn-primary">BUY</button> </form> <h3> ACTIVE ORDERS </h3> <p> Here should go the orders... </p> -
DRF: Nested serializer return in extra dictfield
I have the following object returned from a request which I want to serializer and return. 'data': [ { 'more_data': [ { 'name': 'more_data', 'value': 'test' }, ] 'data_attributes': [ { 'name': 'Package 1', 'attribute': '1', 'type': 'Test' }, ], } ] I want to return the data in the following format, basically nesting the data_attributes inside an extras DictField. { "data": [ { "name": "Package 1", "extras": { "data_attributes": [ { 'name': 'Package 1', 'attribute': '1', 'type': 'Test' } ] } } ] } I'm not sure how to write a nested serializer for this? -
django logout and redirection
i am using django authentification to make a oneToone relation with the user table. I try to use decorator @login_required to the next page after the login. when i logout and click on the back button of firefox, i always go to the previous page even if @login_required is apply. but when i refresh it redirect me on the login page. Is it a cache problem? how can i solve it? I want to do it like how the administration works def logout(request): from django.contrib.auth import logout from django.shortcuts import redirect logout(request) request.session.flush() return redirect('/') from django.contrib.auth.decorators import login_required @login_required(login_url='/') def administration(request): do something return something -
Wagtail CMS: RichTextField | URL embeds cannot be found
I have started using Django and Wagtail as an alternative to PHP solutions. I installed Wagtail following the docs and a small tutorial to get started. I have no custom settings in my settings/base.py concerning the WAGTAILEMBEDS_FINDERS. The only changes I made so far to the Home Page: from django.db import models from wagtail.core.models import Page from wagtail.core.fields import RichTextField from wagtail.admin.edit_handlers import FieldPanel class HomePage(Page): templates = "home/home_page.html" banner_title = models.CharField(max_length=100, blank=False, null=True) banner_imgname = models.CharField(max_length=100, blank=False, null=True) body = RichTextField(blank=True) content_panels = Page.content_panels + [ FieldPanel("banner_title"), FieldPanel("banner_imgname"), FieldPanel('body', classname="full"), ] And this is the simple home_page template: {% extends "base.html" %} {% load static %} {% load wagtailcore_tags %} {% block body_class %}template-homepage{% endblock %} {% block content %} {{ self.banner_title }} {{ self.imgname_title }} {{ page.body|richtext }} {% endblock %} All simple outputs of text from a CharField and RichTextField work fine, but the embed feature, which I -unfortunately - need the most (blog sharing all kinds of embed stuff), does not work properly. I tried Soundcloud, Deviantart, Vimeo, Instagram. Only YouTube embeds. (To confirm there are no other restrictions for the chosen links I embedded them in an editor of a WP installation (sorry :-)). I … -
Fields in custom serializers.Serializer
Why class Meta: fields = ('name') not working fields not working? I see all object, not only name. It is problem class ProjectsSerializer(serializers.Serializer): id = serializers.IntegerField(read_only=True) name = serializers.CharField(required=True, allow_blank=False, max_length=100) isActive = serializers.BooleanField() def create(self, validated_data): return Project.objects.create(**validated_data) def update(self, instance, validated_data): instance.id = validated_data.get('id', instance.id) instance.name = validated_data.get('name', instance.name) instance.isActive = validated_data.get('isActive', instance.isActive) return instance class ProjectsCreateSerializer(ProjectsSerializer):enter code here class Meta: fields = ('name') I expect the output of fields in ProjectsCreateSerializer to be {"name": ""} but the actual output is {"name": "","isActive": false} -
Get a list of all active session keys using default session engine?
Using Django's default session engine, not the database-driven one, is it possible to get a list of all active session keys? -
should ihave to install django every time i want to access my project?
please help how to acces the django project when i quit the command prompt it just dissappears and cannot locate it yet.should ihave to install django every time i want to access my project? how can i do it because it keeps asking me django-admin is not an internal command should ihave to install django every time i want to access my project? how can i do it because it keeps asking me django-admin is not an internal command should ihave to install django every time i want to access my project? how can i do it because it keeps asking me django-admin is not an internal command should ihave to install django every time i want to access my project? how can i do it because it keeps asking me django-admin is not an internal command -
django.urls.exceptions.NoReverseMatch: 'admin' is not a registered namespace
I have a Django projects with two apps, "projects" and "codebox", they were running fine, then at some point I got the following error: django.urls.exceptions.NoReverseMatch: 'admin' is not a registered namespace If I remove the link to my admin panel from my template this error goes away, but then I can't get to my admin panel: <a href="{% url "admin:index" %}">Admin</a> I was working in the urls.py files when this error occurred, have I changed something that is inadvertently having an impact on the admin link? Here is my top level urls.py file: from django.contrib import admin from django.urls import include, path, re_path urlpatterns = [ # path('', include('projects.urls')), path('projects/', include('projects.urls')), re_path('^accounts/', include('django.contrib.auth.urls')), re_path('^logged_out/', include('projects.urls')), path('codebox/', include('codebox.urls')), ] Here is my urls.py for "projects": from django.urls import path, include from . import views app_name = 'projects' urlpatterns = [ path('', views.IndexView.as_view(), name='index'), path('<int:pk>/', views.DetailView.as_view(), name='detail'), path('insight/', views.InsightView.as_view(), name='insight'), path('logged_out/', views.LoggedoutView.as_view(), name='loggedout'), path('insight/subgen/', views.SubgenView.as_view(), name='subgen'), ] And here is urls.py for my second app, codebox: from django.urls import path, include from . import views app_name = 'codebox' urlpatterns = [ path('', views.IndexView.as_view(), name='index'), path('<int:pk>/', views.DetailView.as_view(), name='detail'), path('form/', views.CreateView, name="form"), ] -
Config nested location NGINX
I have a basic issue about Nginx hope you guys help me: Now I config my location in Nginx: server { location / { include proxy_params; proxy_pass http://unix:/run/gunicorn.sock; } } I want to change it into nested location: http://exp.com/api instead of the current: http://exp.com/ I tried but it's not success: server { location / { location /api { include proxy_params; proxy_pass http://unix:/run/gunicorn.sock; } } } -
In Django Admin, can I display a listing of an unrelated record set alongside an admin form?
My use case is to implement something like a messaging form, allowing an administrator to write a message, then send it to group that they will filter from a list of users, from the User model. This is similar to the messaging to usergroups functionality in Joomla! so it's not too weird a use case. So my admin page for the "Message" model would need to contain the Message creation form and a second recordset of site Users, which could be filtered down to those who the administrator wishes to contact. Is this kind of thing possible in Django Admin, or do I need to dip into heavily customising an admin page?
