Django community: RSS
This page, updated regularly, aggregates Django Q&A from the Django community.
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Not Found: /media/ on form submit
I have a form with a ImageField() in it I've already set the media URL and directory and such in setting.py and url.py and on submit everything works perfectly, but suddenly now everytime I try submit my form it fails and says in python terminal : [17/Feb/2018 14:40:08] "POST /form/ HTTP/1.1" 200 37885 Not Found: /media/ , when I didn't even tempered with the setting.py or the url.py below is my code : setting.py STATIC_URL = '/static/' STATICFILES_DIRS = [os.path.join(BASE_DIR, "static")] MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, 'media') url.py urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) model.py class Model_A(models.Model): name = models.CharField(max_length=200, verbose_name="Name (as in NRIC)") def upload_photo_dir(self, filename): path = 'hiring/employees/photo/{}'.format(filename) return path photo = models.ImageField(upload_to=upload_photo_dir) view.py def application_form_view(request): form = Model_AForm(request.POST or None, request.FILES or None) if form.is_valid(): inst = form.save(commit=False) inst.save() context = {'form': form} return render(request, 'form.html', context=context) html <form method="POST" enctype="multipart/form-data" id="application_form" name="application_form"> <label>name :</label> {{ form.name}} <label>Photo:</label> {{ form.photo }} </form> -
Django Channels Invalid Syntax
I am trying to work with Django Channels. Every time I try to run manage.py, I get the following error: File "/usr/local/lib/python2.7/dist-packages/daphne/server.py", line 192 async def handle_reply(self, protocol, message): ^ SyntaxError: invalid syntax I have installed all the necessary components for Channels to work. -
User password reset: Emails not being sent to console
I am currently learning Django, mainly from Andrew Pinkham's book "Django Unleashed", and because the book is prior to Django 2, I cannot use the code in verbatim but adjust the code accordingly. I am currently on Ch. 21 (Extending Authentication). Everything works so far, but I am having trouble with users resetting their passwords. A user can enter the email for resetting the password, and a message appears, stating the email was successfully sent -- but nothing is displayed on the console (the code is still in DEBUG and I have yet to allow emails to be actually sent, other than to the console for testing). Here is an excerpt of my project structure: pysawitweb |_contact |_pysawitweb | |_settings.py | |_urls.py | |_... |_user | |_templates | | |_user | | | |_base_user.html | | | |_logged_out.html | | | |_login.html | | | |_login_form.html | | | |_password_change_done.html | | | |_password_change_form.html | | | |_password_reset_complete.html | | | |_password_reset_confirm.html | | | |_password_reset_email.txt | | | |_password_reset_form.html | | | |_password_reset_sent.html | | | |_password_reset_subject.txt | |_urls.py | |_... |_manage.py In the settings.py file: ... DEBUG = True ALLOWED_HOSTS = [] # Application definition INSTALLED_APPS = [ … -
Recursion error caused in django when trying to read from files
I am working on a project for displaying my university's energy data but when I am trying to read from my university's excel sheets that store data, I am getting the following error: RecursionError at /multiplication/ maximum recursion depth exceeded Request Method: GET Request URL: http://127.0.0.1:8000/multiplication/ Here is my views.py class without pandas: from django.shortcuts import render,get_object_or_404 from django.shortcuts import render_to_response from django.template import RequestContext from django.views.generic import TemplateView from django import forms #import pandas as pd # Create your views here. # def startPage(request): # return render(request, 'multiplication/detail.html') template_name1 = 'multiplication/detail.html' class myForm(forms.Form): quantity1 = forms.IntegerField(required=False) quantity2 = forms.IntegerField(required=False) #main method def multiply_two_integers(x,y): return x*y def read_excel(ExcelFileName): File = read_excel(ExcelFileName) return File def my_view(request): read_excel("AH1_Hahn_26032017_29032017.xl.xlsx") If I try to import pandas as pd, then I get a different type of error: Traceback (most recent call last): File "/Users/NikolasPapastavrou/firstProject/multiplication/views.py", line 14, in <module> import pandas as pd File "/Users/NikolasPapastavrou/firstProject/pandas/__init__.py", line 19, in <module> "Missing required dependencies {0}".format(missing_dependencies)) ImportError: Missing required dependencies ['numpy'] -
Django Pagination returns entire database on page 2
Trying to get pagination to work in Django, looks fine on page one but when I go to page to I see my entire database. class Advancedenter code hereSearch(ListView): template_name= 'saferdb/AdvancedQuery.html' def get(self, request): c = request.GET.getlist('opeclass') q = Question.objects.all() #Ugly q filtering methods paginator = Paginator(q, 25) page = request.GET.get('page') contacts = paginator.get_page(page) return render(request, 'saferdb/list.html', {'text' : count , 'contacts': contacts}) -
in __init__ super(NeonArgparser, self).__init__(*args, **kwargs) TypeError: __init__() got multiple values for keyword argument 'add_config_file_help'
class NeonArgparser(configargparse.ArgumentParser): """ Setup the command line arg parser and parse the arguments in sys.arg (or from configuration file). Use the parsed options to configure the logging module. Arguments: desc (String) : Docstring from the calling function. This will be used for the description of the command receiving the arguments. """ def __init__(self, *args, **kwargs): self._PARSED = False self.work_dir = os.path.join(os.path.expanduser('~'), 'nervana') if 'default_config_files' not in kwargs: kwargs['default_config_files'] = [os.path.join(self.work_dir, 'neon.cfg')] if 'add_config_file_help' not in kwargs: # turn off the auto-generated config help for config files since it # referenced unsettable config options like --version kwargs['add_config_file_help'] = False self.defaults = kwargs.pop('default_overrides', dict()) **super(NeonArgparser, self).__init__(*args, **kwargs)** # ensure that default values are display via --help self.formatter_class = configargparse.ArgumentDefaultsHelpFormatter self.setup_default_args() -
django rest framework modelserializer is_valid return false when declare custom field with source attribute
I was working on some project which read data from rest API then deserialize data for storing into database. Below are model and deserializer class ExchangeInfo(models.Model): server_time = models.BigIntegerField() timezone = models.CharField(max_length=20) class ExchangeInfoSerializer(serializers.ModelSerializer): server_time = serializers.IntegerField(source='serverTime') timezone = serializers.CharField(max_length=20) class Meta: model = ExchangeInfo fields = '__all__' Below is the code I used to deserialize data def load_exchange_info(): exchange_info = client.get_exchange_info() from common.models import ExchangeInfo from common.serializers import ExchangeInfoSerializer exchange_info_serializer = ExchangeInfoSerializer(data=exchange_info) exchange_info_serializer.is_valid() print(exchange_info_serializer.errors) Some how when I try to store the deserialized data to DB, it reflected successfully, but the is valid always return False as below {'server_time': ['This field is required.']} Any suggestion on what the issue is? -
Every other ajax call has a 300ms delay
I noticed a really weird behavior with my ajax calls. Every other ajax call always have a 300ms delay. Here is what the network section look like. I looked at the details of the call. Here is the fast ajax call, and here is the slow ajax call. The slow ajax call has 2 extra fields - DNS lookup and Initial Connection. Why does this happen every other ajax call? How can I ensure consistent ajax performance? The test code: <body> <input type="button" class="btn" id="testButton" value="Test"/> </body> <script> document.getElementById('testButton').onclick = function() { var xhttp = new XMLHttpRequest(); xhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { console.log('done'); } }; xhttp.open("GET", "{% url 'test_ajax' %}", true); xhttp.send(); } </script> def test_ajax(request): return JsonResponse({'a': 'a'}) -
Autocomplete through a selected external key (Django)
I have a query and I have 2 models, one called Detalleventa and Producto class DetalleVenta(models.Model): producto = models.ForeignKey(Producto,on_delete=models.CASCADE,verbose_name='Producto') cantidad = models.IntegerField(verbose_name='Cantidad') preciounit = models.DecimalField(decimal_places=2, max_digits=7, verbose_name='Precio unitario') subtotal = models.DecimalField(decimal_places=2, max_digits=7, verbose_name='Subtotal') venta = models.ForeignKey(Venta,on_delete=models.CASCADE, related_name='detalleventa', verbose_name='Venta') def __str__(self): return '{} - {}'.format(self.venta,self.producto) class Producto(models.Model): nombre = models.CharField(max_length=30,unique=True,verbose_name='Nombre de Producto:') precio = models.DecimalField(decimal_places=2, max_digits=7, verbose_name='Precio de Producto:') categoria = models.ForeignKey(Categoria,on_delete=models.CASCADE,verbose_name='Categoría:') def __str__(self): return self.nombre And in my Detalle forms.py I have: class DetalleForm(forms.ModelForm): class Meta: model = DetalleVenta fields = [ 'producto', 'cantidad', 'preciounit', 'subtotal', ] labels = { 'producto':'Producto', 'cantidad':'Cantidad', 'preciounit':'Prec.Unit.', 'subtotal':'Subtotal', } widgets = { 'producto':forms.Select(attrs={'class':'form-control'}), 'cantidad':forms.NumberInput(attrs={'class':'form-control cantidad'}), 'preciounit':forms.NumberInput(attrs={'class':'form-control'}), 'subtotal':forms.NumberInput(attrs={'class':'form-control subtotal', 'readonly':True}), } DetalleFormSet = inlineformset_factory(Venta, DetalleVenta, form=DetalleForm, extra=1) As you can see in the details form, I have a priceunit field that refers to the price of the product that is in the product model and my question is: is there any way in my details template when selecting, for example, a product X ? ? (external key product) autocomplete its respective price in the input of preciounit? This is my template: {% extends 'base/base.html' %} {% load static %} {% block titulo%} Registrar venta {%endblock%} {% block contenido %} <div class="col-md-12"> <form method="post">{% csrf_token %} … -
Django: Is it possible to use `method(or property)` for `unique_together` in model?
This is my model structure (I simplified fields of model): class SymbolB(models.Model): type = models.CharField(max_length=50) class SymbolA(models.Model): sector = models.CharField(max_length=50) class DailyPrice(StockDataBaseModel): symbol_a = models.ForeignKey(SymbolA, null=True) symbol_b = models.ForeignKey(SymbolB, null=True) date = models.DateField() @property def symbol(self): if self.symbol_a is not None: return self.etf_symbol if self.symbol_b is not None: return self.stock_symbol def clean(self): if type(self.symbol) is SymbolA and DailyPrice.objects.filter(symbol_a=self.symbol, date=self.date): return False elif type(self.symbol) is SymbolB and DailyPrice.objects.filter(symbol_b=self.symbol, date=self.date): return False return True The reason that DailyPrice model has two symbol fields is that it should be related with either of them. I know I can use GenericForeignKey but this site said that GenericForeignKey makes db table and query process more complex so chose above structure. And what I want to do is to prevent DailyPrice model created with same symbol(either symbol_a or symbol_b) and the date. For example, the one with symbol_a = my_symbol and date="2011-11-11" should be unique. That's why the clean() method is overrided in the model. As a result, every time I create DailyPrice model, I should write a code like below: daily_price = DailyPrice( symbol_a=symbol, date=date, open=open, high=high, low=low, close=close,volume=volume, ) if not daily_price.clean(): return else: daily_price.save() which is kinda bothersome and no idea whether this … -
Fastest way to run many startswith queries in django
I have a list of item numbers which can be thousands of elements long. I need to search my SQL database for records that start with the numbers in my list. I am using the django ORM but raw sql works too. As an example my list could look like this: ['123ab', '234dd', '421ad'] I am trying to find a solution that is better than looping through the list and running a startswith query every time like this: for element in list: Item.objects.filter( item_number__startswith=element ).values( 'item_number', 'manufacturer' ) The problem with the loop above is that it would be very slow for a large list of item numbers. Is there a more efficient way of doing this? -
Multiple Mezzanine projects on same server with Nginx and Gunicorn: "server IP address could not be found"
I'm very new to deployment. I'm trying to deploy two Mezzanine 4.2.3 projects (they use Django 1.10.8 according to requirements.txt) on Ubuntu 16.04. I deployed the first one successfully with this tutorial. I can access it via its domain name, say, example.com. I'm trying to get the other one accessible on either food.example.com or preferably example.com/food but the browser returns: "server IP address could not be found". The nginx config for example.com at /etc/nginx/sites-available/example: server { listen 80; server_name [SERVER IP ADDRESS] example.com; location = /favicon.ico { access_log off; log_not_found off; } location /static/ { root /home/example; } location / { include proxy_params; proxy_pass http://unix:/home/example/example.sock; } The nginx config for food.example.com at /etc/nginx/sites-available/food: server { listen 81; server_name food.example.com; location = /favicon.ico { access_log off; log_not_found off; } location /static/ { root /home/food; } location / { include proxy_params; proxy_pass http://unix:/home/food/food.sock; } } I tried to use example.com/food but nginx kept saying there're suspicious symbols in it. I don't know if that's one of the problems preventing the page from being displayed but I changed it to the subdomain food anyway to try and isolate the issue. The gunicorn config file for example.com at /etc/systemd/system/gunicorn.service: [Unit] Description=gunicorn daemon After=network.target [Service] … -
How to add a table in django app models from PostgreSQL?
I have created a django project named Book Store. In my project I have one app named books. I am using PostgreSQL DBMS. I have a database called books. In that database, I have a table named novel. How do I add this table in the models.py file inside books app? I want to register this table under admin site. After successfully adding this table in the models.py file, I believe, I shall be able to register the table in the admin site by writing the following codes in the admin.py file under books app. from django.contrib import admin from . models import novel admin.site.register(novel) I also want to know that if my approach is correct or is there any better way available? As I am new to django, I don't know much about it. I have read django-book but didn't find out my answer. There is an article about SQLite database though. So, can anyone help me out here? Thanks in advance. -
Django logging does not work with django shell
I have logging set up in my Django app to log to both stdout and a file. When I run my django app normally (./manage.py runserver) the logs are updated as expected. However, when I run ./manage.py shell and run the following commands the log is not updated: import logging logger = logging.getLogger('mylogger') logger.error('test') Do I have to do something extra to get logging to work within the shell? -
Publish button doesn't do anything (django forms)
I am following an online django course and one of the exercises includes creating a blog. One of the elements of the blog includes a "Publish" button. But when I click on that button, it doesn't do anything. I have checcked and re-checked the code in HTML, views.py, and urls.py but I don't see whats missing. This is the code: HTML: Publish views.py: @login_required def post_publish(request,pk): post = get_object_or_404(Post,pk=pk) post.publish() return redirect('post_detail',pk=pk) urls.py: url(r'^post/(?P\d+)/publish/$',views.post_publish,name='post_publish'), -
Filtering queryset by next 30 days and date passed
I'm not sure if It's due to lack of sleep, but I cannot for the life of me figure out what's causing this issue. AttributeError: 'datetime.date' object has no attribute 'utcoffset' I'm trying to filter a queryset based on two conditions. If the date has already passed. If the date is within the next 30 days. Model class Member(models.Model): user = models.OneToOneField(User, on_delete=models.CASCADE, blank=True, null=True) ... membership_expiry = models.DateField(null=True, blank=True) club_membership_expiry = models.DateField(null=True, blank=True) medical_expiry = models.DateField(null=True, blank=True) View get_context_data override def get_context_data(self, **kwargs): context = super(MembershipReport, self).get_context_data(**kwargs) members = Member.objects.all() now = date.today() thirty_days = now + timedelta(days=30) context['membership_overdue'] = members.filter(Q(membership_expiry__lte=now) | Q(membership_expiry__gte=now, membership_expiry__lte=thirty_days)) return context I've tried using date.today() datetime.now() and django's timezone.now() all three throw the same error. -
Django: Lazy Load <img>
Django 2.0, Python 3.4 view_album.html <p>Album Title Here</p> {% for image in album.get_images %} <img src="{{ image.foo }}"> {% endfor %} foo is a function which returns a url to the image. I don't want to have users wait for all the images foo functions to run and return before loading the page. Albums could contain 30+ images. I want all the images on one page, no pagination. Don't need some fancy load-while-scrolling thing. I just want the page to load and the images to load after. Is there a simple way to achieve this? -
Django combining data from separate HTML forms to Django View
I have a django application that needs to returns post.request data from two separate parts (products and entries). At the moment, the template is setup as two separate HTML forms and what I need to do is to combine it into one. Therefore upon clicking the button the values for product ID and entry quantity are both passed to the view. I can't work out how to do this so would appreciate any help. HTML Template File: <body> {% for product in products %} <form method="POST"> {% csrf_token %} {{ product.name }} <br/> {{ product.id }} <input type="hidden" name='product_id' value='{{ product.id }}'> <button>Product Object and ID</button> </form> {% endfor %} {% for cart in my_carts_current_entries %} <form method="POST"> {% csrf_token %} <br/> <input type="hidden" name='entry_quantity' value='{{ cart.quantity }}'> <button>Entry Quantity</button> </form> {% endfor %} </body> Views.py def test_view(request): cart_obj, new_obj = Cart.objects.new_or_get(request) my_carts_current_entries = Entry.objects.filter(cart=cart_obj) products = Product.objects.all() if request.POST: product_id = request.POST.get('product_id') print(product_id) product_obj = Product.objects.get(id=product_id) print(product_obj) entry_quantity = request.POST.get('entry_quantity') print(entry_quantity) # Entry.objects.create(cart=cart_obj, product=product_obj, quantity=entry_quantity) return render(request, 'carts/test.html', {'cart_obj': cart_obj, 'my_carts_current_entries': my_carts_current_entries, 'products': products}) -
DRF json 404 insetad of html page
I would like to replace default django 404 (and other in the future) with the DRF response, as easy as it is possible, just to return (standard DRF response): { "detail": "Not found." } So I put this code in my url.py file. from rest_framework.exceptions import NotFound from django.conf.urls import handler404 handler404 = NotFound When I set Debug flag (in the set Ture I'm geting 500, when set it to False 404 but in the html form. I've read doc here: http://www.django-rest-framework.org/api-guide/exceptions/ but to be honest I don't know how to put this into reality. it seems to be easy, but somehow I failed to implement this (above code comes form the other SO threads). Thank you in advance -
Can't get the authorization right while getting the Access Token from Twitter API
Following this doc, I finally got the steps 1 and 2 working by copypasting this answer. Why my original solution didn't work is still beyond me, but whatever I was doing wrong there seems to carry on in this third step, since I get an HTTP Error 401: Authorization Required. The Oauth header I produce is the following: Oauth oauth_consumer_key="omitted", oauth_nonce="ozlmgbmrxftmmfaxnngbpsulickqwrkn", oauth_signature="3ZxJu%252Bv%2FjxyPmghiI85xnuPv3YQ%253D", oauth_signature_method="HMAC-SHA1", oauth_timestamp="1518820400", oauth_token="omitted", oauth_version="1.0" which seems to be exactly the way the doc I linked in the beginning wants it. So maybe my signature is wrong? I can't really figure it out since I do it in a pretty standard way. This is my code for the callback url up until the request to oauth/access_token: def logged(request): print('Processing request from redirected user...') token = request.GET.get('oauth_token', '') user = twitterer.objects.get(oauth_token=token) #my model for the user that's signing in with twitter verifier = user.oauth_verifier = request.GET.get('oauth_verifier', '') url = 'https://api.twitter.com/oauth/access_token' dir_path = path.dirname(path.realpath(__file__)) with open(path.join(dir_path, 'credentials.txt'), 'r') as TweetCred: creds = TweetCred.read().split(linesep) oauth_consumer_key = creds[0].split()[1] consumer_secret = creds[2].split()[1] oauth_nonce = '' for i in range(32): oauth_nonce += chr(random.randint(97, 122)) oauth_timestamp = str(int(time.time())) parameter_string = ('oauth_consumer_key=' + urllib.parse.quote(oauth_consumer_key, safe='') + '&oauth_nonce=' + urllib.parse.quote(oauth_nonce, safe='') + '&oauth_signature_method=HMAC-SHA1' + '&oauth_timestamp=' + oauth_timestamp + … -
server side implementation in python, Django that will automatically perform some tasks and update my website build in Django
I want to develop a website in Django that will scrap some data from the various links, process it and stores in a database and update the website and after an hour the process of scraping, processing and updating continues. I want to know the architecture of this implementation, how it will work, how I would code my server in what technology (REST, node.js). I know this I require a database in Django project, website design but how and where can I code the loop of scrapping->process->update website. what is server side in Django? -
Django-CKEditor can't insert or drag image into rich text editor
I'm installing Django-CKEditor in Django 2.0 Now I have seen the CKEditor rich text editor,and can editor text.But I can't insert or drag image into it. I guess there are something wrong with my model. models.py: # encoding:utf-8 from django.db import models from ckeditor.fields import RichTextField # Create your models here. class Article(models.Model): title = models.CharField(max_length=50, verbose_name='文章标题') desc = models.CharField(max_length=50, verbose_name='文章描述') content = RichTextField(null=True, blank=True,verbose_name='文章内容') category = models.CharField(default="other",max_length=30, verbose_name='标签名称') date_publish = models.DateTimeField(auto_now_add=True, verbose_name='发布时间') image = models.ImageField(upload_to="media/%Y/%m", default=u"media/default.png", max_length=100) class Meta: verbose_name = '文章' verbose_name_plural = verbose_name ordering = ['-date_publish'] def __str__(self): return self.title settings.py: STATIC_URL = '/static/' MEDIA_URL = '/media/' CKEDITOR_UPLOAD_PATH = "uploads/" CKEDITOR_CONFIGS = { 'default': { 'toolbar': None, }, } urls.py: urlpatterns = [ path('blog/', include('blog.urls')), path('admin/', admin.site.urls), path(r'^ckeditor/', include('ckeditor_uploader.urls')), ] Any friend can give me some suggestions? -
Django nested transactions - “with transaction.atomic()” -- Seeking Clarification
In reference to: Django nested transactions - “with transaction.atomic()” (I'm new here and thus not allowed to comment on the original question.) The original question is: given this... def functionA(): with transaction.atomic(): #save something functionB() def functionB(): with transaction.atomic(): #save another thing ...if functionB fails and rolls back, does functionA roll back too? Kevin Christopher Henry replies with, "Yes, if an exception happens in either function they will both be rolled back." He then quotes the docs... https://docs.djangoproject.com/en/2.0/topics/db/transactions/#django.db.transaction.atomic ...which state... atomic blocks can be nested. In this case, when an inner block completes successfully, its effects can still be rolled back if an exception is raised in the outer block at a later point. This documentation quote doesn't seem to address the original question. The doc is saying that when the INNER BLOCK (which is functionB) completes successfully, its effects can still be rolled back if the OUTER block (which is functionA) raises an exception. But the question refers to the opposite scenario. The question asks, if the INNER block (functionB) FAILS, is the OUTER block (functionA) rolled back? This doc quote doesn't address that scenario. However, further down in the doc we see this example... from django.db import IntegrityError, … -
Return fields that are related to a model by a foreignkey
class SenderInfo(models.Model): #to create unique id numbers sender = models.CharField(max_length=15) id_number = models.IntegerField(blank=True, null=True) class Messages(models.Model): message_sender = models.ForeignKey(SenderInfo, related_name='messages') message_body = models.TextField() I want to just return all the messages for each instance of SenderInfo. So I can see all the messages a user has made. I know how to see the Senders of a particular message but what's the simplest method to achieve the opposite? -
Logging into a Django server with Cypress.io
Must be missing something obvious but I am very much stuck on logins into Django due to its CSRF protection. I looked Check out our example recipes using cy.getCookie() to test logging in using HTML web forms but that really doesn't help that much if the first thing it recommends is disabling CSRF. What Django wants: This is what a normal, CSRF-protected, Django login view is expecting in its incoming POST data: csrfmiddlewaretoken=Y5WscShtwZn3e1eCyahdqPURbfHczLyXfyPRsEOWacdUcGNYUn2EK6pWyicTLSXT username=guest password=password next It is not looking for the CSRF in the request headers and it is not setting x-csrf-token on the response headers. And, with my code, I am never passing in the csrf token which gets Django to return a 403 error. Cypress.Commands.add("login", (username, password) => { var login_url = Cypress.env("login_url"); cy.visit(login_url) var hidden_token = cy.get("input[name='csrfmiddlewaretoken']").value; console.log(`hidden_token:${hidden_token}:`) console.log(`visited:${login_url}`) var cookie = cy.getCookie('csrftoken'); // debugger; var csrftoken = cy.getCookie('csrftoken').value; console.log(`csrftoken:${csrftoken}:`) console.log(`request.POST`) cy.request({ method: 'POST', form: true, url: login_url, // body: {'username': 'guest', 'password': 'password', 'csrfmiddlewaretoken': cy.getCookie('csrftoken').value} body: {'username': 'guest', 'password': 'password', 'csrfmiddlewaretoken': hidden_token} }) }) Cypress's error: I suspect that the POST data has something to do with the token being undefined via the both the hidden form input or the cookie acquisition approach, as shown …
